Shell script to move, archive and rename files - shell

I am trying to move a bunch of files into a new directory, "archive" and then zip all these files, and renaming the zip onto "DD-MM-YYYY - DD-MM-YYYY", where the second DD-MM-YYYY is 7 days ahead of the first DD-MM-YYYY.
This is what I have done so far,
CURRDATEforARCHIVE=`date +%Y-%m-%d`
mv /Source/path /Destination/path/inbound/
mv /Destination/path/inbound /Destination/path/$CURRDATEforARCHIVE
cd /Destination/path/
zip -r $CURRDATEforARCHIVE.zip $CURRDATEforARCHIVE
rm -rf /Destination/path/$CURRDATEforARCHIVE
mkdir /Source/path/inbound
But I think my implementation is rather clunky, not very clean. Is there a more "streamlined" manner to achieve it?

The easiest way to achieve the second date is to use date -d with a relative time offset. Just create a second variable with something like:
#!/bin/sh
CURRDATEforARCHIVE=`date +%Y-%m-%d`
FUTUREforARCHIVE=`date -d "now + 7 days" "+%Y-%m-%d"`
echo "file_${CURRDATEforARCHIVE}-${FUTUREforARCHIVE}.zip"
Output
$ sh sevendays.sh
file_2015-07-12-2015-07-19.zip
You should also veriify you successfully created the zip file before removing the sources:
zip -r "$CURRDATEforARCHIVE.zip" "$CURRDATEforARCHIVE"
if [ -f "$CURRDATEforARCHIVE.zip" ] then
rm -rf "/Destination/path/$CURRDATEforARCHIVE"
else
printf "error: zip file creation failed '%s'\n" "$CURRDATEforARCHIVE.zip"
fi
Note: always "quote" your variable to protect against spaces in file names, etc..

Related

mv command and rename not working on multiple flies

Below is a bash script to move files around and rename them. The problem is it doesn't work when there is more than one file in the directory. I'm assuming because the last parameter in the mv command is a file. Any suggestions?
'#!/bin/bash'
'INPUTDIR="/home/southern-uniontn/S001007420"'
'OUTPUTDIR="/mnt/edi-06/southern-uniontn/flats-in"'
'BACKUPDIR="/backup/southern-uniontn/S001007420"'
YEAR=`date +%Y`
MONTH=`date +%m`
DAY=`date +%d`
HOUR=`date +%H`
MINUTE=`date +%M`
######## Do some error checking #########
# Does backup dir exist?
if [ ! -d $BACKUPDIR/$YEAR ]
then
mkdir $BACKUPDIR/$YEAR
fi
if [ ! -d $BACKUPDIR/$YEAR/$MONTH ]
then
mkdir $BACKUPDIR/$YEAR/$MONTH
fi
if [ ! -d $BACKUPDIR/$YEAR/$MONTH/$DAY ]
then
mkdir $BACKUPDIR/$YEAR/$MONTH/$DAY
fi
if [[ $(find $INPUTDIR -type f | wc -l) -gt 0 ]];
then
###### Rename the file, move it to Backup, then copy to the Output Directory #####
for f in $INPUTDIR/*
do
echo "`date` - Move recurring txt flat file to BackupDir for Union TN from Southern"
mv $INPUTDIR/* $BACKUPDIR/$YEAR/$MONTH/$DAY/UnionTN-S001007420-$YEAR$MONTH$DAY-$HOUR$MINUTE.txt
sleep 2
echo "`date` - Copy backup file to the Union TN Output Directory"
cp $BACKUPDIR/$YEAR/$MONTH/$DAY/UnionTN-S001007420-$YEAR$MONTH$DAY-$HOUR$MINUTE.txt $OUTPUTDIR/
done;
fi
Some notes:
Get out of the habit of using ALLCAPS variable names, leave those as reserved
by the shell. One day you'll write PATH=something and then wonder
why your script is
broken.
mkdir -p can create parent directories, and will not error if the dir already exists
store the filenames in an array. Then the shell does not have to duplicate
the work, and you don't need to count how many there are: if there are no
files, the loop has zero iterations
if you want to keep the same directory hierarchy in the outputdir,
you need to do that by hand.
use read to get the date parts
with bash v4.2+, printf can be used instead of calling out to date
use magic value "-1" to mean "now".
printf '%(%Y-%m-%d)T\n' -1 prints "2021-10-25" (as of the day I write this)
This is, I think, what you want:
#!/bin/bash
inputdir='/home/southern-uniontn/S001007420'
outputdir='/mnt/edi-06/southern-uniontn/flats-in'
backupdir='/backup/southern-uniontn/S001007420'
read year month day hour minute < <(printf '%(%Y %m %d %H %M)T\n' -1)
# create backup dirs if not exists
date_dir="$year/$month/$day"
mkdir -p "$backupdir/$date_dir"
mkdir -p "$outputdir/$date_dir"
mapfile -t files < <(find $inputdir -type f)
for f in "${files[#]}"
do
###### Rename the file, move it to Backup, then copy to the Output Directory #####
backup_file="UnionTN-S001007420-$year$month$day-$hour$minute.txt"
printf '%(%c)T - Move recurring txt flat file to backupdir for Union TN from Southern\n' -1
mv "$f" "$backupdir/$date_dir/$backup_file"
printf '%(%c)T - Copy backup file to the Union TN Output Directory\n' -1
cp "$backupdir/$date_dir/$backup_file" "$outputdir/$date_dir/$backup_file"
done
When using a glob with mv, the target must be an existing directory, and all matching files will be moved inside that directory.
In your case,
mv $INPUTDIR/* $BACKUPDIR/$YEAR/$MONTH/$DAY/UnionTN-S001007420-$YEAR$MONTH$DAY-$HOUR$MINUTE.txt
tells mv to move all file inside the $INPUTDIR/* directory to a directory named $BACKUPDIR/$YEAR/$MONTH/$DAY/UnionTN-S001007420-$YEAR$MONTH$DAY-$HOUR$MINUTE.txt.
I'm not sure what you're trying to do, but I hope this help.
Some more advice you could use:
Don't put the shebang (the first line beginning with "#") and the first three variable declarations inside single-quotes.
Some argue it is more portable and better to write /usr/bin/env bash instead of /bin/bash in the shebang
if [ CONDITION ] /then ACTION /fi statements can be simplified by writing [ CONDITION ] && ACTION
You reduce your likely hood of encountering unexpected behaviour when double-quoting your strings and variable (i.e. write "${year}/${month}/" instead of $year/$month.
No need to call mkdir a, followed by mkidr a/b, then mkdir a/b/c and so on, you can just call mkdir -p a/b/c. The p flag tells mkdir to create parent directories if they don't already exist.
It is unnecessary to validate the existence of a directory before calling mkdir since mkdir already validates that for you.
As pointed out by commenters, all-caps variables are conventions for special POSIX related variables. You should use another type of casing.
You could use date to do the formatting for you: date +%Y/%m/%d will print 2021/10/25
Strings without interpolation can have single-quotes.
(Optional, prevent undesired behaviors) Put set -e at the beginning of your scripts, after the shebang, to tell bash to halt if an error is encountered
And finally, use man <command_name> for built-in documentation!

