How can I sort !! delimited records using sort command?
for File1
1!!2!!3
2!3!!3!!1
3!!2!!2
expected output
2!3!!3!!1
3!!2!!2
1!!2!!3
then
sort -t \!\! -k 3 file1
RESULT:
sort: multi-character tab ‘!!’
why isn't it working?
Multi-character delimiters are not allowed in sort -t but you can just use:
sort -t '!' -k1 file
1!!b!!c
2!!f!!w
4!!e!!e
EDIT: If ! can be there in data itself you can use this trick:
sed 's/!!/\x06/g' file | sort -t $'\x06' -k1 | sed 's/\x06/!!/g'
1!!b!!c
2!!f!!w
4!!e!!e
EDIT2: For doing this in single command use awk:
awk -F '!!' -v k=1 '{a[$k,$0]=$0}
END{asort(a, b, "#ind_num_asc"); for (i in b) print b[i]}' file
Related
I'm trying to get as bash variable list of users which are in my csv file. Problem is that number of users is random and can be from 1-5.
Example CSV file:
"record1_data1","record1_data2","record1_data3","user1","user2"
"record2_data1","record2_data2","record2_data3","user1","user2","user3","user4"
"record3_data1","record3_data2","record3_data3","user1"
I would like to get something like
list_of_users="cat file.csv | grep "record2_data2" | <something> "
echo $list_of_users
user1,user2,user3,user4
I'm trying this:
cat file.csv | grep "record2_data2" | awk -F, -v OFS=',' '{print $4,$5,$6,$7,$8 }' | sed 's/"//g'
My result is:
user2,user3,user4,,
Question:
How to remove all "," from the end of my result? Sometimes it is just one but sometimes can be user1,,,,
Can I do it in better way? Users always starts after 3rd column in my file.
This will do what your code seems to be trying to do (print the users for a given string record2_data2 which only exists in the 2nd field):
$ awk -F',' '{gsub(/"/,"")} $2=="record2_data2"{sub(/([^,]*,){3}/,""); print}' file.csv
user1,user2,user3,user4
but I don't see how that's related to your question subject of Getting last X records from CSV file using bash so idk if it's what you really want or not.
Better to use a bash array, and join it into a CSV string when needed:
#!/usr/bin/env bash
readarray -t listofusers < <(cut -d, -f4- file.csv | tr -d '"' | tr ',' $'\n' | sort -u))
IFS=,
printf "%s\n" "${listofusers[*]}"
cut -d, -f4- file.csv | tr -d '"' | tr ',' $'\n' | sort -u is the important bit - it first only prints out the fourth and following fields of the CSV input file, removes quotes, turns commas into newlines, and then sorts the resulting usernames, removing duplicates. That output is then read into an array with the readarray builtin, and you can manipulate it and the individual elements however you need.
GNU sed solution, let file.csv content be
"record1_data1","record1_data2","record1_data3","user1","user2"
"record2_data1","record2_data2","record2_data3","user1","user2","user3","user4"
"record3_data1","record3_data2","record3_data3","user1"
then
sed -n -e 's/"//g' -e '/record2_data/ s/[^,]*,[^,]*,[^,]*,// p' file.csv
gives output
user1,user2,user3,user4
Explanation: -n turns off automatic printing, expressions meaning is as follow: 1st substitute globally " using empty string i.e. delete them, 2nd for line containing record2_data substitute (s) everything up to and including 3rd , with empty string i.e. delete it and print (p) such changed line.
(tested in GNU sed 4.2.2)
awk -F',' '
/record2_data2/{
for(i=4;i<=NF;i++) o=sprintf("%s%s,",o,$i);
gsub(/"|,$/,"",o);
print o
}' file.csv
user1,user2,user3,user4
This might work for you (GNU sed):
sed -E '/record2_data/!d;s/"([^"]*)"(,)?/\1\2/4g;s///g' file
Delete all records except for that containing record2_data.
Remove double quotes from the fourth field onward.
Remove any double quoted fields.
I have a delimited file that is separated by octal \036 or Hexadecimal value 1e.
I need to count the number of delimiters on each line using a bash shell script.
