I have a file in json format, is there a way to convert it to a XContentBuilder?
What I want to do is to read a file with some mapping and then convert it to XContentBuilder
Something like:
XContentBuilder builder = JsonXContent.contentBuilder().source(String json);
Usually the API should accept a String or byte[] so you shouldn't need to convert. Maybe you want CreateIndexRequestBuilder#addMapping(String, String)?
If you really, really, really want an XContentBuilder you can make an XContentParser and copy the contents to a builder. As of Elasticsearch 5.2 this should do it:
String message = "{\"test\":\"test\"}";
XContentBuilder b = XContentFactory.jsonBuilder().prettyPrint();
try (XContentParser p = XContentFactory.xContent(XContentType.JSON).createParser(NamedXContentRegistry.EMPTY, message)) {
b.copyCurrentStructure(p);
}
System.err.println(b.string());
You could probably also do something with raw but I don't think that is worth it.
Pre 5.2 you don't need the NamedXContentRegistry.EMPTY, part.
This seems to work for me:
import static org.elasticsearch.common.xcontent.XContentFactory.jsonBuilder;
import org.elasticsearch.common.xcontent.XContentBuilder;
import org.elasticsearch.common.xcontent.XContentFactory;
import org.elasticsearch.common.xcontent.XContentParser;
import org.elasticsearch.common.xcontent.XContentType;
...
String message = "{\"bob\": \"test\"}";
XContentParser parser = XContentFactory.xContent(XContentType.JSON).createParser(message.getBytes();
parser.close();
XContentBuilder builder = jsonBuilder().copyCurrentStructure(parser);
val x: XContentBuilder = XContentFactory.jsonBuilder().value("{\"bla\":\"blub\"}")
Not sure if this answers your question because you don't provide much information but you can also use strings to add a mapping to an IndexRequestBuilder:
new CreateIndexRequestBuilder(adminclient)
.addMapping("typeName", "{\"mapping\" : \"mapping\"}")
If you really want and need to create a XContentBuilder Object from a string you can do so like this:
String mapping = "{\"bla\":\"blub\"}"
XContentBuilder x = XContentFactory.jsonBuilder().value(mapping)
Related
I have an Array[Byte]. I am trying to convert it into JSON Object.
I tried using GSON library. I got the String representation of the JSON Object. I am stuck at this point and also not sure if this is the correct way.
def getJSONObject(array : Array[Byte]) : JSONObject = {
val jsonString = new Gson().toJson(array)
}
I am trying to convert the NSDictionary into Json using NSJsonSerialization.Serialize. But i am not getting expected output
Code in Xamarin.iOS
var dictionary = new NSDictionary(
new NSString("userName"), new NSString("450012"),
new NSString("password"), new NSString("Abc134"),
new NSString("companyId"), new NSString("CM1")
);
request.Body = NSJsonSerialization.Serialize(dictionary, 0, out error);
the problem is that value of dictionary variable is showing
{{password":Abc134,companyId:CM1,userName:450012}}
instead of
{password:Abc134,companyId:CM1,userName:450012}
it is adding one curly braces at the front and back
is there any way to generate proper json string for user input values
There's nothing wrong with your json. If you print it in the console you will see that the value being printed is the value you expect.
{"password":"Abc134","companyId":"CM1","userName":"450012"}
Give it a try with:
Console.WriteLine($"{json}");
If you really, really want to get rid of of that "extra" curly braces just convert the result into string.
var jsonString = json.ToString();
The above should do the work.
I would just suggest you changing your method to this:
var json2 = NSJsonSerialization.Serialize(dictionary, NSJsonWritingOptions.PrettyPrinted, out error);
Using the PrettyPrinted option.
Hope this helps.-
Yes, you can try to create a custom object to serialize. Create a simple plain object to hold the data you want.
User user = new User() {
UserName = "JohnDoe",
Password = "xxx",
CompanyId = 01
};
request.Body = NSJsonSerialization.Serialize(user, 0, out error);
Then serialize it and you will see the proper json well formed.
I'm using Spring data MongoTemplate to manage mongo operations. I'm trying to save & update json full documents (using String.class in java).
