laravel query builder from normal query - laravel-4

DB::select(DB::raw( 'SELECT a.bill_no, a.account_id, a.bill_date, a.amount_paid,
b.transaction_code,b.amount from bill_det a left join
(select bill_no, transaction_code, sum(amount) as amount from payment_transactions
where status = "success" group by bill_no ) b
on a.bill_no = b.bill_no where a.amount_paid != b.amount order by b.bill_no'));
this is normal query.change into laravel query?.
i tried.
$bill=DB::table('bill_det')->leftJoin('payment_transactions', 'bill_det.bill_no', '=', 'payment_transactions.bill_no')
->select('bill_det.bill_no','bill_det.account_id','bill_det.bill_date','bill_det.amount_paid',
'payment_transactions.transaction_code',DB::raw('sum(payment_transactions.amount) as amount'))
->where('payment_transactions.status','=','success')
->where('sum(payment_transactions.amount)','!=',DB::raw('bill_det.amount_paid'))
->groupBy('bill_det.bill_no')
->orderBy('bill_det.bill_no','desc');
i can't compare -> where('sum(payment_transactions.amount)','!=',DB::raw('bill_det.amount_paid'))
i used like this ->whereRaw('bill_det.amount_paid != sum(payment_transactions.amount)')
{"error":{"type":"Illuminate\Database\QueryException","message":"SQLSTATE[HY000]: General error: 1111 Invalid use of group function (SQL: select count(*) as aggregate from (select '1' as row_count from bill_det left join payment_transactions on bill_det.bill_no = payment_transactions.bill_no where payment_transactions.status = success and bill_det.amount_paid != sum(payment_transactions.amount) group by bill_det.bill_no order by bill_det.bill_no desc) count_row_table)"

DB::select(DB::raw( 'SELECT a.bill_no, a.account_id, a.bill_date, a.amount_paid,
b.transaction_code,b.amount from bill_det a left join
(select bill_no, transaction_code, sum(amount) as amount from payment_transactions
where status = "success" group by bill_no ) b
on a.bill_no = b.bill_no where a.amount_paid != b.amount order by b.bill_no'));
After converting this to laravel Query::
$query = \Illuminate\Support\Facades\DB::table('bill_det')
->select('a.bill_no', 'a.account_id', 'a.bill_date', 'a.amount_paid', 'b.transaction_code', 'b.amount')
->leftJoin(DB::raw('(select bill_no, transaction_code, sum(amount) as amount from payment_transactions
where status = "success" group by bill_no) b'), function($join) {
$join->on('a.bill_no', '=', 'b.bill_no');
})
->where('a.amount_paid','<>', 'b.amount')
->orderBy('b.bill_no')
->get();
In case you want to know how to use raw expression inside where then use this:
$query->whereRaw(DB::raw('(your expression!!)'));

Related

Which is the best efficient way to get many-to-many relation count in laravel?

