I've written a couple of scripts that I want to run automatically on my computer, so I've added the line #! Applications/anaconda/bin/python to the beginning of each script to made it executable. Oddly enough, one of the programs worked perfectly after adding that line and then running chmod +x \path\to\program.py in the terminal. But for the second program I followed the same process but when I try and run the script from the terminal using \path\to\program.py I get an error which reads:
Applications/anaconda/bin/python^M: bad interpreter: No such file or directory. I understand that this means that I have a carriage return on the end of the line that's throwing it off, but I don't understand how to get rid of it. Here are the snippets from my two scripts, this one works:
#! /Applications/anaconda/bin/python
import time
from selenium import webdriver
import easygui
.
.
.
And this one doesn't:
#! Applications/anaconda/bin/python
from datetime import datetime
import calendar
.
.
.
After doing some more digging. I found that the problem was caused because I had edited the script using both a windows computer and a mac. All that was needed to fix the problem was to copy and paste the code to a new .py file and then it worked like a charm. There are also more technical work arounds here: PyCharm. /usr/bin/python^M: bad interpreter
Your second script is missing a "/" at the beginning.
This is, replace #! Applications/anaconda/bin/python with #! /Applications/anaconda/bin/python.
You should try opening your file using vim and run in command mode
:set fileformat=unix
Related
edit : I ended up upgrading to macOS Catalina yesterday and replacing bash with zsh. One thing that should be noted is that the stackcommand worked previously, but despite all the tinkering not ghci
After deleting all the files that had anything to do with Haskell, I retried running curl --proto '=https' --tlsv1.2 -sSf https://get-ghcup.haskell.org | sh
This second time there was an error with the command line tools so I had to install them manually with xcode-select --install. After rerunning the curl, I added the path to the environmental file to my zsh profile manually with :
. "$HOME/.ghcup/env"\
echo '. $HOME/.ghcup/env' >> "$HOME/.zshrc"
Here is the content of the env file :export PATH="$HOME/.cabal/bin:/Users/agnel/.ghcup/bin:$PATH"
Now everything seems to be working (I never reinstalled stack, but I think I might leave that to the side while I learn the basics of the language).
I installed the Haskell Platform yesterday but am having a hard time getting it to work correctly.
The firsts steps I did are:
curl -sSL https://get.haskellstack.org/ | sh
curl --proto '=https' --tlsv1.2 -sSf https://get-ghcup.haskell.org | sh
On step 1. the instructions said to append /Users/.../.local/bin the PATH variable (which I did in /etc/paths. On step 2, the script was supposed to pop up a dialog box (and didn't) when installing the necessary command line tools. It also said to rerun the script once complete (which I did). The script also said I should adjust my PATH variable, and source /Users/.../.ghcup/env in my shell configuration. It asked to this automatically but failed having not found the ~/.bashrc File. (I read that on Mac in contrary to linux, only .bash_profile is loaded upon opening of a terminal window so I adjusted the path variable there manually. I've spent forever messing around with the path variables and every time I try and run "$ ghci" I get the same -bash: ghci: command not found error message. If anyone has a solution to this problem I would be very grateful for an answer. If not, could someone with a working distribution of Haskell on their computer show me what their path variables look like?
Thanks!
A simple solution would just be to restart your terminal and you are good to go.
After installing the Haskell platform for the first time on a new mac with Catalina, I also got
~> ghci
zsh: command not found: ghci
What worked in my case was to use, instead of the plain ghci,
stack ghci
To get back the familiar behaviour, I created in my homedirectory a file named .zshrc containing
alias ghci='stack ghci'
If you open a new terminal, this file will automatically be executed.
I'd be interested to know if there is another solution.
Check if the ghcup command is working or not.
If not, make sure the .zshrc file has command for execution of ghcup. It should look something like this -
[ -f "/Users/myusername/.ghcup/env" ] && source "/Users/myusername/.ghcup/env" # ghcup-env
If the file exists, simply restarting terminal will work.
If it is still not working, set GHC as default using ghcup - follow this
So I have a script called kc which compiles Kotlin files into a jar.
The file is located at ~/Documents/KotlinPlayground/bin and my $PATH looks like this:
/usr/local/bin:/usr/bin:/bin:/usr/sbin:/sbin:~/Documents/KotlinPlayground/bin:~/Library/Android/sdk/platform-tools/
when I just type kc SomeFilt.kt into the command line I get a zsh: command not found: kc, but if I type in ~/Documents/KotlinPlayground/bin/kc SomeFile.kt it works.
So how come zsh can't find my script even though its in the path?
Here is an image showing the problem:
I also tried adding #!/bin/bash to the top of kc and continued getting the same issue
I think the problem is that zsh is not interpreting ~/ correctly. You could replace ~/Documents to /home/user/Documents to solve the problem.
I am writing some automation to control a simulator. I am also using WebDriverAgent along with openatx python bindings in pycharm. There are some things that are fast using cURL in a bash script and some methods that are stronger in the python solution. I want to use a mix of both. I have imported bashSupport into pycharm and would like to execute a bash script from within my file system of the project.
