Is there a way in Spring data to dynamically form the where clause?
What I want to do is have a method (which is like the findBy / get method) which runs a WHERE and AND using the mentioned properties which are NOT NULL.
For example,
Consider the object Person [firstName, lastName, age, gender]
Our method looks something like this
findBy_IfNotNullFirstName_AndIfNotNullLastName_AndIfNotNullAge_AndIfNotNullGender(String firstName, String lastName, Integer age, String gender)
Thanks.
A simpler option is to test if the parameter is null right in the JPQL query:
Exemple from my project:
#Query("select m from MessageEntity m " +
"join fetch m.demandeAnalyseEntities d " +
"where (:patientId is null or d.noPtn= :patientId) " +
" and " +
" ( :labNbr is null or d.noLab= :labNbr) " +
" and " +
" ( :reqDate is null or d.dteReq= :reqDate) " +
" and " +
" ( :reqNum is null or d.noReq= :reqNum) "
)
List<MessageEntity> findMessagesWithDemandesOnly(#Param("patientId") Long pid,
#Param("labNbr") Integer labNo,
#Param("reqDate") String reqDate,
#Param("reqNum") Integer reqNum,
Pageable pageable);
Take a look at JPA Specification and Predicate, and Even better QueryDSL, there both supported by spring data repositories.
This article provide an example:
http://spring.io/blog/2011/04/26/advanced-spring-data-jpa-specifications-and-querydsl/
Another solution: You can extend your JPA repo interface using custom fragment interfaces.
Define your custom methods on a new interface
public interface PersonFragRepository {
List<User> findPersonByWhatever(
String firstName, String lastName, String age, String gender);
}
Provide the implementation
public class PersonFragRepositoryImpl implements PersonFragRepository {
#PersistenceContext
private EntityManager entityManager;
#Override
List<User> findPersonByWhatever(
String firstName, String lastName, String age, String gender) {
...
}
}
Extends your JPA interface
public interface PersonRepository
extends JpaRepository<Person, Integer>, PersonFragRepository
I want to fetch actions list in user class by username with this query but its not working
#Repository
public interface IUserRepository extends CouchbaseRepository<User,Long> {
#Query("SELECT actions from #{#n1ql.bucket} where #{#n1ql.filter} and userName = $1 ")
List<Action> getActionsByUserName(String userName);
where am ı doing wrong?
__id and __cas must be projected. They are included in n1ql.selectEntity
#Query("#{#n1ql.selectEntity} where #{#n1ql.filter} and userName = $1 ")
Or you can project them yourself :
#Query("SELECT actions, meta().id as __id, meta().cas as __cas from #{#n1ql.bucket} where#{#n1ql.selectEntity} where where #{#n1ql.filter} and userName = $1 ")
I have a Springboot app which uses contains 2 Entities, User and Friend Request. The user Entity looks like this:
public class User{
#Id
private BigInteger id;
private String firstName;
private String lastName;
private String email;
private String password;
}
while the FriendRequest Object looks like this:
public class FriendRequest{
#Id
private BigInteger id;
private User sender;
private FriendRequestStatus friendRequestStatus;
private User recipient;
}
The friend request class has 4 properties:
The ID
the sender of a request which is a user
the recipient of a request which is also user
The friendRequestStatus - which can be Pending (if the request has not been accepted), Accepted (if the friend request has been accepted), or Declined (if the request has been declined).
instead of me making a friends table, i want to use the FriendRequest table to get all the friends of a particular user - it works by getting all friends request where a Specific User is a send or receiver and friendRequest is Accepted. Then going further to select the Sender as a friend if the recipient is the user whos friends you are looking for and selecting the recipient if the Sender was the user whos friends you are looking for. At the end i want to get a List.
