I want to write a shell script that searches in all .txt files the word cat and replaces it with mouse.I wrote the following code:
!/bin/bash
read directory
for F in ` find $directory -name '*.txt' -type f`
do
echo $F
`sed -i "s/\<cat\>/mouse/g" $F`
done
I am supposed to use "file" command.I searched for it and it seems like file command finds all the files of a certain type.I want to know how can I include that command in my script.
Assuming you are in the directory where all *.txt files are. You can execute the following command:
find . -name *.txt -exec sed -i "s/\<cat\>/mouse/g" "{}" \;
Related
new here, learning bash for first time.
I'm trying to iterate over files named "list.txt" placed in subfolders, manipulate and create a new files, under the same subfolder. The nest could be like this:
inventory/product_names1/list.txt
inventory/product_names2/list.txt
As product_names is completly random, I would like to iterate over all list.txt files with unix cms like sed/grep/cut and create a new file, under the same random product_names folders.
for f in $( find . -name 'list.txt'); do for list in $f; do cat $f | cut -d']' -f2- > "$f/new_file.txt" ; done ; done
I can access files into the nest using find command. How can I redirect output in the right subfolder if the product_names is random?
inventory/product_names1/list.txt
inventory/product_names1/new_file.txt
inventory/product_names2/list.txt
inventory/product_names2/new_file.txt
This script is intended to work in the root folder, pointing and working with entime path "inventory". $f access to inventory/product_names1/list.txt but I need the output in inventory/product_names1. How can I redirect correctly if I don't have the right value/variable?
You can either use parameter expansion to remove the file name from the path, or you can iterate over all the directories and only work on them if they contain the list.txt file.
#!/bin/bash
for list in inventory/*/list.txt ; do
new=${list%/*}/new_list.txt
echo "$list" "$new"
done
# OR
for dir in inventory/* ; do
if [[ -f $dir/list.txt ]] ; then
echo "$dir"/list.txt "$dir"/new_list.txt
fi
done
find can not only find files but also execute commands when a file is found:
find . -type f -name 'list.txt' -execdir sh -c 'cut -d"]" -f2 list.txt > new_file.txt' \;
Explanations:
-type f condition added to skip directories named list.txt. If some of your list.txt files can be symbolic links and you want to consider them too, use -type f,l with GNU find. With other find you may need to use \(-type f -o -type l\).
-execdir runs the command in the directory where the file was found.
By default find does not print when -execdir is used. If you need it add the -print command:
find . -type f -name 'list.txt' -execdir sh -c 'cut -d"]" -f2 list.txt > new_file.txt' \; -print
I want to rename a file present in several subdirectories using bash script.
my files are in folders:
./FolderA/ABCD/ABCD_Something.ctl
./FolderA/EFGH/EFGH_Something.ctl
./FolderA/WXYZ/WXYZ_Something.ctl
I want to rename all of the .ctl file with the same name (name.ctl).
I tried several command using mv or rename but didnt work.
Working from FolderA:
find . -name '*.ctl' -exec rename *.ctl name.ctl '{}' \;
or
for f in ./*/*.ctl; do mv "$f" "${f/*.ctl/name .ctl}"; done
or
for f in $(find . -type f -name '*.ctl'); do mv $f $(echo "$f" | sed 's/*.ctl/name.ctl/'); done
Can you help me using bash?
thanks
You can do this with one line with:
find . -name *.ctl -exec sh -c 'mv "$1" `dirname "$1"`/name.ctl' x {} \;
The x just allows the filename to be positional character 1 rather than 0 which (in my opinion) wrong to use as a parameter.
Try this:
find . -name '*.ctl' | while read f; do
dn=$(dirname "${f}")
# remove the echo after you sanity check the output
echo mv "${f}" "${dn}/name.ctl"
done
find should get all the files you want, dirname will get just the directory name, and mv will perform the rename. You can remove the quotes if you're sure that you'll never have spaces in the names.
What im trying to do is something along the lines of(this is pseudocode):
for txt in $(some fancy command ./*.txt); do
some command here $txt
You can use find:
find /path -type f -name "*.txt" | while read txt; do
echo "$txt"; # Do something else
done
Use the -exec option to find:
find /usr/share/wordlists/*/* -type f -name '*.txt' -exec yourScript {} \;
Try
find . | grep ".txt" | xargs -I script.sh {}
find returns all files in the directory. grep selects only .txt files and xargs sends the file as Parameter to script.sh
I'm trying to create a batch file in linux that will allow me to change extensions of files in multiple subdirectories. After much searching and experimenting i've found what seems to be a solution:
find /volume1/uploads -name "*.mkv" -exec rename .mkv .avi {} +
When running the script i get the following error:
find: -exec CMD must end by ';'
I've tried adding ; and \; (with or without +) but to no avail. What's wrong with the command and how can I fix it?
Edit: Running on a Synology NAS with DSM 4.2
you have to escape all characters that would be interpreted by bash. in your case these are the semicolon and the curly braces (you forgot to escape the latter in your code):
find /volume1/uploads -name "*.mkv" -exec rename .mkv .avi \{\} \;
the {} (in our case \{\}) is expanded to the filename, so the actual call would look like rename .mkv .avi /volume1/uploads/foo/bla.mkv (which is not the exact syntax the /usr/bin/rename needs, at least on my system).
instead it would be something like:
find /volume1/uploads -name "*.mkv" -exec rename 's/\.mkv$/.avi/' \{\} \;
UPDATE
if you don't want to (or cannot) use perl's rename script, you could use the following simple bash script and save it as /tmp/rename.sh
#!/bin/sh
INFILE=$1
OUTFILE="${INFILE%.mkv}.avi"
echo "moving ${INFILE} to ${OUTFILE}"
mv "${INFILE}" "${OUTFILE}"
make it executable (chmod u+x /tmp/rename.sh) and call:
find /volume1/uploads -name "*.mkv" -exec /tmp/rename.sh \{\} \;
UPDATE2
it turned out that this question is really not about bash but about busybox.
with a limited shell interpreter like busybox, the simplest solution is just to append the new file extension:
find /volume1/uploads -name "*.mkv" -exec mv \{\} \{\}.avi \;
Not sure how different find and rename commands are on your DSM 4.2 OS so try something like:
find /volume1/uploads -name "*.mkv" | while read filename;
do mv -v "${filename}" "$(echo "${filename}" | sed -e 's/\.mkv$/\.avi/')"
done
I have a number of clients running a piece of software within their public_html directory. The software includes a file named version.txt that contains the version number of their software (the number and nothing else).
I want to write a bash script that will look for a file named version.txt directly within every user's /home/xxx/public_html/ and output both the path to the file, and the contents of the file, i.e:
/home/matt/public_html/version.txt: 3.4.07
/home/john/public_html/version.txt: 3.4.01
/home/sam/public_html/version.txt: 3.4.03
So far all I have tried is:
#!/bin/bash
for file in 'locate "public_html/version.txt"'
do
echo "$file"
cat $file
done
But that does not work at all.
find /home -type f -path '*public_html/version.txt' -exec echo {} " " `cat {}` \;
Might work for you, but you can go without echo and cat ("tricking" grep):
find /home -type f -path '*public_html/version.txt' -exec grep -H "." {} \;
Or do it using find:
find /home -name "*/public_html/version.txt" -exec grep -H "" {} \;
for i in /home/*/public_html/version.txt; do
echo $i
cat $i
done
will find all the relevant files (using shell wildcarding), echo the filename out and cat out the file.
If you want a more concise output, you should investigate grep and replace the echo/cat with an appropriate regular expression e.g.
grep "[0-9]\.[0-9]" $i