I am getting below error in my script which is running a SQLLDR :
SQL*Loader-522: lfiopn failed for file (/home/abc/test_loader/load/badfiles/TBLLOAD20150520.bad)
As far my knowledge this is the error related to permission,but i am wondering in the folder "/load" there is no "badfiles" folder present .i have already define badfiles folder outside the load folder,but why in the error it is taking this location ?
is it like my input file having some problem and SQLLDR trying to create a bad file in the mention location ?
below is the SQLLDR command :
$SQLLDR $LOADER_USER/$USER_PWD#$LOADER_HOSTNAME control=$CTLFDIR/CTL_FILE.ctl BAD=$BADFDIR/$BADFILE$TABLE_NAME ERRORS=
0 DIRECT=TRUE PARALLEL=TRUE LOG=$LOGDIR/$TABLE_NAME$LOGFILE &
below is the control file temp :
LOAD DATA
INFILE '/home/abc/test_loader/load/FILENAME_20150417_001.csv' "STR '\n'"
APPEND
INTO TABLE STAGING.TAB_NAME
FIELDS TERMINATED BY ',' OPTIONALLY ENCLOSED BY '"'
(
COBDATE,
--
--
--
FUTUSE30 TERMINATED BY WHITESPACE
)
Yes, your input file is having a problem so the sqlldr wants to create a file containing rejected rows (BAD file). The BAD file creation fails due to insufficient privileges - the user who runs the sqlldr does not have rights to create file in the folder you defined to contain BAD files.
Add write privileges on the BAD folder to the user who runs the sqlldr or place the BAD folder elsewhere.
This is likely some kind of permissions issue on writing the log file, maybe after moving services to a different server.
I ran into the same error. Problem was resolved by changing the name of the existing log file in filesystem and rerunning process. Upon rerunning, the SQLLDR process was able to recreate the log file, and subsequent executions were able to rewrite the log.
Related
I am using this command to import csv file data to postgresql in omnidb windows :
COPY owner."order"(id,type,name)
FROM 'C:\Users\Desktop\omnidb_exported.csv' DELIMITER ';' CSV HEADER;
Getting this error, although it exists:
could not open file "C:\Users\Desktop\omnidb_exported.csv" for
reading: No such file or directory
I have also provided everyone security permissions of read and execute on csv file and its folder. Still the problem exists.
The csv file has delimiter ";" with header information.
This owner schema has 3 tables, which are connected by "id" column.
How to import the csv file data correctly? What is the problem with these commands?
OK, as below:
\copy owner."order"(id,type,name) FROM 'C:\Users\Desktop\omnidb_exported.csv' DELIMITER ';' CSV HEADER;
Just replace the copy to \copy, then can load data sucessfully.
I can't seem to find a way to specify a relative path for my infile when using sql loader.
I'm running it through a command line and this is what it looks like:
C:\app\...in\sqlldr.exe userid=user/pass
control="C:\User...DATA_DATA_TABLE.ctl" log="C:\User...DATA_DATA_TABLE.log"
bad = "C:\User...DATA_DATA_TABLE.bad" discard = "C:\User...DATA_DATA_TABLE.dsc"
(I've added carriage returns just for the readability on here, the command i use is one line)
And this works, it's will start inserting stuff in the table IF the path to my infile in .ctl is absolute like "C:\Usertemp\example.ldr"
My ctl was generated autmatically by sqldeveloper. And i just changed the path to this:
OPTIONS (ERRORS=50)
LOAD DATA
INFILE 'AI_SLA_DATA_DATA_TABLE.ldr' "str '{EOL}'" <-- i'm trying to get relative path here but doesn't work
APPEND
CONTINUEIF NEXT(1:1) = '#'
INTO TABLE "USER"."DATA"
...other sqldeveloper generated stuff
The .ldr file is in the same directory as the .ctl file. Is it possible to get the path of the ctl? I'm pretty sure he searches for the .ldr file next to the sqlldr.exe instead of the ctl.
