Elasticsearch - bump individual result to the top - sorting

Question

I'm working with Elasticsearch. I have an array of documents, and I'm trying to sort documents by the property price, except that I'd like a particular document to be the first result no matter what.
The below is what I'm using as my "sort" array as my attempt to order documents by ID 1213, and then all following documents ordered by price descending.
[
{
"id": {
"mode": "max",
"order": "desc",
"nested_filter": {
"term": {
"id": 1213
}
},
"missing": "_last"
}
},
{
"price": {
"order": "asc"
}
}
]
This doesn't appear to be working, though—document 1213 doesn't appear first. What am I doing wrong here?
As an example—the ideal returned result:
[{"id": 1213, "name": "Blue Sunglasses", "price": 12},
{"id": 1000, "name": "Green Sunglasses", "price": 2},
{"id": 1031, "name": "Purple Sunglasses", "price: 4},
{"id": 5923, "name": "Yellow Sunglasses, "price": 18}]
Instead, I get:
[{"id": 1000, "name": "Green Sunglasses", "price": 2},
{"id": 1031, "name": "Purple Sunglasses", "price: 4},
{"id": 1213, "name": "Blue Sunglasses", "price": 12},
{"id": 5923, "name": "Yellow Sunglasses, "price": 18}]

Answer 1

As others have already asked, what is the reason for the nested_filter?
There's many possible ways to do what you need. Here is one possible way which fits with the simple requirements you mentioned so far:
{
"query" : {
"custom_filters_score" : {
"query" : {
"match_all" : {}
},
"filters" : [
{
"filter" : {
"term" : {
"id" : "1213"
}
},
"boost" : 2
}
]
}
},
"sort" : [
"_score",
"price"
]
}
The assumption here is that your query is simple like the match_all query and does not affect the scores in anyway. If you do have something more complicated for the queries, to not affect the scores, you can try wrapping with a constant_score query. But ideally you get the document set you want where all the documents have the same score and then custom_filters_score query will boost the score of the document you want. You can do this for any number of documents adding further filters or if the documents are equal, use a terms filter. In the end the sort by the score and then the price.

Answer 2

In this case you need to use function_score to modify score of each doc.
{
"query": {
"function_score": {
"functions": [
{
"filter": {
"term": {
"id": "1213"
}
},
"weight": 1
},
{
"script_score": {
"script": "(1 / doc['price'].value)"
}
}
],
"score_mode": "sum",
"boost_mode" : "replace",
"query" : {
//YOUR QUERY GOES HERE
}
}
}
}
Explanation:
{
"script_score": {
"script": "(1 / doc['price'].value)"
}
}
Compute score based on price and give a value < 1. The higher the price the smaller the score (ascending). If you want to switch to descending then just replace it with
"script": "(1 - (1 / doc['price'].value))"
{
"filter": {
term": {
"id": "1213"
}
},
"weight": 1
}
This will give any docs with "id" = 1213 an extra 1 score. The total score at the end will be the sum of those 2 functions.