I'm trying to read som XML with golang. I'm basing it on this example which works. https://gist.github.com/kwmt/6135123#file-parsetvdb-go
This is my files:
Castle0.xml
<?xml version="1.0" encoding="UTF-8" ?>
<Channel>
<Title>test</Title>
<Description>this is a test</Description>
</Channel>
test.go
package main
import (
"encoding/xml"
"fmt"
"io/ioutil"
"os"
)
type Query struct {
Chan Channel `xml:"Channel"`
}
type Channel struct {
title string `xml:"Title"`
desc string `xml:"Description"`
}
func (s Channel) String() string {
return fmt.Sprintf("%s - %d", s.title, s.desc)
}
func main() {
xmlFile, err := os.Open("Castle0.xml")
if err != nil {
fmt.Println("Error opening file:", err)
return
}
defer xmlFile.Close()
b, _ := ioutil.ReadAll(xmlFile)
var q Query
xml.Unmarshal(b, &q)
fmt.Println(q.Chan)
}
Output:
- %!d(string=)
Any one know what I'm doing wrong? (I'm doing this to learn go, so go easy on me :P)
Other packages, including encoding/json and encoding/xml can only see exported data. So firstly your title and desc should be Title and Desc correspondingly.
Secondly, you're using %d (integer) format in Sprintf when printing a string. That's why you're getting %!d(string=), which means "it's not an integer, it's a string!".
Thirdly, there is no query in your XML, so unmarshal directly into q.Chan.
This is the working example. http://play.golang.org/p/l0ImL2ID-j
Related
I am sending the data to the API like following:
{"after": {"amount": 811,"id":123,"status":"Hi"}, "key": [70]}
and i am getting following while printing :
map[after:map[amount:811 id:123 status:Hi ] key:[70]]
Is there any way to print individual field like this??
amount::800
id:123
status:Hi
The code:
package main
import (
"encoding/json"
"fmt"
"io"
"io/ioutil"
"log"
"net/http"
"strings"
)
var (
PORT = ":8080"
)
func main() {
fmt.Println("In Main")
http.HandleFunc("/", changedData)
http.ListenAndServe(PORT, nil)
}
type Data struct {
Id int64 `json:"id"`
Amount float64 `json:"amount"`
Status string `json:"status"`
}
type mark map[string]interface{}
func changedData(w http.ResponseWriter, r *http.Request) {
fmt.Println("Coming From API")
reqBody, _ := ioutil.ReadAll(r.Body)
fmt.Println("Data coming from API ", string(reqBody))
digit := json.NewDecoder(strings.NewReader(string(reqBody)))
for digit.More() {
var result mark
err := digit.Decode(&result)
if err != nil {
if err != io.EOF {
log.Fatal(err)
}
break
}
fmt.Println("final_data ", result)
}
}
Decode to a Go type that matches the structure of the JSON document. You declared a type for the "after" field. Wrap that type with a struct to match the document.
func changedData(w http.ResponseWriter, r *http.Request) {
var v struct{ After Data }
err := json.NewDecoder(r.Body).Decode(&v)
if err != nil {
http.Error(w, "bad request", 400)
return
}
fmt.Printf("final_data: %#v", v.After)
}
Playground example.
I think you can define a struct type if you know the JSON file format or if the JSON format is predefined. As far as I know that mostly using interface{} is a way when you don't know the JSON format or there is no predefined format of the JSON. If you define a struct type and use it while unmarshaling the JSON to struct, you can access the variables by typing like data.Id or data.Status.
Here's an example code:
package main
import (
"encoding/json"
"fmt"
)
type Data struct {
AfterData After `json:"after"`
Key []int `json:"key"`
}
type After struct {
Id int64 `json:"id"`
Amount float64 `json:"amount"`
Status string `json:"status"`
}
func main() {
j := []byte(`{"after": {"amount": 811,"id":123,"status":"Hi"}, "key": [70]}`)
var data *Data
err := json.Unmarshal(j, &data)
if err != nil {
fmt.Println(err.Error())
return
}
fmt.Println(data.AfterData)
fmt.Println(data.AfterData.Id)
fmt.Println(data.AfterData.Amount)
fmt.Println(data.AfterData.Status)
}
Output will be
{123 811 Hi}
123
811
Hi
Go Playground
Trying to implement a simple XML parsing, the code below doesn't work as expected.
