how to autowire bean in the servlet filters in spring application? - spring

Question

I have a spring-boot application.
I have no ApplicationContext.xml or web.xml files in my project. I prefer to avoid them and have everything configured in Java code.
I have read the following the posts about bean injection in servlet filters.
How can I get a Spring bean in a servlet filter?
http://www.deadcoderising.com/2015-05-04-dependency-injection-into-filters-using-delegatingfilterproxy/
spring injection in servlet filter
After reading them, I started to use DelegatingFilterProxy.
My question is how to autowire the bean into filter and avoid using xml files especially for DelegatingFilterProxy configuration.
The code snipped is available from the second post hosted in github.
public class AuditHandler {
public void auditRequest(String appName, ServletRequest request) {
System.out.println(appName + ": Received request from " + request.getRemoteAddr() );
}
}
public class AuditFilter implements Filter {
private final AuditHandler auditHandler;
private String appName;
public AuditFilter(AuditHandler auditHandler) {
this.auditHandler = auditHandler;
}
public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException {
auditHandler.auditRequest(appName, request);
chain.doFilter(request, response);
}
public void init(FilterConfig filterConfig) throws ServletException {
appName = filterConfig.getInitParameter("appName");
}
public void destroy() {}
}
ApplicationContext.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd">
<bean id="auditHandler" class="com.deadcoderising.AuditHandler">
</bean>
<bean id="auditFilter" class="com.deadcoderising.AuditFilter">
<constructor-arg ref="auditHandler"/>
</bean>
</beans>
web.xml
<web-app version="3.0"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
metadata-complete="true">
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath*:applicationContext*.xml</param-value>
</context-param>
<filter>
<filter-name>auditFilter</filter-name>
<filter-class>
org.springframework.web.filter.DelegatingFilterProxy
</filter-class>
<init-param>
<param-name>targetFilterLifecycle</param-name>
<param-value>true</param-value>
</init-param>
<init-param>
<param-name>appName</param-name>
<param-value>di-example</param-value>
</init-param>
</filter>
<filter-mapping>
<filter-name>auditFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
</web-app>

Answer 1

You should add a FilterRegistrationBean to your main Application class (class annotated with #SpringBootApplication) and let Spring provide instance of the AuditHandler:
#Bean
#Autowired
public FilterRegistrationBean auditFilterRegistration(AuditHandler handler) {
FilterRegistrationBean filterRegistrationBean = new FilterRegistrationBean();
filterRegistrationBean.setFilter(new AuditFilter(handler));
filterRegistrationBean.setOrder(3); // ordering in the filter chain
return filterRegistrationBean;
}
If this doesn't work (e.g. your AuditHandler implementation is not annotated properly or it's not on the default package scanning path) you can instruct Spring to provide it (also in your #SpringBootApplication annotated class):
#Bean
public AuditHandler auditHandler() {
return new AuditHandlerImplementation();
}