Prompt the user for a file name, without the path (Ex: xyz.out)
- Using the find command, provide the full path to the file
- At the end, “print number of locations of that file found”
- If it’s not found, then display “not found
and this is my script
#! /bin /bash
echo "please enter your file name"
read filename
if [ -f $filename ];
then
echo "file $filename found"
find $PWD -type f | grep $filename
#find "$(cd ..; pwd)" -name $filename
else
echo "file $filename was not found"
fi
but the thing is At the end, i need to “print number of locations of that file found”
help me out with this
Something like this to get the count:
find $PWD -type f -name $filename 2>/dev/null | wc -l
This should work:
find "$PWD" -type f -name "$fname" |grep "" -c
In trying to keep it as short as possible, one approach with Posix shell would be to fill a temporary file with the file names returned by find, cat the file to provide your output, and use wc to provide the line count (note: you use your own pattern instead of "*cmpf*" shown below):
$ find . -name "*cmpf*" -printf "%P\n" >tmp; cat tmp; c=$(wc -l <tmp); \
rm tmp; printf "[%s] files found\n" $c
cmpf1f2.c
cmpf1f2_2.c
bin/cmpf1f2_2
bin/cmpf1f2
snip/cmpf1f2_notes.txt
cmpf1f2_for.c
[6] files found
If bash is available, another approach is to read the matching files into an array and then use the number of elements as your count. Example:
$ a=( $(find . -name "*cmpf*" -printf "%P\n") ); printf "%s\n" ${a[#]}; \
printf -- "--\n'%s' files found.\n" ${#a[#]}
cmpf1f2.c
cmpf1f2_2.c
bin/cmpf1f2_2
bin/cmpf1f2
snip/cmpf1f2_notes.txt
cmpf1f2_for.c
--
'6' files found.
Both approaches give you both the files and directories in which they reside as well as the count of the files returned.
Note: if you would like ./ before each file and directory names, use the %p format instead of %P above.
Related
I want to iterate over a list of files. This list is the result of a find command, so I came up with:
getlist() {
for f in $(find . -iname "foo*")
do
echo "File found: $f"
# do something useful
done
}
It's fine except if a file has spaces in its name:
$ ls
foo_bar_baz.txt
foo bar baz.txt
$ getlist
File found: foo_bar_baz.txt
File found: foo
File found: bar
File found: baz.txt
What can I do to avoid the split on spaces?
You could replace the word-based iteration with a line-based one:
find . -iname "foo*" | while read f
do
# ... loop body
done
There are several workable ways to accomplish this.
If you wanted to stick closely to your original version it could be done this way:
getlist() {
IFS=$'\n'
for file in $(find . -iname 'foo*') ; do
printf 'File found: %s\n' "$file"
done
}
This will still fail if file names have literal newlines in them, but spaces will not break it.
However, messing with IFS isn't necessary. Here's my preferred way to do this:
getlist() {
while IFS= read -d $'\0' -r file ; do
printf 'File found: %s\n' "$file"
done < <(find . -iname 'foo*' -print0)
}
If you find the < <(command) syntax unfamiliar you should read about process substitution. The advantage of this over for file in $(find ...) is that files with spaces, newlines and other characters are correctly handled. This works because find with -print0 will use a null (aka \0) as the terminator for each file name and, unlike newline, null is not a legal character in a file name.
The advantage to this over the nearly-equivalent version
getlist() {
find . -iname 'foo*' -print0 | while read -d $'\0' -r file ; do
printf 'File found: %s\n' "$file"
done
}
Is that any variable assignment in the body of the while loop is preserved. That is, if you pipe to while as above then the body of the while is in a subshell which may not be what you want.
The advantage of the process substitution version over find ... -print0 | xargs -0 is minimal: The xargs version is fine if all you need is to print a line or perform a single operation on the file, but if you need to perform multiple steps the loop version is easier.