I was trying to use awk, not sure if this is the best way.
Sample Input (| is a representation of \036)
Example|Running|123|
Expected output:
3
awk -F'|' '{print NF-1}' file
Change | to whatever separator you like. If your file can have empty lines then you need to tweak it to:
awk -F'|' '{print (NF ? NF-1 : 0)}' file
You can try
awk '{print gsub(/\|/,"")}'
Simply try
awk -F"|" '{print substr($3,length($3))}' OFS="|" Input_file
Explanation: Making field separator -F as | and then printing the 3rd column by doing $3 only as per your need. Then setting OFS(output field separator) to |. Finally mentioning Input_file name here.
This will work as far as I know
echo "Example|Running|123|" | tr -cd '|' | wc -c
Output
3
This should work for you:
awk -F '\036' '{print NF-1}' file
3
-F '\036' sets input field delimiter as octal value 036
Awk may not be the best tool for this. Gnu grep has a cool -o option that prints each matching pattern on a separate line. You can then count how many matching lines are generated for each input line, and that's the count of your delimiters. E.g. (where ^^ in the file is actually hex 1e)
$ cat -v i
a^^b^^c
d^^e^^f^^g
$ grep -n -o $'\x1e' i | uniq -c
2 1:
3 2:
if you remove the uniq -c you can see how it's working. You'll get "1" printed twice because there are two matching patterns on the first line. Or try it with some regular ascii characters and it becomes clearer what the -o and -n options are doing.
If you want to print the line number followed by the field count for that line, I'd do something like:
$grep -n -o $'\x1e' i | tr -d ':' | uniq -c | awk '{print $2 " " $1}'
1 2
2 3
This assumes that every line in the file contains at least one delimiter. If that's not the case, here's another approach that's probably faster too:
$ tr -d -c $'\x1e\n' < i | awk '{print length}'
2
3
0
0
0
This uses tr to delete (-d) all characters that are not (-c) 1e or \n. It then pipes that stream of data to awk which just counts how many characters are left on each line. If you want the line number, add " | cat -n" to the end.
Situation
I have many URLs in a file, and I need to find out how many unique URLs exist.
I would like to run either a bash script or a command.
myfile.log
/home/myfiles/www/wp-content/als/xm-sf0ab5df9c1262f2130a9b313192deca4-f0ab5df9c1262f2130a9b313192deca4-c23c5fbca96e8d641d148bac41017635|https://public.rgfl.org/HS/PowerPoint%20Presentations/Health%20and%20Safety%20Law.ppt,18,17
/home/myfiles/www/wp-content/als/xm-s4bf050d47df5bfaf0486a50a8528cb16-4bf050d47df5bfaf0486a50a8528cb16-c23c5fbca96e8d641d148bac41017635|https://public.rgfl.org/HS/PowerPoint%20Presentations/Health%20and%20Safety%20Law.ppt,15,14
/home/myfiles/www/wp-content/als/xm-sad122bf22152ba4823a520cc2fe59f40-ad122bf22152ba4823a520cc2fe59f40-c23c5fbca96e8d641d148bac41017635|https://public.rgfl.org/HS/PowerPoint%20Presentations/Health%20and%20Safety%20Law.ppt,17,16
/home/myfiles/www/wp-content/als/xm-s3c0f031eebceb0fd5c4334ecef15292d-3c0f031eebceb0fd5c4334ecef15292d-c23c5fbca96e8d641d148bac41017635|https://public.rgfl.org/HS/PowerPoint%20Presentations/Health%20and%20Safety%20Law.ppt,12,11
/home/myfiles/www/wp-content/als/xm-sff661e8c3b4f94957926d5434d0ad549-ff661e8c3b4f94957926d5434d0ad549-c23c5fbca96e8d641d148bac41017635|https://quality.gha.org/Portals/2/documents/HEN/Meetings/nursesinstitute/062013/nursesroleineliminatingharm_moddydunning.pptx,17,16
