serialize temporary into boost archive - c++11

The following is not possible for any boost output archive:
int foo(){
return 4;
}
ar << static_cast<unsigned int>(foo());
Is there an alternative without out creating a local temporary x=foo().
and why is the underlying archive operator <<(T & t) not const reference , for an output archive such that the above would work?

This seems to work, and I think this is why:
... To help detect such cases, output archive operators expect to be
passed const reference arguments.
It seems worth noting that in your example ar << foo(); does not work either (i.e. it doesn't have to do with your cast).
#include <fstream>
#include <iostream>
#include <boost/serialization/serialization.hpp>
#include <boost/archive/text_iarchive.hpp>
#include <boost/archive/text_oarchive.hpp>
unsigned int foo(){
return 4;
}
int main()
{
{
std::ofstream outputStream("someFile.txt");
boost::archive::text_oarchive outputArchive(outputStream);
outputArchive << static_cast<const int&>(foo());
}
std::ifstream inputStream("someFile.txt");
boost::archive::text_iarchive inputArchive(inputStream);
int readBack;
inputArchive >> readBack;
std::cout << "Read back: " << readBack << std::endl;
return 0;
}

Related

How to use std::chrono::milliseconds as a default parameter

Scenario
I have a C++ function which intakes a parameter as std::chrono::milliseconds. It is basically a timeout value. And, it is a default parameter set to some value by default.
Code
#include <iostream>
#include <chrono>
void Fun(const std::chrono::milliseconds someTimeout = std::chrono::milliseconds(100)) {
if (someTimeout > 0) {
std::cout << "someNumberInMillis is: " << someNumberInMillis.count() << std::endl;
}
}
int main() {
unsigned int someValue = 500;
Fun(std::chrono::milliseconds(someValue))
}
Issue
All of above is okay but, when I call Fun with a value then fails to compile and I get the following error:
No viable conversion from 'bool' to 'std::chrono::milliseconds' (aka
'duration >')
Question:
What am I doing wrong here? I want the caller of Fun to be explicitly aware that it is using std::chrono::milliseconds when it invokes Fun. But the compiler doesn't seem to allow using std::chrono::milliseconds as a parameter?
How use std::chrono::milliseconds as a default parameter?
Environment
Compiler used is clang on macOS High Sierra
With the other syntax errors fixed, this compiles without warnings in GCC 9:
#include <iostream>
#include <chrono>
void Fun(const std::chrono::milliseconds someNumberInMillis
= std::chrono::milliseconds(100))
{
if (someNumberInMillis > std::chrono::milliseconds{0}) {
std::cout << "someNumberInMillis is: " << someNumberInMillis.count()
<< std::endl;
}
}
int main()
{
unsigned int someValue = 500;
Fun(std::chrono::milliseconds(someValue));
}

Why forwarding reference does not work?

I have problem with this piece of code:
#include <string>
#include <iostream>
struct A{
template<class UT>
A(UT &&s) : internal(std::forward<std::string>(s)){
}
std::string internal;
};
int main(){
const std::string &s = "hello";
A a1{ s };
std::cout << "s = " << s << std::endl;
}
This current example does not compiles and if I change s to be non const, it moves the string.
I have similar codes that works OK, but in this case there is something wrong I can not see.
You are using a forwarding reference incorrectly. You don't give std::forward the destination type. You give it the template it deduced:
A(UT &&s) : internal(std::forward<UT>(s)){

Move or swap a stringstream

I want to move a stringstream, in the real world application I have some stringstream class data member, which I want to reuse for different string's during operation.
stringstream does not have a copy-assignment or copy constructor, which makes sense. However, according to cppreference.com and cplusplus.com std::stringstream should have a move assignment and swap operation defined. I tried both, and both fail.
Move assignment
#include <string> // std::string
#include <iostream> // std::cout
#include <sstream> // std::stringstream
int main () {
std::stringstream stream("1234");
//stream = std::move(std::stringstream("5678"));
stream.operator=(std::move(std::stringstream("5678")));
//stream.operator=(std::stringstream("5678"));
return 0;
}
source: http://ideone.com/Izyanb
prog.cpp:11:56: error: use of deleted function ‘std::basic_stringstream<char>& std::basic_stringstream<char>::operator=(const std::basic_stringstream<char>&)’
stream.operator=(std::move(std::stringstream("5678")));
The compiler states that there is no copy assignment for all three statements, which is true. However, I fail to see why it is not using the move-assignment, especially since std::move is supposed to return a rvalue reference. Stringstream should have a move assignment, as shown here: http://en.cppreference.com/w/cpp/io/basic_stringstream/operator%3D
PS: I'm working with c++11, hence rvalue-references are part of the 'world'.
Swap
This I found really strange, I copied example code from cplusplus.com and it failed:
// swapping stringstream objects
#include <string> // std::string
#include <iostream> // std::cout
#include <sstream> // std::stringstream
int main () {
std::stringstream foo;
std::stringstream bar;
foo << 100;
bar << 200;
foo.swap(bar);
int val;
foo >> val; std::cout << "foo: " << val << '\n';
bar >> val; std::cout << "bar: " << val << '\n';
return 0;
}
source: http://ideone.com/NI0xMS
cplusplus.com source: http://www.cplusplus.com/reference/sstream/stringstream/swap/
prog.cpp: In function ‘int main()’:
prog.cpp:14:7: error: ‘std::stringstream’ has no member named ‘swap’
foo.swap(bar);
What am I missing? Why can't I move or swap a stringstream? How should I swap or move a stringstream?
This is a missing feature on GCC : see bug 54316 , it has been fixed (you can thank Jonathan Wakely) for the next versions (gcc 5)
Clang with libc++ compiles this code :
int main () {
std::stringstream stream("1234");
std::stringstream stream2 = std::move(std::stringstream("5678"));
return 0;
}
Live demo
And it also compiles the example with std::stringstream::swap
I have an alternative to moving or swapping, one can also clear and set a stringstream to a new string:
#include <string> // std::string
#include <iostream> // std::cout
#include <sstream> // std::stringstream
int main () {
std::stringstream ss("1234");
ss.clear();
ss.str("5678");
int val;
ss >> val; std::cout << "val: " << val << '\n';
return 0;
}
It's a clean work around that does not require one to refactor code, except for the localized section where the swap is changed to a clear() and str().