Example:
String content = "{MyId": "1","code":"UG","variables":[1,2,3,4,5]}";
String updatedContent = "{MyId": "1","code":"XX","variables":[6,7,8,9,10]}";
I know that I can update code & variables independently using:
Query query = new Query(where("MyId").is("1"));
Update update1 = new Update().set("code", "XX");
getMongoTemplate().upsert(query, update1, collectionId);
Update update2 = new Update().set("variables", "[6,7,8,9,10]");
getMongoTemplate().upsert(query, update2, collectionId);
But due to our application architecture, it could be more useful for us to directly replace the full object. As I know:
getMongoTemplate().save(content,collectionId)
getMongoTemplate().save(updatedContent,collectionId)
implements saveOrUpdate functionality, but this creates two objects, do not update anything.
I'm missing something? Any approach? Thanks
You can use Following Code :
Query query = new Query();
query.addCriteria(Criteria.where("MyId").is("1"));
Update update = new Update();
Iterator<String> iterator = json.keys();
while(iterator.hasNext()) {
String key = iterator.next();
if(!key.equals("MyId")) {
Object value = json.get(key);
update.set(key, value);
}
}
mongoTemplate.updateFirst(query, update, entityClass);
There may be some other way to get keyset from json, you can use according to your convenience.
You can use BasicDbObject to get keyset.
you can get BasicDbObject using mongoTemplate.getConverter().
I have seen this question asked, but have not found answers that work so I am asking it again.
I have a restful web service with a POST method that returns a serialized List.
<ArrayOfstring xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://schemas.microsoft.com/2003/10/Serialization/Arrays">
<string>QoL5vA8OKgydWIn%2fdWiu70nobBrJo4N9iXeHmtM7Aj4%3d</string>
<string>vxHyJiSSSvDSZWXOdcfl5FMQC97xxGEWDO8Zy8Qp3X5CwADUbEE8ifACQHR1n7uamEaIUbf85ZuBDB8FFCNY2tJAMJ2jNw09SqGVTpMU5uI06DLtuYnJqsPIF735NOhlvRhBLPnpp62DFMCVsDNHy55UBF3Ggi06ZWTiJ8LTYIf3FYiFLPpXLZ1wWeE5chAWQGfz7zDYJa1OgSZ</string>
<string>OqGAT7Yqe6DfyVD29BeIXFyGtabVCloaC9FA1Fp20JkJ9T17ZzyqhnGxwWda7FqqyJUM8YK9OdcOCgTYrl4JxalECdtJm75TdSG8IAPQlFHp6Gidg4EwZaO9FKahlYMm5JrFpxTmLrdLgMAkYEV7gIR6zIyIByAGwYYDDwH3QCHrym3CuueRnFWAHCJu1LJbx0zRtt7g3yEaTiJ</string>
</ArrayOfstring>
The code performing the call is as follows below.
XDocument xDocResponse = RestPOSTToXDocument(szBaseUri, szInput);
string szNamespace = xDocResponse.Root.Name.Namespace.ToString();
IXmlUtils utility = new XmlUtils();
List<string> lst = utility.DeserializeList<string>(xDocResponse, szNamespace);
I have also attempted a different version of the call as shown below.
List<List<string>> lst = utility.DeserializeList<List<string>>(xDocResponse, szNamespace);
Both versions of the calls generate the error provided below.
An exception of type 'System.InvalidOperationException' occurred in System.Xml.dll but was not handled in user code
Additional information: There is an error in XML document (0, 0).
My Deserialize method is provided below.
public List<T> DeserializeList<T>(XDocument doc, string szNamespace)
{
List<T> result = null;
XmlSerializer serializer = new XmlSerializer(typeof(List<T>), szNamespace);
using (System.Xml.XmlReader reader = doc.CreateReader())
{
result = (List<T>)serializer.Deserialize(reader);
}
return result;
}
The XML within the XDocument is valid, so I do not understand why this error is being generated. Also, even if I attempt to get the elements via navigation in the XDocument, it does not work. If I look at the doc.Root.value, it appears that all of the strings are concatenated together into a single string.
Does anyone have any information on how I may deserialize this XDocument into a List?
Thanks to the assistance of mellamokb, I found the problem. When my List is serialized, it is serialized into an ArrayOfstring. If I take the XML and replace ArrayOfstring with ArrayOfString, the deserialization works.