Any tips to do this? I can't find answers on docs.oracle.
Thanks.
I've never tried adding a relative path to the .ctl file, but for me it works fine as a command-line argument, e.g.
C:\app\...in\sqlldr.exe userid=user/pass
control="DATA_DATA_TABLE.ctl" log="DATA_DATA_TABLE.log"
bad = "DATA_DATA_TABLE.bad" discard ="DATA_DATA_TABLE.dsc"
data="AI_SLA_DATA_DATA_TABLE.ldr"
I am working with multiple source files with single source instance. I created three flat files and one destination table to experiment multiple sources. I am using ‘File list’ concept, for that I created a text file which contains all the flat file names.
Example:
Filename : File_list.txt
File content : Price1.txt
Price2.txt
Price3.txt
In the above example Price1.txt, Price2.txt and Price3.txt are flat file names. I specified File_list.txt as a source file while running the Workflow in Informatica. So it will iterate through all the flat files in the specified file (File_list.txt) and insert all the values to destination table.
Now what I want to do is once data is inserted to the destination, I need to delete that source file in that directory location.
How to achieve this?.
You'll need to write a custom script that will use the File_list.txt as input and perform the delete operations. You can then call it using Post-Session Success Command session component, or as a separate Command Task in the workflow linked using a $YourSessionName.Status = SUCCEEDED condition.
I have more than 30 files to load the data.
The path changes at every run in those files. So the path becomes
INFILE "/home/dmf/Cycle7Data/ITEM_IMAGE.csv"
INFILE "/home/dmf/Cycle8Data/ITEM_IMAGE.csv"
The file names change on every control file (SUPPLIER.csv)
Is there any way to pass the File path in a variable, or set any Env. Variable?
So that the control file is not edited everytime
You can pass the data file name on the command line; from the documentation:
DATA specifies the name of the data file containing the data to be loaded. If you do not specify a file extension or file type, then the default is .dat.
If you specify a data file on the command line and also specify data files in the control file with INFILE, then the data specified on the command line is processed first. The first data file specified in the control file is ignored. All other data files specified in the control file are processed.
So pass the relevant file name with each invocation, e.g.
sqlldr user/passwd control=myfile.ctl data=/home/dmf/Cycle7Data/ITEM_IMAGE.csv
If you have lots of files to load from a directory you could have a shell script that loops over the directory contents and passes each file name in turn to an SQL*Loader session.
Oracle DB/Windows XP:-
I am running an batch file that calls an “.ctl” file which in turn calls an “.xls” file, both present in the same folder.
The idea is to load the data onto Oracle db present on an remote oracle server.(non local machine)
I am getting this error, no matter what I do.
Oracle error:- LRM-00116: syntax error at 'control' following '='
The .bat file code is as below
rem SET SQLLOGIN=remod/P3w1d0ry#wsd
pause Ready to Load the remo.Temp_data Table
sqlldr userid=%SQLLOGIN% control=TempData.ctl errors=100
pause
The .ctl file is as follows:-
LOAD DATA
INFILE "data.xls"
replace
into table remo.Temp_data
FIELDS TERMINATED BY ',' OPTIONALLY ENCLOSED BY '"'
TRAILING NULLCOLS
(
test_abbr "rtrim(:test_abbr)",
test_pk "rtrim(:test_pk)",
test_sk "rtrim(:test_sk)",
test_dt "rtrim(:test_dt)",
test_email "rtrim(:test_email)",
)
You've remarked out the the SET of SQLLOGIN. Also you might want to put a call in front of the sqlldr statement. You'll also need some data to load...
SET SQLLOGIN=remod/P3w1d0ry#wsd
pause Ready to Load the remo.Temp_data Table
call sqlldr userid=%SQLLOGIN% control=TempData.ctl data=mydata.csv errors=100