bin sh start multiple processes - shell

I am trying to start multiple processes for my development server by creating a #!/bin/sh file with shell commands in it.
E.g.:
#!/bin/sh
read -p "Start all servers? (Y/n)" answer
if test "$answer" = "Y"
then
cd ./www/src; node ./index.js;
cd ./www/; ./gulp;
cd ./api/; nodemon ./init.js;
cd ./api-test/; node ./index.js;
else
echo "Cancelled."
fi
Because for example nodemon will setup a watch process or node a http server process, the first command will start (cd ./www/src; node ./index.js;) and not continue to startup the other processes.
I can't figure out how to start all 4 processes independent of each other..
Anybody?

I would prefer to write some functions to spawn each process consistently:
One function called spawn_once will only run the command if it is not already running, therefore allowing only one instance
One second function called spawn will run the command even if it is already running (allow multiple instances)
Use the most appropriate for your use case
#!/bin/sh
# Spawn command $1 from path $2
spawn() {
local cmd=$1; local path=$2
( [ ! -z "$path" ] && cd "$path"; eval "$cmd"; ) &
}
# Spawn command $1 from path $2, only if command $1 is not running
# in other words, run only a single instance
spawn_once() {
local cmd=$1; local path=$2
(
[ ! -z "$path" ] && cd "$path"
pgrep -u "$USER" -x "$cmd" >/dev/null || eval "$cmd"
) &
}
# Use spawn or spawn_once to start your multiple commands
# The format is: spawn "<command with args>" "<path>"
spawn "node ./index.js" "./www/src"
spawn_once "./gulp" "./www/" # only one instance allowed
spawn "node ./index.js" "./api-test/"
Explanation:
( [ ! -z "$path" ] && cd "$path"; eval "$cmd"; ) & : Change directory (if path argument was set) and run the command in a subshell (&), i.e. in the background, so it does not affect the current directory for other commands and does not block the script while the command is running.
spawn_once: pgrep -u "$USER" -x "$cmd" >/dev/null || eval "$cmd" : Check if the command has already been started with pgrep, otherwise (||) run the command.

You can use ampersand "&" to execute task in background
for example:
#!/bin/sh
read -p "Start all servers? (Y/n)" answer
if test "$answer" = "Y"
then
cd ./www/src
node ./index.js &
cd $OLDPWD && cd ./www/
./gulp &
.........
else
echo "Cancelled."
fi

Related

Simple bash script for starting application silently

Here I am again. Today I wrote a little script that is supposed to start an application silently in my debian env.
Easy as
silent "npm search 1234556"
This works but not at all.
As you can see, I commented the section where I have some troubles.
This line:
$($cmdLine) &
doesn't hide application output but this one
$($1 >/dev/null 2>/dev/null) &
works perfectly. What am I missing? Many thanks.
#!/bin/sh
# Daniele Brugnara
# October, 2013
# Silently exec a command line passed as argument
errorsRedirect=""
if [ -z "$1" ]; then
echo "Please, don't joke me..."
exit 1
fi
cmdLine="$1 >/dev/null"
# if passed a second parameter, errors will be hidden
if [ -n "$2" ]; then
cmdLine="$cmdLine 2>/dev/null"
fi
# not working
$($cmdLine) &
# works perfectly
#$($1 >/dev/null 2>/dev/null) &
With the use of evil eval following script will work:
#!/bin/sh
# Silently exec a command line passed as argument
errorsRedirect=""
if [ -z "$1" ]; then
echo "Please, don't joke me..."
exit 1
fi
cmdLine="$1 >/dev/null"
# if passed a second parameter, errors will be hidden
if [ -n "$2" ]; then
cmdLine="$cmdLine 2>&1"
fi
eval "$cmdLine &"
Rather than building up a command with redirection tacked on the end, you can incrementally apply it:
#!/bin/sh
if [ -z "$1" ]; then
exit
fi
exec >/dev/null
if [ -n "$2" ]; then
exec 2>&1
fi
exec $1
This first redirects stdout of the shell script to /dev/null. If the second argument is given, it redirects stderr of the shell script too. Then it runs the command which will inherit stdout and stderr from the script.
I removed the ampersand (&) since being silent has nothing to do with running in the background. You can add it back (and remove the exec on the last line) if it is what you want.
I added exec at the end as it is slightly more efficient. Since it is the end of the shell script, there is nothing left to do, so you may as well be done with it, hence exec.
& means that you're doing sort of multitask whereas
1 >/dev/null 2>/dev/null
means that you redirect the output to a sort of garbage and that's why you don't see anything.
Furthermore cmdLine="$1 >/dev/null" is incorrect, you should use ' instead of " :
cmdLine='$1 >/dev/null'
you can build your command line in a var and run a bash with it in background:
bash -c "$cmdLine"&
Note that it might be useful to store the output (out/err) of the program, instead of trow them in null.
In addition, why do you need errorsRedirect??
You can even add a wait at the end, just to be safe...if you want...
#!/bin/sh
# Daniele Brugnara
# October, 2013
# Silently exec a command line passed as argument
[ ! $1 ] && echo "Please, don't joke me..." && exit 1
cmdLine="$1>/dev/null"
# if passed a second parameter, errors will be hidden
[ $2 ] && cmdLine+=" 2>/dev/null"
# not working
echo "Running \"$cmdLine\""
bash -c "$cmdLine" &
wait