EDIT: Here's a nice test script so you can get an idea of the difference between different attempts at solving this problem
#!/usr/bin/env bash
dir=/tmp/getlist.test/
mkdir -p "$dir"
cd "$dir"
touch 'file not starting foo' foo foobar barfoo 'foo with spaces'\
'foo with'$'\n'newline 'foo with trailing whitespace '
# while with process substitution, null terminated, empty IFS
getlist0() {
while IFS= read -d $'\0' -r file ; do
printf 'File found: '"'%s'"'\n' "$file"
done < <(find . -iname 'foo*' -print0)
}
# while with process substitution, null terminated, default IFS
getlist1() {
while read -d $'\0' -r file ; do
printf 'File found: '"'%s'"'\n' "$file"
done < <(find . -iname 'foo*' -print0)
}
# pipe to while, newline terminated
getlist2() {
find . -iname 'foo*' | while read -r file ; do
printf 'File found: '"'%s'"'\n' "$file"
done
}
# pipe to while, null terminated
getlist3() {
find . -iname 'foo*' -print0 | while read -d $'\0' -r file ; do
printf 'File found: '"'%s'"'\n' "$file"
done
}
# for loop over subshell results, newline terminated, default IFS
getlist4() {
for file in "$(find . -iname 'foo*')" ; do
printf 'File found: '"'%s'"'\n' "$file"
done
}
# for loop over subshell results, newline terminated, newline IFS
getlist5() {
IFS=$'\n'
for file in $(find . -iname 'foo*') ; do
printf 'File found: '"'%s'"'\n' "$file"
done
}
# see how they run
for n in {0..5} ; do
printf '\n\ngetlist%d:\n' $n
eval getlist$n
done
rm -rf "$dir"
There is also a very simple solution: rely on bash globbing
$ mkdir test
$ cd test
$ touch "stupid file1"
$ touch "stupid file2"
$ touch "stupid file 3"
$ ls
stupid file 3 stupid file1 stupid file2
$ for file in *; do echo "file: '${file}'"; done
file: 'stupid file 3'
file: 'stupid file1'
file: 'stupid file2'
Note that I am not sure this behavior is the default one but I don't see any special setting in my shopt so I would go and say that it should be "safe" (tested on osx and ubuntu).
find . -iname "foo*" -print0 | xargs -L1 -0 echo "File found:"
find . -name "fo*" -print0 | xargs -0 ls -l
See man xargs.
Since you aren't doing any other type of filtering with find, you can use the following as of bash 4.0:
shopt -s globstar
getlist() {
for f in **/foo*
do
echo "File found: $f"
# do something useful
done
}
The **/ will match zero or more directories, so the full pattern will match foo* in the current directory or any subdirectories.
I really like for loops and array iteration, so I figure I will add this answer to the mix...
I also liked marchelbling's stupid file example. :)
$ mkdir test
$ cd test
$ touch "stupid file1"
$ touch "stupid file2"
$ touch "stupid file 3"
Inside the test directory:
readarray -t arr <<< "`ls -A1`"
This adds each file listing line into a bash array named arr with any trailing newline removed.
Let's say we want to give these files better names...
for i in ${!arr[#]}
do
newname=`echo "${arr[$i]}" | sed 's/stupid/smarter/; s/ */_/g'`;
mv "${arr[$i]}" "$newname"
done
${!arr[#]} expands to 0 1 2 so "${arr[$i]}" is the ith element of the array. The quotes around the variables are important to preserve the spaces.
The result is three renamed files:
$ ls -1
smarter_file1
smarter_file2
smarter_file_3
find has an -exec argument that loops over the find results and executes an arbitrary command. For example:
find . -iname "foo*" -exec echo "File found: {}" \;
Here {} represents the found files, and wrapping it in "" allows for the resultant shell command to deal with spaces in the file name.
In many cases you can replace that last \; (which starts a new command) with a \+, which will put multiple files in the one command (not necessarily all of them at once though, see man find for more details).
I recently had to deal with a similar case, and I built a FILES array to iterate over the filenames:
eval FILES=($(find . -iname "foo*" -printf '"%p" '))
The idea here is to surround each filename with double quotes, separate them with spaces and use the result to initialize the FILES array.
The use of eval is necessary to evaluate the double quotes in the find output correctly for the array initialization.
To iterate over the files, just do:
for f in "${FILES[#]}"; do
# Do something with $f
done
In some cases, here if you just need to copy or move a list of files, you could pipe that list to awk as well.
Important the \"" "\" around the field $0 (in short your files, one line-list = one file).
find . -iname "foo*" | awk '{print "mv \""$0"\" ./MyDir2" | "sh" }'
Ok - my first post on Stack Overflow!
Though my problems with this have always been in csh not bash the solution I present will, I'm sure, work in both. The issue is with the shell's interpretation of the "ls" returns. We can remove "ls" from the problem by simply using the shell expansion of the * wildcard - but this gives a "no match" error if there are no files in the current (or specified folder) - to get around this we simply extend the expansion to include dot-files thus: * .* - this will always yield results since the files . and .. will always be present. So in csh we can use this construct ...
foreach file (* .*)
echo $file
end
if you want to filter out the standard dot-files then that is easy enough ...
foreach file (* .*)
if ("$file" == .) continue
if ("file" == ..) continue
echo $file
end
The code in the first post on this thread would be written thus:-
getlist() {
for f in $(* .*)
do
echo "File found: $f"
# do something useful
done
}
Hope this helps!
