How to stop script when "if" is false - bash

Question

I'm learning BASH scripting, and I've got a problem. I wrote a generator, that checks if there is script with same name as given and if not it makes one, makes it executable and gives it proper shebang. But it doesn't work. I wanted it to exit when there is already one script with that name. Can you tell me what I'm doing wrong?
#!/bin/bash
clear
echo "Name the script"
read name
echo "What shell? (bash/sh)"
read type
if [ -e ./$name ]
then
echo "You already have that script"
read
exit
else
touch $name
chmod 755 $name
fi
case $type in
"bash") echo '#!/bin/bash' > $name ;;
"sh") echo '#!/bin/bash' > $name ;;
*) echo "I don't know what do you want" ;;
esac
vim $name

Answer 1

There is an extra read which is holding you up:
if [[ -e ./$name ]]
then
echo "'./$name' already exists" # <<<< always report the name
# read <<<< This is the line which is causing problems
exit 1 # <<<< indicate there was an error
else
touch "$name"
chmod 755 "$name"
fi
Quote filenames incase they contain embedded whitespace (you don't need them around variables if you use [[ ]].
Also note that the #! line for sh is wrong (you are using bash for both)
Edit:
If you have /etc/shells on your system, this is a good exercise in using select menu. Try this:
#!/bin/bash
read -p "Name the script: " name
if [[ -e ./$name ]]
then
echo "'./$name' already exists" # <<<< always report the name
# read <<<< This is the line which is causing problems
exit 1 # <<<< indicate there was an error
else
touch "$name"
chmod 755 "$name"
fi
declare -a shells
i=0
while read shell
do
if [[ $shell != \#* && $shell != "" ]]
then
shells[i++]="$shell"
fi
done < /etc/shells
PS3='Please select the shell: '
select type in "${shells[#]}" QUIT
do
echo "You selected $type"
if [[ $type == QUIT ]]
then
exit 2
fi
break
done
echo "#!$type" > "$name"
vim $name
You might also consider using $EDITOR rather than hard-coding vim.