Self-daemonizing bash script

I want to make a script to be self-daemonizing, i.e., no need to invoke nohup $SCRIPT &>/dev/null & manually on the shell prompt.
My plan is to create a section of code like the following:
#!/bin/bash
SCRIPTNAME="$0"
...
# Preps are done above
if [[ "$1" != "--daemonize" ]]; then
nohup "$SCRIPTNAME" --daemonize "${PARAMS[#]}" &>/dev/null &
exit $?
fi
# Rest of the code are the actual procedures of the daemon
Is this wise? Do you have better alternatives?
Here are things I see.
if [[ $1 != "--daemonize" ]]; then
Shouln't that be == --daemonize?
nohup $SCRIPTNAME --daemonize "${PARAMS[#]}" &>/dev/null &
Instead of calling your script again, you could just summon a subshell that's placed in a background:
(
Codes that run in daemon mode.
) </dev/null >/dev/null 2>&1 &
disown
Or
function daemon_mode {
Codes that run in daemon mode.
}
daemon_mode </dev/null >/dev/null 2>&1 &
disown

rc.d start does not terminate?

So I wrote the Arch Linux rc.d script for mongod daemon (following an example), but when I do:
sudo rc.d start mongod
it just gets stuck on:
:: Starting /usr/bin/mongod [BUSY]
and never transitions to "DONE" phase. Any tips?
Here is my script:
#!/bin/bash
# import predefined functions
. /etc/rc.conf
. /etc/rc.d/functions
# Point to the binary
DAEMON=/usr/bin/mongod
# Get the ARGS from the conf
. /etc/conf.d/crond
# Function to get the process id
PID=$(get_pid $DAEMON)
case "$1" in
start)
stat_busy "Starting $DAEMON"
# Check the PID exists - and if it does (returns 0) - do no run
[ -z "$PID" ] && $DAEMON $ARGS &> /dev/null
if [ $? = 0 ]; then
add_daemon $DAEMON
stat_done
else
stat_fail
exit 1
fi
;;
stop)
stat_busy "Stopping $DAEMON"
kill -HUP $PID &>/dev/null
rm_daemon $DAEMON
stat_done
;;
restart)
$0 stop
sleep 1
$0 start
;;
*)
echo "usage: $0 {start|stop|restart}"
esac
I've looked at how apache does it, but I can't figure out what they are doing that's different. Here's a piece of their httpd script:
case "$1" in
start)
stat_busy "Starting Apache Web Server"
[ ! -d /var/run/httpd ] && install -d /var/run/httpd
if $APACHECTL start >/dev/null ; then
add_daemon $daemon_name
stat_done
else
stat_fail
exit 1
fi
;;
For one thing, you are passing an $ARGS variable that is never actually defined. You will probably want to either pass some configuration options, or the location of a mongodb.conf file using the -f or --config option, to inform the daemon of the location of your database, log file, IP bindings, etc.
The mongod defaults assume that you database location is /data/db/. If this does not exist, or the daemon does not have permissions to that location, then the init script will fail.
You should probably also run the daemon with a user account other than yourself or root (the default pacman package creates a user named mongodb), and give this user read/write access to the data path and log file.
[ -z "$PID" ] && /bin/su mongodb -c "/usr/bin/mongod --config /etc/mongodb.conf --fork" > /dev/null
I would suggest referring to the mongodb init script provided in the Arch Community package, and comparing that to what you have here. Or, install MongoDB using pacman, which sets all of this up for you.
If all else fails, add some 'echo' commands inside of your if and else blocks to track down exactly where the init script is hanging, check mongodb's logs, and report back to us.