/home/myfiles/www/wp-content/als/xm-s32c41ec2a5440ad220008b9abfe9add2-32c41ec2a5440ad220008b9abfe9add2-c23c5fbca96e8d641d148bac41017635|https://quality.gha.org/Portals/2/documents/HEN/Meetings/nursesinstitute/062013/nursesroleineliminatingharm_moddydunning.pptx,19,18
/home/myfiles/www/wp-content/als/xm-s28787ca2f4372ddb3616d3fd53c161ab-28787ca2f4372ddb3616d3fd53c161ab-c23c5fbca96e8d641d148bac41017635|https://quality.gha.org/Portals/2/documents/HEN/Meetings/nursesinstitute/062013/nursesroleineliminatingharm_moddydunning.pptx,22,21
/home/myfiles/www/wp-content/als/xm-s89a7b68158e38391da9f0de1e636c0d5-89a7b68158e38391da9f0de1e636c0d5-c23c5fbca96e8d641d148bac41017635|https://quality.gha.org/Portals/2/documents/HEN/Meetings/nursesinstitute/062013/nursesroleineliminatingharm_moddydunning.pptx,13,12
/home/myfiles/www/wp-content/als/xm-sc4b14e10f6151995f21334061ff1d139-c4b14e10f6151995f21334061ff1d139-c23c5fbca96e8d641d148bac41017635|https://royalmechanical.files.wordpress.com/2011/06/hy-wire-car-2.pptx,13,12
/home/myfiles/www/wp-content/als/xm-se589d47d163e43fa0c0d68e824e2c286-e589d47d163e43fa0c0d68e824e2c286-c23c5fbca96e8d641d148bac41017635|https://royalmechanical.files.wordpress.com/2011/06/hy-wire-car-2.pptx,19,18
/home/myfiles/www/wp-content/als/xm-s52f897a623c539d09bfb988bfb153888-52f897a623c539d09bfb988bfb153888-c23c5fbca96e8d641d148bac41017635|https://royalmechanical.files.wordpress.com/2011/06/hy-wire-car-2.pptx,14,13
/home/myfiles/www/wp-content/als/xm-sccf27a904c5b88e96a3522b2e1180fed-ccf27a904c5b88e96a3522b2e1180fed-c23c5fbca96e8d641d148bac41017635|https://royalmechanical.files.wordpress.com/2011/06/hy-wire-car-2.pptx,18,17
/home/myfiles/www/wp-content/als/xm-s6874bf9d589708764dab754e5af06ddf-6874bf9d589708764dab754e5af06ddf-c23c5fbca96e8d641d148bac41017635|https://royalmechanical.files.wordpress.com/2011/06/hy-wire-car-2.pptx,17,16
/home/myfiles/www/wp-content/als/xm-s46c55ec8387dbdedd7a83b3ad541cdc1-46c55ec8387dbdedd7a83b3ad541cdc1-c23c5fbca96e8d641d148bac41017635|https://royalmechanical.files.wordpress.com/2011/06/hy-wire-car-2.pptx,19,18
/home/myfiles/www/wp-content/als/xm-s08cfdc15f5935b947bbaa93c7193d496-08cfdc15f5935b947bbaa93c7193d496-c23c5fbca96e8d641d148bac41017635|https://royalmechanical.files.wordpress.com/2011/06/hydro-power-plant.ppt,9,8
/home/myfiles/www/wp-content/als/xm-s86e267bd359c12de262c0279cee0c941-86e267bd359c12de262c0279cee0c941-c23c5fbca96e8d641d148bac41017635|https://royalmechanical.files.wordpress.com/2011/06/hydro-power-plant.ppt,15,14
/home/myfiles/www/wp-content/als/xm-s5aa60354d134b87842918d760ec8bc30-5aa60354d134b87842918d760ec8bc30-c23c5fbca96e8d641d148bac41017635|https://royalmechanical.files.wordpress.com/2011/06/hydro-power-plant.ppt,14,13
Desired Result:
Unique Urls: 4
cut -d "|" -f 2 file | cut -d "," -f 1 | sort -u | wc -l
Output:
4
See: man cut, man sort
An awk solution would be
awk '{sub(/^[^|]*\|/,"");gsub(/,[^,]*/,"");i+=a[$0]++?0:1}END{print i}' file
4
If you happen to use GNU awk then below would also give you the same result
awk '{i+=a[gensub(/.*(http[^,]*).*/,"\\1",1)]++?0:1}END{print i}' file
4
Or even short as pointed out in this cracker comment by #cyrus
awk -F '[|,]' '{i+=!a[$2]++} END{print i}' file
4
which uses awk multiple field separator functionality with more idiomatic awk.
