The question is the following.
How can I set default route for non-existed pages in Laravel 5? So when page not found, than some default view is shown with status 200.
I think for non-existing pages you should use status code 404 but if you wants to pass 200 ok then this should work fine.
create a file 404.blade.php at views >> errors directory and place abort(200); in it.
Update
Or you can place this code in file app/Exceptions/Handler.php
public function render($request, Exception $e)
{
// 404 page with status code 200
if ($e instanceof ModelNotFoundException) {
return response()->view('errors.404', [], 200);
}
return parent::render($request, $e);
}
Note: creating a file 404.blade.php at views >> errors directory is must OR pass another custom view.
You can create a custom 404 view by creating a Blade template called 404.blade.php and placing it in the resources/views/errors directory.
However, do not send a 200 OK HTTP status. That just breaks everything the HTTP protocol stands for.
Related
My question is whenever there is a 403 error I should redirect to my own custom page or show the flash message(on the same page) something like that.How can I achieve this in Laravel?.
You can use app/Exceptions/Handler.php for this
public function render($request, Exception $e)
{
if ($e->getStatusCode() == 403) {
return redirect('yourpage'); // this will be on a 403 exception
}
return parent::render($request, $e); // all the other exceptions
}
You can create a view for specific HTTP error codes. If you set up a Blade template at resources/views/errors/403.blade.php, it will get used for all 403 error responses.
Source
Alternatively you can set up a custom exception handler for 403 responses if you need something more involved. I found a good example of this here.
you can make you own page in inside the view .resources/views/errors/yourblade.blade.php
after that just return your page to that page.
You can use app/Exceptions/Handler.php for this as Thomas Moors stated above or you can use a try catch for basic error handling.
try {
do Something //
}
catch (Exception $e) {
//log error in log file or dv
return redirect->('home');
}
I have a Route defined as:
$app->post('api/v1/Subject','SubjectController#createSubject');
And in the Controller I have the following code:
public function createSubject(Request $request){
$Subject = Subject::create($request->all());
return response()->json($Subject);
}
Now, when someone sends incorrect data, it triggers a Query Exception - "SQLSTATE[23000]: Integrity constraint violation:" which is understood.
However, what I want is: I want do not want Lumen to send its own default Error Page in API Response. I want to capture this error event and send my own customized response. How can I do that?
Since I could not find a solution, I tried to add my own view at: /resources/views/errors/500.blade.php but Lumen is even ignoring this template. Please help. Ideally, I would want to capture this error event and send my own customized response.
EDIT:
Lumen was reporting two exceptions - PDOException and QueryException at the 500 error response. So, to get a custom error message, I put the following code in side function render() in app\Exceptions\Handler:
public function render($request, Exception $e)
{
if($e instanceof PDOException){
return response('It is my Custom response for PDOException that caused 500 error response.');
}
if($e instanceof QueryException){
return response('It is my Custom response for QueryException that cuased 500 error response.');
}
return parent::render($request, $e);
}
I'm looking for a modern (Laravel 5.4) way to display custom 500 error page only for HTTP (non ajax/fetch) response. I read some threads but each response looks like a trick or is outdated. There is probably something to modify in \App\Exceptions\Handler, but I did not find the "right way".
Is there a simple way to display a specific page on fatal error (uncatched, returning 500) in Laravel 5.4?
In other words, when I have a syntax error on one of my controller, it displays "Whoops something went wrong" with some HTML and 500 error code. I would like to display something else, with the same rules as default behavior (ideally only for HTML browser, not for ajax/fetch, etc.).
EDIT: only in production environment.
Laravel makes it easy to display custom error pages for various HTTP status codes. For example, if you wish to customize the error page for 404 HTTP status codes, create a resources/views/errors/404.blade.php. This file will be served on all 404 errors generated by your application. The views within this directory should be named to match the HTTP status code they correspond to. The HttpException instance raised by the abort function will be passed to the view as an $exception variable.
https://laravel.com/docs/5.4/errors#custom-http-error-pages
From the selected "best answer" of this thread: https://laracasts.com/discuss/channels/general-discussion/custom-error-page-er500
You could modify \App\Exceptions\Handler::render():
public function render($request, Exception $exception)
{
if (config('app.debug') && !$this->isHttpException($exception)) {
$exception = new \Symfony\Component\HttpKernel\Exception\HttpException(500);
}
return parent::render($request, $exception);
}
Your exception will be reported in the logs as usually, but woops page will be replaced by your 500.blade.php view.
Sometimes you have to catch the specific exception in order to render the error view. in Laravel 5.4 you can do this by editing the report() method in the App\Exceptions\Handler class
public function report(Exception $exception)
{
if ($exception instanceof CustomException) {
// here you can log the error and return the view, redirect, etc...
}
return parent::report($exception);
}
I am using Laravel 5.0. Is there any way to forward to default 404 page error if the user wrong url. I want to forward all the time if the user entered wrong url in my project.
In your resources/views/errors folder make sure you have a 404.blade.php file and if that is not there then create it and put something in this file.
Basically, if that 404 file is not present there then You'll see an error like this:
Sorry, the page you are looking for could not be found.
NotFoundHttpException in Application.php line 901:
....
.
Sepending on your environment setup. FYI, in app\Exceptions\Handler.php file the handler method handles/catches the errors. So check it, you may customize it, for example:
use Exception;
use Illuminate\Foundation\Exceptions\Handler as ExceptionHandler;
// You can use/catch this but basically this is not included in Handler
use Symfony\Component\HttpKernel\Exception\AccessDeniedHttpException;
class Handler extends ExceptionHandler {
//...
public function render($request, Exception $e)
{
// Customize it, extra code
if ($e instanceof AccessDeniedHttpException) {
return response(view('errors.403'), 403);
}
// The method has only this line by default
return parent::render($request, $e);
}
}
Then, make sure, the 403.blade.php is also available in your resources/views/errors directory.
I'm using Laravel 4 framework and I've defined a whole bunch of routes, now I wonder for all the undefined urls, how to route them to 404 page?
In Laravel 5.2. Do nothing just create a file name 404.blade.php in the errors folder , it will detect 404 exception automatically.
Undefined routes fires the Symfony\Component\HttpKernel\Exception\NotFoundHttpException exception which you can handle in the app/start/global.php using the App::error() method like this:
/**
* 404 Errors
*/
App::error(function(\Symfony\Component\HttpKernel\Exception\NotFoundHttpException $exception, $code)
{
// handle the exception and show view or redirect to a diff route
return View::make('errors.404');
});
The recommended method for handling errors can be found in the Laravel docs:
http://laravel.com/docs/4.2/errors#handling-404-errors
Use the App::missing() function in the start/global.php file in the following manner:
App::missing(function($exception)
{
return Response::view('errors.missing', array(), 404);
});
according to the official documentation
you can just add a file in: resources/views/errors/
called 404.blade.php with the information you want to display on a 404 error.
I've upgraded my laravel 4 codebase to Laravel 5, for anyone who cares:
App::missing(function($exception) {...});
is NO LONGER AVAILABLE in Laravel 5, in order to return the 404 view for all non-existent routes, try put the following in app/Http/Kernel.php:
public function handle($request) {
try {
return parent::handle($request);
}
catch (Exception $e) {
echo \View::make('frontend_pages.page_404');
exit;
// throw $e;
}
}