I have a varchar2(20) column with a value like '2015-01-26T20:29:51Z'.
I successfully convert it to a date with to_date(dEnteredDate,'YYYY-MM-DD"T"HH24:MI:SS"Z"')
I wish to convert it to local time by subtracting my SessionTimeZone, currently -07:00 and have a regular date with time, no timezone info.
I do this in MS SQL with;
SET #diff = datediff(hh,GetUTCDate(), GetDate());
SET #dlocal = DATEADD(hh, #diff, #UTCDateTime)
How can I accomplish the same in Oracle 10g?
You can do it like this:
select to_timestamp(dEnteredDate,'YYYY-MM-DD"T"HH24:MI:SS"Z"')- interval '7' hour from test_3;
Here - interval '7' hour will subtract the required time difference and give you the desired result without timezone.
You can do it like this
select cast(to_timestamp_TZ(dEnteredDate||' UTC','YYYY-MM-DD"T"HH24:MI:SS"Z" tzr') at local as date)
from ...
Related
I would like to know how to convert current time to TIMEZONE in oracle
I tried this and worked perfectly
SELECT (select tzname from qct_timezone_config tzc where gmtoffset =
(select usr_time_zone from qct_user_token where resource_id = 11385)) AS TIMEZONE,
TO_CHAR(CAST(SYSTIMESTAMP AS TIMESTAMP WITH TIME ZONE) AT TIME ZONE
(select tzname from qct_timezone_config tzc where gmtoffset =
(select usr_time_zone from qct_user_token where resource_id = 11385)),
'DD-MON-RR HH:MI:SS.FF AM') AS USER_TIME
FROM dual
But what i want to know is what if the time '03-AUG-2017 11.00.00 AM' is sent from the other system (i want to convert this time to a specific TimeZone) and how to rewrite this query.
You already have everthing in you query, to convert a timestamp to a specific timezone you have to use "AT TIME ZONE" precising the timezone you want your timestamp to be converted:
select systimestamp AT TIME ZONE 'America/Los_Angeles' "West Coast Time" from dual;
I'm not sure what you want to accomplish and the timestamp you want to convert needs to include a timezone if you want to convert it to another timezone.
Was wondering if anyone could help with precision time conversion.
Sample: 1501646399999 which is GMT: Wednesday, August 2, 2017 3:59:59.999 AM
I used the below query, but it always rounds off to 02-AUG-17 04:00:00. Can anyone please guide me
select TO_TIMESTAMP('1970-01-01 00:00:00.000', 'YYYY-MM-DD hh24:mi:SS.FF3') + ((1/86400000) * 1501646399999)
from dual;
The problem is that you're adding a number to your fixed timestamp, which is causing that timestamp to be implicitly converted to a date - which doesn't have sub-second precision.
If you add an interval instead then it stays as a timestamp:
alter session set nls_timestamp_format = 'YYYY-MM-DD HH24:MI:SS.FF3';
select TO_TIMESTAMP('1970-01-01 00:00:00.000', 'YYYY-MM-DD hh24:mi:SS.FF3')
+ numtodsinterval(1501646399999/1000, 'SECOND')
from dual;
TO_TIMESTAMP('1970-01-0
-----------------------
2017-08-02 03:59:59.999
Incidentally, you could slightly simplify your query with a timestamp literal:
select TIMESTAMP '1970-01-01 00:00:00' + numtodsinterval(...)
You may also want to check if you should be declaring that timestamp as being UTC, and converting back to local time zone after adding the epoch value; or leaving it explicitly as UTC but as a timestamp with time zone value. It depends exactly what that number is supposed to represent. (You said it's GMT/UTC, but still...)
I need a query to update a time in an appointment date by keeping the date but changing the time.
For example
10-Feb-2016 09:00:00
and i want to change it to 10-Feb-2016 10:00:00.
Update Appointment
set vdate = '10:00:00'
where vdate= '10-Feb-2016'
I get the "0 row has been updated'. Not sure if i'm missing something.
Thanks in advance.
You can use trunc() which sets the time part of a DATE (or TIMESTAMP) to 00:00:00, then add the 10 hours to it:
Update Appointment
set vdate = trunc(vdate) + interval '10' hour
where trunc(vdate) = DATE '2016-02-10'
This would change all rows that have a date 2016-02-10. If you only want to do that for those that are at 09:00 (ignoring the minutes and seconds) then just add one hour to those rows
Update Appointment
set vdate = trunc(vdate) + interval '1' hour
where trunc(vdate, 'hh24') = timestamp '2016-02-10 09:00:00'
trunc(vdate, 'hh24') will set the minutes and seconds of the date value to 00:00, so that the comparison with 2016-02-10 09:00:00 works properly.
Unrelated, but: do not rely on implicit data type conversion. '10-Feb-2016' is a string value, not a DATE literal. To specify a date either use an ANSI DATE literal (as I have done in the above statement) or use the to_date() function with a format mask to convert a string literal to a proper date value.
