XSLT - how can I filter data source by data from external XML? - xpath

Question

I have the following XML data structure:
<root>
<info>
<creationDate>2015-03-11 11:45:49</creationDate>
</info>
<promotions>
<promotion>
<header>
<id>1</id>
<name>Name 1</name>
</header>
<positions>
<position>
<id>1</id>
<name>Some position name 1</name>
</position>
<position>
<id>2</id>
<name>Some position name 2</name>
</position>
</position>
</positions>
</promotion>
<promotion>
<header>
<id>2</id>
<name>Name 2</name>
</header>
<positions>
<position>
<id>3</id>
<name>Some position name 3</name>
</position>
</positions>
</promotion>
</promotions>
</root>
Which is used as primary data source for my template like this:
<xsl:template match="root">
...
I need to filter the above by "filter.xml" file, containing promotion Id's to filter out, and it needs to work on IE7 . Is something like this possible?
For starters I tried to find a way to add filter in xsl:apply-templates select statement, so that only promotion with Id=2 will be processed by template but failed - is it possible to write Xpath that will say:
"Give me everything from root node but promotions only with Id = 2" ?
Thanks.
EDIT1:
Sorry about the namespace - it shouldn't be there in the first place. As for the filter.xml - it is not clearly defined yet - for now, I'm using the following:
<usedUpPromotions>
<header>
<promotionId>
1
</promotionId>
</header>
<header>
<promotionId>
2
</promotionId>
</header>
<header>
<promotionId>
3
</promotionId>
</header>
</usedUpPromotions>
I think of using something like:
<xsl:apply-templates select="root[hereIsMyWhereId != (document('Load externalXmlHere')/select/IdtoFilterOut)"/>
But I can't seem to find a way to filter out data that way...
EDIT2:
I'll try to explain using code as example - let's assume for a moment that we have the following:
XmlData initialXmlData; <- this is our XML data before filtering
XmlData filter; -< this contains the filter.xml data
Html GenerateHtmlFromTemplate(XmlData initialXmlData) - this is my Xslt template
{
...some precessing here
}
I would like to modify my template to achieve the following:
Html GenerateHtmlFromTemplate(XmlData initialXmlData, XmlData filter)
{
XmlData filteredData = data.FilterBy(filter);
...same processing here as above, but use 'filteredData', instead of 'initialXmlData'
}
I hope it's more clear now :) - the main problem, it would seem is that the Id element, I want to filter by, is inside array variable, so I cannot simply use:
in my primary template - instead I bypassed the problem, by filtering on for-each loop later on but I would still like to know if it is possible to simply tell the template "from now on use filtered data, instead of original".
Edit3:
#michael.hor257k - to answer your question, I have modified templates you provided:
Template.xml:
<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/xsl" href="#"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:ksx="http://www.test.com/test" xmlns:ds="http://www.w3.org/2000/09/xmldsig#">
<xsl:output encoding="utf-8" indent="no" method="html"/>
<root xmlns="http://www.test.com/test">
<info>
<creationDate>2015-03-11 11:45:49</creationDate>
</info>
<promotions>
<promotion>
<header>
<id atr="tre">1</id>
<name>Promotion 1</name>
</header>
<positions>
<position>
<id>1</id>
<name>Position 1a</name>
</position>
<position>
<id>2</id>
<name>Position 1b</name>
</position>
</positions>
</promotion>
<promotion>
<header>
<id>2</id>
<name>Promotion 2</name>
</header>
<positions>
<position>
<id>3</id>
<name>Position 2a</name>
</position>
</positions>
</promotion>
</promotions>
</root>
<xsl:param name="new-path" select="'new.xml'"/>
<xsl:variable name="new-promotions" select="document($new-path)/newPromotions/promotion" />
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="ksx:root">
<xsl:copy>
<xsl:apply-templates select="ksx:promotions/ksx:promotion[not(ksx:header/ksx:id=$new-promotions/header/id)]"/>
<xsl:apply-templates select="$new-promotions"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
new.xml:
<?xml version="1.0" encoding="utf-8"?>
<newPromotions>
<promotion>
<header>
<id>2</id>
<name>New Promotion 2</name>
</header>
<positions>
<position>
<id>4</id>
<name>New Position 2A</name>
</position>
</positions>
</promotion>
<promotion>
<header>
<id>3</id>
<name>New Promotion 3</name>
</header>
<positions>
<position>
<id>5</id>
<name>New Position 3A</name>
</position>
</positions>
</promotion>
</newPromotions>
If you save those, and open template.xml in Chrome it will work nicely - what I wanted however was to filter out data outside template node:
<xsl:template match="ksx:root">
So, I tried this:
<xsl:template match="ksx:root[ksx:promotion/ksx:header/ksx:id=1]">
And I expected to get all data from root but with promotions filtered to those with Id = 1 - but it gave all data and no errors, now I noticed that this:
<xsl:template match="ksx:root[ksx:promotions/ksx:promotion/ksx:header/ksx:id=$new-promotions/header/id]">
causes an error "Variables cannot be used within this expression" - so I guess, what I want to do is probably impossible from outside the template node...?
Sorry for the confusion - I hope now it is more clear. I simply wanted to treat template node as a method and "pass" filtered data to it, instead of filtering the data inside of it.
Edit4:
In my specific case, I have large "root" dataset of promotions, and small, external XML file that contains promotion Id's to hide during processing. So in my case filtering would mean: "Take everything from root element, but filter promotions so only those which Ids are NOT in the external file, will be processed". So if I have:
<root xmlns="http://www.test.com/test">
<info>
<creationDate>2015-03-11 11:45:49</creationDate>
</info>
<someData1>Some data 1</someData1>
<someData2>Some data 2</someData2>
<someData3>Some data 3</someData3>
<promotions>
<promotion>
<header>
<id>1</id>
<name>Promotion 1</name>
</header>
<positions>
<position>
<id>1</id>
<name>Position 1a</name>
</position>
<position>
<id>2</id>
<name>Position 1b</name>
</position>
</positions>
</promotion>
<promotion>
<header>
<id>2</id>
<name>Promotion 2</name>
</header>
<positions>
<position>
<id>3</id>
<name>Position 2a</name>
</position>
</positions>
</promotion>
<promotion>
<header>
<id>3</id>
<name>Promotion 3</name>
</header>
<positions>
<position>
<id>4</id>
<name>Position 3a</name>
</position>
</positions>
</promotion>
</promotions>
</root>
And filter by:
<?xml version="1.0" encoding="UTF-8"?>
<usedUpPromotions>
<id>1</id>
<id>2</id>
</usedUpPromotions>
Then I would expect to get:
<root xmlns="http://www.test.com/test">
<info>
<creationDate>2015-03-11 11:45:49</creationDate>
</info>
<someData1>Some data 1</someData1>
<someData2>Some data 2</someData2>
<someData3>Some data 3</someData3>
<promotions>
<promotion>
<header>
<id>3</id>
<name>Promotion 3</name>
</header>
<positions>
<position>
<id>4</id>
<name>Position 3a</name>
</position>
</positions>
</promotion>
</promotions>
</root>

