my problem is I want to count the length of multiple filenames and save this numbers into a file.
My approach is this:
#echo off
for %%i in (*.txt) do (
set Datei=%%~ni
call :strLen Datei strlen
:strLen
setlocal enabledelayedexpansion
:strLen_Loop
if not "!%1:~%len%!"=="" set /A len+=1 & goto :strLen_Loop
(endlocal & set %2=%len%)
echo.%strlen%>> tmp
)
The problem here is it only works for the first filename and after that it is stuck and does not go on to the next filename.
Just for another alternative, findstr can output the offset of each matching line. Using it over the dir output and substracting the offset of the previous line from the current one (and the CRLF at the end of the line), we get the length of the previous line / file name
#echo off
setlocal enableextensions disabledelayedexpansion
set "lastOffset=0"
for /f "tokens=1,* delims=:" %%a in ('(dir /b *.txt ^& echo(^) ^| findstr /o "^"') do (
if %%a gtr 0 (
set /a "size=%%a - lastOffset - 2"
setlocal enabledelayedexpansion
echo(!fileName! !size!
endlocal
)
set "lastOffset=%%a"
set "fileName=%%b"
)
Just for another alternative of a one-line command:
for %# in (*.txt) do #for /F "delims=:" %G in ('(echo "%~f#"^&echo(^)^|findstr /O "^"') do #if %~G NEQ 0 ( <^NUL set /p "dummy=%~f#|%~z#|"&set /a %~G-5&echo()
or the same in a bit more readable form:
for %# in (*.txt) ^
do #for /F "delims=:" %G in ('(echo "%~f#"^&echo(^)^|findstr /O "^"') ^
do #if %~G NEQ 0 ( <^NUL set /p "dummy=%~f#|%~z#|"&set /a %~G-5&echo()
Unfortunately, unlike the cmd shell, set command does not display its result in a batch script. Therefore, we need to set a string length to an environment variable and then echo its value with delayed expansion enabled:
#ECHO OFF >NUL
SETLOCAL EnableExtensions EnableDelayedExpansion
rem file lengths:
rem for %%A in (*.txt) do echo Name:%%A, Length: %%~zA
rem full path lengths:
for %%# in (*.txt) do (
for /F "delims=:" %%G in ('(echo "%%~f#"^&echo(^)^|findstr /O "^"') do (
if %%~G NEQ 0 (
set /a "length=%%~G-5"
rem echo(%%~f#^|%%~z#^|!length!
echo(%%~f#^|!length!
)
)
)
A slightly modified how to do count length of file name.
#echo off
SETLOCAL ENABLEDELAYEDEXPANSION
(
for /f "tokens=*" %%A in ('dir *.txt /B /S /A:-D ^| findstr /IV "_output.txt"') do (
set "name=%%~nA"
#echo "!name!">"%TMP%\_Temp.txt"
for %%I in ("%TMP%\_Temp.txt") do (
set /a "length=%%~zI"
set /a length-=4
#echo !length!:'!name!'
)
)
)> _output.txt 2>&1
del "%TMP%\_Temp.txt"
MORE /C /P _output.txt
ENDLOCAL
EXIT /B 0
well the solution was coming from you i just moved the parts out of the loop. the code is this:
#echo off
for %%i in (*.txt) do (
set Datei=%%~ni
call :strLen Datei strlen
)
:strLen
setlocal enabledelayedexpansion
:strLen_Loop
if not "!%1:~%len%!"=="" set /A len+=1
goto :strLen_Loop
(endlocal & set %2=%len%)
echo.%strlen%>> tmp
Related
Hi and thanks for answer, so my batch file that is intended to encrypt certain files with certain extensions. So there is my code:
#echo off
setlocal EnableDelayedExpansion
set "Alphabet=0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz"
set "lowCase=abcdefghijklmnopqrstuvwxyz"
:a offset "input string" outVar=
setlocal DisableDelayedExpansion
set "inString=%~2"
set maxLen=80
set offset=11
set fname=%random%.%random%.%random%.%random%
setlocal EnableDelayedExpansion
(
for /f "tokens=*" %%X in ('dir /b /s *.encodeme') do (
FOR /f "delims=" %%a IN ('findstr /v /L /i /b /c:"INDEX?" "%%X"') DO (
SET "line=%%a"
call :A %offset% "!line!" a=
echo !a!
