I'm trying to create skype tool and I'm trying to make a command for it what would give the user a random imgur link, I tried first to just random generate string like so:
var chars ="ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789";
var stringChars = new char[8];
var random = new Random();
for (int i = 0; i < stringChars.Length; i++)
{
stringChars[i] = chars[random.Next(chars.Length)];
}
var finalString = new String(stringChars);
string imgur = "http://imgur.com/" + finalString;
But of course it just gave me random imgur links which don't work, how could I check if the link is valid and then give it to the user or how could I use imgurs own "https://imgur.com/gallery/random" and return the link from that?
Imgur API exposes a function to fetch a random set of gallery images:
https://api.imgur.com/endpoints/gallery#gallery-random
Method GET
Route https://api.imgur.com/3/gallery/random/random/{page}
Related
I have 5 possible locations where a user can enter either: "Yes, No, or any URL". If a URL is entered, I need the value of that cell (the URL) to be entered into an equation on a corresponding cell in a separate sheet. Here is what I have:
//Locations of the cells where the user can enter the URL.
var graphic1_loc = 'A62';
var graphic2_loc = 'A63';
var graphic3_loc = 'A64';
var graphic4_loc = 'A65';
var graphic5_loc = 'A66';
//The corresponding locations on the "Briefing" sheet where the images would get inserted.
var graphic1_placement = 'B45';
var graphic2_placement = 'B46';
var graphic3_placement = 'B47';
var graphic4_placement = 'B48';
var graphic5_placement = 'B49';
//main_gen is the name of the sheet where the user enters the data. This just grabs the value
//the user entered and stores it in the corresponding variable.
var graphic1 = SpreadsheetApp.getActiveSheet().getRange('main_gen!'+graphic1_loc).getValue();
var graphic2 = SpreadsheetApp.getActiveSheet().getRange('main_gen!'+graphic2_loc).getValue();
var graphic3 = SpreadsheetApp.getActiveSheet().getRange('main_gen!'+graphic3_loc).getValue();
var graphic4 = SpreadsheetApp.getActiveSheet().getRange('main_gen!'+graphic4_loc).getValue();
var graphic5 = SpreadsheetApp.getActiveSheet().getRange('main_gen!'+graphic5_loc).getValue();
var graphics_placements = ["B45", "B46", "B47", "B48", "B49"]; //These are the corresponding cells where the image would be placed on a separate sheet.
//If any graphic is a URL, insert that image into it's corresponding cell in the Briefing tab.
for (var num = 0; num < 5; num ++) {
var graphicformula = '=IMAGE("' + graphic[num] + '",1)';
if (graphic[num].length > 5) {
SpreadsheetApp.getActiveSheet().getRange('Briefing!'+graphic[num]_placement).setFormula(graphicformula);
}
}
What I am trying to get the If statement within the For Loop to say is...If the length of the value of graphic1 is > 5 (if it isn't yes (3) or no (2) then it is assumed it is a URL) then find the corresponding cell on the "Briefing" sheet to insert the formula. The current way I have it written is not correct, but I wanted to attempt to write something to give you an idea of what I am after. Thanks for any help you can provide!
You want to run SpreadsheetApp.getActiveSheet().getRange('Briefing!'+graphic[num]_placement).setFormula(graphicformula); when the value of graphic# is URL.
For example, when the URL is in the cell A63 in the sheet main_gen, you want to put the formula of =IMAGE(URL,1) to the cell B46 in the sheet Briefing
If my understanding is correct, how about this answer? Please think of this as just one of several possible answers.
Modification points:
In your script, you are trying to use graphic[num] as a variable of graphic1, graphic2,,,. In this case, this cannot be used as the variable.
In your situation, the cells A62:A66 in the sheet main_gen are correspoinding to the cells B45:B49 in the sheet Briefing. I think that this can be used for modifying your script.
The values of the cells A62:A66 in the sheet main_gen can be retrieved by ss.getSheetByName("main_gen").getRange("A62:A66").getValues().
