Spring rest Json issue - spring

Question

I found below answered question
Different names of JSON property during serialization and deserialization
Unfortunately this does not work when we use Spring Restful webservice. I am not sure what is cauisng the issue but it gives some Field abiguity exception.
What I want to do is Serialize and deserialize a field name with different names.
For e.g.
class Test {
private String name;
#JsonProperty("myName")
public String getName() {
return name;
}
#JsonProperty("yourName")
public void setName(String name) {
this.name = name;
}
}
This does not work in Spring rest

Answer 1

You can not set #JsonProperty for both (getter & setter). You can set for the field or setter method.
But you want different name for request and response, Create two classes like this.
class StudentResponse{
#JsonProperty(name="student_name)
private String name;
//getter & setter
}
class StudentRequest{
#JsonProperty(name="name)
private String name;
//getter & setter
}

Answer 2

Damith is right, you seem to not be able to mark both methods within the same class, however there is a way to solve this:
First off, you will have to Create a custom deserializer (or serializer, depends on your preference).
My example object:
#JsonDeserialize(using = ObjectDeserializer.class)
public class MyObject {
private String name;
public void setName(String name) {
this.name = name;
}
#JsonProperty("SomeOtherName")
public String getName() {
return name;
}
}
Note, i mark the getter as the property with the first name. And I give the class a custom deserializer. Which looks like that:
public class ObjectDeserializer extends JsonDeserializer<MyObject> {
#Override
public MyObject deserialize(JsonParser jp, DeserializationContext ctxt)
throws IOException, JsonProcessingException {
MyObject object = new MyObject();
JsonNode node = jp.getCodec().readTree(jp);
JsonNode jsonNode = node.get("MyCustomSerializeName");
object.setName(jsonNode.getTextValue());
return object;
}
}
This class will create my custom object and get the name of the setter field description (rather than relying on the property name).
Put together, i get:
public class DeserializeTest {
public static void main(String[] args) throws JsonGenerationException, JsonMappingException, IOException {
ObjectMapper mapper = new ObjectMapper();
MyObject o = new MyObject();
o.setName("Hello");
String writeValueAsString = mapper.writeValueAsString(o);
System.out.println(writeValueAsString);
String jsonObj = "{\"MyCustomSerializeName\":\"Other Test\"}";
MyObject readValue = mapper.readValue(jsonObj, MyObject.class);
System.out.println(readValue.getName());
}
}
And this outputs:
{"SomeOtherName":"Hello"}
Other Test
I hope that helps you.