Note: See the [ awk manual ] for more info.
Parse with sed, and since file appears to be already sorted,
(with respect to URLs), just run uniq, and count it:
echo Unique URLs: $(sed 's/^.*|\([^,]*\),.*$/\1/' file | uniq | wc -l)
Use GNU grep to extract URLs:
echo Unique URLs: $(grep -o 'ht[^|,]*' file | uniq | wc -l)
Output (either method):
Unique URLs: 4
tr , '|' < myfile.log | sort -u -t '|' -k 2,2 | wc -l
tr , '|' < myfile.log translates all commas into pipe characters
sort -u -t '|' -k 2,2 sorts unique (-u), pipe delimited (-t '|'), in the second field only (-k 2,2)
wc -l counts the unique lines
I would like to sort those files using Unix commands:
MyFile_fdfdsf_20140326.txt
MyFile_4fg5d6_20100301.csv
MyFile_dfgfdklm_19990101.tar.gz
The result I am waiting for here is MyFile_fdfdsf_20140326.txt
So I'd like to get the file with the newest date.
I can't use 'sort -k', as the position of the key (the date) may vary
But in my file name there are always two "_" delimiters and a dot '.' for the file extension
Any help would be appreciated :)
Then use -t to indicate the field separator and set it to _:
sort -t'_' -k3
See an example of sorting the file names if they are in a file. I used -n for numeric sort and -r for reverse order:
$ sort -t'_' -nk3 file
MyFile_dfgfdklm_19990101.tar.gz
MyFile_4fg5d6_20100301.csv
MyFile_fdfdsf_20140326.txt
$ sort -t'_' -rnk3 file
MyFile_fdfdsf_20140326.txt
MyFile_4fg5d6_20100301.csv
MyFile_dfgfdklm_19990101.tar.gz
From man sort:
-t, --field-separator=SEP
use SEP instead of non-blank to blank transition
-n, --numeric-sort
compare according to string numerical value
-r, --reverse
reverse the result of comparisons
Update
Thank you for you answer. It's perfect. But out of curiosity, what if
I had an unknown number of delimiters, but the date was always after
the last "_" delimiter. MyFile_abc_def_...20140326.txt sort -t''
-nk??? file – user3464809
You can trick it a little bit: print the last field, sort and then remove it.
awk -F_ '{print $NF, $0}' a | sort | cut -d'_' -f2-
See an example:
$ cat a
MyFile_fdfdsf_20140326.txt
MyFile_4fg5d6_20100301.csv
MyFile_dfgfdklm_19990101.tar.gz
MyFile_dfgfdklm_asdf_asdfsadfas_19940101.tar.gz
MyFile_dfgfdklm_asdf_asdfsadfas_29990101.tar.gz
$ awk -F_ '{print $NF, $0}' a | sort | cut -d'_' -f2-
dfgfdklm_asdf_asdfsadfas_19940101.tar.gz
dfgfdklm_19990101.tar.gz
4fg5d6_20100301.csv
fdfdsf_20140326.txt
dfgfdklm_asdf_asdfsadfas_29990101.tar.gz
E.g.
Given a file input.txt, which has the following content:
He likes cats, really?
the output would be like:
H
e
l
i
k
s
c
a
t
,
r
l
y
?
Note the order of characters in output does not matter.
One way using grep -o . to put each character on a newline and sort -u to remove duplicates:
$ grep -o . file | sort -u
Or a solution that doesn't required sort -u or multiple commands written purely in awk:
$ awk '{for(i=1;i<=NF;i++)if(!a[$i]++)print $i}' FS="" file
How about:
echo "He likes cats, really?" | fold -w1 | sort -u
An awk way:
awk '{$1=$1}1' FS="" OFS="\n" file | sort -u
You can use sed as follows:
sed 's/./\0\n/g' input.txt | sort -u