I've a simple bash script to run the parameter as a command on the server, the necessity for this i am creating the required command as a string on the other server and trying to execute it remotely.
PROFILE=/coremedia/home/picroot/.profile
source $PROFILE
"$1"
the parameter i am sending to script :
/coremedia/pic-cms-tools/bin/cm publish -u admin -p admin -t "/Config/Static Texts/PDF Texts/pdf.eudatasheet.ocEnergyConsConvAlone" "/Config/Static Texts/PDF Texts/pdf.eudatasheet.ocEnergyConsForcedAlone"
But it couldn't find the necessary command it is stopped when we reached :
/coremedia/pic-cms-tools/bin/cm
I've tried many configurations on my side to handle the string but i've still couldn't reach a solution, obviously i am missing a small critical thing...
Any help would be appreciated, many thanks in advance!
Replace eval $1 with eval "$#" to evaluate all the parameters, not just the first one.
Related
I am relatively new to working in bash and one of the biggest pains with this script I have to run is that I get prompted for passwords repeatedly when running this script. I am unable to pass ssh keys or use any options except expect due to security restrictions but I am struggling to understand how to use expect.
Does Expect require a separate file from this script to call itself, it seems that way looking at tutorials but they seem rather complex and confusing for a new user. Also how do I input into my script that I want it to auto fill in any prompt that says Password: ? Also this script runs with 3 separate unique variables every time the script is called. How do I make sure that those are gathered but the password is still automatically filled?
Any assistance is greatly appreciated.
#!/bin/bash
zero=`echo $2`
TMPIP=`python bin/dgip.py $zero`
IP=`echo $TMPIP`
folder1=`echo $zero | cut -c 1-6`
folder2=`echo $zero`
mkdir $folder1
cd $folder1
mkdir $folder2
cd $folder2
scp $1#`echo $IP`:$3 .
Embedding expect code in an shell script is not too difficult. We have to be careful to get the quoting correct. You'll do something like this:
#!/usr/bin/env bash
user=$1
zero=$2
files=$3
IP=$(python bin/dgip.py "$zero")
mkdir -p "${zero:0:6}/$zero"
cd "${zero:0:6}/$zero"
export user IP files
expect <<<'END_EXPECT' # note the single quotes here!
set timeout -1
spawn scp $env(user)#$env(IP):$env(files) .
expect {assword:}
send "$env(my_password)\r"
expect eof
END_EXPECT
Before you run this, put your password into your shell's exported environment variables:
export my_password=abc123
bash script.sh joe zero bigfile1.tgz
bash script.sh joe zero bigfile2.tgz
...
Having said all that, public key authentication is much more secure. Use that, or get your sysadmins to enable it, if at all possible.
Writing a script to retrieve various environment parameters back from a list of servers. My script returns no value when ran but the same command returns the desired value outside of a script.
I have tried using a couple of variations to retrieve the same data. One of the commands fails because of restrictions placed on the accounts I have access to. The second command works but only if executed in an elevated mode.
This fails with access denied (pwdx is restricted)
dzdo pgrep -f /some/path | xargs pwdx
This works outside of a script but returns no value within a script
dzdo /bin/readlink -e /proc/"$(pgrep -f /some/path)"/cwd
When using "bash -x" to execute my scriipt, I see the "readlink" code is blank.
Ideally, I would like to return the PID and path of the process running as the "pgrep" command does. I can work with the path alone as returned by the "readlink" version returns. The end goal is to gather the information from several servers for audit purposes. (version, etc.)
Am I using the wrong syntax for the "readlink" command? I'm fairly new to coding bash scripts so I appreciate any guidance to help understand when to to what if I'm using a command in a script vs command line.
If pwdx is the restricted program, you need to run that with dzdo, not pgrep.
pgrep -f /some/path | dzdo xargs pwdx
I would like to pass parameters to a perl script using positional parameters inside a bash script "tablecheck.sh". I am using an alias "tablecheck" to call "tablecheck.sh".
#!/bin/bash
/scripts/tables.pl /var/lib/mysql/$1/ /var/mysql/$1/mysql.sock > /tmp/chktables_$1 2>&1 &
Perl script by itself works fine. But when I do "tablecheck MySQLinstance", $1 stays $1. It won't get replaced by the instance. So I get the output as follows:
Exit /scripts/tables.pl /var/lib/mysql/$1/ /var/mysql/$1/mysql.sock > /tmp/chktables_$1 2>&1 &
The job exits.
FYI: alias tablecheck='. pathtobashscript/tablecheck.sh'
I have a bunch of aliases in another bash script. Hence . command.
Could anyone help me... I have gone till the 3rd page of Google to find an answer. Tried so many things with no luck.
I am a noob. But may be it has something to do with it being a background job or $1 in a path... I don't understand why the $1 won't get replaced...