My problem is i dont know how to achieve this in MongoDB for springboot , when using Postgre this was the query i ran, and it worked perfectly:
#Query(value = "SELECT * \n" +
"FROM ( \n" +
"SELECT DISTINCT CASE sender WHEN 1 THEN recipient ELSE sender END AS friend_id \n" +
"FROM friendrequest WHERE 1 IN (recipient, sender) \n" +
"AND friendrequeststatus = 'ACCEPTED' \n" +
") f \n" +
"LEFT JOIN users u\n" +
"ON f.friend_id = u.id\n" +
"ORDER BY friend_id \n-- #pageable\n"
,nativeQuery = true)
Page<User> getFriends(Pageable pageable);
but how to replicate it in MongoDB for Springboot is a big problem
I want to assign the result of a query to a DTO object. The DTO looks like this:
#Getter
#Setter
#NoArgsConstructor
public class Metric {
private int share;
private int shareholder;
public Metric(int share, int shareholder) {
this.share = share;
this.shareholder = shareholder;
}
}
And the query looks like the following:
#RepositoryRestResource(collectionResourceRel = "shareholders", path = "shareholders")
public interface ShareholderRepository extends PagingAndSortingRepository<Shareholder, Integer> {
#Query(value = "SELECT new com.company.shareholders.sh.Metric(SUM(s.no_of_shares),COUNT(*)) FROM shareholders s WHERE s.attend=true")
Metric getMetrics();
}
However, this didn't work, as I got the following exception:
Caused by:org.hibernate.QueryException: could not resolve property: no_of_shares of:com.company.shareholders.sh.Shareholder[SELECT new com.company.shareholders.sh.Metric(SUM(s.no_of_shares),COUNT(*)) FROM com.company.shareholders.sh.Shareholder s WHERE s.attend=true]
In my project I've used projections to this like shown below:
#Repository
public interface PeopleRepository extends JpaRepository<People, Long> {
#Query(value = "SELECT p.name AS name, COUNT(dp.people_id) AS count " +
"FROM people p INNER JOIN dream_people dp " +
"ON p.id = dp.people_id " +
"WHERE p.user_id = :userId " +
"GROUP BY dp.people_id " +
"ORDER BY p.name", nativeQuery = true)
List<PeopleDTO> findByPeopleAndCountByUserId(#Param("userId") Long userId);
#Query(value = "SELECT p.name AS name, COUNT(dp.people_id) AS count " +
"FROM people p INNER JOIN dream_people dp " +
"ON p.id = dp.people_id " +
"WHERE p.user_id = :userId " +
"GROUP BY dp.people_id " +
"ORDER BY p.name", nativeQuery = true)
Page<PeopleDTO> findByPeopleAndCountByUserId(#Param("userId") Long userId, Pageable pageable);
}
The interface to which the result is projected:
public interface PeopleDTO {
String getName();
Long getCount();
}
The fields from the projected interface must match the fields in this entity. Otherwise field mapping might break.
Also if you use SELECT table.column notation always define aliases matching names from entity as shown in example.
In your case change #Query like shown below:
#Query(value = "SELECT new " +
"SUM(s.no_of_shares) AS sum,COUNT(*) AS count FROM " +
"shareholders s WHERE s.attend=true", nativeQuery = true)
MetricDTO getMetrics();
And create interface MetricDTO like shown below:
public interface MetricDTO {
Integer getSum();
Long getCount();
}
Also make sure the return type of getSum() and getCount() is correct this may vary based not database.
First, you can have a look at the Spring Data JPA documentation, you can find some help at this section : Class-based Projections (DTOs).
There is also a paragraph titled Avoid boilerplate code for projection DTOs, where they advise you to use Lombok's #Value annotation, to produce an immutable DTO. This is similar to Lombok's #Data annotation, but immutable.
If you apply it to your example, the source will look like :
#Value
public class MetricDto {
private int share;
private int shareholder;
}
Then, as your query is a NativeQuery, specifiy it in your Spring Data Repository.
You can find help in the documentation : Native Queries.