I have students and subjects table in many-to-many relation (pivot table is student_subject).
Student Model
public function subjects()
{
return $this->belongsToMany(Subject::class, 'student_subject');
}
Subject Model
public function students()
{
return $this->belongsToMany(Student::class, 'student_subject');
}
Here I want the particular student subjects counts. I tried the below methods it's working fine but I want the best efficient way for this purpose.
1.
$student = Student::find($id);
$subject_count = $student->subjects()->count();
I checked the SQL query through laravel debuger it shows as below
select * from `students` where `students`.`id` = '10' limit 1
select count(*) as aggregate from `subjects` inner join `student_subject` on `subjects`.`id` = `student_subject`.`subject_id` where `student_subject`.`student_id` = 10 and `subjects`.`deleted_at` is null
$student = Student::withCount('subjects')->find($id);
$subject_count = $student->subjects_count;
I checked the SQL query through laravel debuger it shows as below
select `students`.*, (select count(*) from `subjects` inner join `student_subject` on `subjects`.`id` = `student_subject`.`subject_id` where `students`.`id` = `student_subject`.`student_id` and `subjects`.`deleted_at` is null) as `subjects_count` from `students` where `students`.`id` = '10' limit 1
$student = Student::find($id);
$subject_count = $student->loadCount('subjects')->subjects_count;
I checked the SQL query through laravel debuger it shows as below
select * from `students` where `students`.`id` = '10' limit 1
select `id`, (select count(*) from `subjects` inner join `student_subject` on `subjects`.`id` = `student_subject`.`subject_id` where `students`.`id` = `student_subject`.`student_id` and `subjects`.`deleted_at` is null) as `subjects_count` from `students` where `students`.`id` in (10)
$student = Student::find($id);
$subject_count = DB::table('student_subject')->where('student_id', $student->id)->count();
I checked the SQL query through laravel debuger it shows as below
select * from `students` where `students`.`id` = '10' limit 1
select count(*) as aggregate from `student_subject` where `student_id` = 10
According to the above ways which one is best and why? or if any different best way also there?
Doing relation()->count() is probably faster.
But if all you need is the count, withCount() should be better in terms of memory consumption.

Raw Laravel query as a collection with conditions

I've got a fairly complex query that I'd rather not write in Eloquent so I've written it raw. The only problem is that I need to be able to search/filter through the data using the front-end this query is connected to.
This what I've tried but I'm getting an "Call to a member function get() on null" error.
Here's my code:
$report = collect(DB::connection('mysql2')->select("SELECT
t2.holder,
t2.merchantTransactionId,
t2.bin,
t2.last4Digits,
t3.expDate,
(CASE WHEN t3.expDate < CURDATE() THEN 'Expired'
WHEN t3.expDate > CURDATE() THEN 'Due to expire' END) AS expInfo,
t2.uuid
FROM transactions AS t2
INNER JOIN (
SELECT t1.uuid, t1.holder, t1.bin, t1.last4Digits, LAST_DAY(CONCAT(t1.expiryYear, t1.expiryMonth, '01')) AS expDate
FROM transactions t1
JOIN (SELECT t1.merchant_access
FROM total_control.users,
JSON_TABLE(merchant_access, '$[*]' COLUMNS (
merchant_access VARCHAR(32) PATH '$')
) t1
WHERE users.id = :userId
) AS t2
ON t1.merchantUuid = t2.merchant_access
WHERE t1.paymentType = 'RG'
AND t1.status = 1
) t3
ON t2.uuid = t3.uuid
WHERE t3.expDate BETWEEN DATE_SUB(CURDATE(), INTERVAL 30 DAY) AND DATE_ADD(CURDATE(), INTERVAL 30 DAY)
GROUP BY t2.holder, t2.bin, t2.last4Digits
ORDER BY t2.holder ASC", ['userId' => $request->userId]))
->when($request->search['holder'], function($q) use ($request) {
$q->where('t2.holder', 'LIKE', '%'.$request->search['holder'].'%');
})->get();
return $report;