Your statement is subject to the evil implicit data type conversion and will fail if the SQL client running the statement uses a different NLS setting (it will fail on my computer for example)
If what you want to do is add an hour to a date, then you can do:
Update Appointment
set vdate = vdate + 1/24
where vdate = to_date('10/02/2016 09:00', 'dd/mm/yyyy hh24:mi');
since in Oracle, date differences are measured in number of days, and an hour is 1/24th of a day.
If what you want to do is specify an exact time (e.g. to 10:25:48), then you could do the following instead:
Update Appointment
set vdate = trunc(vdate) + 10/24 + 25/(24*60) + 48/(24*60*60)
where vdate = to_date('10/02/2016 09:00', 'dd/mm/yyyy hh24:mi');
Bear in mind that these updates will update all rows that have a date of 10th Feb 2016 at 9am. You'd need to change your query's where clause if you wanted to specify a more specific row or set of rows.
Try like this.
UPDATE MyTable
SET MyDate = DATEADD(HOUR, 4, CAST(CAST(MyDate AS DATE) AS DATETIME))
or
UPDATE MyTable
SET MyDate = DATEADD(HOUR, 4, CAST(FLOOR(CAST(MyDate AS FLOAT)) AS DATETIME))
How can i convert the result of select statement of time interval field in respective time in Am/Pm format.
My Field is:
Interval Day(2) To Second(6)
I tried this:
select To_Char(Att_EntranceTime , 'HH:MI AM') From EMPLOYEEATTENDENCETABLE;
however this does not help me, i have also tried to add the basetime from systime to my interval field but that did not help.. can someone suggest me what to do?
Intervals can't be directly formatted, as you've discovered. You can add your interval to any date which has its time set to midnight, and then format the resulting date to show the time in your desired format. For example you could add it to today's date using trunc(sysdate):
to_char(trunc(sysdate) + my_interval, 'HH:MI AM')
You need to truncate it to set the time to midnight; otherwise the result will be your interval plus the current system time.
Or you can use any fixed date; here's an example with some dummy data set-up:
create table my_table (my_interval interval day(2) to second(6));
insert into my_table (my_interval) values (interval '0 12:34:56.78' day to second);
insert into my_table (my_interval) values (interval '99 01:02:03.456' day to second);
select my_interval, to_char(date '1970-01-01' + my_interval, 'HH:MI AM') as formatted
from my_table;
MY_INTERVAL FORMATTED
-------------------- ---------
+00 12:34:56.780000 12:34 PM
+99 01:02:03.456000 01:02 AM
The second value shows a potential problem. Your interval is defined to allow a two-digit day number, which means the interval can span anything less than 100 days. If you only extract the time portion you lose that information about the number of days. That may be what you want to happen though. If the interval is supposed to be representing a time of day, which wanting to show AM/PM implies - and it's unusual to store an actual time separate from its date - then having or allowing a number of days seems strange.
We are using Oracle database.
In our table timestamp is stored as seconds since 1970, how can I convert the time stamp obtained through current_timestamp() function to seconds
This would do it:
select round((cast(current_timestamp as date) - date '1970-01-01')*24*60*60) from dual
Though I wouldn't use current_timestamp if I was only interested in seconds, I would use SYSDATE:
select round((SYSDATE - date '1970-01-01')*24*60*60) from dual
Maybe not completely relevant. I had to resolve other way around problem (e.g. Oracle stores timestamp in V$RMAN_STATUS and V$RMAN_OUTPUT) and I had to convert that to date/timestamp. I was surprised, but the magic date is not 1970-01-01 there, but 1987-07-07. I looked at Oracle's history and the closest date I can think of is when they ported Oracle products to UNIX. Is this right?
Here's my SQL
SELECT /*+ rule */
to_char(min(stamp)/(24*60*60) + date '1987-07-07', 'DD-MON-YYYY HH24:MI:SS') start_tm
, to_char(to_char(max(stamp)/(24*60*60) + date '1987-07-07', 'DD-MON HH24:MI:SS')) end_tm
FROM V$RMAN_STATUS
START WITH (RECID, STAMP) =
(SELECT MAX(session_recid),MAX(session_stamp) FROM V$RMAN_OUTPUT)
CONNECT BY PRIOR RECID = parent_recid ;
I needed to send timestamp to GrayLog via GELF from Oracle DB. I tried different versions and solutions but only one worked correctly.
SQL:
SELECT REPLACE((CAST(dat AS DATE) - TO_DATE('19700101', 'YYYYMMDD')) * 86400 + MOD(EXTRACT(SECOND FROM dat), 1), ',', '.') AS millis
FROM (SELECT SYSTIMESTAMP AT TIME ZONE 'GMT' AS dat FROM dual)
The result for Systmiestamp
2018/12/18 19:47:29,080988 +02:00
will be
1545155249.080988