You will need something like :
#Query(value = "SELECT new
com.company.shareholders.sh.MetricDto(SUM(s.no_of_shares),COUNT(*)) FROM
shareholders s WHERE s.attend=true", nativeQuery = true)
MetricDto getMetrics();
Query query = sessionFactory.getCurrentSession()
.createNativeQuery(stringQuery).unwrap(org.hibernate.query.Query.class);
((NativeQueryImpl) query).setResultTransformer(new AliasToBeanResultTransformer(DtoClass.class));
You are writing a mixed query of native and jpql; no_of_shares is your column name in the database, but jpa is expecting you to provide not native syntax so try to replace no_of_shares with the corresponding field in your entity class. Or just add nativeQuery = true to make jpa understand it's a native query.
I'm using Spring Data JPA, and when I use #Query to to define a query WITHOUT Pageable, it works:
public interface UrnMappingRepository extends JpaRepository<UrnMapping, Long> {
#Query(value = "select * from internal_uddi where urn like %?1% or contact like %?1%",
nativeQuery = true)
List<UrnMapping> fullTextSearch(String text);
}
But if I add the second param Pageable, the #Query will NOT work, and Spring will parse the method's name, then throw the exception No property full found. Is this a bug?
public interface UrnMappingRepository extends JpaRepository<UrnMapping, Long> {
#Query(value = "select * from internal_uddi where urn like %?1% or contact like %?1%",
nativeQuery = true)
Page<UrnMapping> fullTextSearch(String text, Pageable pageable);
}
You can use pagination with a native query. It is documented here: Spring Data JPA - Reference Documentation
"You can however use native queries for pagination by specifying the count query yourself:
Example 59. Declare native count queries for pagination at the query method using #Query"
public interface UserRepository extends JpaRepository<User, Long> {
#Query(value = "SELECT * FROM USERS WHERE LASTNAME = ?1",
countQuery = "SELECT count(*) FROM USERS WHERE LASTNAME = ?1",
nativeQuery = true)
Page<User> findByLastname(String lastname, Pageable pageable);
}
A similar question was asked on the Spring forums, where it was pointed out that to apply pagination, a second subquery must be derived. Because the subquery is referring to the same fields, you need to ensure that your query uses aliases for the entities/tables it refers to. This means that where you wrote:
select * from internal_uddi where urn like
You should instead have:
select * from internal_uddi iu where iu.urn like ...
Considering that the UrnMapping class is mapped to the internal_uddi table, I would suggest this:
#Repository
public interface UrnMappingRepository extends JpaRepository<UrnMapping, Long> {
#Query(value = "select iu from UrnMapping iu where iu.urn like %:text% or iu.contact like %:text%")
Page<UrnMapping> fullTextSearch(#Param("text") String text, Pageable pageable);
}
Please note that you might have to turn off native queries with dynamic requests.
With #Query , we can use pagination as well where you need to pass object of Pageable class at end of JPA method
For example:
Pageable pageableRequest = new PageRequest(page, size, Sort.Direction.DESC, rollNo);
Where,
page = index of page (index start from zero)
size = No. of records
Sort.Direction = Sorting as per rollNo
rollNo = Field in User class
UserRepository repo
repo.findByFirstname("John", pageableRequest);
public interface UserRepository extends JpaRepository<User, Long> {
#Query(value = "SELECT * FROM USER WHERE FIRSTNAME = :firstname)
Page<User> findByLastname(#Param("firstname") String firstname, Pageable pageable);
}
Please reference :Spring Data JPA #Query, if you are using Spring Data JPA version 2.0.4 and later. Sample like below:
#Query(value = "SELECT u FROM User u ORDER BY id")
Page<User> findAllUsersWithPagination(Pageable pageable);
Declare native count queries for pagination at the query method by using #Query
public interface UserRepository extends JpaRepository<User, Long> {
#Query(value = "SELECT * FROM USERS WHERE LASTNAME = ?1",
countQuery = "SELECT count(*) FROM USERS WHERE LASTNAME = ?1",
nativeQuery = true)
Page<User> findByLastname(String lastname, Pageable pageable);
}
Hope this helps
https://docs.spring.io/spring-data/jpa/docs/current/reference/html/#jpa.query-methods
Rewrite your query to:
select iu from internal_uddi iu where iu.urn....
description: http://forum.spring.io/forum/spring-projects/data/126415-is-it-possible-to-use-query-and-pageable?p=611398#post611398
I found it works different among different jpa versions, for debug, you'd better add this configurations to show generated sql, it will save your time a lot !
spring.jpa.show-sql=true
spring.jpa.properties.hibernate.format_sql=true
for spring boot 2.1.6.RELEASE, it works good!