It just returns a {[]} empty Results, while it should fill it.
Why ?...
package main
import "fmt"
import "encoding/xml"
import "bytes"
type Name struct {
Name string `xml:"NAME"`
}
type Results struct {
Names []Name `xml:"RESULTS"`
}
func main() {
data := []byte(`
<?xml version="1.0" encoding="UTF-8"?>
<RESULTS>
<NAME>Apple</NAME>
<NAME>Banana</NAME>
</RESULTS>
`)
var r Results
decoder := xml.NewDecoder(bytes.NewBuffer(data))
unError := decoder.Decode(&r)
if unError != nil {
fmt.Println("XML Unmarshaling error:", unError )
}else{
fmt.Printf("%v", r)
}
}
Tryed in the Playground, and locally (go1.17.2).
I would suggest you to use a online struct generator like xmltogo, so use this as:
type RESULTS struct {
XMLName xml.Name `xml:"RESULTS"`
Text string `xml:",chardata"`
NAME []string `xml:"NAME"`
}
Try on playground
In the below program I'm extracting some data from an API.
It outputs a rather complex data.
When I ioutil.ReadAll(resp.Body), the result is of type []uint8.
If I try to read the results, its just a random array of integers.
However, I'm able to read it if I convert it to string using string(diskinfo)
But I want to use this in a Struct and having trouble unmarshalling.
package main
import (
"encoding/json"
"fmt"
"io/ioutil"
"net/http"
"net/url"
"reflect"
)
type ApiResults struct {
results []struct {
statement_id int `json.statement_id`
series []struct {
name string `json.name`
tags struct {
host string `json.host`
}
columns []string `json.columns`
values []interface{} `json.values`
}
}
}
func main() {
my_url := "my_url"
my_qry := fmt.Sprintf("my_query")
resp, err := http.Get(my_url + url.QueryEscape(my_qry))
if err != nil {
fmt.Printf("ERROR: %v\n", err)
} else {
fmt.Println(reflect.TypeOf(resp))
diskinfo, _ := ioutil.ReadAll(resp.Body)
fmt.Println(reflect.TypeOf((diskinfo)))
fmt.Println(diskinfo)
fmt.Println(string(diskinfo))
diskinfo_string := string(diskinfo)
data := ApiResults{}
json.Unmarshal([]byte(diskinfo_string), &data)
//fmt.Printf("Values = %v\n", data.results.series.values)
//fmt.Printf("Server = %v\n", data.results.series.tags.host)
}
}
If I view the data as a string, I get this (formatted):
{"results":[
{"statement_id":0,
"series":[
{"name":"disk",
"tags":{"host":"myServer1"},
"columns":["time","disk_size"],
"values":[["2021-07-07T07:53:32.291490387Z",1044]]},
{"name":"disk",
"tags":{"host":"myServer2"},
"columns":["time","disk_size"],
"values":[["2021-07-07T07:53:32.291490387Z",1046]]}
]}
]}
I think my Apireturn struct is also structured incorrectly because the API results have info for multiple hosts.
But first, I doubt if the data has to be sent in a different format to the struct. Once I do this, I can probably try to figure out how to read from the Struct next.
