Swap part of a string in Ruby - ruby

What's the easiest way in Ruby to interchange a part of a string with another value. Let's say that I have an email, and I want to check it on two domains, but I don't know which one I'll get as an input. The app I'm building should work with #gmail.com and #googlemail.com domains.
Example:
swap_string 'user#gmail.com' # >>user#googlemail.com
swap_string 'user#googlemail.com' # >>user#gmail.com

If you're looking to substitute a part of a string with something else, gsub works quite well.
Link to Gsub docs
It lets you match a part of a string with regex, and then substitute just that part with another string. Naturally, in place of regex, you can just use a specific string.
Example:
"user#gmail.com".gsub(/#gmail/, '#googlemail')
is equal to
user#googlemail.com
In my example I used #gmail and #googlemail instead of just gmail and googlemail. The reason for this is to make sure it's not an account with gmail in the name. It's unlikely, but could happen.
Don't match the .com either, as that can change depending on where the user's email is.

Assuming googlemail.com and gmail.com are the only two possibilities, you can use sub to replace a pattern with given replacement:
def swap_string(str)
if str =~ /gmail.com$/
str.sub("gmail.com","googlemail.com")
else
str.sub("googlemail.com","gmail.com")
end
end
swap_string 'user#gmail.com'
# => "user#googlemail.com"
swap_string 'user#googlemail.com'
# => "user#gmail.com"

You can try with Ruby gsub :
eg:
"user#gmail.com".gsub("gmail.com","googlemail.com");
As per your need of passing a string parameter in a function this should do:
def swap_mails(str)
if str =~ /gmail.com$/
str.sub('gmail.com','googlemail.com');
else
str.sub('googlemail.com','gmail.com');
end
end
swap_mails "vgmail#gmail.com" //vgmail#googlemail.com
swap_mails "vgmail#googlemail.com" ////vgmail#gmail.com

My addition :
def swap_domain str
str[/.+#/] + [ 'gmail.com', 'googlemail.com' ].detect do |d|
d != str.split('#')[1]
end
end
swap_domain 'user#gmail.com'
#=> user#googlemail.com
swap_domain 'user#googlemail.com'
#=> user#gmail.com
And this is bad code, imo.

String has a neat trick up it's sleeve in the form of String#[]:
def swap_string(string, lookups = {})
string.tap do |s|
lookups.each { |find, replace| s[find] = replace and break if s[find] }
end
end
# Example Usage
lookups = {"googlemail.com"=>"gmail.com", "gmail.com"=>"googlemail.com"}
swap_string("user#gmail.com", lookups) # => user#googlemail.com
swap_string("user#googlemail.com", lookups) # => user#gmail.com
Allowing lookups to be passed to your method makes it more reusable but you could just as easily have that hash inside of the method itself.

Related

How to split a string which contains multiple forward slashes

I have a string as given below,
./component/unit
and need to split to get result as component/unit which I will use this as key for inserting hash.
I tried with .split(/.\//).last but its giving result as unit only not getting component/unit.
I think, this should help you:
string = './component/unit'
string.split('./')
#=> ["", "component/unit"]
string.split('./').last
#=> "component/unit"
Your regex was almost fine :
split(/\.\//)
You need to escape both . (any character) and / (regex delimiter).
As an alternative, you could just remove the first './' substring :
'./component/unit'.sub('./','')
#=> "component/unit"
All the other answers are fine, but I think you are not really dealing with a String here but with a URI or Pathname, so I would advise you to use these classes if you can. If so, please adjust the title, as it is not about do-it-yourself-regexes, but about proper use of the available libraries.
Link to the ruby doc:
https://docs.ruby-lang.org/en/2.1.0/URI.html
and
https://ruby-doc.org/stdlib-2.1.0/libdoc/pathname/rdoc/Pathname.html
An example with Pathname is:
require 'pathname'
pathname = Pathname.new('./component/unit')
puts pathname.cleanpath # => "component/unit"
# pathname.to_s # => "component/unit"
Whether this is a good idea (and/or using URI would be cool too) also depends on what your real problem is, i.e. what you want to do with the extracted String. As stated, I doubt a bit that you are really intested in Strings.
Using a positive lookbehind, you could do use regex:
reg = /(?<=\.\/)[\w+\/]+\w+\z/
Demo
str = './component'
str2 = './component/unit'
str3 = './component/unit/ruby'
str4 = './component/unit/ruby/regex'
[str, str2, str3, str4].each { |s| puts s[reg] }
#component
#component/unit
#component/unit/ruby
#component/unit/ruby/regex

How to extract part of the string which comes after given substring?