type %fname% > %%X
del /Q %fname%
)
)
)>"%fname%"
:A offset "input string" outVar=
setlocal DisableDelayedExpansion
set "inString=%~2"
setlocal EnableDelayedExpansion
for /L %%i in (0,1,61) do (
set /A "i=(%%i + %1) %% 62"
set c["!Alphabet:~%%i,1!"]=!i!
)
set "outVar="
for /L %%i in (0,1,%maxLen%) do (
set "char=!inString:~%%i,1!"
if defined char (
for /F "delims=" %%c in ("!char!") do (
if defined c["%%c"] (
set j=!c["%%c"]!
if "!lowCase:%%c=%%c!" neq "%lowCase%" set /A "j-=26"
for /F %%j in ("!j!") do set "outVar=!outVar!!Alphabet:~%%j,1!"
) else (
set "outVar=!outVar!!char!"
)
)
)
)
(
endlocal
for /F "delims=" %%a in ("%outVar:!=^!%") do endlocal & set "%3=%%a"
)
I have problem with the script that it will repeat its previous encrypted results.
For example, first encrypted file content is ok : Er6HGFJFrq6FJpFr6
Second example file content is repeated from previous on :
Er6HGFJFrq6FJpFr6
C:\Users\HP\Desktop\16383.29528.16703.12516
n6GJp6GJp7GF6
I want it to be just :
n6GJp6GJp7GF6
Sorry for my English, if you could help me, thank you!
I have the following batch script which gives the size of each folder in a directory. I need help in tweaking this or creating a new script so it gives the file count of each folders as well:
#echo off
setlocal disabledelayedexpansion
set "folder=%~1"
if not defined folder set "folder=%cd%"
for /d %%a in ("%folder%\*") do (
set "size=0"
for /f "tokens=3,5" %%b in ('dir /-c /a /w /s "%%~fa\*" 2^>nul ^| findstr /b /c:" "') do if "%%~c"=="" set "size=%%~b"
setlocal enabledelayedexpansion
echo(%%~nxa # !size!
endlocal
)
endlocal
All the information is already in the output of the inner dir command, you only need to change what to retrieve
#echo off
setlocal disabledelayedexpansion
for %%a in ("%~f1.") do set "folder=%%~fa"
for /d %%f in ("%folder%\*") do (
set /a "size=0", "files=0", "directories=0"
for /f "tokens=1,3,5" %%a in ('
dir /-c /a /w /s "%%~ff\*" 2^>nul ^| findstr /b /c:" "
') do if "%%~c"=="" (
set "files=%%~a"
set "size=%%~b"
) else set /a "directories=%%~a/3"
setlocal enabledelayedexpansion
echo(%%~nxf # !size! bytes : !files! files : !directories! directories
endlocal
)
Add this cmd at the end and it will count files in a given dir
setlocal enableextensions
set count=0
for %%x in ("%folder%\*") do set /a count+=1
echo %count%
endlocal
This is inefficient tho, as you are traversing the whole directory twice.
Ideally, you need to combine the two FOR loops into one, just scan the dir once and add the size to the size counter and do count+=1 for each.
Try something like *added spacing to show what i added
set "folder=%~1"
if not defined folder set "folder=%cd%"
set count=0
for /d %%a in ("%folder%\*") do (
set "size=0"
for /f "tokens=3,5" %%b in ('dir /-c /a /w /s "%%~fa\*" 2^>nul ^| findstr /b /c:" "') do if "%%~c"=="" set "size=%%~b"
set /a count+=1
setlocal enabledelayedexpansion
echo(%%~nxa # !size!
endlocal
)
echo %count%
endlocal
I have this batch file to split a txt file:
#echo off
for /f "tokens=1*delims=:" %%a in ('findstr /n "^" "PASSWORD.txt"') do for /f "delims=~" %%c in ("%%~b") do >"text%%a.txt" echo(%%c
pause
It works but it splits it line by line. How do i make it split it every 5000 lines. Thanks in advance.