The ioutil.ReadAll already provides you the data in the type byte[]. Therefore you can just call json.Unmarshal passing it as a parameter.
import (
"encoding/json"
"io/ioutil"
"net/http"
)
func toStruct(res *http.Response) (*ApiResults, error) {
body, err := ioutil.ReadAll(res.Body)
if err != nil {
return nil, err
}
defer res.Body.Close()
data := ApiResults{}
if err := json.Unmarshal(body, &data); err != nil {
return nil, err
}
return data, nil
}
There also seems to be an issue with your struct. The correct way to use struct tags is as follows. Plus, fields need to be exported for the json tag (used by json.Umarshal) to work – starting with uppercase will do it.
type ApiResults struct {
Results []struct {
StatementId int `json:"statement_id"`
Series []struct {
Name string `json:"name"`
Tags struct {
Host string `json:"host"`
} `json:"tags"`
Columns []string `json:"columns"`
Values []interface{} `json:"values"`
} `json:"series"`
} `json:"results"`
}
How to prevent converting <p> to \u003cp\u003e in json.Marshal ?
package main
import (
"encoding/json"
"fmt"
)
type User struct {
Name string
}
func main() {
user := User{Name: "<p>Frank</p>"}
b, err := json.Marshal(&user)
if err != nil {
fmt.Println(err)
return
}
fmt.Println(user)
fmt.Println(string(b))
}
It outputs:
{<p>Frank</p>}
{"Name":"\u003cp\u003eFrank\u003c/p\u003e"}
playground
This is already explained in this question. In short - you can create your own Marshaller implementation if you need to preserve these characters, but even encoded the json output will be a perfectly valid one and should not break anything.
I'm writing a websocket client in Go. I'm receiving the following JSON from the server:
{"args":[{"time":"2013-05-21 16:57:17"}],"name":"send:time"}
I'm trying to access the time parameter, but just can't grasp how to reach deep into an interface type:
package main;
import "encoding/json"
import "log"
func main() {
msg := `{"args":[{"time":"2013-05-21 16:56:16", "tzs":[{"name":"GMT"}]}],"name":"send:time"}`
u := map[string]interface{}{}
err := json.Unmarshal([]byte(msg), &u)
if err != nil {
panic(err)
}
args := u["args"]
log.Println( args[0]["time"] ) // invalid notation...
}
Which obviously errors, since the notation is not right:
invalid operation: args[0] (index of type interface {})
I just can't find a way to dig into the map to grab deeply nested keys and values.
Once I can get over grabbing dynamic values, I'd like to declare these messages. How would I write a type struct to represent such complex data structs?
You may like to consider the package github.com/bitly/go-simplejson
See the doc： http://godoc.org/github.com/bitly/go-simplejson
Example:
time, err := json.Get("args").GetIndex(0).String("time")
if err != nil {
panic(err)
}
log.Println(time)
The interface{} part of the map[string]interface{} you decode into will match the type of that field. So in this case:
args.([]interface{})[0].(map[string]interface{})["time"].(string)
should return "2013-05-21 16:56:16"
However, if you know the structure of the JSON, you should try defining a struct that matches that structure and unmarshal into that. Ex:
type Time struct {
Time time.Time `json:"time"`
Timezone []TZStruct `json:"tzs"` // obv. you need to define TZStruct as well
Name string `json:"name"`
}
type TimeResponse struct {
Args []Time `json:"args"`
}
var t TimeResponse
json.Unmarshal(msg, &t)
That may not be perfect, but should give you the idea
I'm extremely new to Golang coming from Python, and have always struggled with encode/decoding json. I found gjson at https://github.com/tidwall/gjson, and it helped me immensely:
package main
import "github.com/tidwall/gjson"
func main() {
msg := (`{"args":[{"time":"2013-05-21 16:56:16", "tzs":[{"name":"GMT"}]}],"name":"send:time"}`)
value := gjson.Get(msg, "args.#.time")
println(value.String())
}
-----------------------
["2013-05-21 16:56:16"]
Additionally, I noticed the comment of how to convert into Struct
package main
import (
"encoding/json"
"fmt"
)
type msgFormat struct {
Time string `json:"time"`
Tzs msgFormatTzs `json:"tzs"`
Name string `json:"name"`
}
type msgFormatTzs struct {
TzsName string `json:"name"`
}
func main() {
msg := (`{"args":[{"time":"2013-05-21 16:56:16", "tzs":[{"name":"GMT"}]}],"name":"send:time"}`)
r, err := json.Marshal(msgFormatTzs{msg})
if err != nil {
panic(err)
}
fmt.Printf("%v", r)
}
Try on Go playground