If I copy your exact set up (which I agree with other commenters, is some what unusual) then I believe I am getting the same error message
$ tablecheck foo
[1]+ Exit 127 /scripts/tables.pl /var/lib/mysql/$1/ /var/mysql/$1/mysql.sock > /tmp/chktables_$1 2>&1
In the /tmp/chktables_foo file that it makes there is an additional error message, in my case "bash: /scripts/tables.pl: No such file or directory"
I suspect permissions are wrong in your case
I am writing a simple bash script (checkServs.sh) that will ssh into a list of servers and perform a health check on them.
I keep getting errors on the following line:
SERVERS=(blah1.example.com blah2.example.com blah3.example.com blah4.example.com)
Error is:
checkServs.sh: 3: checkServs.sh: Syntax error: "(" unexpected
I've checked online examples and this seems correct, isn't it? Thanks in advance!
I don't know about the syntax error, but this should work:
SERVERS="blah1.example.com blah2.example.com blah3.example.com blah4.example.com"
for server in $SERVERS
do
echo $server
done
EDIT: As noted by Jonathan Leffler in a comment, maybe you are not running the script with bash. Other shells, such as dash, may not recognize the array syntax. If that's the case, you can do:
SERVERS=(blah1.example.com blah2.example.com blah3.example.com blah4.example.com)
for i in $(seq 0 3)
do
echo ${SERVERS[$i]}
done
But if you just want to loop through the names and run an SSH command (ie if having an array won't provide useful functionality), the first method is more straightforward.
Your remote server probably calls a different shell when executing commands. Try to add bash -c to your arguments:
ssh user#server bash -c "<your commands>"
Or:
ssh user#server bash < yourscript.sh ## None in yourscript.sh must read input though.
An opening parenthesis starts a subshell, which is not a correct thing to have on the right side of an equals sign. It expects a string expression, not a command.
Quotation marks are used to keep a string expression together.
My host upgraded my version of FreeBSD and now one of my scripts is broken. The script simply uploads a data feed to google for their merchant service.
The script (that was working prior to the upgrade):
ftp ftp://myusername:mypassword#uploads.google.com/<<END_SCRIPT
ascii
put /usr/www/users/myname/feeds/mymerchantfile.txt mymerchantfile.txt
exit
END_SCRIPT
Now the script says "unknown host". The same script works on OSX.
I've tried removing the "ftp://". - No effect
I can log in from the command line if I enter the username and password manually.
I've search around for other solutions and have also tried the following:
HOST='uploads.google.com'
USER='myusername'
PASSWD='mypassword'
ftp -dni <<END_SCRIPT
open $HOST
quote USER $USER
quote PASS $PASS
ascii
put /usr/www/users/myname/feeds/mymerchantfile.txt mymerchantfile.txt
END_SCRIPT
And
HOST='uploads.google.com'
USER='myusername'
PASSWD='mypassword'
ftp -dni <<END_SCRIPT
open $HOST
user $USER $PASS
ascii
put /usr/www/users/myname/feeds/mymerchantfile.txt mymerchantfile.txt
END_SCRIPT
Nothing I can find online seems to be doing the trick. Does anyone have any other ideas? I don't want to use a .netrc file since it is executed by cron under a different user.
ftp(1) shows that there is a simple -u command line switch to upload a file; and since ascii is the default (shudder), maybe you can replace your whole script with one command line:
ftp -u ftp://username:password#uploads.google.com/mymerchantfile.txt\
/usr/www/users/myname/feeds/mymerchantfile.txt
(Long line wrapped with \\n, feel free to remove the backslash and place it all on one line.)
ftp $HOSTNAME <<EOFEOF
$USER
$PASS
ascii
put $LOCALFILE $REMOTETEMPFILE
rename $REMOTETEMPFILE $REMOTEFINALFILE
EOFEOF
Please note that the above code can be easily broken by, for example, using spaces in the variables in question. Also, this method gives you virtually no way to detect and handle failure reliably.
Look into the expect tool if you haven't already. You may find that it solves problems you didn't know you had.
Some ideas:
just a thought since this is executed in a subshell which should inherit correctly from parent, does an env show any difference when executed from within the script than from the shell?
Do you use a correct "shebang"?
Any proxy that requires authentication?
Can you ping the host?
In BSD, you can create a NETRC script that ftp can use for logging on. You can even specify the NETRC file in your ftp command too using the -N parameter. Otherwise, the default NETRC is used (which is $HOME/.netrc).
Can you check if there's a difference in the environment between your shell-login, and the cron-job? From your login, run env, and look out for ftp_proxy and http_proxy.
Next, include a line in the cron-job that will dump the environment, e.g. env >/tmp/your.env.
Maybe there's some difference...Also, did you double-check your correct usage of the -n switch?