For example I have url string like:
https://abc.s3-something.amazonaws.com/subfolder/1234/5.html?X-Amz-Credential=abcd12bhhh34-1%2Fs3%2Faws4_request&X-Amz-Date=2016&X-Amz-Expires=3&X-Amz-SignedHeaders=host&X-Amz-Signature=abcd34hhhhbfbbf888ksdskj
From this string I need to extract number 1234 which comes after subfolder/. I tried with gsub but no luck. Any help would be appreciated.
Suppose your url is saved in a variable called url.
Then the following should return 1234
url.match(/subfolder\/(\d*)/)[1]
Explanation:
url.match(/ # call the match function which takes a regex
subfolder\/ # search for the first appearance of the string 'subfolder/'
# note: we must escape the `/` so we don't end the regex early
(\d*) # match any number of digits in a capture group,
/)[1] # close the regex and return the first capture group
lwassink has the right idea, but it can be done more simply. If subfolder is always the same:
url = "https://abc.s3-something.amazonaws.com/subfolder/1234/5.html?X-Amz-Credential=abcd12bhhh34-1%2Fs3%2Faws4_request&X-Amz-Date=2016&X-Amz-Expires=3&X-Amz-SignedHeaders=host&X-Amz-Signature=abcd34hhhhbfbbf888ksdskj"
url[/subfolder\/\K\d+/]
# => "1234"
The \K discards the matched text up to that point, so only "1234" is returned.
If you want to get the number after any subfolder, and the domain name is always the same, you might do this instead:
url[%r{amazonaws\.com/[^/]+/\K\d+}]
# => "1234"
s.split('/')[4]
Add a .to_i at the end if you like.
Or, to key it on a substring like you asked for...
a = s.split '/'
a[a.find_index('subfolder') + 1]
Or, to do it as a one-liner I suppose you could:
s.split('/').tap { |a| #i = 1 + a.find_index('subfolder')}[#i]
Or, since I am a damaged individual, I would actually write that:
s.split('/').tap { |a| #i = 1 + (a.find_index 'subfolder')}[#i]
url = 'http://abc/xyz'
index= url.index('/abc/')
url[index+5..length_of_string_you_want_to_extract]
Hope, that helps!

Optimising ruby regexp -- lots of match groups

I'm working on a ruby baser lexer. To improve performance, I joined up all tokens' regexps into one big regexp with match group names. The resulting regexp looks like:
/\A(?<__anonymous_-1038694222803470993>(?-mix:\n+))|\A(?<__anonymous_-1394418499721420065>(?-mix:\/\/[\A\n]*))|\A(?<__anonymous_3077187815313752157>(?-mix:include\s+"[\A"]+"))|\A(?<LET>(?-mix:let\s))|\A(?<IN>(?-mix:in\s))|\A(?<CLASS>(?-mix:class\s))|\A(?<DEF>(?-mix:def\s))|\A(?<DEFM>(?-mix:defm\s))|\A(?<MULTICLASS>(?-mix:multiclass\s))|\A(?<FUNCNAME>(?-mix:![a-zA-Z_][a-zA-Z0-9_]*))|\A(?<ID>(?-mix:[a-zA-Z_][a-zA-Z0-9_]*))|\A(?<STRING>(?-mix:"[\A"]*"))|\A(?<NUMBER>(?-mix:[0-9]+))/
I'm matching it to my string producing a MatchData where exactly one token is parsed:
bigregex =~ "\n ... garbage"
puts $~.inspect
Which outputs
#<MatchData
"\n"
__anonymous_-1038694222803470993:"\n"
__anonymous_-1394418499721420065:nil
__anonymous_3077187815313752157:nil
LET:nil
IN:nil
CLASS:nil
DEF:nil
DEFM:nil
MULTICLASS:nil
FUNCNAME:nil
ID:nil
STRING:nil
NUMBER:nil>
So, the regex actually matched the "\n" part. Now, I need to figure the match group where it belongs (it's clearly visible from #inspect output that it's _anonymous-1038694222803470993, but I need to get it programmatically).
I could not find any option other than iterating over #names:
m.names.each do |n|
if m[n]
type = n.to_sym
resolved_type = (n.start_with?('__anonymous_') ? nil : type)
val = m[n]
break
end
end
which verifies that the match group did have a match.
The problem here is that it's slow (I spend about 10% of time in the loop; also 8% grabbing the #input[#pos..-1] to make sure that \A works as expected to match start of string (I do not discard input, just shift the #pos in it).
You can check the full code at GH repo.
Any ideas on how to make it at least a bit faster? Is there any option to figure the "successful" match group easier?
You can do this using the regexp methods .captures() and .names():
matching_string = "\n ...garbage" # or whatever this really is in your code
#input = matching_string.match bigregex # bigregex = your regex
arr = #input.captures
arr.each_with_index do |value, index|
if not value.nil?
the_name_you_want = #input.names[index]
end
end
Or if you expect multiple successful values, you could do:
success_names_arr = []
success_names_arr.push(#input.names[index]) #within the above loop
Pretty similar to your original idea, but if you're looking for efficiency .captures() method should help with that.
I may have misunderstood this completely but but I'm assuming that all but one token is not nil and that's the one your after?
If so then, depending on the flavour of regex you're using, you could use a negative lookahead to check for a non-nil value
([^\n:]+:(?!nil)[^\n\>]+)
This will match the whole token ie NAME:value.

