I have multiple .dat files, which i will get to know dynamically. dat file will have two columns seperated by comma. Will be like key value pairs. For example:
File1:
entry1,100
entry2,200
entry3,300
File2:
entry1,500
entry3,750
Now I want the output as
File3:
entry1,100,500
entry2,200
entry3,300,750
Assuming you want to include unpairable lines from both files - such as entry2,200 from File2 the following command should work:
join -t, -a1 -a2 file1 file2
-t, instructs join to use comma as a delimiter, -a1 -a2 instructs join to include unpairable lines from each file.
You can use awk when input files are not already sorted:
awk 'BEGIN{FS=OFS=","} FNR==NR{a[$1]=$2; next} {print $0 (($1 in a)?OFS a[$1]:"")}' f2.dat f1.dat
entry1,100,500
entry2,200
entry3,300,750
Related
I have to join two files by values in one column. I need to use unix bash.
My first file looks like this:
user_id, song_id, timestamp
00001638d6189236866af9bbf309ae6c2347ffdc,SOBBMDR12A8C13253B,1203083335
00001638d6189236866af9bbf309ae6c2347ffdc,SOBXALG12A8C13C108,984663773
00001cf0dce3fb22b0df0f3a1d9cd21e38385372,SODDNQT12A6D4F5F7E,1275071044
00001cf0dce3fb22b0df0f3a1d9cd21e38385372,SODDNQT12A6D4F5F7E,1097509573
Second file:
user_id, natural_key
00000b722001882066dff9d2da8a775658053ea0,6944471
00001638d6189236866af9bbf309ae6c2347ffdc,19309784
0000175652312d12576d9e6b84f600caa24c4715,10435505
00001cf0dce3fb22b0df0f3a1d9cd21e38385372,5232769
Of course both files have many more rows. I would like to join both files by first column (user_id) and get this result:
natural_key, song_id, timestamp
19309784,SOBBMDR12A8C13253B,1203083335
19309784,SOBXALG12A8C13C108,984663773
5232769,SODDNQT12A6D4F5F7E,1275071044
5232769,SODDNQT12A6D4F5F7E,1097509573
I tried to do something with join and awk but to no avail. Could anyone help?
With GNU join, sed, sort and bash:
echo "natural_key, song_id, timestamp"
join -t, <(sed '1d' file1 |sort -t, -k1,1) <(sed '1d' file2 | sort -t, -k1,1) -o 2.2,1.2,1.3
Output:
natural_key, song_id, timestamp
19309784,SOBBMDR12A8C13253B,1203083335
19309784,SOBXALG12A8C13C108,984663773
5232769,SODDNQT12A6D4F5F7E,1097509573
5232769,SODDNQT12A6D4F5F7E,1275071044
This one in GNU awk (regex FS). That header spacing in your example I'm just going to ignore:
$ awk 'BEGIN{FS=", ?";OFS=","}NR==FNR{a[$1]=$2;next}$1 in a{print a[$1],$2,$3}' file2 file1
natural_key,song_id,timestamp
19309784,SOBBMDR12A8C13253B,1203083335
19309784,SOBXALG12A8C13C108,984663773
5232769,SODDNQT12A6D4F5F7E,1275071044
5232769,SODDNQT12A6D4F5F7E,1097509573
Explained:
$ awk '
BEGIN { FS=", ?"; OFS="," } # set the delimiters
NR==FNR { a[$1]=$2; next } # hash the first file in paramaters
$1 in a { print a[$1], $2, $3 } # if key is found in hash, output
' file2 file1 # mind the order
Using the mlr util:
mlr --csvlite join -j user_id -f f1.csv \
then cut -o -f ' natural_key',' song_id',' timestamp' f2.csv
Output:
natural_key, song_id, timestamp
19309784,SOBBMDR12A8C13253B,1203083335
19309784,SOBXALG12A8C13C108,984663773
5232769,SODDNQT12A6D4F5F7E,1275071044
5232769,SODDNQT12A6D4F5F7E,1097509573
Note the leading spaces in the headers. These are left intact here because:
Most of the source data headers have leading spaces, but the data does not.
The leading spaces, if unquoted, will fail with most CSV oriented utils.
I need to compare 2 csv files and make modifications to the second column. I wrote out the logic out of how I would want to achieve this however, it seems to confuse the thread a lot more than I wanted too so I'll just write out the example.
Any help would be appreciated. Thanks in advance.
file1
user1,distinguishedName1
user2,distinguishedName2
user3,distinguishedName3
user4,distinguishedName4
user5,distinguishedName5
file2
user1,distinguishedName1
user3,distinguishedName13
user5,distinguishedName12
user6,distinguishedName4
desired outcome:
user1,distinguishedName1
user2,distinguishedName2
user3,distinguishedName13
user4,distinguishedName4
user5,distinguishedName12
user6,distinguishedName4
The solution using join command combined with awk command:
join -t',' -j1 -a1 -a2 file1 file2 | awk -F',' '{if(NF==3) $0=$1FS$3}1'
The output:
user1,distinguishedName1
user2,distinguishedName2
user3,distinguishedName13
user4,distinguishedName4
user5,distinguishedName12
user6,distinguishedName4
Explanation:
-- for join command:
-t',' - defines field separator
-j1 - tells to join on first field 1
-a FILENUM - print unpairable lines coming from file FILENUM, where FILENUM is 1 or 2, corresponding to FILE1 or FILE2
-- for awk command:
NF - contains a total number of fields
FS - field separator(i.e. ,)
if(NF==3) $0=$1FS$3 - the condition, checks if there's a complement third field(as result of joining the files on lines with common first field) to perform the replacement
https://linux.die.net/man/1/join
awk to the rescue!