Another solution for job...
Goal was :
select/filter filenames recursively in directories
handle each names (whatever space in path...)
#!/bin/bash -e
## #Trick in order handle File with space in their path...
OLD_IFS=${IFS}
IFS=$'\n'
files=($(find ${INPUT_DIR} -type f -name "*.md"))
for filename in ${files[*]}
do
# do your stuff
# ....
done
IFS=${OLD_IFS}
for i in `find . -type f -name "VF-Outlet*.edi" -exec basename \{} \;` ; do
if [ -n "${i}" ];
then
echo file "VF-Outlet found";
sed -e 's/\*UK\*00/\*UP\*/g;s/XQ.*$/XQ\*H\*20150104\*20150110/g' $i > ${i}_fix
else
echo file "VF-Outlet" not found;
fi
done
The above code works if the file is found. The 'echo' statement prints file found.
If the file is not found however, nothing prints. I tried all the various tests for empty string, and unset variables, nothing works.
Also if I try:
i=`find . -type f -name "VF-Outlet*.edi" -exec basename \{} \;`;
Then do the test:
if [ -n "${i}" ];
then
echo file ${i} found;
else
echo file "VF-Outlet" not found;
fi
done
It works correctly if the file is found or not.
Need help in figuring this out. I need the for loop to test multiple files.
The reason it is not working is due to the fact that "for" does not take null value as input for the variable "i"
For ex:
for i in echo > /dev/null; do echo hi; done
The above command wont give any result, because no value has been assigned to value $i for running the loop.
In the case mentioned here if we check the script in debug mode, we can see that the script dies at initial variable assignment.
# sh -x script.sh
+ find . -type f -name VF-Outlet*.edi -exec basename {} ;
here, script.sh file contains the script you have provided.
If there is a file present in the directory, the script will successfully execute.
# sh -x tet
+ find . -type f -name VF-Outlet*.edi -exec basename {} ;
+ [ -n VF-Outlet1.edi ]
+ echo file VF-Outlet found
file VF-Outlet found
As #shellter mentioned, this not how I would have done. You can use -f instead of -n to check if a file exists.
Hope this helps!
I want to remove all the images which has the name without the "#2x", and I want to write a shell script to finish this. This is what I do:
#!/bin/bash
dir="/Users/me/Workspace/"
cd $dir
all_pngs=`find . -name "*.png" | sort -u`
for png in $all_pngs
do
# echo "$png"
#get the dirname
dirname=`dirname $png`
#get the filename without dir
filename=`basename $png`
#get name without suffix
name=`echo "$filename" | cut -d '.' -f1`
realname=`echo "$name" | grep -v "#2x"`
if [ -n $realname ]; then
echo "$realname"
fi
done
My problem is that I don't know how can I find the name without the "#2x".
I'm not really sure what you're trying to do with the rest of your script, but just something like this should work
find /Users/me/Workspace/ -type f -name '*.png' \! -name '*#2x*' -exec echo rm '{}' +
Remove the echo when you're confident that's what you want.
Since the ! exp has a higher precedence in find than the implied -a between tests and actions the above gets treated as
find /Users/me/Workspace/ (-type f) AND (-name '*.png') AND (! -name '*#2x*') AND (-exec echo rm '{}' +)
You have used many unwanted operation in your for loop which are not necessary( but exactly any purpose of it?). You need simple logic in your for..loop as below. OR in one sentence you can use nice answer given by #BroSlow
You can check if your file name contain "#2x" or not like
if [[ $png = *#2x* ]] //Yes it contain "#2x"
then
echo "File name contain #2x keep as it is."
else
//remove file // rm -f $png
fi
Using grep
if grep -o "#2x" <<<"$png" >/dev/null
then
echo "File name contain #2x keep as it is."
else
//remove file // rm -f $png
fi
I have been looking for a way to list file that do not exist from a list of files that are required to exist. The files can exist in more than one location. What I have now:
#!/bin/bash
fileslist="$1"
while read fn
do
if [ ! -f `find . -type f -name $fn ` ];
then
echo $fn
fi
done < $fileslist
If a file does not exist the find command will not print anything and the test does not work. Removing the not and creating an if then else condition does not resolve the problem.
How can i print the filenames that are not found from a list of file names?
New script:
#!/bin/bash
fileslist="$1"
foundfiles="~/tmp/tmp`date +%Y%m%d%H%M%S`.txt"
touch $foundfiles
while read fn
do
`find . -type f -name $fn | sed 's:./.*/::' >> $foundfiles`
done < $fileslist
cat $fileslist $foundfiles | sort | uniq -u
rm $foundfiles
#!/bin/bash
fileslist="$1"
while read fn
do
FPATH=`find . -type f -name $fn`
if [ "$FPATH." = "." ]
then
echo $fn
fi
done < $fileslist
You were close!