How do I determine if a shell script is running with root permissions?

I've got a script I want to require be run with su privileges, but the interesting scripted command that will fail comes very late in the script, so I'd like a clean test up front to determine if the scrip will fail without SU capabilities.
What is a good way to do this for bash, sh, and/or csh?
bash/sh:
#!/usr/bin/env bash
# (Use #!/bin/sh for sh)
if [ `id -u` = 0 ] ; then
echo "I AM ROOT, HEAR ME ROAR"
fi
csh:
#!/bin/csh
if ( `id -u` == "0" ) then
echo "I AM ROOT, HEAR ME ROAR"
endif
You might add something like that at the beginning of your script:
#!/bin/sh
ROOTUID="0"
if [ "$(id -u)" -ne "$ROOTUID" ] ; then
echo "This script must be executed with root privileges."
exit 1
fi

Best way to make a shell script daemon?

I'm wondering if there is a better way to make a daemon that waits for something using only sh than:
#! /bin/sh
trap processUserSig SIGUSR1
processUserSig() {
echo "doing stuff"
}
while true; do
sleep 1000
done
In particular, I'm wondering if there's any way to get rid of the loop and still have the thing listen for the signals.
Just backgrounding your script (./myscript &) will not daemonize it. See http://www.faqs.org/faqs/unix-faq/programmer/faq/, section 1.7, which describes what's necessary to become a daemon. You must disconnect it from the terminal so that SIGHUP does not kill it. You can take a shortcut to make a script appear to act like a daemon;
nohup ./myscript 0<&- &>/dev/null &
will do the job. Or, to capture both stderr and stdout to a file:
nohup ./myscript 0<&- &> my.admin.log.file &
Redirection explained (see bash redirection)
0<&- closes stdin
&> file sends stdout and stderr to a file
However, there may be further important aspects that you need to consider. For example:
You will still have a file descriptor open to the script, which means that the directory it's mounted in would be unmountable. To be a true daemon you should chdir("/") (or cd / inside your script), and fork so that the parent exits, and thus the original descriptor is closed.
Perhaps run umask 0. You may not want to depend on the umask of the caller of the daemon.
For an example of a script that takes all of these aspects into account, see Mike S' answer.
Some of the top-upvoted answers here are missing some important parts of what makes a daemon a daemon, as opposed to just a background process, or a background process detached from a shell.
This http://www.faqs.org/faqs/unix-faq/programmer/faq/ describes what is necessary to be a daemon. And this Run bash script as daemon implements the setsid, though it misses the chdir to root.
The original poster's question was actually more specific than "How do I create a daemon process using bash?", but since the subject and answers discuss daemonizing shell scripts generally, I think it's important to point it out (for interlopers like me looking into the fine details of creating a daemon).
Here's my rendition of a shell script that would behave according to the FAQ. Set DEBUG to true to see pretty output (but it also exits immediately rather than looping endlessly):
#!/bin/bash
DEBUG=false
# This part is for fun, if you consider shell scripts fun- and I do.
trap process_USR1 SIGUSR1
process_USR1() {
echo 'Got signal USR1'
echo 'Did you notice that the signal was acted upon only after the sleep was done'
echo 'in the while loop? Interesting, yes? Yes.'
exit 0
}
# End of fun. Now on to the business end of things.
print_debug() {
whatiam="$1"; tty="$2"
[[ "$tty" != "not a tty" ]] && {
echo "" >$tty
echo "$whatiam, PID $$" >$tty
ps -o pid,sess,pgid -p $$ >$tty
tty >$tty
}
}
me_DIR="$( cd "$( dirname "${BASH_SOURCE[0]}" )" && pwd )"
me_FILE=$(basename $0)
cd /
#### CHILD HERE --------------------------------------------------------------------->
if [ "$1" = "child" ] ; then # 2. We are the child. We need to fork again.
shift; tty="$1"; shift