BASH Script for creating multiple directories, moving files, and then renaming said files

I am trying to make a bash script to create directories with the same name as each file in a given directory, then move said files to their respective directories, and then rename the files.
Basically - a quantum chemistry program that I use requires that the input files be named "ZMAT". So, if I have multiple jobs, I currently need to manually create directories, and then move the ZMAT files into them (can only run one job per folder).
When I run my code, I get "binary operator expected". I am not sure what this means. Some help please.
Here is what I have so far:
#!/bin/bash
if [ -e *.ZMAT ];
then
echo "CFOUR Job Detected"
for INPFILE in *.ZMAT; do
BASENAME=$(basename $INPFILE )
INPFILE=$BASENAME.ZMAT
OUTFILE=$BASENAME.out
XYZFILE=$BASENAME.xyz
ERRORFILE=$BASENAME.slu
if [ ! -e $ERRORFILE ];
then
# Create folder in scratch directory with the basename
mkdir /scratch/CFOUR/$BASENAME
# Move the file to its directory
mv -f $INPFILE /scratch/CFOUR/$BASENAME
# cd to the new directory
cd /scratch/CFOUR/$BASENAME
# Change the file name to just ZMAT
mv -f $INPFILE ZMAT
echo "Submitting CFOUR Job"
# Submit to scheduler
#RUN_COMMAND="sbatch -J $BASENAME _CFOUR_MRCC_SLURM.SUB"
#eval $RUN_COMMAND
else
echo "Error File Detected - Not Submitting Job"
fi
done
fi
An alternative would be to create symlinks to the original files.
As you said before, each ZMAT symlink would need to be in its own directory.
The upside is that the original data doesn't move, so less risk of breaking it, but the tool you want to use should read the symlinks as if they are the files it is looking for.
This one-liner creates an out directory in the current folder that you could subsequently move wherever you want it. You could easily create it where you do want it by replacing "out" with whatever absolute path you wanted
for i in *.ZMAT; do mkdir -p out/$i ; ln -s $PWD/$i out/$i/ZMAT ; done
I believe I have solved my problem. Here is the new script, which appears to be working fine. Any input is welcome though!
#!/bin/bash
SUBDIR=$(pwd)
for i in *.ZMAT; do
BASENAME=$(basename $i .ZMAT)
INPFILE=$BASENAME.ZMAT
OUTFILE=$BASENAME.out
XYZFILE=$BASENAME.xyz
ERRORFILE=$BASENAME.slu
if [ ! -e $ERRORFILE ];
then
mkdir /scratch/CFOUR/$BASENAME # Create Scratch Folder
cp $INPFILE /scratch/cdc/CFOUR/$BASENAME # Move Input to Scratch
cd /scratch/CFOUR/$BASENAME #cd to Scratch Folder
mv -f $INPFILE ZMAT # Change Input Name
echo "Submitting CFOUR Job"
# Submit to scheduler
#RUN_COMMAND="sbatch -J $BASENAME _CFOUR_MRCC_SLURM.SUB"
#eval $RUN_COMMAND
cd $SUBDIR #Go back to SUBDIR
else
echo "Error File Already Exists"
fi
done

