I want to delete a file from a directory which contains many subdirectories but the deletion should not happen in one subdiretory(searc) whose name is already predefined but path varies as shown below.So now how to delete a file i am using the below command
find . -type f -name "*.txt" -exec rm -f {} \;
this command deletes all the files in the directory.So How can we delete the file without serching that subdirectory.
The subdirectory file name will be same but the path will different
for eg
Main
|
a--> searc
|
b-->x--->searc
|
c-->y-->x-->searc
now the
the subdirectory not to be searched can be present any where as shown above
I think you want the -prune option. In combination with a successful name match, this prevents descent into the named directories. Example:
% mkdir -p test/{a,b,c}
% touch test/{a,b,c}/foo.txt
% find test -name b -prune -o -name '*.txt' -print
test/a/foo.txt
test/c/foo.txt
I am not completely sure what you're asking, so I can give only somewhat generic advice.
You already know the -name option. This refers to the filename only. You can, however, also use -wholename (a.k.a. -path), which refers to the full path (beginning with the one given as first option to find).
So if you want to delete all *.txt files except in the foo/bar subdirectory, you can do this:
find . -type f -name "*.txt" ! -wholename "./foo/bar/*" -delete
Note the -delete option; it doesn't require a subshell, and is easier to type.
If you would like to exclude a certain directory name regardless of where in the tree it might be, just don't "root" it. In the above example, foo/bar was "rooted" to ./, so only a top-level foo/bar would match. If you write ! -wholename "*/foo/bar/*" instead (allowing anything before or after via the *), you would exclude any files below any directory foo/bar from the operation.
You can use xargs instead of the exec
find .... <without the --exec stuff> | grep -v 'your search' | xargs echo rm -f
Try this first. If it is satisfactory, you can remove the echo.
Related
I need to delete all files with a pattern name: 2020*.js
Inside a specific directory: server/db/migrations/
And then show what it have been deleted: `| xargs``
I'm trying this:
find . -name 'server/db/migrations/2020*.js' #-delete | xargs
But nothing is deleted, and shows nothing.
What I'm doing wrong?
The immediate problem is that -name only looks at the last component of the file name (so 2020xxx.js) and cannot match anything with a slash in it. You can use the -path predicate but the correct solution is to simply delete these files directly:
rm -v server/db/migrations/2020*.js
The find command is useful when you need to traverse subdirectories.
Also, piping the output from find to xargs does not do anything useful; if find prints the names by itself, xargs does not add any value, and if it doesn't, well, xargs can't do anything with an empty input.
If indeed you want to traverse subdirectories, try
find server/db/migrations/ -type f -name '2020*.js' -print -delete
If your shell supports ** you could equally use
rm -v server/db/migrations/**/2020*.js
which however has a robustness problem if there can be very many matching files (you get "command line too long"). In that scenario, probably fall back to find after all.
You're looking for something like this:
find server/db/migrations -type f -name '2020*.js' -delete -print
You have try this:
find . -name 'server/db/migrations/2020*.js' | xargs rm
This is my directory structure
find -type f -print0 | xargs -0 ls -t
./lisst.txt ./SAMN03272855/SRR1734376/SRR1734376_1.fastq.gz
./SAMN03272854/SRR1734375/SRR1734375_2.fastq.gz ./SAMN07605670/SRR6006890/SRR6006890_2.fastq.gz
./SAMN03272854/SRR1734375/SRR1734375_1.fastq.gz ./SAMN07605670/SRR6006890/SRR6006890_1.fastq.gz
./SAMN03272855/SRR1734376/SRR1734376_2.fastq.gz
So this is a small subset of my folder/files where i have around 70.
I have a made a list of files which i want to keep and other i would like to delete.
My list.txt contains SAMN03272854,SAMN03272855 but I want to remove SAMN07605670.
