Correct usage of bc in a shell script? - bash

Question

I'm simply trying to multiplying some float variables using bc:
#!/bin/bash
a=2.77 | bc
b=2.0 | bc
for cc in $(seq 0. 0.001 0.02)
do
c=${cc} | bc
d=$((a * b * c)) | bc
echo "$d" | bc
done
And this does not give me an output. I know it's a silly one but I've tried a number of combinations of bc (piping it in different places etc.) to no avail.
Any help would be greatly appreciated!

Answer 1

bc is a command-line utility, not some obscure part of shell syntax. The utility reads mathematical expressions from its standard input and prints values to its standard output. Since it is not part of the shell, it has no access to shell variables.
The shell pipe operator (|) connects the standard output of one shell command to the standard input of another shell command. For example, you could send an expression to bc by using the echo utility on the left-hand side of a pipe:
echo 2+2 | bc
This will print 4, since there is no more here than meets the eye.
So I suppose you wanted to do this:
a=2.77
b=2.0
for c in $(seq 0. 0.001 0.02); do
echo "$a * $b * $c" | bc
done
Note: The expansion of the shell variables is happening when the shell processes the argument to echo, as you could verify by leaving off the bc:
a=2.77
b=2.0
for c in $(seq 0. 0.001 0.02); do
echo -n "$a * $b * $c" =
echo "$a * $b * $c" | bc
done
So bc just sees numbers.
If you wanted to save the output of bc in a variable instead of sending it to standard output (i.e. the console), you could do so with normal command substitution syntax:
a=2.77
b=2.0
for c in $(seq 0. 0.001 0.02); do
d=$(echo "$a * $b * $c" | bc)
echo "$d"
done

Answer 2

To multiply two numbers directly, you would do something like:
echo 2.77 * 2.0 | bc
It will produce a result to 2 places - the largest number of places of the factors. To get it to a larger number of places, like 5, would require:
echo "scale = 5; 2.77 * 2.0" | bc
This becomes more important if you're multiplying numerals that each have a large number of decimal places.
As stated in other replies, bc is not a part of bash, but is a command run by bash. So, you're actually sending input directly to the command - which is why you need echo. If you put it in a file (named, say, "a") then you'd run "bc < a". Or, you can put the input directly in the shell script and have a command run the designated segment as its input; like this:
cat <<EOF
Input
EOF
... with qualifiers (e.g. you need to write "" as "\", for instance).
Control flow constructs may be more problematic to run in BC off the command line. I tried the following
echo "scale = 6; a = 2.77; b = 2.0; define f(cc) { auto c, d; c = cc; d = a*b*c; return d; } f(0); f(0.001); f(0.02)" | bc
and got a syntax error (I have a version of GNU-BC installed). On the other hand, it will run fine with C-BC
echo "scale = 6; a = 2.77; b = 2.0; define f(cc) { auto c, d; c = cc; d = a * b * c; return d; } f(0); f(0.001); f(0.02)" | cbc
and give you the expected result - matching the example you cited ... listing numbers to 6 places.
C-BC is here (it's operationally a large superset of GNU-BC and UNIX BC, but not 100% POSIX compliant):
https://github.com/RockBrentwood/CBC
The syntax is closer to C, so you could also write it as
echo "scale = 6, a = 2.77, b = 2.0; define f(cc) { return a * b * cc; } f(0); f(0.001); f(0.02)" | cbc
to get the same result. So, as another example, this
echo "scale = 100; for (x = 0, y = 1; x < 50; y *= ++x); y" | cbc
will give you 50 factorial. However, comma-expressions, like (x = 0, y = 1) are not mandated for bc by POSIX, so it will not run in other bc dialects, like GNU BC.