Here is test.bash:
#!/bin/bash
fn=test.bash
exists=`find . -type f -name $fn`
if [ -n "$exists" ]
then
echo Found it
fi
It sets $exists = to the result of the find. the if -n checks if the result is not null.
Try replacing body with [[ -z "$(find . -type f -name $fn)" ]] && echo $fn. (note that this code is bound to have problems with filenames containing spaces).
More efficient bashism:
diff <(sort $fileslist|uniq) <(find . -type f -printf %f\\n|sort|uniq)
I think you can handle diff output.
Give this a try:
find -type f -print0 | grep -Fzxvf - requiredfiles.txt
The -print0 and -z protect against filenames which contain newlines. If your utilities don't have these options and your filenames don't contain newlines, you should be OK.
The repeated find to filter one file at a time is very expensive. If your file list is directly compatible with the output from find, run a single find and remove any matches from your list:
find . -type f |
fgrep -vxf - "$1"
If not, maybe you can massage the output from find in the pipeline before the fgrep so that it matches the format in your file; or, conversely, massage the data in your file into find-compatible.
I use this script and it works for me
#!/bin/bash
fileslist="$1"
found="Found:"
notfound="Not found:"
len=`cat $1 | wc -l`
n=0;
while read fn
do
# don't worry about this, i use it to display the file list progress
n=$((n + 1))
echo -en "\rLooking $(echo "scale=0; $n * 100 / $len" | bc)% "
if [ $(find / -name $fn | wc -l) -gt 0 ]
then
found=$(printf "$found\n\t$fn")
else
notfound=$(printf "$notfound\n\t$fn")
fi
done < $fileslist
printf "\n$found\n$notfound\n"
The line counts the number of lines and if its greater than 0 the find was a success. This searches everything on the hdd. You could replace / with . for just the current directory.
$(find / -name $fn | wc -l) -gt 0
Then i simply run it with the files in the files list being separated by newline
./search.sh files.list
I need to loop through a directory recursively and remove all files with extension .pdf and .doc. I'm managing to loop through a directory recursively but not managing to filter the files with the above mentioned file extensions.
My code so far
#/bin/sh
SEARCH_FOLDER="/tmp/*"
for f in $SEARCH_FOLDER
do
if [ -d "$f" ]
then
for ff in $f/*
do
echo "Processing $ff"
done
else
echo "Processing file $f"
fi
done
I need help to complete the code, since I'm not getting anywhere.
As a followup to mouviciel's answer, you could also do this as a for loop, instead of using xargs. I often find xargs cumbersome, especially if I need to do something more complicated in each iteration.
for f in $(find /tmp -name '*.pdf' -or -name '*.doc'); do rm $f; done
As a number of people have commented, this will fail if there are spaces in filenames. You can work around this by temporarily setting the IFS (internal field seperator) to the newline character. This also fails if there are wildcard characters \[?* in the file names. You can work around that by temporarily disabling wildcard expansion (globbing).
IFS=$'\n'; set -f
for f in $(find /tmp -name '*.pdf' -or -name '*.doc'); do rm "$f"; done
unset IFS; set +f
If you have newlines in your filenames, then that won't work either. You're better off with an xargs based solution:
find /tmp \( -name '*.pdf' -or -name '*.doc' \) -print0 | xargs -0 rm
(The escaped brackets are required here to have the -print0 apply to both or clauses.)
GNU and *BSD find also has a -delete action, which would look like this:
find /tmp \( -name '*.pdf' -or -name '*.doc' \) -delete
find is just made for that.
find /tmp -name '*.pdf' -or -name '*.doc' | xargs rm
Without find:
for f in /tmp/* tmp/**/* ; do
...
done;
/tmp/* are files in dir and /tmp/**/* are files in subfolders. It is possible that you have to enable globstar option (shopt -s globstar).
So for the question the code should look like this:
shopt -s globstar
for f in /tmp/*.pdf /tmp/*.doc tmp/**/*.pdf tmp/**/*.doc ; do
rm "$f"
done
Note that this requires bash ≥4.0 (or zsh without shopt -s globstar, or ksh with set -o globstar instead of shopt -s globstar). Furthermore, in bash <4.3, this traverses symbolic links to directories as well as directories, which is usually not desirable.
