How to solve 5 * 5 Cube in efficient easy way - algorithm

Question

There is 5*5 cube puzzle named Happy cube Problem where for given mat , need to make a cube .
http://www.mathematische-basteleien.de/cube_its.htm#top
Its like, 6 blue mats are given-
From the following mats, Need to derive a Cube -
These way it has 3 more solutions.
So like first cub
For such problem, the easiest approach I could imagine was Recursion based where for each cube, I have 6 position , and for each position I will try check all other mate and which fit, I will go again recursively to solve the same. Like finding all permutations of each of the cube and then find which fits the best.So Dynamic Programming approach.
But I am making loads of mistake in recursion , so is there any better easy approach which I can use to solve the same?
I made matrix out of each mat or diagram provided, then I rotated them in each 90 clock-wise 4 times and anticlock wise times . I flip the array and did the same, now for each of the above iteration I will have to repeat the step for other cube, so again recursion .
0 0 1 0 1
1 1 1 1 1
0 1 1 1 0
1 1 1 1 1
0 1 0 1 1
-------------
0 1 0 1 0
1 1 1 1 0
0 1 1 1 1
1 1 1 1 0
1 1 0 1 1
-------------
1 1 0 1 1
0 1 1 1 1
1 1 1 1 0
0 1 1 1 1
0 1 0 1 0
-------------
1 0 1 0 0
1 1 1 1 1
0 1 1 1 0
1 1 1 1 1
1 1 0 1 0
-------------
1st - block is the Diagram
2nd - rotate clock wise
3rd - rotate anti clockwise
4th - flip
Still struggling to sort out the logic .

Answer 1

I can't believe this, but I actually wrote a set of scripts back in 2009 to brute-force solutions to this exact problem, for the simple cube case. I just put the code on Github: https://github.com/niklasb/3d-puzzle
Unfortunately the documentation is in German because that's the only language my team understood, but source code comments are in English. In particular, check out the file puzzle_lib.rb.
The approach is indeed just a straightforward backtracking algorithm, which I think is the way to go. I can't really say it's easy though, as far as I remember the 3-d aspect is a bit challenging. I implemented one optimization: Find all symmetries beforehand and only try each unique orientation of a piece. The idea is that the more characteristic the pieces are, the less options for placing pieces exist, so we can prune early. In the case of many symmetries, there might be lots of possibilities and we want to inspect only the ones that are unique up to symmetry.
Basically the algorithm works as follows: First, assign a fixed order to the sides of the cube, let's number them 0 to 5 for example. Then execute the following algorithm:
def check_slots():
for each edge e:
if slot adjacent to e are filled:
if the 1-0 patterns of the piece edges (excluding the corners)
have XOR != 0:
return false
if the corners are not "consistent":
return false
return true
def backtrack(slot_idx, pieces_left):
if slot_idx == 6:
# finished, we found a solution, output it or whatever
return
for each piece in pieces_left:
for each orientation o of piece:
fill slot slot_idx with piece in orientation o
if check_slots():
backtrack(slot_idx + 1, pieces_left \ {piece})
empty slot slot_idx
The corner consistency is a bit tricky: Either the corner must be filled by exactly one of the adjacent pieces or it must be accessible from a yet unfilled slot, i.e. not cut off by the already assigned pieces.
Of course you can ignore to drop some or all of the consistency checks and only check in the end, seeing as there are only 8^6 * 6! possible configurations overall. If you have more than 6 pieces, it becomes more important to prune early.