Regular expressions with callback based upon match

I have a function that takes an input string and then runs the string through several regular expressions until it finds a match. Once a match is found, I return an output that is a function of the original string and the match. So in ruby:
str = "my very long original string ... millions of characters"
case str
when regex1
do_something1(str,$1)
when regex2
do_something2(str,$1)
when regex3
do_something3(str,$1)
...
when regex100000
do_something100000(str,$1)
else
do_something_else(str)
end
Now, is Ruby actually optimizing this switch loop so that str only gets traversed once? Assuming it isn't, then this functionality could be performed much more efficiently with one big long regular expression that had embedded callbacks. Something like this:
/(?<callback:do_something1>regex1)|
(?<callback:do_something2>regex2)|
(?<callback:do_something3>regex3)|
...
(?<callback:do_something100000>regex100000)/
Is there any technology that does this?
If Ruby 1.9, and if you use named groups in your regular expressions, then you can combine all of the regular expressions into one with a bit of trickery. Here's the class that does the heavy lifting:
class BigPatternMatcher
def initialize(patterns_and_functions, no_match_function)
#regex = make_big_regex(patterns_and_functions)
#no_match_function = no_match_function
end
def match(s, context)
match = #regex.match(s)
context.send(function_name(match), match)
end
private
FUNC_GROUP_PREFIX = "func_"
FUNC_GROUP_REGEX = /^#{FUNC_GROUP_PREFIX}(.*)$/
def function_name(match)
if match
match.names.grep(FUNC_GROUP_REGEX).find do |name|
match[name]
end[FUNC_GROUP_REGEX, 1]
else
#no_match_function
end
end
def make_big_regex(patterns_and_functions)
patterns = patterns_and_functions.map do |pattern, function|
/(?<#{FUNC_GROUP_PREFIX}#{function}>#{pattern.source})/
end
Regexp.union(patterns)
end
end
We'll come back to how this works. To use it, you'll need a list of regular expressions and the name of the function that should be invoked for each one. Make sure to use named groups only:
PATTERNS_AND_FUNCTIONS = [
[/ABC(?<value>\d+)/, :foo],
[/DEF(?<value>\d+)/, :bar],
]
And the functions, including one that gets called when there's no match:
def foo(match)
p ["foo", match[:value]]
end
def bar(match)
p ["bar", match[:value]]
end
def default(match)
p ["default"]
end
And, finally, here's how it's used. BigPatternMatcher#match takes the string to match, and the object on which the function should be called:
matcher = BigPatternMatcher.new(PATTERNS_AND_FUNCTIONS, :default)
matcher.match('blah ABC1 blah', self) # => ["foo", "1"
matcher.match('blah DEF2 blah', self) # => ["bar", "2"]
matcher.match('blah blah', self) # => ["default"]
See below the fold for the trickery that makes it work.
BigPatternMatcher#make_big_regex combines all of the regular expressions into one, each surrounded in parentheses and separated by |, e.g.
/(ABC(?<value>\\d+))|(DEF(?<value>\\d+))/
That isn't enough, though. We need some way, when one of the sub-expression matches, to identify which one matched, and therefore which function to call. To do that, we'll make each sub-expression its own named group, with the name based on the function that should be called:
/(?<func_foo>ABC(?<value>\\d+))|(?<func_bar>DEF(?<value>\\d+))/
Now, let's see how we get from a match to calling a function. Given the string:
"blah ABC1 blah"
Then the match group is:
#<MatchData "ABC1" func_foo:"ABC1" value:"1" func_bar:nil value:nil>
To figure out which function to call, we just have to find the match with a name that starts with "func_" and which has a non-nil value. The part of the group's name after "func_" names the function to call.
Measuring the performance of this against the straightforward technique in your question is an exercise for the reader.

