"Record has already been inserted" on commit in Oracle Forms 6i - oracle

I'm not an Oracle forms guy, but I'm stuck maintaining an old Oracle Forms 6i app that our company has, so I apologize if I sound like I don't really understand forms, because I don't.
We have a pre-existing form that I've had to make some change to. It has a master/detail type setup. There are a series of "rows" for the details. When I enter master info and the first detail record, I can save just fine. When I add a second row of info to the details section, it gets to the KEY-COMMIT trigger, but when it actually hits the "commit;" line, it gives me the error "Record has already been inserted."
But there is only the one record associated with the master details in the table. When I clear that message it asks, "Do you want to save the changes you have made?" If I click "Yes", it just gives me the "Record has already been inserted" message in the status bar and nothing happens. If I try to exit the form, it again asks if I want to save the changes, but "yes" does nothing but keep me on the form. Clicking "No" removes the second detail record.
I'm confused. I'm clearly missing something.

Your detail data block has the Enforce Primary Key property set to Yes. It means that rows inserted/updated/deleted by this block are not queried by rowid, but by primary key.
It does not matter, how is primary key set in database, but how is set in forms. Check all items in your detail block and find those with Primary Key (Item) property. Then check, if there is a duplicate record in database.
I prefer using rowid and uncheck Enforce Primary Key property. If your block works directly with database table (not view), it works fine

Related

Form WHERE clause

I have an APEX form I'm developing for "user settings". I have a table with a sequence as a primary key and the users ID in another column...in addition to a few columns where each users saved settings are stored (things like "N" for do not receive notices).
I haven't used Oracle APEX in a while so excuse this likely newbie question...The insert works fine, but I'm having trouble with making the form only show the current users values. In my Form Region the source is set to my Table, and I have a WHERE clause like this:
USER_ID = 813309
But that's not working (813309 is my id and I'm just hard-coding it for now). The form always comes up with a "New" record.
For a form to load a specific record you can set the primary key page item to the value you need. You can do so in the url using the link builder from another page or you can set a computation on the item. That is what I would try in your case: add a computation to your item P_USER_ID of type "Static Value" with value 813309. Make sure the computation happens before the "Fetch Row" - the value obviously needs to be set before the process runs.
In such cases, I prefer creating a Report + Form combination (using the Wizard, of course): it creates an interactive report (so that you can review data in a table), and a form which is used to add new records or update/delete existing ones.
Doing so, when you pick a user in interactive report and click the icon at the beginning of a row, Apex redirects you to the form page, passing primary key column value to the form which then fetches appropriate data from the table.
Not that it won't work the way you're trying to do it, it's just simpler if you let Apex do everything for you.
So: did you create an automatic row fetch pre-rendering process? If not, do so because - without it - Apex doesn't know what to fetch. Also, if you hardcoded user_id, it won't do much good. Consider storing username into the table so that you could reference it via :APP_USER Apex variable.

Oracle forms Multiple rows modification issue

I m using forms 11g
I have one master-detail form.
I want to restrict the user from saving the non detail block record, If record entered in the corresponding master block has been rollbacked.
To be clear when i query or move out of that field i see a message 'do you want to save changes made?'
when i say 'NO', my master block values rolled back , but non detail block records are saving
I tried to use issue_rollback(null); but not working

Field goes null when button press oracle forms?

I am creating form for search data in oracle forms 10g
when user select LOV from non-database field and press search button then non-database field goes null. I want field not null when button press
A screenshot would help; it is unclear where's that non-database field placed. If it is a tabular layout forum, is it placed within all the other fields? Or is it somewhere in a control, non-database block?
Anyway: here's how I'd do that.
First of all, if possible, avoid inventing your own searching algorithm. Forms is very good at doing such things by itself. Shortly:
enter query mode
enter search criteria (select it from a list of values; why not?)
execute query
absolutely no additional programming is necessary (apart from the LoV)
If, for some reason, you have to do it "your way":
put the non-database LoV field into a separate control block
WHEN-BUTTON-PRESSED should
use SET_BLOCK_PROPERTY and set database block's DEFAULT_WHERE (or, maybe even better, ONETIME_WHERE) to a selected LoV value
navigate to a database block (GO_BLOCK)
EXECUTE_QUERY
alternatively, WHEN-BUTTON-PRESSED would only EXECUTE_QUERY, but you'd use PRE-QUERY trigger on the database block that sets the searching criteria, for example :database_block.name := :control_block.lov_field;
As of your question:
it seems that the LoV field is part of the database block, and it gets cleared once you execute query. See if you can re-fill it using POST-QUERY trigger
Or, if it is not, check what the WHEN-BUTTON-PRESSED trigger is doing - maybe it clears it
See of what I wrote helps. If not, please, edit the question (your initial message) and provide additional information which would help us help you.