I ran this
find . ! -name 'lisst.txt' -type d -exec rm -vrf {} +
It removed everything
QUESTION UPDATE
In my list it contains the folder i want to keep and the one which are not there are to be removed.
The folders which are to be removed also contains subdirectories and files. I want to remove everything
Your command selects each directory in the tree, except a directories of the funny name lisst.txt. Once it finds a directory, you do a recursive remove of this directory. No surprise that your files are gone.
You can't use rm -r when you want to spare certain files from deletion. This means that you also can't remove a directory, which somewhere below in its subtree has a file you want to keep.
I would run two find commands: The first removes all the files, ignoring directories, and second one removes all directories, which are empty (bottom-up). Assuming that SAMN03272854 is indeed a file (as you told us in your question), this would be:
find . -type f \( ! \( -name SAMN03272854 -o -name SAMN03272855 \) \) -exec rm {}
find . -depth -type d -exec rmdir {} 2>/dev/null
The error redirection in the latter command suppresses messages from rmdir for directories which still contain files you want to keep. Of course other messages are also suppressed. I would during debugging run the command without error redirection, to see whether it is basically correct.
Things would get more complicated, if you have files and directories to keep, because to keep a directory likely implies to keep all the files below it. In this case, you can use the -prune option of find, which excludes directories including their subdirectories from being processed. See the find man page, which gives examples for this.
I converted/compressed several MP4 files from several folders using VLC.
The names of the converted/compressed files end with -converted, for example. 2. bubble sort-converted.mp4.
It's really cumbersome to go into each folder and delete all the original files and leave the converted files.
Using some zsh/bash command I'd like to recursively delete all the original files and leave the converted files.
For example I'll delete 3 - sorting/2. bubble sort.mp4 and will leave 3 - sorting/2. bubble sort-converted.mp4.
TLDR;
In easy words, delete all the files with .mp4 extension, where filesnames don't end with -converted using some zsh/bash command.
Also If there is some way to rename the converted file to the original name after deleting the original files, that will be a plus.
Thank you!
find can be used with a logical expression to match the desired files and delete them.
In your case the following can be used to verify whether it matches the files you want to delete. It finds all files that don't have converted in their names but do end in .mp4.
find . -type f -not \( -name '*converted*' \) -a -name "*.mp4"
Once you are satsified with the file list result then add -delete to do the actual delete.
find . -type f -not \( -name '*converted*' \) -a -name "*.mp4" -delete
Give this a try:
find . -name '*.mp4' | grep -v 'converted' | xargs rm -f
The zsh pure solution:
rm -f ^(*.mp4-converted)(.)
^ ................. negates
*-converted ....... pattern
(.) ............... regular files
Using gnu parallel (in case of many files)
parallel --no-notice rm -rf ::: ^(*converted)(.)
This will work even if your file names contain ', " or space:
find . -name '*.mp4' |
grep -v 'converted' |
parallel -X rm -f
I have a directory with this structure:
root
|-dir1
| |-pred_20181231.csv
|
|-dir2
| |-pred_20181234.csv
...
|-dir84
|-pred_2018123256.csv
I want to run a command that will rename all the pred_XXX.csv files to pred.csv.
How can I easily achieve that?
I have looked into the rename facility but I do not understand the perl expression syntax.
EDIT: I tried with this code: rename -n 's/\training_*.csv$/\training_history.csv/' *.csv but it did not work
Try with this command:
find root -type f -name "*.csv" -exec perl-rename 's/_\d+(\.csv)/$1/g' '{}' \;
Options used:
-type f to specify file or directory.
-name "*.csv" to only match files with extension csv
-exec\-execdir to execute a command, in this case, perl-rename
's/_\d+(\.csv)/$1/g' search a string like _20181234.csv and replace it with .csv, $1 means first group found.
NOTE
Depending in your S.O. you could use just rename instead of perl-rename.