$DEBUG && print_debug "*** CHILD, NEW SESSION, NEW PGID" "$tty"
umask 0
$me_DIR/$me_FILE XXrefork_daemonXX "$tty" "$#" </dev/null >/dev/null 2>/dev/null &
$DEBUG && [[ "$tty" != "not a tty" ]] && echo "CHILD OUT" >$tty
exit 0
fi
##### ENTRY POINT HERE -------------------------------------------------------------->
if [ "$1" != "XXrefork_daemonXX" ] ; then # 1. This is where the original call starts.
tty=$(tty)
$DEBUG && print_debug "*** PARENT" "$tty"
setsid $me_DIR/$me_FILE child "$tty" "$#" &
$DEBUG && [[ "$tty" != "not a tty" ]] && echo "PARENT OUT" >$tty
exit 0
fi
##### RUNS AFTER CHILD FORKS (actually, on Linux, clone()s. See strace -------------->
# 3. We have been reforked. Go to work.
exec >/tmp/outfile
exec 2>/tmp/errfile
exec 0</dev/null
shift; tty="$1"; shift
$DEBUG && print_debug "*** DAEMON" "$tty"
# The real stuff goes here. To exit, see fun (above)
$DEBUG && [[ "$tty" != "not a tty" ]] && echo NOT A REAL DAEMON. NOT RUNNING WHILE LOOP. >$tty
$DEBUG || {
while true; do
echo "Change this loop, so this silly no-op goes away." >/dev/null
echo "Do something useful with your life, young padawan." >/dev/null
sleep 10
done
}
$DEBUG && [[ "$tty" != "not a tty" ]] && sleep 3 && echo "DAEMON OUT" >$tty
exit # This may never run. Why is it here then? It's pretty.
# Kind of like, "The End" at the end of a movie that you
# already know is over. It's always nice.
Output looks like this when DEBUG is set to true. Notice how the session and process group ID (SESS, PGID) numbers change:
<shell_prompt>$ bash blahd
*** PARENT, PID 5180
PID SESS PGID
5180 1708 5180
/dev/pts/6
PARENT OUT
<shell_prompt>$
*** CHILD, NEW SESSION, NEW PGID, PID 5188
PID SESS PGID
5188 5188 5188
not a tty
CHILD OUT
*** DAEMON, PID 5198
PID SESS PGID
5198 5188 5188
not a tty
NOT A REAL DAEMON. NOT RUNNING WHILE LOOP.
DAEMON OUT
# double background your script to have it detach from the tty
# cf. http://www.linux-mag.com/id/5981
(./program.sh &) &
Use your system's daemon facility, such as start-stop-daemon.
Otherwise, yes, there has to be a loop somewhere.
$ ( cd /; umask 0; setsid your_script.sh </dev/null &>/dev/null & ) &
It really depends on what is the binary itself going to do.
For example I want to create some listener.
The starting Daemon is simple task :
lis_deamon :
#!/bin/bash
# We will start the listener as Deamon process
#
LISTENER_BIN=/tmp/deamon_test/listener
test -x $LISTENER_BIN || exit 5
PIDFILE=/tmp/deamon_test/listener.pid
case "$1" in
start)
echo -n "Starting Listener Deamon .... "
startproc -f -p $PIDFILE $LISTENER_BIN
echo "running"
;;
*)
echo "Usage: $0 start"
exit 1
;;
esac
this is how we start the daemon (common way for all /etc/init.d/ staff)
now as for the listener it self,
It must be some kind of loop/alert or else that will trigger the script
to do what u want. For example if u want your script to sleep 10 min
and wake up and ask you how you are doing u will do this with the
while true ; do sleep 600 ; echo "How are u ? " ; done
Here is the simple listener that u can do that will listen for your
commands from remote machine and execute them on local :
listener :
#!/bin/bash
# Starting listener on some port
# we will run it as deamon and we will send commands to it.
#
IP=$(hostname --ip-address)
PORT=1024
FILE=/tmp/backpipe
count=0
while [ -a $FILE ] ; do #If file exis I assume that it used by other program
FILE=$FILE.$count
count=$(($count + 1))
done
# Now we know that such file do not exist,
# U can write down in deamon it self the remove for those files
# or in different part of program
mknod $FILE p
while true ; do
netcat -l -s $IP -p $PORT < $FILE |/bin/bash > $FILE
done
rm $FILE
So to start UP it : /tmp/deamon_test/listener start
and to send commands from shell (or wrap it to script) :
test_host#netcat 10.184.200.22 1024
uptime
20:01pm up 21 days 5:10, 44 users, load average: 0.62, 0.61, 0.60
date
Tue Jan 28 20:02:00 IST 2014
punt! (Cntrl+C)
Hope this will help.
Have a look at the daemon tool from the libslack package:
http://ingvar.blog.linpro.no/2009/05/18/todays-sysadmin-tip-using-libslack-daemon-to-daemonize-a-script/
On Mac OS X use a launchd script for shell daemon.
If I had a script.sh and i wanted to execute it from bash and leave it running even when I want to close my bash session then I would combine nohup and & at the end.
example: nohup ./script.sh < inputFile.txt > ./logFile 2>&1 &
inputFile.txt can be any file. If your file has no input then we usually use /dev/null. So the command would be:
nohup ./script.sh < /dev/null > ./logFile 2>&1 &
After that close your bash session,open another terminal and execute: ps -aux | egrep "script.sh" and you will see that your script is still running at the background. Of cource,if you want to stop it then execute the same command (ps) and kill -9 <PID-OF-YOUR-SCRIPT>
See Bash Service Manager project: https://github.com/reduardo7/bash-service-manager
Implementation example
#!/usr/bin/env bash
export PID_FILE_PATH="/tmp/my-service.pid"
export LOG_FILE_PATH="/tmp/my-service.log"
export LOG_ERROR_FILE_PATH="/tmp/my-service.error.log"
. ./services.sh
run-script() {
local action="$1" # Action
while true; do
echo "### Running action '${action}'"
echo foo
echo bar >&2
[ "$action" = "run" ] && return 0
sleep 5
[ "$action" = "debug" ] && exit 25
done
}
before-start() {
local action="$1" # Action
echo "* Starting with $action"
}
after-finish() {
local action="$1" # Action
local serviceExitCode=$2 # Service exit code
echo "* Finish with $action. Exit code: $serviceExitCode"
}
action="$1"
serviceName="Example Service"
serviceMenu "$action" "$serviceName" run-script "$workDir" before-start after-finish
Usage example
$ ./example-service
# Actions: [start|stop|restart|status|run|debug|tail(-[log|error])]
$ ./example-service start
# Starting Example Service service...
$ ./example-service status
# Serive Example Service is runnig with PID 5599
$ ./example-service stop
# Stopping Example Service...
$ ./example-service status
# Service Example Service is not running
Here is the minimal change to the original proposal to create a valid daemon in Bourne shell (or Bash):
#!/bin/sh
if [ "$1" != "__forked__" ]; then
setsid "$0" __forked__ "$#" &
exit
else
shift
fi
trap 'siguser1=true' SIGUSR1
trap 'echo "Clean up and exit"; kill $sleep_pid; exit' SIGTERM
exec > outfile
exec 2> errfile
exec 0< /dev/null
while true; do
(sleep 30000000 &>/dev/null) &
sleep_pid=$!
wait
kill $sleep_pid &>/dev/null
if [ -n "$siguser1" ]; then
siguser1=''
echo "Wait was interrupted by SIGUSR1, do things here."
fi
done
Explanation:
Line 2-7: A daemon must be forked so it doesn't have a parent. Using an artificial argument to prevent endless forking. "setsid" detaches from starting process and terminal.
Line 9: Our desired signal needs to be differentiated from other signals.
Line 10: Cleanup is required to get rid of dangling "sleep" processes.
Line 11-13: Redirect stdout, stderr and stdin of the script.
Line 16: sleep in the background
Line 18: wait waits for end of sleep, but gets interrupted by (some) signals.
Line 19: Kill sleep process, because that is still running when signal is caught.
Line 22: Do the work if SIGUSR1 has been caught.
Guess it does not get any simpler than that.
Like many answers this one is not a "real" daemonization but rather an alternative to nohup approach.
echo "script.sh" | at now
There are obviously differences from using nohup. For one there is no detaching from the parent in the first place. Also "script.sh" doesn't inherit parent's environment.
By no means this is a better alternative. It is simply a different (and somewhat lazy) way of launching processes in background.
P.S. I personally upvoted carlo's answer as it seems to be the most elegant and works both from terminal and inside scripts
try executing using &
if you save this file as program.sh
you can use
$. program.sh &

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