I have tried subprocess import and os but it doesn't seem to be executing my script. Here is an example:
import subprocess
subprocess.call(['launch_wda.sh'])
with device.session('com.apple.mobilesafari') as app:
print app.orientation
app(label="Address").tap()
app(label="Address").set_text("facebook.com \n")
the launch_wda.sh is in my file structure of the project. Is my syntax incorrect or am I missing something else?
Try these changes:
Add ./ before script name. As this could be some path related issue.
Try adding shell=True if you are not under Posix system and you do not have something like this #!/bin/sh as a first line of your bash script.
Last but not the least, check the permissions for the bash script.
Hope this helps.
I tried activating a VirtualEnv through a shell script like the one below but it doesn't seem to work,
#!/bin/sh
source ~/.virtualenvs/pinax-env/bin/activate
I get the following error
$ sh virtualenv_activate.sh
virtualenv_activate.sh: 2: source: not found
but if I enter the same command on terminal it seems to work
$ source ~/.virtualenvs/pinax-env/bin/activate
(pinax-env)gautam#Aspirebuntu:$
So I changed the shell script to
#!/bin/bash
source ~/.virtualenvs/pinax-env/bin/activate
as suggested and used
$ bash virtualenv_activate.sh
gautam#Aspirebuntu:$
to run the script .
That doesn't throw an error but neither does that activate the virtual env
So any suggestion on how to solve this problem ?
PS : I am using Ubuntu 11.04
TLDR
Must run the .sh script with source instead of the script solely
source your-script.sh
and not
your-script.sh
Details
sh is not the same as bash (although some systems simply link sh to bash, so running sh actually runs bash). You can think of sh as a watered down version of bash. One thing that bash has that sh does not is the "source" command. This is why you're getting that error... source runs fine in your bash shell. But when you start your script using sh, you run the script in an shell in a subprocess. Since that script is running in sh, "source" is not found.
The solution is to run the script in bash instead. Change the first line to...
#!/bin/bash
Then run with...
./virtualenv_activate.sh
...or...
/bin/bash virtualenv_activate.sh
Edit:
If you want the activation of the virtualenv to change the shell that you call the script from, you need to use the "source" or "dot operator". This ensures that the script is run in the current shell (and therefore changes the current environment)...
source virtualenv_activate.sh
...or...
. virtualenv_activate.sh
As a side note, this is why virtualenv always says you need to use "source" to run it's activate script.
source is an builtin shell command in bash, and is not available in sh. If i remember correctly then virtual env does a lot of path and environment variables manipulation. Even running it as bash virtualenv_blah.sh wont work since this will simply create the environment inside the sub-shell.
Try . virtualenv_activate.sh or source virtualenv_activate.sh this basically gets the script to run in your current environment and all the environment variables modified by virtualenv's activate will be available.
HTH.
Edit: Here is a link that might help - http://ss64.com/bash/period.html
On Mac OS X your proposals seems not working.
I have done it this way. I'am not very happy with solution, but share it anyway here and hope, that maybe somebody will suggest the better one:
In activate.sh I have
echo 'source /Users/andi/.virtualenvs/data_science/bin/activate'
I give execution permissions by: chmod +x activate.sh
And I execute this way:
`./activate.sh`
Notice that there are paranthesis in form of ASCII code 96 = ` ( Grave accent )
For me best way work as below.
Create start-my-py-software.sh and pest below code
#!/bin/bash
source "/home/snippetbucket.com/source/AIML-Server-CloudPlatform/bin/activate"
python --version
python /home/snippetbucket.com/source/AIML-Server-CloudPlatform/main.py
Give file permission to run like below.
chmod +x start-my-py-software.sh
Now run like below
.start-my-py-software.sh
and that's it, start my python based server or any other code.
ubuntu #18.0
In my case, Ubuntu 16.04, the methods above didn't worked well or it needs much works.
I just made a link of 'activate' script file and copy it to home folder(or $PATH accessible folder) and renamed it simple one like 'actai'.
Then in a terminal, just call 'source actai'. It worked!
I have written a ruby daemon and I would like for it to run when I log in. It is normally run by going to the command line and calling ruby my_ruby_script.rb. How can I start my daemon on login? (Running 10.6 Snow Leopard).
There's an option to add applications etc that need to start at login, you could try writing a shell script or an apple script thing that launches terminal and runs ruby my_ruby_script.rb, or possibly even just add my_ruby_script.rb to this list after adding a #!/bin/env ruby line to the top of that file. http://support.apple.com/kb/HT2602?viewlocale=en_US gives precise instructions as to how to add an application to be started at login.
If you need to use AppleScript to actually start a terminal application (I believe this is not the case, but I am not in front of my mac now and hence can't test), just create an applescript file with something like
do shell script "ruby <path>/my_ruby_script.rb"
Hope this helps
As Panda said, add:
#!/bin/env ruby
to the begining of the file, and then you could add a reference to your file inside ~/.bashrc or ~/.profile or even /etc/profile , depending on your needs.
Check this out: https://stackoverflow.com/questions/3484429/profile-and-bashrc-doesnt-work-on-my-mac/3484472#3484472