Sort sort = new Sort(Sort.Direction.DESC, "column_name");
int pageNumber = 3, pageSize = 5;
Pageable pageable = PageRequest.of(pageNumber - 1, pageSize, sort);
#Query(value = "select * from integrity_score_view " +
"where (?1 is null or data_hour >= ?1 ) " +
"and (?2 is null or data_hour <= ?2 ) " +
"and (?3 is null or ?3 = '' or park_no = ?3 ) " +
"group by park_name, data_hour ",
countQuery = "select count(*) from integrity_score_view " +
"where (?1 is null or data_hour >= ?1 ) " +
"and (?2 is null or data_hour <= ?2 ) " +
"and (?3 is null or ?3 = '' or park_no = ?3 ) " +
"group by park_name, data_hour",
nativeQuery = true
)
Page<IntegrityScoreView> queryParkView(Date from, Date to, String parkNo, Pageable pageable);
you DO NOT write order by and limit, it generates the right sql
I had the same issue - without Pageable method works fine.
When added as method parameter - doesn't work.
After playing with DB console and native query support came up to decision that method works like it should. However, only for upper case letters.
Logic of my application was that all names of entity starts from upper case letters.
Playing a little bit with it. And discover that IgnoreCase at method name do the "magic" and here is working solution:
public interface EmployeeRepository
extends PagingAndSortingRepository<Employee, Integer> {
Page<Employee> findAllByNameIgnoreCaseStartsWith(String name, Pageable pageable);
}
Where entity looks like:
#Data
#Entity
#Table(name = "tblEmployees")
public class Employee {
#Id
#Column(name = "empID")
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer id;
#NotEmpty
#Size(min = 2, max = 20)
#Column(name = "empName", length = 25)
private String name;
#Column(name = "empActive")
private Boolean active;
#ManyToOne
#JoinColumn(name = "emp_dpID")
private Department department;
}
When using nativeQuery that is having (nativeQuery = true), you may do the pagination yourself in the query by adding (LIMIT :sizeValue OFFSET :page)
Note:
Your page value passed to this method should be offset * size
Example
#Query(value = "SELECT * FROM person " +
"LIMIT ?1 OFFSET ?2", nativeQuery = true)
Optional<List<TDriverJob>> findPersons(int size, int page);
I tried all above solution and non worked , finally I removed the Sorting from Pagination and it worked
the following tutorial helped me
-> https://www.baeldung.com/spring-data-jpa-query
At this point 4.3. Spring Data JPA Versions Prior to 2.0.4
VERY IMPORTANT to add \ n-- #pageable \ n
Without this I was wrong
Also the pagination setting must be without ordering
PageRequest paginaConf = new PageRequest ((param1 - 1)
, param2);
Finally to convert the Page <Object []>
Page <Object []> list = myQueryofRepo ();
List <XXXModel> lstReturn = myConversor (list.getContent ());
Page <XXXModel> ret = new PageImpl <XXXModel> (lstReturn, pageConf, param2);
This bugged me for a while but I managed with a very smooth solution.
The challenge is JPA did not automatically detect the count query so I resolved to use the countName which according JPA docs Returns the name of the javax.persistence.NamedQuery to be used to execute count queries when pagination is used. Will default to the named query name configured suffixed by .count.
So I created a named query
#NamedNativeQuery(
name = "[queryName].count",
query = [your count query],
resultSetMapping = "[query resultSetMapping name]"
)
}
As indicated, the count query should be suffixed with .count
Count query returns Long so add the resultSetMapping as
#SqlResultSetMapping(
name="[query resultSetMapping name]",
columns={#ColumnResult(name="count", type = Long.class)})
Then in your repository, use the count query as indicated below
#Query(countName ="[queryName].count" , nativeQuery = true)
Page<Object> [mainQuery](...params)
Hope this helps!