Is it possible to look through custom document and find custom object by using JDK's XPath?
If I am right class org.jaxen.DefaultNavigator is used for that purpose in Jaxen. Also C#'s XPathNavigator.
Does Java's XPath have something similar?
e.g.
javax.xml.xpath.XPath xp = XPathFactory.newInstance().newXPath();
MyOwnNodeList nodeList = (MyOwnNodeList) xpath.evaluate("//*[#Id='id']", myOwnDocumentTree, XPathConstants.NODESET);
Related
I am new to UFT. I have a long "complex" xpath that finds precisely one element in chrome browser developer tools. When I use the same xpath in uft, the tool complains that the xpath is not in the object repository. Why does this happen and how do I fix it ?
This is what the xpath looks like:
//div[#class='a b c']//div[#class='p-q r-s']//div[#class='m n']//button[contains(text(), 'yes')]
I have to use such complex xpath because there are no ID attributes in this part of the page or any other 1-2 attributes which can uniquely identify the element.
Please help.
EDIT: My Vbscript code looks similar to this code:
Dim aButtonLoc
aButtonLoc = "//div[#class='a-b c-d-e g']" & _
"//div[#class='p-q r-s-t']//div[#class='uv w-x']" & _
"//button[contains(text(), 'Yes')]"
Error message: The {full xpath here} object was not found in the Object Repository. Check the Object Repository to confirm that the object exists or to find the correct name for the object.
There is an error in my aButtonLoc locator. It should have xpath mentioned, like this: aButtonLoc = "xpath:=//d...etc."
I've been able to set, via code, the xpaths for the placeholders found in the document.
for (Object o : finderSdtRun.results) {
if (o instanceof SdtRun){
SdtPr sdtPr=((SdtRun) o).getSdtPr();
Tag t = sdtPr.getTag();
CTDataBinding ctDataBinding = Context.getWmlObjectFactory().createCTDataBinding();
//JAXBElement jaxbDB = Context.getWmlObjectFactory().createSdtPrDataBinding(ctDataBinding);
sdtPr.setDataBinding(ctDataBinding);
ctDataBinding.setXpath("tuttappostaferragost");
ctDataBinding.setStoreItemID("something");
ObjectFactory factory = new org.opendope.xpaths.ObjectFactory();
DataBinding db = factory.createXpathsXpathDataBinding();
db.setXpath("tuttappostaferragost");
db.setStoreItemID("something");
Xpaths.Xpath xp = factory.createXpathsXpath();
xp.setDataBinding(db);
xp.setId("something");
try {
wordMLPackage.getMainDocumentPart().getXPathsPart().getContents().getXpath().add(xp);
} catch (Docx4JException e) {
e.printStackTrace();
}
;
The problem is that, once set, they are not recognized by word, so I thought to add the created Xpaths to a new XpathPart, and then add it to the main Document part.
But I failed because the method:
wordMLPackage.getMainDocumentPart().getXPathsPart()
returns null. This sounded reasonable, since only content control was set, without any Xpath.
Then I set the Xpaths via content control toolkit and the same line of code like above, returned me null, which added a lot of confusion in my yet confused ideas.
Is there any way to tell the document that new Xpath have been added to the document?
I mean, if there is a way to add Xpath via code (the w:databinding w:storedItemId tags), why it is not possible to make it work?
In general I want to add Xpath and all information necessary, via code, avoiding the use of any toolkit.
Thank you :D
First, you have to decide whether you want plain old Word databinding, or the additional OpenDoPE capabilities (which use the content control tag to support repeats, conditionals etc).
You only need an XPaths part if you are using the OpenDoPE extensions.
I'll assume for now that you are just looking to do basic Word content control databinding.
To set that up programmatically, you need to add a custom xml part, and a rel from it to its itemProps.xml part, which contains something like:
<ds:datastoreItem ds:itemID="{5448916C-134B-45E6-B8FE-88CC1FFC17C3}" xmlns:ds="http://schemas.openxmlformats.org/officeDocument/2006/customXml">
<ds:schemaRefs/>
</ds:datastoreItem>
(to add a part B to part A, use partA.addTargetPart)
You can see it is this part with gives the custom xml part its itemID; this corresponds with the value you set in:
DataBinding db = factory.createXpathsXpathDataBinding();
db.setStoreItemID("something");
Then, set the XPath via the method you were using.
I have an element whose html is like :
<div class="gwt-Label textNoStyle textNoWrap titlePanelGrayDiagonal-Text">Announcements</div>
I want to check the presence of this element. So I am doing something like :
WebDriver driver = new FirefoxDriver(profile);
driver.findElement(By.cssSelector(".titlePanelGrayDiagonal-Text"));
But its not able to evaluate the CSSSelector.
