Bash-scripting. Check file-status - bash

Question

I've been handed an assignment which goes as follows;
I should write a program that checks a file and print out if one of the following happens:
File is created
file is modified
file is deleted
I've made a working program ( my noobish way):
bool=true
if [ -e "$1" ]
then
dato=$(date -r "$1" "+%s")
datony=$(date -r "$1" "+%s")
while [ "$bool" = true ]
do
echo "File exists!"
sleep $2
datony=$(date -r "$1" "+%s")
if [ "$dato" -ne "$datony" ]
then
bool=false
echo "File modified!"
fi
if [ ! -e "$1" ]; then
bool=false
echo "File erased"
fi
done
fi
if [ ! -e "$1" ]
then
while [ "$bool" = true ]
do
echo "File does not exist!"
sleep $2
if [ -e "$1" ]
then
bool=false
echo "File created!"
fi
done
fi
The problem now is that i should make a new script that should take multiple files and check their statuses using my existing script. I need som help with how i should use my script to do that.

Answer 1

If you want to continue using $1 for files and $2 for sleep time.
first, put sleep time in a variable
sleepTime=$2
Put all the code you already made in a function (or a program)
checkFile(){
bool=true
if [ -e "$1" ]
then
dato=$(date -r "$1" "+%s")
datony=$(date -r "$1" "+%s")
while [ "$bool" = true ]
do
echo "File exists!"
sleep $2
datony=$(date -r "$1" "+%s")
if [ "$dato" -ne "$datony" ]
then
bool=false
echo "File modified!"
fi
if [ ! -e "$1" ]; then
bool=false
echo "File erased"
fi
done
fi
if [ ! -e "$1" ]
then
while [ "$bool" = true ]
do
echo "File does not exist!"
sleep $2
if [ -e "$1" ]
then
bool=false
echo "File created!"
fi
done
fi
}
create another function to separate the files and call the other function on background.
func_splitFiles(){
while [ ! -z $1 ];
do
checkFile $1 $sleepTime &
shift;
done;
}
In the "main" program you just call the function to split files passing $1
func_splitFiles $1
You should call the program passing files between quotes.
program.sh "file1 file2 file3" 1