How to replace the last occurrence of a substring in ruby?

I want to replace the last occurrence of a substring in Ruby. What's the easiest way?
For example, in abc123abc123, I want to replace the last abc to ABC. How do I do that?
How about
new_str = old_str.reverse.sub(pattern.reverse, replacement.reverse).reverse
For instance:
irb(main):001:0> old_str = "abc123abc123"
=> "abc123abc123"
irb(main):002:0> pattern="abc"
=> "abc"
irb(main):003:0> replacement="ABC"
=> "ABC"
irb(main):004:0> new_str = old_str.reverse.sub(pattern.reverse, replacement.reverse).reverse
=> "abc123ABC123"
"abc123abc123".gsub(/(.*(abc.*)*)(abc)(.*)/, '\1ABC\4')
#=> "abc123ABC123"
But probably there is a better way...
Edit:
...which Chris kindly provided in the comment below.
So, as * is a greedy operator, the following is enough:
"abc123abc123".gsub(/(.*)(abc)(.*)/, '\1ABC\3')
#=> "abc123ABC123"
Edit2:
There is also a solution which neatly illustrates parallel array assignment in Ruby:
*a, b = "abc123abc123".split('abc', -1)
a.join('abc')+'ABC'+b
#=> "abc123ABC123"
Since Ruby 2.0 we can use \K which removes any text matched before it from the returned match. Combine with a greedy operator and you get this:
'abc123abc123'.sub(/.*\Kabc/, 'ABC')
#=> "abc123ABC123"
This is about 1.4 times faster than using capturing groups as Hirurg103 suggested, but that speed comes at the cost of lowering readability by using a lesser-known pattern.
more info on \K: https://www.regular-expressions.info/keep.html
Here's another possible solution:
>> s = "abc123abc123"
=> "abc123abc123"
>> s[s.rindex('abc')...(s.rindex('abc') + 'abc'.length)] = "ABC"
=> "ABC"
>> s
=> "abc123ABC123"
When searching in huge streams of data, using reverse will definitively* lead to performance issues. I use string.rpartition*:
sub_or_pattern = "!"
replacement = "?"
string = "hello!hello!hello"
array_of_pieces = string.rpartition sub_or_pattern
( array_of_pieces[(array_of_pieces.find_index sub_or_pattern)] = replacement ) rescue nil
p array_of_pieces.join
# "hello!hello?hello"
The same code must work with a string with no occurrences of sub_or_pattern:
string = "hello_hello_hello"
# ...
# "hello_hello_hello"
*rpartition uses rb_str_subseq() internally. I didn't check if that function returns a copy of the string, but I think it preserves the chunk of memory used by that part of the string. reverse uses rb_enc_cr_str_copy_for_substr(), which suggests that copies are done all the time -- although maybe in the future a smarter String class may be implemented (having a flag reversed set to true, and having all of its functions operating backwards when that is set), as of now, it is inefficient.
Moreover, Regex patterns can't be simply reversed. The question only asks for replacing the last occurrence of a sub-string, so, that's OK, but readers in the need of something more robust won't benefit from the most voted answer (as of this writing)
You can achieve this with String#sub and greedy regexp .* like this:
'abc123abc123'.sub(/(.*)abc/, '\1ABC')
simple and efficient:
s = "abc123abc123abc"
p = "123"
s.slice!(s.rindex(p), p.size)
s == "abc123abcabc"
string = "abc123abc123"
pattern = /abc/
replacement = "ABC"
matches = string.scan(pattern).length
index = 0
string.gsub(pattern) do |match|
index += 1
index == matches ? replacement : match
end
#=> abc123ABC123
I've used this handy helper method quite a bit:
def gsub_last(str, source, target)
return str unless str.include?(source)
top, middle, bottom = str.rpartition(source)
"#{top}#{target}#{bottom}"
end
If you want to make it more Rails-y, extend it on the String class itself:
class String
def gsub_last(source, target)
return self unless self.include?(source)
top, middle, bottom = self.rpartition(source)
"#{top}#{target}#{bottom}"
end
end
Then you can just call it directly on any String instance, eg "fooBAR123BAR".gsub_last("BAR", "FOO") == "fooBAR123FOO"
.gsub /abc(?=[^abc]*$)/, 'ABC'
Matches a "abc" and then asserts ((?=) is positive lookahead) that no other characters up to the end of the string are "abc".

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