Use some shell looping:
for file in **/*.csv
do
echo mv "$(dirname "$file")/$(basename "$file")" "$(dirname "$file")/pred.csv"
done
On modern shells ** is a wildcard that matches multiple directories in a hierarchy, an alternative to find, which is a fine solution too. I'm not sure if this should instead be /**/*.csv or /root/**/*.csv based on tree you provided, so I've put echo before the 'mv' to see what it's about to do. After making sure this is going to do what you expect it to do, remove the echo.
So I have some folder
|-Folder1
||-SubFolder1
||-SubFolder2
|-Folder2
||-SubFolder3
||-SubFolder4
Each subfolder contains several jpg I want to zip to the root folder...
I'm a little bit stuck on "How to enter each folder"
Here is my code:
find ./ -type f -name '*.jpg' | while IFS= read i
do
foldName=${PWD##*/}
zip ../../foldName *
done
The better would be to store FolderName+SubFolderName and give it to the zip command as name...
Zipping JPEGs (for Compression) is Usually Wasted Effort
First of all, attempting to compress already-compressed formats like JPEG files is usually a waste of time, and can sometimes result in archives that are larger than the original files. However, it is sometimes useful to do so for the convenience of having a bunch of files in a single package.
Just something to keep in mind. YMMV.
Use Find's -execdir Flag
What you need is the find utility's -execdir flag. The GNU find man page says:
-execdir command {} +
Like -exec, but the specified command is run from the subdirec‐
tory containing the matched file, which is not normally the
directory in which you started find.
For example, given the following test corpus:
cd /tmp
mkdir -p foo/bar/baz
touch foo/bar/1.jpg
touch foo/bar/baz/2.jpg
you can zip the entire set of files with find while excluding the path information with a single invocation. For example:
find /tmp/foo -name \*jpg -execdir zip /tmp/my.zip {} +
Use Zip's --junk-paths Flag
The zip utility on many systems supports a --junk-paths flag. The man page for zip says:
--junk-paths
Store just the name of a saved file (junk the path), and do not
store directory names.
So, if your find utility doesn't support -execdir, but you do have a zip that supports junking paths, you could do this instead:
find /tmp/foo -name \*jpg -print0 | xargs -0 zip --junk-paths /tmp/my.zip
You can use dirname to get the directory name of a file/directory it is located in.
You can also simplify the find command to search only for directories by using -type d. Then you should use basename to get only the name of the subdirs:
find ./*/* -type d | while read line; do
zip --junk-paths "$(basename $line)" $line/*.jpg
done
Explanation
find ./*/* -type d
will print out all directories located in ./*/* which will result in all subdirs of directories located in the current dir
while read line reads each line from the stream and stores it in the variable "line". Thus $line will be the relative path to the subdir, e.g. "Folder1/Subdir2"
"$(basename $line)" returns the only the name of the subdir, e.g. "Subdir2"
Update: add --junk-paths to the zip command if you do not want the directy paths to be stored in the zip filde
So a little check, I finally got something working:
find ./*/* -type d | while read line; do
#printf '%s\n' "$line"
zip ./"$line" "$line"/*.jpg
done
But this create un archive containing:
Subfolder.zip
Folder
|-Subfolder
||-File1.jpg
||-File2.jpg
||-File3.jpg
Instead I fold like it to be:
Subfolder.zip
|-File1.jpg
|-File2.jpg
|-File3.jpg
So I tried using basename and dirname in differnet combination...Always got some error...
And just to learn how to: what if I would like the new archive to be created in the same root directory as "Folder"?
Ok finally got it!
find ./* -name \*.zip -type f -print0 | xargs -0 rm -rf
find ./*/* -type d | while read line; do
#printf '%s\n' "$line"
zip --junk-paths ./"$line" "$line"/*.jpg
done
find . -name \*.zip -type f -mindepth 2 -exec mv -- '{}' . \;
In first row I simply remove all .zip files,
Then I zip all and in the final row I move all zip to the root directory!
Thanks everbody for your help!