awk -F, '!a[$1]++' file2 file1
user1,distinguishedName1
user3,distinguishedName13
user5,distinguishedName12
user6,distinguishedName4
user2,distinguishedName2
user4,distinguishedName4
this order is based on file2 and file1 record order, if you want sorted order just pipe to sort
awk ... | sort
File1
abcd-efg|random1||abcd|10.10.1.1||
bcde-ab|random2||bc|10.1.2.2||
efgh-bd|ramdom3||fgh|10.2.1.1||
ijkl|random4||mno|10.3.2.3||
File2
10.10.1.1| yes
10.1.2.2| no
10.2.1.1| yes
10.3.2.3| no
Output should be
abcd-efg|random1||abcd|10.10.1.1||yes
bcde-ab|random2||bc|10.1.2.2||no
efgh-bd|ramdom3||fgh|10.2.1.1||yes
ijkl|random4||mno|10.3.2.3||no
I was trying to join both text files based on ip address using awk and joins but some how not able to get the right output.
Could you help me get through the right output.Thanks in advance
$ awk -F'|' 'FNR==NR{a[$1]=$2; next} {print $0 a[$5]}' file2 file1
abcd-efg|random1||abcd|10.10.1.1|| yes
bcde-ab|random2||bc|10.1.2.2|| no
efgh-bd|ramdom3||fgh|10.2.1.1|| yes
ijkl|random4||mno|10.3.2.3|| no
This approach will work even if the IPs are in the files in different orders.
How it works
-F'|'
Set the field separator on input to |.
FNR==NR{a[$1]=$2; next}
When reading the first file, file2, save the second field as a value in associative array a under the key of the first field. Skip remaining commands and jump to the next line.
print $0 a[$5]
If we get here, we are working on the second file, file1. Print the line followed by the value of a for this IP.
BSD/OSX
On BSD (OSX) awk, try:
awk -F'|' 'FNR==NR{a[$1]=$2; next;} {print $0 a[$5];}' file2 file1
Unix join command can be used for this
join -t\| -j1 5 -j2 1 -o1.1,1.2,1.3,1.4,1.5,1.6,2.2 file1 file2
Explanation of options:
-t\| : Field separator is '|' (escaped)
-j1 5 -j2 1 : Join based on 5th field of file1 and 1st field of file2
-o1.1,1.2,1.3,1.4,1.5,1.6,2.2 : Output the 6 fields from file1 and 2nd field from file2
If the input files are not sorted, they need to be sorted first, like below
join -t\| -j1 5 -j2 1 -o1.1,1.2,1.3,1.4,1.5,1.6,2.2 <(sort -t'|' -k5 file1) <(sort -t'|' -k1 file2)
Assuming both files have IP address in same order as shown in OP's example
paste -d'\0' file1 <(cut -d' ' -f2 file2)
cut -d' ' -f2 file2 select second column of file2, column separation is space character specified by delimiter -d' '
Using process substitution, output of cut command is passed as file input to paste command
paste command then combines file1 and output of cut column wise without any character in between (reference: paste without delimiter)
I have 2 files:
File1
123:dataset1:dataset932
534940023023:dataset:dataset039302
49930:dataset9203:dataset2003
File2
49930:399402:3949304:293000232:30203993
123:49030:1204:9300:293920
534940023023:49993029:3949203:49293904:29399
and I would like to create
Desired result:
49930:399402:3949304:293000232:30203993:dataset9203:dataset2003
534940023023:49993029:3949203:49293904:29399:dataset:dataset039302
etc
where the result contains one line for each pair of input lines that have identical first column (with : as the column separator).
The join command is your friend here. You'll likely need to sort the inputs (either pre-sort the files, or use a process substitution if available - e.g. with bash).
Something like:
join -t ':' <(sort file2) <(sort file1) >file3
When you do not want to sort files, play with grep:
while IFS=: read key others; do
echo "${key}:${others}:$(grep "^${key}:" file1 | cut -d: -f2-)"
done < file2
file1.txt
112|9305|/inst.exe
112|9305|/lkj.exe
112|9305|/dje.jar
112|9305|/ind.pdf
112|9306|/ma.exe
112|9306|/ngg.pdf
112|9307|/jhhh.dat
112|9312|/ee.dat
112|9312|/qwq.dll
file2.txt
117|9305|www.gahan.com
117|9306|www.google.com
117|9312|www.mihan.com
117|9307|translate.com
expected output
112|9305|www.gahan.com/inst.exe
112|9305|www.gahan.com/lkj.exe
112|9305|www.gahan.com/dje.jar
112|9305|www.gahan.com/ind.pdf
112|9306|www.google.com/ma.exe
112|9306|www.google.com/ngg.pdf
112|9307|translate.com/jhhh.dat
112|9312|www.mihan.com/ee.dat
112|9312|www.mihan.com/qwq.dll
I want to add third column of file2.txt to third column of file1.txt based on second column values. In fact I want join them based on second column but there is no one bye one correspondence between them. How can I do these with awk or grep or sed in shell script.
You can use awk like this:
awk 'BEGIN{FS=OFS="|"} FNR==NR{a[$2]=$3; next} $2 in a{$3=a[$2] $3} 1' file2.txt file1.txt
112|9305|www.gahan.com/inst.exe
112|9305|www.gahan.com/lkj.exe
112|9305|www.gahan.com/dje.jar
112|9305|www.gahan.com/ind.pdf
112|9306|www.google.com/ma.exe
112|9306|www.google.com/ngg.pdf
112|9307|translate.com/jhhh.dat
112|9312|www.mihan.com/ee.dat
112|9312|www.mihan.com/qwq.dll