I am writing a script where I face a very strange problem.
My script is :
#!/bin/bash
set -x
cd /scripts/my-scripts
echo "Getting data from database."
mysql -N -umyuser -pmypass -hdb.test.example.com COLLEGE -e"select distinct id as myid from candidate_info where name = 'john' and id is not null " > test_skus &
echo "DONE"
echo `wc -l test_skus`
It gives 0 as word count. But if I remove & at end of this :
mysql -N -umyuser -pmypass -hdb.test.example.com COLLEGE -e"select distinct id as myid from candidate_info where name = 'john' and id is not null " > test_skus &
It give results. What can be the reason ? Please help
Related
In my script i execute correctly when first time in the if loop execute after the third time of execution its not working properly .what can i do is any mistake ah...? please fix my issue...?in the script i gave the value for customer name as ABC then again i gave the ABC that time it ececute the if condition correctly,but i gave the third time as ABC its not working properly..!
#!/bin/bash
echo " --- Enter the Database name ---"
read databasename
echo " --- enter the table name --- "
read table_name
sqlite3 $databasename.db "DROP TABLE IF EXISTS $table_name;"
sqlite3 $databasename.db "CREATE TABLE IF NOT EXISTS $table_name(cus_id INTEGER PRIMARY KEY AUTOINCREMENT UNIQUE,cus_name TEXT NOT NULL UNIQUE ,cus_domain TEXT UNIQUE, cus_status TEXT NOT NULL,Port INTEGER NOT NULL);"
echo " --- Enter the total number of rows do you want ---"
read cus_count
echo "--- Enter the following details one by one---"
port_num=8080
for((i=1;i<=cus_count;i++))
do
echo "enter the $i customer details"
echo "---Enter the customer name---"
read c_name
customer=$(sqlite3 $databasename.db "select cus_name from $table_name")
if [[ "$port_num" == "$port_num" ]]; then
port_num=$(($port_num + 1))
fi
if [[ $c_name != $customer ]]
then
echo "---Enter the Status(Active/Inactive)---"
read c_status
c_domain="$c_name"
else
echo "---OOPS you entered customer name already available---"
echo "---Please enter new customer name---"
i=$(($i - 1))
fi
sqlite3 $databasename.db "INSERT OR IGNORE INTO $table_name (cus_name,cus_domain,cus_status, Port) VALUES(\"$c_name\",\"${c_domain,,}.com\",\"$c_status\",\"$port_num\") ;"
done
echo " --- Records from the $table_name ---"
sqlite3 $databasename.db "select * from $table_name;"
please refer to below on "bash script arithmetic operations"
http://tldp.org/LDP/abs/html/arithexp.html
or
http://tldp.org/LDP/abs/html/ops.html
Here is the script which works well when executed in standalone but fails when scheduled as a cronjob,
#!/bin/bash
# TARGET TABLE COUNT FOR Server
#
CURRENTTARGETREF=$(sqlplus -s $DB_USER/$DB_PASS << END
set pagesize 0 feedback off verify off heading off echo off;
SELECT CURRENTTARGETREF FROM PARAMETER
exit;
END
)
TABLENAME="TARGET$CURRENTTARGETREF"
TARGETCOUNT=$(sqlplus -s $DB_USER/$DB_PASS << END
set pagesize 0 feedback off verify off heading off echo off;
SELECT COUNT(*) FROM $TABLENAME
exit;
END
)
echo "Current Target table count in server: $TARGETCOUNT"
#
# COUNTER TABLE COUNT FOR server
#
S1=`echo "SELECT COUNT(*) FROM COUNTER WHERE SERVERID=1;" | sqlplus $DB_USER/$DB_PASS | sed -n '/COUNT(\*)/{n;n;p}'`
S2=`echo "SELECT COUNT(*) FROM COUNTER WHERE SERVERID=2;" | sqlplus $DB_USER/$DB_PASS | sed -n '/COUNT(\*)/{n;n;p}'`
#
echo "Current Counter table count with SERVERID '1' in server:$S1"
echo "Current Counter table count with SERVERID '2' in server:$S2"
#
below is the cronjob for this script
31 01 * * * DS=$(date +\%Y-\%m-\%d); /path/Databasecount.sh >> /path/test.out.$DS.txt 2>&1
And i wanted to send the output of the script to mail and could you someone please help me on this.
I have a problem with executing a psql-query in a bash script.