This does not make much sense. I would welcome an explanation of why this is necessary though it may have something to do with String vs string.
Essentially, I had to do the following:
string szXml = xDocResponse.ToString();
int nEndRoot = szXml.IndexOf(">");
szXml = szXml.Replace("ArrayOfstring", "ArrayOfString");
xDocResponse = utility.LoadXDocument(szXml);
string szNamespace = xDocResponse.Root.Name.Namespace.ToString();
List<string> lst = utility.DeserializeList<string>(xDocResponse, szNamespace);
Simply get the response stream and deserealize into string array and store it to List
Code Snippet:
List<string> listNew=new List<string>();
using (Stream answer = webResponse.GetResponseStream())
{
DataContractSerializer xmlSer = new DataContractSerializer(typeof(string[]));
var stringArr= (string[])xmlSer.ReadObject(answer);
foreach (string item in GenreList)
{
listNew.Add(item);
}
}
I am trying to update multiple value in index using Java Api through Elastic Search Script. But not able to update fields.
Sample code :-
1:
UpdateResponse response = request.setScript("ctx._source").setScriptParams(scriptParams).execute().actionGet();
2:
UpdateResponse response = request.setScript("ctx._source.").setScriptParams(scriptParams).execute().actionGet();
if I mentioned .(dot) in ("ctx._source.") getting illegalArgument Exception and if i do not use dot, not getting any exception but values not getting updated in Index.
Can any one tell me the solutions to resolve this.
First of all, your script (ctx._source) doesn't do anything, as one of the commenters already pointed out. If you want to update, say, field "a", then you would need a script like:
ctx._source.a = "foobar"
This would assign the string "foobar" to field "a". You can do more than simple assignment, though. Check out the docs for more details and examples:
http://www.elasticsearch.org/guide/reference/api/update/
Updating multiple fields with one script is also possible. You can use semicolons to separate different MVEL instructions. E.g.:
ctx._source.a = "foo"; ctx._source.b = "bar"
In Elastic search have an Update Java API. Look at the following code
client.prepareUpdate("index","typw","1153")
.addScriptParam("assignee", assign)
.addScriptParam("newobject", responsearray)
.setScript("ctx._source.assignee=assignee;ctx._source.responsearray=newobject ").execute().actionGet();
Here, assign variable contains object value and response array variable contains list of data.
You can do the same using spring java client using the following code. I am also listing the dependencies used in the code.
import org.elasticsearch.action.update.UpdateRequest;
import org.elasticsearch.index.query.QueryBuilder;
import org.springframework.data.elasticsearch.core.query.UpdateQuery;
import org.springframework.data.elasticsearch.core.query.UpdateQueryBuilder;
private UpdateQuery updateExistingDocument(String Id) {
// Add updatedDateTime, CreatedDateTime, CreateBy, UpdatedBy field in existing documents in Elastic Search Engine
UpdateRequest updateRequest = new UpdateRequest().doc("UpdatedDateTime", new Date(), "CreatedDateTime", new Date(), "CreatedBy", "admin", "UpdatedBy", "admin");
// Create updateQuery
UpdateQuery updateQuery = new UpdateQueryBuilder().withId(Id).withClass(ElasticSearchDocument.class).build();
updateQuery.setUpdateRequest(updateRequest);
// Execute update
elasticsearchTemplate.update(updateQuery);
}
XContentType contentType =
org.elasticsearch.client.Requests.INDEX_CONTENT_TYPE;
public XContentBuilder getBuilder(User assign){
try {
XContentBuilder builder = XContentFactory.contentBuilder(contentType);
builder.startObject();
Map<String,?> assignMap=objectMap.convertValue(assign, Map.class);
builder.field("assignee",assignMap);
return builder;
} catch (IOException e) {
log.error("custom field index",e);
}
IndexRequest indexRequest = new IndexRequest();
indexRequest.source(getBuilder(assign));
UpdateQuery updateQuery = new UpdateQueryBuilder()
.withType(<IndexType>)
.withIndexName(<IndexName>)
.withId(String.valueOf(id))
.withClass(<IndexClass>)
.withIndexRequest(indexRequest)
.build();