How can I combine two blocks to simplify my code? - ruby

Question

Hi I am a student learning Ruby. I am using the quick start guide at ruby-lang.org, which has some examples of Ruby basics.
I studied the MegaGreeter class, and I am trying to figure out how to puts two arguments (name and age) in the same each block in order to simplify my code.
I think there would be another way. (Using regular loops instead of each.)
Calculate the array's size.
Use a loop like in C.
But I want to use the each loop. Below is my code:
class MegaGreeter
attr_accessor :name
attr_accessor :age
#Creat the object
def initialize(name=nil, age=0)
#name = name
#age = age
#tmp = Array.new()
#i = 0
end
#Say hi to everybody
def say_hi
if #name.nil?
puts "please give me the input !!"
elsif #name.respond_to?("each")
#list responding
#name.each do |name|
#tmp[#i] = "hi ~! #{name}"
#i += 1
end
#i=0
#age.each do |age|
#tmp[#i] += " and you are #{age} years old"
puts #tmp[#i]
#i += 1
end
else
puts "give me array ~"
end
end
end
a = MegaGreeter.new()
a.name = ["juno","yoonhe"]
a.age = [1,2]
a.say_hi

Answer 1

You can use the Array method zip to first combine your two arrays. It groups the elements by their position in the array, so the first element of the #name array will be grouped with the first element of the #age array and so on.
#name = ['Foo', 'Bar']
#age = [23, 41]
name_and_age = #name.zip(#age)
# [['Foo', 23], ['Bar' 41]]
Now the names and ages are grouped together, and you can iterate over them using each.
name_and_age.each do |name, age|
puts name, age
end
# Foo 23
# Bar 41
Putting it back into your original code:
class MegaGreeter
attr_accessor :name, :age
#Creat the object
def initialize(name = nil, age = 0)
#name = name
#age = age
end
#Say hi to everybody
def say_hi
if #name.nil?
puts "please give me the input !!"
elsif #name.respond_to?("each")
#list responding
#name.zip(#age).each do |name, age|
puts "hi ~! #{name} and you are #{age} years old"
end
else
puts "give me array ~"
end
end
end