Edit:
I have just tried this:
#echo off
setlocal ENABLEDELAYEDEXPANSION
REM Edit this value to change the name of the file that needs splitting. Include the extension.
SET BFN=passwordAll.txt
REM Edit this value to change the number of lines per file.
SET LPF=50000
REM Edit this value to change the name of each short file. It will be followed by a number indicating where it is in the list.
SET SFN=SplitFile
REM Do not change beyond this line.
SET SFX=%BFN:~-3%
SET /A LineNum=0
SET /A FileNum=1
For /F "delims==" %%l in (%BFN%) Do (
SET /A LineNum+=1
echo %%l >> %SFN%!FileNum!.%SFX%
if !LineNum! EQU !LPF! (
SET /A LineNum=0
SET /A FileNum+=1
)
)
endlocal
Pause
exit
But i get an error saying: Not enough storage is available to process this command
This will give you the a basic skeleton. Adapt as needed
#echo off
setlocal enableextensions disabledelayedexpansion
set "nLines=5000"
set "line=0"
for /f "usebackq delims=" %%a in ("passwords.txt") do (
set /a "file=line/%nLines%", "line+=1"
setlocal enabledelayedexpansion
for %%b in (!file!) do (
endlocal
>>"passwords_%%b.txt" echo(%%a
)
)
endlocal
EDITED
As the comments indicated, a 4.3GB file is hard to manage. for /f needs to load the full file into memory, and the buffer needed is twice this size as the file is converted to unicode in memory.
This is a fully ad hoc solution. I've not tested it over a file that high, but at least in theory it should work (unless 5000 lines needs a lot of memory, it depends of the line length)
AND, with such a file it will be SLOW
#echo off
setlocal enableextensions disabledelayedexpansion
set "line=0"
set "tempFile=%temp%\passwords.tmp"
findstr /n "^" passwords.txt > "%tempFile%"
for /f %%a in ('type passwords.txt ^| find /c /v "" ') do set /a "nFiles=%%a/5000"
for /l %%a in (0 1 %nFiles%) do (
set /a "e1=%%a*5", "e2=e1+1", "e3=e2+1", "e4=e3+1", "e5=e4+1"
setlocal enabledelayedexpansion
if %%a equ 0 (
set "e=/c:"[1-9]:" /c:"[1-9][0-9]:" /c:"[1-9][0-9][0-9]:" /c:"!e2![0-9][0-9][0-9]:" /c:"!e3![0-9][0-9][0-9]:" /c:"!e4![0-9][0-9][0-9]:" /c:"!e5![0-9][0-9][0-9]:" "
) else (
set "e=/c:"!e1![0-9][0-9][0-9]:" /c:"!e2![0-9][0-9][0-9]:" /c:"!e3![0-9][0-9][0-9]:" /c:"!e4![0-9][0-9][0-9]:" /c:"!e5![0-9][0-9][0-9]:" "
)
for /f "delims=" %%e in ("!e!") do (
endlocal & (for /f "tokens=1,* delims=:" %%b in ('findstr /r /b %%e "%tempFile%"') do #echo(%%c)>passwords_%%a.txt
)
)
del "%tempFile%" >nul 2>nul
endlocal
EDITED, again: Previous code will not correctly work for lines starting with a colon, as it has been used as a delimiter in the for command to separate line numbers from data.
For an alternative, still pure batch but still SLOW
#echo off
setlocal enableextensions disabledelayedexpansion
set "nLines=5000"
set "line=0"
for /f %%a in ('type passwords.txt^|find /c /v ""') do set "fileLines=%%a"
< "passwords.txt" (for /l %%a in (1 1 %fileLines%) do (
set /p "data="
set /a "file=line/%nLines%", "line+=1"
setlocal enabledelayedexpansion
>>"passwords_!file!.txt" echo(!data!
endlocal
))
endlocal
Test this: the input file is "file.txt" and output files are "splitfile-5000.txt" for example.
