I understand that each process has their own, separate heap unlike threads (which share a common heap, which thus slows heap memory allocation down as functions like malloc need to use locks for synchronization). However, how does it get decided where, and how much, memory is given to each process, and how is it ensured that this does not conflict with the memory allocated to other processes?
I have not been able to find a definitive answer on this through searching, but if one exists, please provide a link as I would greatly appreciate it. Thank you!
In order to answer the question, you need to understand about virtual memory. In virtual memory, the memory is contiguous as to what user processes can see. The heap is given a very big about of the virtual memory which is limited only by the amount of physical RAM and swap space to back the allocations. In itself the process only sees a contiguous virtual address space. On Linux, the memory allocations are done using the buddy algorithm and the kernel keeps a page struct for every page. The page struct along with the memory map of the process in the task_struct thus allows the Linux kernel to follow what page is free and which isn't.
After some tests with help of Task Manager, I understood one thing about gcnew — memory allocated for local variables remaines allocated even if control leaves function, and is re-allocated only when control re-enters this function — so I'm in perplexity, how to deallocate memory myself. Here is some example of the problem:
void Foo(void)
{
System::Text::StringBuilder ^ t = gcnew System::Text::StringBuilder("");
int i = 0;
while(++i < 20000000) t->Append(i);
return;
}
As I mentioned, memory for variable t remains after leaving Foo(), delete not work as it works for new, and calling Foo() once, only gives me pointless allocated memory.
This is gcnew, which means garbage collected allocation. It will be disposed and deallocated by GC thread
Your function uses memory for code and data. The code is a fixed amount and will be used the entire time the library or program is loaded. The data is only used when the function is executing.
Data used by a program is either static or dynamic. Static data is laid out by the compiler and is basically equivalent to code (except that it might be marked as non-executable and/or read-only to prevent accidents). Dynamic data is temporary and allocated from a stack or heap (or CPU registers).
In a classic program, the stack and heap share the same memory address range with the stack at one end, growing toward the heap and the heap at the other end, trying not to grow into the stack. However, with modern address ranges on the order of 1TB, a heap generally has a lot of room.
Keep in mind that when a program requests an address range, it's just signaling to the operating system that it's okay to use that address for data reading, data writing and/or code execution. Until it actually puts something there, there is no load on the system. Also keep in mind with a virtual memory system, process memory is effectively allocated on the swap file/device (hard drive) with optimizations especially using RAM for caching, copy on write and many other techniques. (Data written to a memory address might never make it to the swap file, but that's up to the operating system.)
The data your function needs is for the two variables: t and i. t is a reference to a garbage collected object. i is an integer. Both are quite small and short-lived. You could think of them as being on the stack. When the function returns, the stack frame is popped and their memory is reused by the next stack operation. If you are looking at memory allocation, there won't be a change because the amount of memory allocated to the stack would not be changed.
Now in the execution of your function, a new object is created and, the way it's filled with data, it takes up quite a bit of memory. You could consider that object to be created in the heap. You don't need to delete it since it is a garbage collection object. When the garbage collector runs by walking all objects reachable from a set of root objects, it will find that the object is not reachable and add its space to a free list. When space for a new object is needed that doesn't fit into any blocks on the free list, more of the heap's address range will be used.
The CLR heap is compactable, which means it can move objects around in order to coalesce free blocks. Using this ability, it can move objects out of areas of allocated memory and give it back to the operating system, thereby freeing up space in the swap file.
So, there are three things that have to happen for you to see a reduction in the amount of memory allocated to the process:
The garbage collection has run to find unreachable objects.
The heap has been compacted.
The heap allocation has been reduced.
None of these things are really necessary until the swap file can't grow anymore. Obviously, the system has been designed for performance and to be a good citizen so it wouldn't take it that far. You can influence when garbage collection runs but this is only very rarely helpful and is generally not done.
What is difference between kmem_cache_alloc and kmalloc() in kernel memory allocation? which one is used when?
Kmalloc - allocates contiguous region from the physical memory. But keep in mind, allocating and free'ing memory is a lot of work.