Below is my code.
run_sql(){
sql_sel="$1;";#sql select
table=$2;#table name
for i in "${!GP_SERVER_NAMES[#]}"
do
logmsg "Executing [$sql_sel] on "${GP_SERVER_NAMES[$i]}": " $loglvl;
result_host[$i]=`${PSQL_HOST[$i]}${sql_sel}`;
#result_host[$i]=cleanresult "`$(${PSQL_HOST[$i]} "$tx_fix $sql_sel" 2>&1`");
if [[ `checkresult "${result_host[$i]}"` != 'true' ]]; then
logmsg "Error occured during sql select: Result for "${GP_SERVER_NAMES[$i]}" '${table}': ${result_host[$i]};" '1' '1';
raise_alarm "${GP_SYNC_SQL_ERR}" "${i}" "${table}" "${result_host}";
fi
logmsg "Result for" ${GP_SERVER_NAMES[$i]} " '${table}': ${result_host[$i]}";
done
final_result='true';
for i in "${!result_host[#]}"
do
if [[ `checkresult "${result_host[$i]}"` = 'true' ]]; then
final_result='false';
I am trying to executing the query on many different servers, with the following command
result_host[$i]=${PSQL_HOST[$i]}${sql_sel};
The above variables have the following meaning:
1. result_host[$i] : is an array that holds the i-th result of the sql query.
2. PSQL_HOST[$i] : is the command line psql-statement, including the IP address which is of the form
psql -t -q -h -U password -d database -c
3. $sql_sel : is the sql_statement
When I run the script, I get the following output.
scriptname.sh: line 168: SELECT: command not found
ERROR: syntax error at end of input
LINE 1: SELECT
^
Why is that? Any help, comments or suggestions would be appreciated.
Below is the Perl script that I have written
my $COUNT_1;
my $parameter1 = 'PU_CLERK';
$COUNT_1 = `sqlplus -s hr/password\#dbname\#sql_script.sql $parameter1`;
SQL SCRIPT:
select count(*) from employees
where job_id <> '&1'
and salary > 9000
and commission_pct is not null
order by first_name desc
/
exit;
When I run this query by passing the argument &1 it is giving me a string with an error message. But when I run the same query by hardcoding I'm getting the output properly (the count is 15 which is the correct answer).
select count(*) from employees
where job_id <> 'PU_CLERK'
and salary > 9000
and commission_pct is not null
order by first_name desc
/
exit;
I'm not able to understand where I'm going wrong. How do I pass parameters in Perl. We used to do the same way in shell script and it was working absolutely fine.
EDIT:
This is the error message im getting
perl call_sql.pl
value of first variable isold 2: whe
re job_id <> '&1'
new 2: where job_id <> 'PU_CLERK'
15
So its basically not printing the 15 value its printing all those string also when i use '&1' in my sql script
EDIT2:
Hi Guys finally it is working. In my sql code instead of giving '&1' i gave '$1' Now i want to know is $1 of some significance in Perl? Thanks..
I don't know the answer to your current problem, but using the DBI module is the better solution, so I wrote a sample script to get you started. You may need to tweak some things to get it to work.
use strict;
use warnings;
use DBI;
my $dbname = "mydb";
my $user = "foo";
my $passwd = "bar";
my $dbh = DBI->connect("dbi:Oracle:$dbname", $user, $passwd)
or die $DBI::errstr;
my $parameter1 = 'PU_CLERK';
my $statement = "select count(*) from employees
where job_id <> ?
and salary > 9000
and commission_pct is not null
order by first_name desc";
my $sth = $dbh->prepare($statement) or die $dbh->errstr;
$sth->execute($parameter1) or die $sth->errstr;
while (my $row = $sth->fetchrow_arrayref) {
print "#$row"; # or whatever you want to do with it
}
$dbh->disconnect or warn $dbh->errstr;
This has nothing with perl.
Proof: make an shell script, say mytest.sh with the next content:
#!/bin/bash
echo "$0: Got $# args" >&2 #to stderr
i=0
for arg
do
let i++
echo "$0: arg($i)=$arg=" >&2 #to stderr
done
echo "15" #result to stdout
make it executable, with chmod 755 mytest.sh
Now modify your perl script as:
my $COUNT_1;
my $parameter1 = 'PU_CLERK';
$COUNT_1 = `./mytest.sh -s hr/password\#dbname\#sql_script.sql $parameter1`;
print "script returned: $COUNT_1\n";
run it
$ perl script.pl
result:
./mytest.sh: Got 3 args
./mytest.sh: arg(1)=-s=
./mytest.sh: arg(2)=hr/password#dbname#sql_script.sql=
./mytest.sh: arg(3)=PU_CLERK=
script returned: 15
e.g. the perl
correctly run the external script
correctly passes the arguments to it
so, search for the error in the sqlplus doccumentation...
I have the code like this
v_use_xref_result=`sqlplus -s $UP <
Select Code_Desc
From Code_Detail
Where Code='UXLOC'
and CODE_TYPE='UXRF'
EOF`
if [ "$v_use_xref_result" == "Y" ]; then
echo "s" else
echo "n"
fi
when I query the same in sql developer I am getting the result as Y for this query Select Code_Desc From Code_Detail Where Code='UXLOC' and CODE_TYPE='UXRF' the datatype of Code_Desc is varchar
but I am unable to check in if condition. i am getting "n" as result for this script.
can anyone help me how to check it in if condition.
As written, the heredoc syntax in your script doesn't seem to be correct. Try saying:
v_use_xref_result=$(sqlplus -s $UP <<EOF
Select Code_Desc
From Code_Detail
Where Code='UXLOC'
and CODE_TYPE='UXRF'
EOF
)