ORA-01427: Subquery returns more than one row

When I execute the query below, I get the message like this: "ORA-01427: Sub-query returns more than one row"
Define REN_RunDate = '20160219'
Define MOP_ADJ_RunDate = '20160219'
Define RID_RunDate = '20160219'
Define Mbr_Err_RunDate = '20160219'
Define Clm_Err_RunDate = '20160219'
Define EECD_RunDate = '20160219'
select t6.Member_ID, (Select 'Y' from MBR_ERR t7 where t7.Member_ID = t6.Member_ID and t7.Rundate = &Mbr_Err_RunDate ) Mbr_Err,
NVL(Claim_Sent_Amt,0) Sent_Claims, Rejected_Claims,Orphan_Claim_Amt,Claims_Accepted, MOP_Adj_Sent Sent_MOP_Adj,Net_Sent,
(Case
When Net_Sent < 45000 then 0
When Net_Sent > 25000 then 20500
Else
Net_Sent - 45000
End
)Net_Sent_RI,
' ' Spacer,
Total_Paid_Claims CMS_Paid_Claims, MOP_Adjustment CM_MOP_Adj, MOP_Adjusted_Paid_claims CM_Net_Claims, Estimated_RI_Payment CM_RI_Payment
from
(
select NVL(t3.Member_ID,t5.Member_ID)Member_ID, t3.Claim_Sent_Amt, NVL(t4.Reject_Claims_Amt,0) Rejected_Claims, NVL( t8.Orphan_Amt,0) Orphan_Claim_Amt,
(t3.Claim_Sent_Amt - NVL(t4.Reject_Claims_Amt,0) - NVL(t8.Orphan_Amt,0)) Claims_Accepted,
NVL(t2.MOP_Adj_Amt,0) MOP_Adj_Sent ,
( (t3.Claim_Sent_Amt - NVL(t4.Reject_Claims_Amt,0)) - NVL(t2.MOP_Adj_Amt,0) - NVL(t8.Orphan_Amt,0) ) Net_Sent,
t5.Member_ID CMS_Mbr_ID,t5.Total_Paid_Claims,t5.MOP_Adjustment, t5.MOP_Adjusted_Paid_Claims, t5.Estimated_RI_Payment
From
(
Select t1.Member_ID, Sum( t1.Paid_Amount) Claim_Sent_Amt
From RENS t1
where t1.rundate = &REN_RunDate
group by t1.Member_ID
) t3
Left Join MOP_ADJ t2
on (t3.Member_ID = t2.Member_ID and t2.rundate = &MOP_ADJ_RunDate)
Left Join
(select Member_ID, sum(Claim_Total_Paid_Amount) Reject_Claims_Amt from CLAIM_ERR
where Rundate = &Claim_Err_RunDate
and Claim_Total_Paid_Amount != 0
Group by member_ID
)t4
on (t4.Member_ID = t3.Member_ID )
Full Outer Join
(
select distinct Member_ID,Total_Paid_Claims,MOP_Adjustment,MOP_Adjusted_Paid_Claims, Estimated_RI_Payment
from RID
where Rundate = &RID_RunDate
and Estimated_RI_Payment != 0
)t5
On(t5.Member_ID = t3.Member_ID)
Left Outer Join
(
select Member_ID, Sum(Claim_Paid_Amount) Orphan_Amt
From EECD
where RunDate = &EECD_RunDate
group by Member_ID
)t8
On(t8.Member_ID = t3.Member_ID)
)t6
order by Member_ID
You have this expression among the select columns (at the top of your code):
(Select 'Y' from MBR_ERR t7 where t7.Member_ID = t6.Member_ID
and t7.Rundate = &Mbr_Err_RunDate ) Mbr_Err
If you want to select the literal 'Y', then just select 'Y' as Mbr_Err. If you want to select either 'Y' or null, depending on whether the the subquery returns exactly one row or zero rows, then write it that way.
I suspect this subquery (or perhaps another one in your code, used in a similar way) returns more than one row - in which case you will get exactly the error you got.