Storing a boost::spirit::qi::rule in a std::list

I have read the other thread about copy or reference semantics for boost::spirt::qi::rule. I am using Boost 1.42.
using boost::spirit::qi::phrase_parse;
typedef boost::spirit::qi::rule < std::string::const_iterator, boost::spirit::ascii::space_type > rule_type;
std::list < rule_type > ruleList;
std::string const s("abcdef");
std::string::const_iterator iter = s.begin(), end = s.end();
std::cout << typeid(char_).name() << std::endl;
ruleList.push_back(char_);
ruleList.push_back(*ruleList.back());
assert(phrase_parse(iter, s.end(), ruleList.back(), boost::spirit::ascii::space));
assert(iter == s.end());
This fails with...
Assertion `phrase_parse(iter, s.end(), ruleList.back(), traits::space())' failed.
Aborted (core dumped)
Is there a way to store rules in a STL list or deque? (References don't die until removed).
With Boost V1.45, this (essentially your code from above) works without problems (MSVC2010, g++ 4.5.1):
#include <list>
#include <string>
#include <iostream>
#include <boost/spirit/include/qi.hpp>
using namespace boost::spirit;
int main()
{
typedef qi::rule<std::string::const_iterator, ascii::space_type> rule_type;
std::list<rule_type> ruleList;
std::string const s("abcdef");
std::string::const_iterator iter = s.begin(), end = s.end();
std::cout << typeid(qi::char_).name() << std::endl;
ruleList.push_back(qi::char_);
ruleList.push_back(*ruleList.back());
assert(qi::phrase_parse(iter, s.end(), ruleList.back(), ascii::space));
assert(iter == s.end());
return 0;
}
Therefore, I assume it's a bug in the version of Spirit you're using.
I could not get your example to compile. Aside from not using the correct types from ...::qi, you added a () to the trait::space type.
This works w/o problem for me (boost 1.44)
#include <boost/spirit/include/qi.hpp>
#include <string>
#include <vector>
#include <cassert>
using boost::spirit::qi::phrase_parse;
typedef boost::spirit::qi::rule < std::string::const_iterator, boost::spirit::qi::space_type > rule_type;
int main() {
std::list < rule_type > ruleList;
std::string const s("abcdef");
std::string::const_iterator iter = s.begin(), end = s.end();
ruleList.push_back(*boost::spirit::qi::char_);
assert(phrase_parse(iter, s.end(), ruleList.back(), boost::spirit::qi::space));
assert(iter == s.end());
}
~>g++ test.cpp && ./a.out
~>
please note I use qi::space_type and `qi::space instead of the ascii namespace. I have no idea what/where the trait namespace is.

stringstream manipulators & vstudio 2003

I am trying to use a stringstream object in VC++ (VStudio 2003) butI am getting an error when I use the overloaded << operator to try and set some manipulators.
I am trying the following:
int SomeInt = 1;
stringstream StrStream;
StrStream << std::setw(2) << SomeInt;
This will not compile (error C2593: 'operator <<' is ambiguous).
Does VStudio 2003 support using manipulators in this way?
I know that I can just set the width directly on the stringstream object e.g. StrStream.width(2);
I was wondering why the more usual method doesn't work?
Are you sure you included all of the right headers? The following compiles for me in VS2003:
#include <iostream>
#include <sstream>
#include <iomanip>
int main()
{
int SomeInt = 1;
std::stringstream StrStream;
StrStream << std::setw(2) << SomeInt;
return 0;
}
I love this reference site for stream questions like this.
/Allan
You probably just forgot to include iomanip, but I can't be sure because you didn't include code for a complete program there.
This complete program works fine over here using VS 2003:
#include <sstream>
#include <iomanip>
int main()
{
int SomeInt = 1;
std::stringstream StrStream;
StrStream << std::setw(2) << SomeInt;
}

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