Promise chaining with Q nodejs - promise

Question

I have this code here but I cannot figure out why the second FS.readfile() executes last. Basically I want to:
readFile(passwd)
.then(console(textpasswd)
.then(readFile(hosts).
.then(console(texthosts);
But what happens is the readFile(hosts) executes last in the chain. I sense something is wrong with my deferring, but what?
Here is the code
module.paths.push('/usr/local/lib/node_modules');
var Q = require('q');
var FS=require('fs');
var deferred = Q.defer();
var p=deferred.promise;
FS.readFile("/etc/passwd", "utf-8", function (error, text) {
if (error) {
deferred.reject(new Error(error));
} else {
deferred.resolve(text);
}
});
p.then(function (text) {
console.log(text);
}).then(FS.readFile("/etc/hosts", "utf-8", function (error, text) {
if (error) {
deferred.reject(new Error(error));
} else {
deferred.resolve(text);
}
})
).then(function (text) {
console.log(text);
});

Answer 1

The deferred must obtain a new promise to continue the chain correctly. Also notice the first (function())() must be executed to return a promise although you don't need to do it this way. So here is my solution. (I cleaned it up a little):
module.paths.push('/usr/local/lib/node_modules');
var Q = require('q');
var FS = require('fs');
(function () {
var deferred = Q.defer();
FS.readFile("/etc/passwd", "utf-8", function (error, text) {
if (error) {
deferred.reject(new Error(error));
} else {
deferred.resolve(text);
}
})
return deferred.promise;
})().then(function (text) {
console.log(text);
}).then(function () {
var deferred = Q.defer();
FS.readFile("/etc/hosts", "utf-8", function (error, text) {
if (error) {
deferred.reject(new Error(error));
} else {
deferred.resolve(text);
}
})
return deferred.promise;
}).then(function (text) {
console.log(text);
}).then(function () {
console.log('The End');
});