how to pass select subquery in where clause using laravel

This is my SQl query
select sum(stock.total_in_stock) as total_in_stock
,stock.name
,stock.inventory_id
from (
select i.store_id
,i.model_id
,i. total_in_stock
,i.id as inventory_id
, m.*
from `inventory` as `i`
left join `model_store` as `ms` on `ms`.`store_id` = `i`.`store_id`
left join `model` as `m` on `m`.`id` = `ms`.`model_id`
where `i`.`model_id` = m.id
and `m`.`status` = 1
and `ms`.`status` = 1
and `i`.`created_at` = (
select si.created_at
from inventory AS si
where si.model_id = i.model_id
and si.store_id = i.store_id
and si.status=1
order by si.created_at desc limit 1
)
) as stock
group by stock.model_id
In laravel, it is written as this:
$results1 = DB::table('inventory as i')
->select(DB::raw( 'sum(stock.total_in_stock) as total_in_stock,stock.name,stock.inventory_id FROM ( SELECT i.store_id,i.model_id,i. total_in_stock,i.id as inventory_id, m.* '))
->leftJoin('model_store as ms','ms.store_id','=','i.store_id')
->leftJoin('model as m','m.id','=','ms.model_id')
->where('i.model_id','=', 'm.id')
->where('m.status','=', '1')
->where('ms.status','=', '1')
->where("i.created_at","=",function($query) {
$query->select(DB::raw("si.created_at FROM inventory AS si WHERE si.model_id = i.model_id AND si.store_id = i.store_id AND si.status=1 ORDER BY si.created_at DESC LIMIT 1)) as stock GROUP BY stock.model_id"));
});
It gives me the following error:-
SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ')' at line 1 (SQL: select sum(stock.total_in_stock) as total_in_stock,stock.name,stock.inventory_id FROM ( SELECT i.store_id,i.model_id,i. total_in_stock,i.id as inventory_id, m.* from `inventory` as `i` left join `model_store` as `ms` on `ms`.`store_id` = `i`.`store_id` left join `model` as `m` on `m`.`id` = `ms`.`model_id` where `i`.`model_id` = m.id and `m`.`status` = 1 and `ms`.`status` = 1 and `i`.`created_at` = (select si.created_at FROM inventory AS si WHERE si.model_id = i.model_id AND si.store_id = i.store_id AND si.status=1 ORDER BY si.created_at DESC LIMIT 1 )) as stock GROUP BY stock.model_id))
It takes 2 closing brackets at the end and gives the above error. Please help me writing the above SQL query in laravel.
Answering your question that's in the tile: the subquery where needs fix:
->where("i.created_at", function($query) {
$query->from('inventory as si')
->selectRaw('max(si.created_at)')
->whereRaw('si.model_id = i.model_id AND ...');
});
However, in order to create a subquery in the from clause, you need to pass raw query, so your whole code requires a bit of toSql() and setBindings(...), which is cumbersome.
So to get the answer to your problem, better describe the problem itself instead.

How to write join select statements in code igniter

SELECT
q1.user_id,q2.count,q2.total,q1.choice
FROM
(
SELECT
"table1"."user_id" as user_id,"table2"."choice" as choice
FROM
"table1", "table2"
WHERE
"table1"."user_id" = table2.ref_id
AND
"table1"."active" = 1
)q1
LEFT OUTER JOIN
(
SELECT
count(table1.*) as count, SUM(table2.add1) as total,table1.user_id as user_id
FROM
"table1", "table2"
WHERE
"table1"."type" = 1
AND
table1"."some_id" IN(SELECT user_id FROM "table2", "table3" WHERE "table3"."user_id" = table3.refid)
group by
"table2"."user_id"
)q2
ON
q2.user_id=q1.user_id
ORDER BY
q2.count ASC
I have one query like this. It is working fine in db.But don't know how to write this in codeigniter using subqueries. Or is there any other way I could get the same results?
you can use $this->db->query() for this..
doc here
$sql='SELECT
q1.user_id,q2.count,q2.total,q1.choice
FROM
(
SELECT
"table1"."user_id" as user_id,"table2"."choice" as choice
FROM
"table1", "table2"
WHERE
"table1"."user_id" = table2.ref_id
AND
"table1"."active" = 1
)q1
LEFT OUTER JOIN
(
SELECT
count(table1.*) as count, SUM(table2.add1) as total,table1.user_id as user_id
FROM
"table1", "table2"
WHERE
"table1"."type" = 1
AND
table1"."some_id" IN(SELECT user_id FROM "table2", "table3" WHERE "table3"."user_id" = table3.refid)
group by
"table2"."user_id"
)q2
ON
q2.user_id=q1.user_id
ORDER BY
q2.count ASC';
$result=$this->db->query($sql);

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