Conditional Makefile - makefile

Question

I'm working on a Makefile with changeable sources and compiler.
Basically, what I want it to do is display a message in green if the compilation worked out well and in red otherwise. Additionally I want to avoid displaying the usual error messages (and compilation messages) a Makefile produces. (As I tried to do with all the '#')
Here's what I have for now :
COMP = gcc
NAME = test
RM = rm -f
SRC = main.c
OBJS = $(SRC:.c=.o)
CFLAGS = -Werror
all: $(NAME)
$(NAME):
#$(COMP) -c $(SRC)
#$(COMP) -o $(NAME) $(OBJS)
ifeq ($?, 0)
#echo -e '\033[1;32;40mCompilation : OK\033[0m'
else
#echo -e '\033[1;31;40mCompilation : ERROR\033[0m'
endif
clean:
#$(RM) $(OBJS)
fclean: clean
#$(RM) $(NAME)
re: fclean all
.PHONY: all clean fclean re
All it does is display "Compilation : ERROR" when it compiles well, but I thought that if $? equals 0 that meant it worked out, so I can't find any explanation.
Would you know how to make it do what I'm looking for?
Thanks a lot.
EDIT : Wonderful help from many of you, I'm still looking into the recipe but I've found a way to simply display when it succeeded and when it failed.
$(NAME): $(OBJS)
#$(COMP) $(OBJS) -o $(NAME) && echo -e "\033[32mCompilation: OK\033[0m" || echo -e "\033[31mCompilation: ERROR\033[0m"
I'll keep on digging, thanks.

Answer 1

$? is a shell variable not a make variable, you are testing a make variable with that if statement and the recipe for your target only ever has the one echo line in it.
(See the output from make -qp to see what I mean.)
To do what you want you would need a shell test on $? however realize that make will exit on the first failing command so you will never see the failure echo output this way (unless you capture/hide the failure from make with an if or similar construct on the compilation command).
Something like this will work for capturing/hiding the exit status from the compilation from make but allow you to use it.
#if $(COMP) -c $(SRC); then \
echo -e '\033[1;32;40mCompilation : OK\033[0m'; \
else \
_ret=$$?; \
echo -e '\033[1;31;40mCompilation : ERROR\033[0m'; \
exit $$_ret;\
fi
The bit with _ret is to have make exit with the exit code of the compilation and not a static exit 1 or whatever.

Answer 2

What you want is something like this:
$(NAME):
#$(COMP) -c $(SRC)
#$(COMP) -o $(NAME) $(OBJS); \
if [ $$? == 0 ]; then \
echo -e '\033[1;32;40mCompilation : OK\033[0m'; \
else \
echo -e '\033[1;31;40mCompilation : ERROR\033[0m'; \
fi; \
true
Notice that I used the '\' to concatinate the bash command with the if statement, so they all appear as a single recipe. I also added a true statement to the end such that no matter what the if statement returns, the concatenated recipe will return true, and make will not fail. You could also do:
$(NAME):
#$(COMP) -o $(NAME) $(OBJS) || echo ....
where the echo would only print if the previous command failed.