Answer 1

To process only promotions with Id=2, you can use (from the context of root):
<xsl:apply-templates select="promotions/promotion[header/id='2']"/>
Added:
Here's an example showing how you can "merge" your input XML with an overriding XML document. Given:
XML
<root>
<info>
<creationDate>2015-03-11 11:45:49</creationDate>
</info>
<promotions>
<promotion>
<header>
<id>1</id>
<name>Promotion 1</name>
</header>
<positions>
<position>
<id>1</id>
<name>Position 1a</name>
</position>
<position>
<id>2</id>
<name>Position 1b</name>
</position>
</positions>
</promotion>
<promotion>
<header>
<id>2</id>
<name>Promotion 2</name>
</header>
<positions>
<position>
<id>3</id>
<name>Position 2a</name>
</position>
</positions>
</promotion>
</promotions>
</root>
new.xml
<newPromotions>
<promotion>
<header>
<id>2</id>
<name>New Promotion 2</name>
</header>
<positions>
<position>
<id>4</id>
<name>New Position 2A</name>
</position>
</positions>
</promotion>
<promotion>
<header>
<id>3</id>
<name>New Promotion 3</name>
</header>
<positions>
<position>
<id>5</id>
<name>New Position 3A</name>
</position>
</positions>
</promotion>
</newPromotions>
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:param name="new-path" select="'path/to/new.xml'"/>
<xsl:variable name="new-promotions" select="document($new-path)/newPromotions/promotion" />
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="promotions">
<xsl:copy>
<xsl:apply-templates select="promotion[not(header/id=$new-promotions/header/id)]"/>
<xsl:apply-templates select="$new-promotions"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Result
<?xml version="1.0" encoding="UTF-8"?>
<root>
<info>
<creationDate>2015-03-11 11:45:49</creationDate>
</info>
<promotions>
<promotion>
<header>
<id>1</id>
<name>Promotion 1</name>
</header>
<positions>
<position>
<id>1</id>
<name>Position 1a</name>
</position>
<position>
<id>2</id>
<name>Position 1b</name>
</position>
</positions>
</promotion>
<promotion>
<header>
<id>2</id>
<name>New Promotion 2</name>
</header>
<positions>
<position>
<id>4</id>
<name>New Position 2A</name>
</position>
</positions>
</promotion>
<promotion>
<header>
<id>3</id>
<name>New Promotion 3</name>
</header>
<positions>
<position>
<id>5</id>
<name>New Position 3A</name>
</position>
</positions>
</promotion>
</promotions>
</root>
In response to your edit #4:
So in my case filtering would mean: "Take everything from root
element, but filter promotions so only those which Ids are NOT in the
external file, will be processed".
My answer above does two things:
It copies everything from the input XML document except promotions whose IDs are in the external file;
It adds all the promotions listed in the external file.
If you only want to do #1 but not #2, then change this:
<xsl:template match="promotions">
<xsl:copy>
<xsl:apply-templates select="promotion[not(header/id=$new-promotions/header/id)]"/>
<xsl:apply-templates select="$new-promotions"/>
</xsl:copy>
</xsl:template>
to:
<xsl:template match="promotions">
<xsl:copy>
<xsl:apply-templates select="promotion[not(header/id=$new-promotions/header/id)]"/>
</xsl:copy>
</xsl:template>
In the given example, the result will be:
<?xml version="1.0" encoding="UTF-8"?>
<root>
<info>
<creationDate>2015-03-11 11:45:49</creationDate>
</info>
<promotions>
<promotion>
<header>
<id>1</id>
<name>Promotion 1</name>
</header>
<positions>
<position>
<id>1</id>
<name>Position 1a</name>
</position>
<position>
<id>2</id>
<name>Position 1b</name>
</position>
</positions>
</promotion>
</promotions>
</root>