If you want to do something recursively, I suggest you use recursion (yes, you can do it using stacks and so on, but hey).
recursiverm() {
for d in *; do
if [ -d "$d" ]; then
(cd -- "$d" && recursiverm)
fi
rm -f *.pdf
rm -f *.doc
done
}
(cd /tmp; recursiverm)
That said, find is probably a better choice as has already been suggested.
Here is an example using shell (bash):
#!/bin/bash
# loop & print a folder recusively,
print_folder_recurse() {
for i in "$1"/*;do
if [ -d "$i" ];then
echo "dir: $i"
print_folder_recurse "$i"
elif [ -f "$i" ]; then
echo "file: $i"
fi
done
}
# try get path from param
path=""
if [ -d "$1" ]; then
path=$1;
else
path="/tmp"
fi
echo "base path: $path"
print_folder_recurse $path
This doesn't answer your question directly, but you can solve your problem with a one-liner:
find /tmp \( -name "*.pdf" -o -name "*.doc" \) -type f -exec rm {} +
Some versions of find (GNU, BSD) have a -delete action which you can use instead of calling rm:
find /tmp \( -name "*.pdf" -o -name "*.doc" \) -type f -delete
For bash (since version 4.0):
shopt -s globstar nullglob dotglob
echo **/*".ext"
That's all.
The trailing extension ".ext" there to select files (or dirs) with that extension.
Option globstar activates the ** (search recursivelly).
Option nullglob removes an * when it matches no file/dir.
Option dotglob includes files that start wit a dot (hidden files).
Beware that before bash 4.3, **/ also traverses symbolic links to directories which is not desirable.
This method handles spaces well.
files="$(find -L "$dir" -type f)"
echo "Count: $(echo -n "$files" | wc -l)"
echo "$files" | while read file; do
echo "$file"
done
Edit, fixes off-by-one
function count() {
files="$(find -L "$1" -type f)";
if [[ "$files" == "" ]]; then
echo "No files";
return 0;
fi
file_count=$(echo "$files" | wc -l)
echo "Count: $file_count"
echo "$files" | while read file; do
echo "$file"
done
}
This is the simplest way I know to do this:
rm **/#(*.doc|*.pdf)
** makes this work recursively
#(*.doc|*.pdf) looks for a file ending in pdf OR doc
Easy to safely test by replacing rm with ls
The following function would recursively iterate through all the directories in the \home\ubuntu directory( whole directory structure under ubuntu ) and apply the necessary checks in else block.
function check {
for file in $1/*
do
if [ -d "$file" ]
then
check $file
else
##check for the file
if [ $(head -c 4 "$file") = "%PDF" ]; then
rm -r $file
fi
fi
done
}
domain=/home/ubuntu
check $domain
There is no reason to pipe the output of find into another utility. find has a -delete flag built into it.
find /tmp -name '*.pdf' -or -name '*.doc' -delete
The other answers provided will not include files or directories that start with a . the following worked for me:
#/bin/sh
getAll()
{
local fl1="$1"/*;
local fl2="$1"/.[!.]*;
local fl3="$1"/..?*;
for inpath in "$1"/* "$1"/.[!.]* "$1"/..?*; do
if [ "$inpath" != "$fl1" -a "$inpath" != "$fl2" -a "$inpath" != "$fl3" ]; then
stat --printf="%F\0%n\0\n" -- "$inpath";
if [ -d "$inpath" ]; then
getAll "$inpath"
#elif [ -f $inpath ]; then
fi;
fi;
done;
}
I think the most straightforward solution is to use recursion, in the following example, I have printed all the file names in the directory and its subdirectories.
You can modify it according to your needs.
#!/bin/bash
printAll() {
for i in "$1"/*;do # for all in the root
if [ -f "$i" ]; then # if a file exists
echo "$i" # print the file name
elif [ -d "$i" ];then # if a directroy exists
printAll "$i" # call printAll inside it (recursion)
fi
done
}
printAll $1 # e.g.: ./printAll.sh .
OUTPUT:
> ./printAll.sh .
./demoDir/4
./demoDir/mo st/1
./demoDir/m2/1557/5
./demoDir/Me/nna/7
./TEST
It works fine with spaces as well!
Note:
You can use echo $(basename "$i") # print the file name to print the file name without its path.
OR: Use echo ${i%/##*/}; # print the file name which runs extremely faster, without having to call the external basename.
Just do
find . -name '*.pdf'|xargs rm
If you can change the shell used to run the command, you can use ZSH to do the job.
#!/usr/bin/zsh
for file in /tmp/**/*
do
echo $file
done
This will recursively loop through all files/folders.
The following will loop through the given directory recursively and list all the contents :
for d in /home/ubuntu/*;
do
echo "listing contents of dir: $d";
ls -l $d/;
done