How to insert rows in phpMyAdmin

I have a database which I've opened in phpMyAdmin. I clicked the "Insert" button, which has an icon showing one row being inserted between two others.
When I actually try to insert a row, I get the following error:
1062 - Duplicate entry '294' for key 'PRIMARY'
How do I get phpMyAdmin to insert a row (presumably by increasing all the higher-numbered rows by 1) as the icon and the term "Insert" implies? It only seems to want to "Add" a row to the end, not "Insert" it.
As I said, the icon specifically shows one row being inserted between two others, and this is what I want to do. How do I get it to do what it claims it will do?
First, "INSERT" is standard SQL terminology for putting something in the database; it doesn't specifically mean "putting it between two existing values". I see how the icon can be a bit confusing, but when "insertting" data there is no difference between putting something at the end or in the middle of the database. For that matter, there's no real inherent order to data stored in a database; you can select many different ways to sort it when you display the data (and phpMyAdmin generally does a good job of guessing what's reasonable), but data just exists. You can select to sort it by the primary key or alphabetically by user name or any means you wish.
Second, your primary key shouldn't change. It's the key that holds your data together; if you start changing that your references from other tables will be messed up (see below). So don't change that.
Third, if you have your primary key set up with auto_increment (the A_I checkbox in phpMyAdmin), then you shouldn't ever need to set it or worry about it yourself. It's all managed by MySQL. If you aren't happy with the order and want to move 294 to 295 so you can insert something else at 294, then your database design needs tweaking because that's not how auto_incrementing primary keys are designed to work. As a simple solution, you may wish to create another field called "sort_value" or something that you can change.
Which all brings me to the root cause of your trouble: you're trying to create a new row while reusing an existing auto_increment value, and MySQL is smart enough to know this is a bad idea.
So as I said above, changing your primary key (whether or not it's auto generated) is a bad idea, but it may not be obvious why if you only have one table. But relational databases are designed so that you can reference tables from other tables, so for instance a customer database might have a table for "customers", "products", and "purchases" where the purchases table references the primary key ID from both customers and products...imagine the carnage your data would see if you then change the value of those keys in the customer table. You'd show customers associated with some other customer's purchases. So it might not make sense in your database, but overall that's the best way to handle things.
If you really, really don't want to change your database structure, don't reference that key from any other tables, and don't want to listen to my advice, you should be able to simply turn off the auto_increment function on your primary key and reorder them however you wish.

Current version of data in database has changed since user initiated update process

I have a Master Detail form in my Oracle APEX application. When I am trying to update data in this form, I am getting below error.
Current version of data in database has changed since user initiated
update process. current row version identifier =
"26D0923D8A5144D6F483C2B9815D07D3" application row version identifier
= "1749BCD159359424E1EE00AC1C3E3FCB" (Row 1)
I have cleared browser cache and try to update. But it not worked.
How can I solve this?
I have experienced similar problem where my detail records set has timestamp fields. By default master detail wizard creates the timestamp fields as date picker type fields. If you set the date format on these, it would resolve the issue.
This blog post tries to address this issue on a Tabular Form (I know that's not what the original issue was with, but thought it might be related). It says the same as #sangam does below.
Short version: If you have an updated field that's timestamp datatype, you should set a date/time format.
http://apexbyg.blogspot.com/2015/05/tabular-form-bug.html
My tabular form has a field that's timestamp datatype, but I had already set a date format, so this didn't help me.
Here's another possibility, which I discovered was the case in my application.
That would be if the data the original checksum was calculated on is truly different than the pre-update checksum calculation, due to a design-flaw in your query!
In my application, the source for one of the updateable fields was COALESCE(name_calced, name_preferred). In the source table, the person's name could already be loaded in the record by an external process and we save it to one field - name_calced. But the end-user can enter a preferred name, which we wanted to save to the name_preferred field. We wanted to initially populate the displayed, updateable tabular form field with name_calced, if one existed, or name_preferred if the user had already provided a preferred name. Then they could change that value and save it back to the database.
I finally discovered that the Save action threw the error message if name_calced was non-null, but name_preferred was null. I realized that the initial checksum was calculated based on name_calced, but the pre-update checksum was based on name_preferred, so the application thought someone had changed the value in the background and showed the error message.
What I don't understand is how this problem didn't show up in the past 3 years the application has been running in production!
My solution is to make the field source only on name_preferred, which immediately solved this problem. I also think the back-end process will also get changed to pre-populate that table field from name_calced, so the user always sees the base value, if there is one.
I just had this issue myself. Now, I realize that tabular forms are deprecated at this time, but I have an application that was developed beforehand and still uses them. This issue occurred and I had to get one of our big guns at Oracle to help me out. I do a lot of DB work and a decent amount of Apex development but I'm more of a Java, WebLogic, etc guy, and I really couldn't figure this one out.
In my case, it turned out to be really simple. One of the columns in my tabular form was a hidden field, generated via a sub query. Being hidden, this column is not editable by the user and should not be part of the MRU update. I had the field set to "Hidden Column (saves states)" and setting its type to "Hidden Column" fixed the issue. So, this leads to sub queries being executed in such a way as to change the checksum for the overall query before hitting submit (save), causing the error.
For those who are continuing to troubleshoot this, look at your query for every field that you have specified and note which columns are editable in the tabular form. All other fields should be set in a way that makes them not save state so that they are not part of the update.
I had this error when I had two update processes processing on submit.
My solution was to add a condition to both processing steps. I had forgotten to do this when I made an additional process for Button A, but I never updated Button B to limit it's behaviors.
Navigation:
Processing -> Processes -> [Your Process Name] -> Server-side Condition -> When Button Pressed = [Your button Name]
In my case I had a column from a secondary table that was not set as Query Only and was being updated! The error would occur trying to save a column not in the table being updated. It took me half a day to figure it out (the column names were the same).
Set your Link column hidden to display only in the form.
Set "Send On Page Submit" to 'No' or disable the link column that is your primary key ( Rownum/rowid/id etc).
Hope it will work for you.
I have noticed this error comes when I was working Tabular Form and has disabled one of the form operations i.e. by setting server-side condition to "Never" for add, apply changes (submit) buttons
When I have restored back to its original state, it worked as expected.
In case you have to hide Add/Update button, use some other option.
https://compknowledgebase.blogspot.com/2018/12/oracle-apex-error-current-version-of.html

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