I have two tables
table 1: cat_a
table 2:prod_a
Out put must be
When category_id =1 then product_id count must be 7
when category_id = 3 then product_id count must be 5
when category_id = 6 then product_id count must be 3
when category_id = 7 then product_id count must be 2
when category_id = 5 then product_id count must be 2
Please help me . I have searched lot of questions and answers and forums. couldn't find exact solutions.
I don't want spoon feeding answers . Please mention the hint or way with answer.
My problem resloved.
SELECT count( product_id)
FROM prod_A
WHERE category_id IN (SELECT category_id FROM cat_A START WITH category_id = <i_category_id>
CONNECT BY PRIOR category_id = parent_catogory);
Related
I have two tables product and condition where product_id is primary key of product and its foreign key in condition.
product
product_id name
1 eggs
2 milk
condition
product_id condition_name
1 new
2 bad
1 normal
I need a procedure which can give me the name of the all product which is not have bad condition.
You can simply use single query as follows:
select p.name
from product p
where not exists (select 1 from condition c where p.product_id = c.product_id
and c.condition_name = 'bad');
First, I know there is a common issue in Stack Overflow, but the following solutions are not working well here. So I still need some help.
Oracle - Update COUNT of rows with specific value
Oracle - Update rows with a min value in the group of a column from another table
Oracle update statement with group function
Oracle - Update COUNT of rows with specific value
The problem is: I have a +700k lines table:
REVIEWS (PRODUCT_ID, REVIEW, REVIEW_DATE, RELEASE_DATE, ..., REVIEW_COUNT)
I'm trying to update REVIEW_COUNT by counting the lines with the same PRODUCT_ID (I want just reviews before product release). So the code below works very well for my purpose:
SELECT COUNT(PRODUCT_ID) FROM REVIEWS
WHERE REVIEW_DATE < RELEASE_DATE
GROUP BY PRODUCT_ID
But I'm having a hard time to do the update. First I tried this:
UPDATE REVIEWS R
SET R.REVIEWS_COUNT =
(SELECT COUNT(RR.PRODUCT_ID) FROM REVIEWS RR
WHERE RR.DATA < RR.REL_DATE
GROUP BY RR.PRODUCT_ID)
The error is "more than one row", which is not surprising, but since I'm using the group by statement, it shouldn't occur. So I tried a self-join:
UPDATE REVIEWS R
SET R.REVIEWS_COUNT =
(SELECT COUNT(RR.PRODUCT_ID) FROM REVIEWS RR
WHERE RR.PRODUCT_ID = R.PRODUCT_ID AND RR.DATA < RR.REL_DATE)
But the query is taking forever and I don't think that should take so long, the simple select is pretty normal-fast.
I've also tested some more fancy and more simple stuff, but the outcome remains the same: long time waiting and it seems just wrong.
Please, what I'm missing in such easy update?
Maybe instead of updating you could define view:
select product_id, review_date, release_date,
count(case when review_date < release_date then 1 end)
over (partition by product_id) review_count
from reviews;
You could also try merge instead update:
merge into reviews a
using (select product_id, count(product_id) cnt from reviews
where review_date < release_date
group by product_id ) b
on (a.product_id = b.product_id)
when matched then update set reviews_count = b.cnt
dbfiddle
I think your second update is correct:
UPDATE REVIEWS R
SET R.REVIEWS_COUNT =
(SELECT COUNT(RR.PRODUCT_ID) FROM REVIEWS RR
WHERE RR.PRODUCT_ID = R.PRODUCT_ID AND RR.DATA < RR.REL_DATE)
;
This will update every record in the reviews table. Is that what you wanted?
An index on product_id will make the inner query run faster, but it will still update all 700K or so records.
I have one table where I want to retrieve data group by the user but I want the latest entry in result how can I do that by using eloquent.
here is an eloquent query I am using.
Product::whereNotNull('user_id')
->orderBy('id','desc')
->groupBy('user_id')
->get();
here is my table
Id Name user_id
-------------------------
1 A 1
2 b 1
3 c 2
4 d 2
5 e 3
6 f 3
result my query is giving me
Id Name user_id
-------------------------
1 A 1
3 c 2
5 e 3
result i want
Id Name user_id
-------------------------
2 b 1
4 d 2
6 f 3
Product::whereRaw('id IN (select MAX(id) FROM products GROUP BY user_id)')
->whereNotNull('user_id')
->orderBy('id','desc')
->get();
You will need a nested query for that, i don't think you can avoid it but this solution should work.
GroupBy happens before OrderBy so you have to get your last record before you do your ordering
Try this :
$subquery = Product::orderBy('id','DESC');
$products = DB::table(DB::raw("({$subquery->toSql()}) as subquery"))
->whereNotNull('user_id')
->groupBy('user_id')
->get();
2nd way : use unique() method in collection (The unique method returns all of the unique models in the collection):
$products = Product::whereNotNull('user_id')
->orderBy('id','desc')
->get()
->unique('user_id');
Check out Laravel Docs
latest / oldest
The latest and oldest methods allow you to easily order results by date. By default, result will be ordered by the created_at column. Or, you may pass the column name that you wish to sort by:
$product = Product::latest()->first();
I want to find the orders number from table#orders where DelivaryDateRevision less than max revisions from each country(table#maxrevisions). Countrycode is not the foreign key to the other table.
Can I fetch the orders table records if the country code is missing in the maxrevisions table.
Table: orders
OrderNumber | CountryCode | DelivaryDateRevision
123--------------- IN-------------------9
234--------------- US-------------------3
238-------------- IN------------------ 3
table: maxrevisions
CountryCode| MaxRevision
IN ---------------6
US--------------- 4
My query:
SELECT distinct o.ordernumber,o.countrycode
FROM orders o
left outer join maxrevisions m
on o.CountryCode=m.CountryCode
and
o.DelivaryDateRevision<rs.MaxRevision;
but I am getting the wrong result. Can I get any help here?
Your major omission seems to be a WHERE clause which compares the two revisions:
SELECT
o.ordernumber,
o.countrycode
FROM orders o
LEFT JOIN maxrevisions m
ON o.CountryCode = m.CountryCode
WHERE
o.DelivaryDateRevision < m.MaxRevision OR m.MaxRevision IS NULL;
Demo
Select
ordernumber,
countrycode,
deliverydateversion
from orders o
where deliverydateversion >
(
select max(revision)
from maxrevisiontab
where countrycode= o.countrycode
)
Please change the table names and column names as per your structure.
I cant remember the right aproach in php to sort data from related tables anymore? Iam not sure if its even possible in one query?
table brands
id name
------------
1 Disney
2 Pepsi
3 Sony
table products
id name brandId
-----------------------
1 cd-playerX 3
2 nice poster 1
3 usb-radio 3
4 cd-playerY 3
I want to list all the products sorted by the name of the brand table (order=asc) like this:
nice poster (Disney)
cd-playerX (Sony)
cd-playerY (Sony)
usb-radio (Sony)
Anyone?
select p.name + ' (' + b.name + ')' as fullName
from products as p
left join brands as b
on p.id = b.brandId
order by b.name asc, p.name asc --optional for brands with multiple products