Even I tried like :
By.cssSelector("gwt-Label.textNoStyle.textNoWrap.titlePanelGrayDiagonal-Text")
tried with this as well :
By.cssSelector("div.textNoWrap.titlePanelGrayDiagonal-Text")
Note : titlePanelGrayDiagonal-Text class is used by only this element in the whole page. So its unique.
Contains pseudo selector I can not use.
I want to identify only with css class.
Versions: Selenium 2.9 WebDriver
Firefox 5.0
When using Webdriver you want to use W3C standard css selectors not sizzle selectors like you may be used to using in jquery. In your example you would want to use:
driver.findElement(By.cssSelector("div[class='titlePanelGrayDiagonal-Text']"));
From reading over your post what you should do since that class is unique is just do a FindElement(By.ClassName("titlePanelGrayDiagonal-Text"));
Also the CssSelector doesn't handle the contains keyword it was something that the w3 talked about but never added.
I haven't used css selectors, but this is the xpath selector I would use:
"xpath=//div[#class='gwt-Label textNoStyle textNoWrap titlePanelGrayDiagonal-Text']"
The css selector should then probably be something like
"css=div[class='gwt-Label textNoStyle textNoWrap titlePanelGrayDiagonal-Text']"
Source: http://release.seleniumhq.org/selenium-remote-control/0.9.2/doc/dotnet/Selenium.html
Did you ever tried following code,
By.cssSelector("div#gwt-Label.textNoStyle.textNoWrap.titlePanelGrayDiagonal-Text");
I believe using a wildcard in CSS would be more helpful. Something as follows
driver.findElement(By.cssSelector("div[class$='titlePanelGrayDiagonal-Text']");
This will look into the class attribute and see what that attribute is ending with. Since your class attribute is ending with "titlePanelGrayDiagonal-Text" string, the added '$' in the css statement will find the element and then you can perform whatever action you're trying to perform.
i have to extract d company name and face value from
http://money.rediff.com/companies/20-microns-ltd/15110088
i noticed that this task could be accomplished using xpath api.
since this is an html page, i am using jtidy parser.
this is the xpath for the face value which i have to extract.
/html/body/div[4]/div[6]/div[9]/div/table/tbody/tr[4]/td[2]
This is my code
URL oracle = new URL("http://money.rediff.com/companies/20-microns-ltd/15110088");
URLConnection yc = oracle.openConnection();
InputStream is = yc.getInputStream();
is = oracle.openStream();
Tidy tidy = new Tidy();
tidy.setQuiet(true);
tidy.setShowWarnings(false);
Document tidyDOM = tidy.parseDOM(is, null);
XPathFactory xPathFactory = XPathFactory.newInstance();
XPath xPath = xPathFactory.newXPath();
String expression = "/html";
XPathExpression xPathExpression = xPath.compile(expression);
Object result = xPathExpression.evaluate(tidyDOM,XPathConstants.NODESET);
System.out.println(result.toString());
please guide me further, because, i cannot find a right solution for the above
Try not to use "full" xpaths.
//div[#id='leftcontainer']//div[9]//table//tr[4]/td[2]
is better than
/html/body/.../.../.../.../.../...
Most HTML pages are not valid or even well-formed. So the DOM structure may change when processed by "real-world HTML parsers". For example, a <tbody> may be inserted under <table> if there isn't one. Things are worse when different HTML parsers generate different DOM trees so one XPath may be valid for one parser, but not the other. I would rather use "wildcards" like table//tr[4] instead of table/tbody/tr[4] or table/tr[4] so that I can forget about <tbody>. Such expressions are more robust when used against the messy real-world HTML pages.
You can use Firepath, a plugin for Firebug which is then a plugin for Firefox, to debug XPath expressions.
p.s. You can try my JHQL (http://github.com/wks/jhql) project for exactly this task. You will like it if you have more pages to extract data from.
This line will not work but I think I have used correct xpath?
driver.findElement(By.xpath("//a[contains(#class,'cke_button_bold')]")).click();
to locate a button like below :
<a id="cke_73" class="cke_off cke_button_bold">
id is a dynamic number so can be used as fixed locator here. And class is a compound class which is not supported by WebDriver findElement method...
I created simple html file and your xpath works with FirefoxDriver in WebDriver 2.1.0.
Also you can try to use
driver.findElement(By.className("cke_button_bold"))
Classname is supported by webdriver Api
Step 1:
Find the CSS Selector
Possible CSS Selectors here:
css=a[id*='cke']
css=.cke_off cke_button_bold
The above can be used Or Already we are having the method .ClassName But for avoiding duplication of Elements and Ambiguity we can use CSS Selector.