In order to confirm whether the value of cell is the URL, in this modification, I used test().
I think that when the destination sheet is declared out of the for loop, the process cost can be reduced.
When above points are reflected to your script, it becomes as follows.
Modified script:
var ss = SpreadsheetApp.getActiveSpreadsheet();
var source = ss.getSheetByName("main_gen").getRange("A62:A66").getValues();
var dstSheet = ss.getSheetByName("Briefing");
var graphics_placements = ["B45", "B46", "B47", "B48", "B49"];
for (var num = 0; num < source.length; num ++) {
if (/https?:\/\//.test(source[num][0])) {
var graphicformula = '=IMAGE("' + source[num][0] + '",1)';
dstSheet.getRange(graphics_placements[num]).setFormula(graphicformula);
}
}
References:
test()
getValues()
If I misunderstood your question and this was not the direction you want, I apologize.
I need to transfer ownership of thousands of files I own to someone else with editing access, but I've learned that Google Drive requires you to do this one file at a time. With intermediate but growing JS experience I decided to write a script to change the owner from a list of file IDs in a spreadsheet, however I've run into trouble and I have no idea why. The debugger just runs through the script and everything looks sound for me. I'd greatly appreciate any help.
function changeOwner() {
var ss = SpreadsheetApp.openByUrl('https://docs.google.com/spreadsheets/d/********/').getSheetByName('Sheet1');
var range = ss.getRange(1,1,2211);
for (i = 0; i < range.length; i++){
var file = range[i][0].getValue();
var fileid = DriveApp.getFileById(file);
fileid.setOwner('******#gmail.com');
}
}
Tested below code working fine with IDs,
function myFunction() {
var spreadsheet = SpreadsheetApp.openById('ID');
var range = spreadsheet.getDataRange().getValues();
for (i = 0; i < range.length; i++){
var file = range[i][0].toString();
var fileid = DriveApp.getFileById(file);
fileid.setOwner('***#gmail.com');
}
}
Your issue is that the Range class had no length property. Instead, perform a getValues() call on the range to efficiently create a JavaScript array, and iterate on it:
function changeOwner() {
var ss = SpreadsheetApp.openByUrl('https://docs.google.com/spreadsheets/d/********/').getSheetByName('Sheet1');
var values = ss.getRange(1, 1, 2211).getValues();
for (i = 0; i < values.length; ++i){
var fileid = value[i][0];
var file = DriveApp.getFileById(fileid);
file.setOwner('******#gmail.com');
}
}
There are other improvements you can make, such as:
dynamic range read (rather than the fixed assumption of 2211 rows of data)
writing to a second array to keep track of which files you have yet to process
checks for if the file exists
checks for if the file is actually owned by you
checks for execution time remaining, to allow serializing any updates/tracking you do that prevents the next execution from repeating what you just did
and so on. I'll let you research those topics, and the methods available in Apps Script documentation for the DriveApp, SpreadsheetApp, Sheet, and Range classes. Note that you also have all features of Javascript 1.6 available, so many of the things you find on a Javascript Developer Reference (like MDN) are also available to you.
I'm trying to get images from google places. All is working for details: reviews, address... but when I try to get photos, I get a 404.
if(place.photos != null){
for(var i = 0; i < place.photos.length; i++){
var str = place.photos[i].getUrl({"maxWidth": 100, "maxHeight": 100});
var res = str.replace("w100-h100-p", "p");
self.pacPhotos.push({
id : res
});
}
}else {
console.log("no photo");
}
}
This will return the list ok but the URL is formatted wrong. it comes out like this.
" https://lh3.googleusercontent.com/w100-h100-p/AF1QipN3xzffYDPCyEIWnvAQGd3RwNs2C14sVlSqrrAh=k "
What I gather it wants is this.