Kmem_cache_alloc - Here, your process keeps some copies of the some pre-defined size objects pre-allocated. Say you have struct that you know you will be requiring very frequently, so instead of allocating it from the main memory (kmalloc) when you need it, you already keep multiple copies of it allocated & when you want it, it returns the address of the block already allocated (saves a lot of time). Similarly, when you free it, you don't give it back, it actually isn't free'd, it goes back to the allocated pool so that if some process again asks for it, you can return this address of the already allocated struct.
kmalloc: It uses the generic slab caches available to any kernel code. so your module will share slab cache with other components in kernel.
kmem_cache_alloc: It will allocate objects from a dedicated slab cache created by kmem_cache_create. If you specifically want a better slab cache management dedicated to your module only, that too for a specific type of objects, use kmem_cache_create followed by kmem_cache_alloc. USB/SCSI drivers use this. kmem_cache_create takes sizeof your object you want to create slab of, a name which appears in /proc/slabinfo and flags to govern behavior of your slab cache.
Ref: https://www.mail-archive.com/kernelnewbies#nl.linux.org/msg13191.html & LDD
I need to have a malloc-like interface that allows to allocate blocks of memory in a shared segment. I don't want to set the size of this segment statically, the allocator should be able to manage growth as needed. The locking must be not only among threads of a single process, but system-wide: many processes might try to allocate blocks in the pool concurrently.
Is there a ready made library that can do this? I've found libmm, but it doesn't seem to allow interprocess locking, and I am a bit worried that it looks a abandoned, last update was on 2006.
Here's my question: Does calling free or delete ever release memory back to the "system". By system I mean, does it ever reduce the data segment of the process?
Let's consider the memory allocator on Linux, i.e ptmalloc.
From what I know (please correct me if I am wrong), ptmalloc maintains a free list of memory blocks and when a request for memory allocation comes, it tries to allocate a memory block from this free list (I know, the allocator is much more complex than that but I am just putting it in simple words). If, however, it fails, it gets the memory from the system using say sbrk or brk system calls. When a memory is free'd, that block is placed in the free list.
Now consider this scenario, on peak load, a lot of objects have been allocated on heap. Now when the load decreases, the objects are free'd. So my question is: Once the object is free'd will the allocator do some calculations to find whether it should just keep this object in the free list or depending upon the current size of the free list it may decide to give that memory back to the system i.e decrease the data segment of the process using sbrk or brk?
Documentation of glibc tells me that if the allocation request is much larger than page size, it will be allocated using mmap and will be directly released back to the system once free'd. Cool. But let's say I never ask for allocation of size greater than say 50 bytes and I ask a lot of such 50 byte objects on peak load on the system. Then what?
From what I know (correct me please), a memory allocated with malloc will never be released back to the system ever until the process ends i.e. the allocator will simply keep it in the free list if I free it. But the question that is troubling me is then, if I use a tool to see the memory usage of my process (I am using pmap on Linux, what do you guys use?), it should always show the memory used at peak load (as the memory is never given back to the system, except when allocated using mmap)? That is memory used by the process should never ever decrease(except the stack memory)? Is it?
I know I am missing something, so please shed some light on all this.
Experts, please clear my concepts regarding this. I will be grateful. I hope I was able to explain my question.
There isn't much overhead for malloc, so you are unlikely to achieve any run-time savings. There is, however, a good reason to implement an allocator on top of malloc, and that is to be able to trace memory leaks. For example, you can free all memory allocated by the program when it exits, and then check to see if your memory allocator calls balance (i.e. same number of calls to allocate/deallocate).
For your specific implementation, there is no reason to free() since the malloc won't release to system memory and so it will only release memory back to your own allocator.
Another reason for using a custom allocator is that you may be allocating many objects of the same size (i.e you have some data structure that you are allocating a lot). You may want to maintain a separate free list for this type of object, and free/allocate only from this special list. The advantage of this is that it will avoid memory fragmentation.
No.
It's actually a bad strategy for a number of reasons, so it doesn't happen --except-- as you note, there can be an exception for large allocations that can be directly made in pages.