Get date from filename and sort into folders?

I'm running wget to get data from an FTP server like this:
wget -r -nH -N --no-parent ftp://username:password#example.com/ -P /home/data/
All of the files are in a format similar to this:
2016_07_10_bob-randomtext.csv.gz
2016_07_11_joe-importantinfo.csv.gz
Right now it's putting all of these files into /home/data/.
What I want to do is get the time from the filename and put it into their own folders based on the date. For example:
/home/data/2016_07_10/2016_07_10_bob-randomtext.csv.gz
/home/data/2016_07_11/2016_07_11_joe-importantinfo.csv.gz
Based off the answers here, it is possible to get the date from a file name. However, I'm not really sure how to turn that into a folder automatically...
Sorry if this is a bit confusing. Any help or advice would be appreciated.
Keeping the download of all the files into one directory, /home/files
destination=/home/data
for filename in /home/files/*; do
if [[ -f "$filename" ]]; then # ignore it if it's a directory (not a file)
name=$(basename "$filename")
datedir=$destination/${name:0:10} # first 10 characters of the filename
mkdir -p "$datedir" # create the directory if it doesn't exist
mv "$filename" "$datedir"
fi
done

bash script to unzip recently uploaded file into server

I want to unzip file automatically after being uploaded into server.
I'm not experienced in bash but I've tried this
for file in *.zip
do
unzip -P pcp9100 "$file" -d ./
done
It's not working as I want.
Okay, assuming you want this to be continuously done in a loop, you can do something like:
while true; do
for file in *.zip; do
unzip -P pcp9100 "${file}" -d ./
rm "${file}"
done
sleep 3
done
Of course there are several things that can go wrong here.
File has an incorrect password
The file inside is also a zip file and does not have the same password
Permissions are incorrect
First, your permissions should be correct. Secondly, you can create a directory called "ExtractedFiles" and one called "IncorrectPasswords" which you can do something like:
while true; do
for file in *.zip; do
unzip -P pcp9100 "${file}" -d ./ExtractedFiles || mv "${file}" ./IncorrectPasswords
rm "${file}"
done
sleep 3
done

shell script to create folder daily with time-stamp and push time-stamp generated logs

I have a cron job which runs every 30 minutes to generate log files with time-stamp like this:
test20130215100531.log,
test20130215102031.log
I would like to create one folder daily with date time-stamp and push log files in to respective date folder when generated.
I need to achieve this on AIX server with bash.
Maybe you are looking for a script like this:
#!/bin/bash
shopt -s nullglob # This line is so that it does not complain when no logfiles are found
for filename in test*.log; do # Files considered are the ones starting with test and ending in .log
foldername=$(echo "$filename" | awk '{print (substr($0, 5, 8));}'); # The foldername is characters 5 to 13 from the filename (if they exist)
mkdir -p "$foldername" # -p so that we don't get "folder exists" warning
mv "$filename" "$foldername"
echo "$filename $foldername" ;
done
I only tested with your sample, so do a proper testing before using in a directory that contains important stuff.
Edit in response to comments:
Change your original script to this:
foldername=$(date +%Y%m%d)
mkdir -p /home/app/logs/"$foldername"
sh sample.sh > /home/app/logs/"$foldername"/test$(date +%Y%m%d%H%M%S).log
Or if the directory is created somewhere else, just do this:
sh sample.sh > /home/app/logs/$(date +%Y%m%d)/test$(date +%Y%m%d%H%M%S).log
You should use logrotate! It can do this for you already, and you can just write to the same log file.
Check their man pages for info:
http://linuxcommand.org/man_pages/logrotate8.html

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