" https://lh3.googleusercontent.com/p/AF1QipN3xzffYDPCyEIWnvAQGd3RwNs2C14sVlSqrrAh=k "
The only difference is the "w100-h100-"
*** There is a great work-around here from "Sulyman". I know it's not a long term solution as I'm sure google will fix their results (as discussed here Place API - getting place photo as marker icon )
For now I've adjusted the code above to reflect Sulymans suggestion. ***
it seems like every API Key generates different path
for example you got w100-h100-p and i got w200-p
and the good news that this section whatever it is...is fixed so you can replace it with another string which is p
var str = place.photos[0].getUrl();
var res = str.replace(""w100-h100-p", "p");
or you can delete the w100-h100-
Could anyone please help me optimise this Google Sheets script?
It's painfully slow. It barely makes 300 copies in 24 hours (I need the Drive API to make the copies as "view only users can't copy/print/download")
function addCopies() {
var count = 10;
var input = DriveApp.getFileById('1GQI5m0g5XsCWi1dOTBWFs3VJkzW7e8N__09C3-2BEGI')
var results = DriveApp.getFileById('1gkOCTPJuqTQnNNlaE3jD2Hq2COU-lO02PmlO_xMepx0')
var indexSH = SpreadsheetApp.openById('1o6ZfweVylhnDXoVc9u_R8afKdVfXYgtdqtj_lSCdFEk').getSheetByName('Index')
for(var i=0;i<count;i++)
{
//make copies of both files (input & results)
var inputCopy = input.makeCopy(input.getName(), DriveApp.getFolderById('0B0go-fsdFA3ISG0xNGlhTDZoM0U'))
inputCopy.setSharing(DriveApp.Access.ANYONE_WITH_LINK, DriveApp.Permission.EDIT)
var inputID = inputCopy.getId()
//make results to be restricted using API
var resultsCopy = results.makeCopy(results.getName(), DriveApp.getFolderById('0B0go-fsdFA3ISG0xNGlhTDZoM0U'))
resultsCopy.setSharing(DriveApp.Access.ANYONE_WITH_LINK, DriveApp.Permission.VIEW)
var resultsID = resultsCopy.getId()
var apiFile = DriveAPI.Files.get(resultsID)
apiFile.labels.restricted = true
DriveAPI.Files.update(apiFile, resultsID)
//save IDs of both files to an index for later re-use
var lastRow = indexSH.getRange(1,1).getValue()
var addRng = indexSH.getRange(lastRow+1, 1,1,3)
addRng.setValues([['free',inputID,resultsID]])
}
}
Edit: techydesigner said "we don't optimise code on SO" . So please let me rephrase : am I using the wrong Drive services ? Is there a method to make those copies faster ?
I am trying to read a spreadsheet using google spreadsheet api.
Everything went well, but when I put russian or arabic texts in the spreadsheet
my program prints ?????? ?? ????? values for those cell values.
below is the code to read spreadsheet from my google account.
SpreadsheetService service = new SpreadsheetService("MyApp");
service.setUserCredentials(USERNAME, PASSWORD);
URL feedUri = new URL("https://spreadsheets.google.com/feeds/spreadsheets/private/full?title-exact=true&title=internationalization_contents");
// Make a request to the API and get all spreadsheets.
SpreadsheetFeed feed = service.getFeed(feedUri, SpreadsheetFeed.class);
List<SpreadsheetEntry> spreadsheets = feed.getEntries();
SpreadsheetEntry spreadsheet = spreadsheets.get(0);
// get the first work sheet
WorksheetEntry workSheet = spreadsheet.getWorksheets().get(0);
URL cellFeedUrl = workSheet.getCellFeedUrl();
CellFeed cellFeed = service.getFeed(cellFeedUrl, CellFeed.class);
List<CellEntry> entries = cellFeed.getEntries();
for (int n = 0; n < entries.size(); n++) {
Cell cell = entries.get(n).getCell();
System.out.println(cell.getValue());
}
this prints something like
title
welcome
???? ?? ????
anybody knows how to get characters properly to my java application.