It increases internal fragmentation and therefore can actually waste memory. (You can only return aligned pages to the OS, so pulling aligned pages out of a block will usually create two guaranteed-to-be-small blocks --smaller than a page, anyway-- to either side of the block. If this happens a lot you end up with the same total amount of usefully-allocated memory plus lots of useless small blocks.)
A kernel call is required, and kernel calls are slow, so it would slow down the program. It's much faster to just throw the block back into the heap.
Almost every program will either converge on a steady-state memory footprint or it will have an increasing footprint until exit. (Or, until near-exit.) Therefore, all the extra processing needed by a page-return mechanism would be completely wasted.
It is entirely implementation dependent. On Windows VC++ programs can return memory back to the system if the corresponding memory pages contain only free'd blocks.
I think that you have all the information you need to answer your own question. pmap shows the memory that is currenly being used by the process. So, if you call pmap before the process achieves peak memory, then no it will not show peak memory. if you call pmap just before the process exits, then it will show peak memory for a process that does not use mmap. If the process uses mmap, then if you call pmap at the point where maximum memory is being used, it will show peak memory usage, but this point may not be at the end of the process (it could occur anywhere).
This applies only to your current system (i.e. based on the documentation you have provided for free and mmap and malloc) but as the previous poster has stated, behavior of these is implmentation dependent.
This varies a bit from implementation to implementation.
Think of your memory as a massive long block, when you allocate to it you take a bit out of your memory (labeled '1' below):
111
If I allocate more more memory with malloc it gets some from the system:
1112222
If I now free '1':
___2222
It won't be returned to the system, because two is in front of it (and memory is given as a continous block). However if the end of the memory is freed, then that memory is returned to the system. If I freed '2' instead of '1'. I would get:
111
the bit where '2' was would be returned to the system.
The main benefit of freeing memory is that that bit can then be reallocated, as opposed to getting more memory from the system. e.g:
33_2222
I believe that the memory allocator in glibc can return memory back to the system, but whether it will or not depends on your memory allocation patterns.
Let's say you do something like this:
void *pointers[10000];
for(i = 0; i < 10000; i++)
pointers[i] = malloc(1024);
for(i = 0; i < 9999; i++)
free(pointers[i]);
The only part of the heap that can be safely returned to the system is the "wilderness chunk", which is at the end of the heap. This can be returned to the system using another sbrk system call, and the glibc memory allocator will do that when the size of this last chunk exceeds some threshold.
The above program would make 10000 small allocations, but only free the first 9999 of them. The last one should (assuming nothing else has called malloc, which is unlikely) be sitting right at the end of the heap. This would prevent the allocator from returning any memory to the system at all.
If you were to free the remaining allocation, glibc's malloc implementation should be able to return most of the pages allocated back to the system.
If you're allocating and freeing small chunks of memory, a few of which are long-lived, you could end up in a situation where you have a large chunk of memory allocated from the system, but you're only using a tiny fraction of it.
Here are some "advantages" to never releasing memory back to the system:
Having already used a lot of memory makes it very likely you will do so again, and
when you release memory the OS has to do quite a bit of paperwork
when you need it again, your memory allocator has to re-initialise all its data structures in the region it just received
Freed memory that isn't needed gets paged out to disk where it doesn't actually make that much difference
Often, even if you free 90% of your memory, fragmentation means that very few pages can actually be released, so the effort required to look for empty pages isn't terribly well spent
Many memory managers can perform TRIM operations where they return entirely unused blocks of memory to the OS. However, as several posts here have mentioned, it's entirely implementation dependent.
But lets say I never ask for allocation of size greater than say 50 bytes and I ask a lot of such 50 byte objects on peak load on the system. Then what ?
This depends on your allocation pattern. Do you free ALL of the small allocations? If so and if the memory manager has handling for a small block allocations, then this may be possible. However, if you allocate many small items and then only free all but a few scattered items, you may fragment memory and make it impossible to TRIM blocks since each block will have only a few straggling allocations. In this case, you may want to use a different allocation scheme for the temporary allocations and the persistant ones so you can return the temporary allocations back to the OS.