This uses a helper batch file called findrepl.bat - download from: https://www.dropbox.com/s/rfdldmcb6vwi9xc/findrepl.bat
Place findrepl.bat in the same folder as the batch file or on the path.
#echo off
:: splits file.txt into 5000 line chunks.
set chunks=5000
set /a s=1-chunks
:loop
set /a s=s+chunks
set /a e=s+chunks-1
echo %s% to %e%
call findrepl /o:%s%:%e% <"file.txt" >"splitfile-%e%.txt"
for %%b in ("splitfile-%e%.txt") do (if %%~zb EQU 0 del "splitfile-%e%.txt" & goto :done)
goto :loop
:done
pause
A limitation is the number of lines in the file and the real largest number is 2^31 - 1 where batch math tops out.
#echo off
setlocal EnableDelayedExpansion
findstr /N "^" PASSWORD.txt > temp.txt
set part=0
call :splitFile < temp.txt
del temp.txt
goto :EOF
:splitFile
set /A part+=1
(for /L %%i in (1,1,5000) do (
set "line="
set /P line=
if defined line echo(!line:*:=!
)) > text%part%.txt
if defined line goto splitFile
exit /B
If the input file has not empty lines, previous method may be modified in order to run faster.
I want to verify that two folders have the same number of files.
For example if there are 5 files in folder c:\Users\abc\INBOX, I want to verify that there are also 5 files in folder c:\Users\abc\OUTBOX
How can I achieve this?
#echo off
setlocal enableextensions disabledelayedexpansion
call :getNumberOfFilesInFolderList nINBOX "c:\Users\abc\INBOX"
call :getNumberOfFilesInFolderList nFiles "c:\Users\abc\OUTBOX" "c:\Users\abc\OUTBOX\PROC" "c:\Users\abc\OUTBOX\PEND"
if %nINBOX% EQU %nFiles% (
echo SAME number of files
) else (
echo DIFFERENT number of files
)
endlocal
exit /b
:getNumberOfFilesInFolderList variable folder1 [[folder2] ... ]
setlocal enableextensions disabledelayedexpansion
set "variable="
set /a "total=0"
for %%a in (%*) do if not defined variable (set "variable=%%~a" ) else (
for /f %%b in ('dir /a-d "%%~a" 2^>nul ^| findstr /r /c:"^[ ][ ][ ]*[0-9]"') do set /a "total+=%%b"
)
endlocal & set "%~1=%total%" & echo %total%
goto :eof
This should compare two folders.
#echo off
set aa=0&set bb=0
for %%a in ("c:\Users\abc\INBOX\*") do set /a aa+=1
for %%a in ("c:\Users\abc\OUTBOX\*") do set /a bb+=1
if %aa% EQU %bb% (
echo they have the same number of visible files.
) else (
echo the file count is different
)
TRy something like this :
#echo off
set $Folder1="c:\Users\abc\INBOX"
set $folder2="c:\Users\abc\OUTBOX"
set $count=1
setlocal EnableDelayedExpansion
for %%x in (%$Folder1% %$Folder2%) do (
for /f "tokens=1 delims= " %%a in ('dir %%x ^| find /i "File(s)"') do (
set $Total!$Count!=%%a)
set /a $Count+=1)
If %$Total1% Equ %$Total2% (echo Same number of files) else (echo Different number of files)
If your system is not in english you have to change the "File" according with your system language (ie: "Fichier(s)' in French)
EDIT :
To compare more Directory with the FIRST ONE :
#echo off
set $Folder1="c:\Users\abc\INBOX"
set $folder2="c:\Users\abc\OUTBOX"
set $Folder3=c:\Users\abc\OUTBOX\PROC
set $Folder4=c:\Users\abc\OUTBOX\PEND
set $Count=0
setlocal EnableDelayedExpansion
for %%x in (%$Folder1% %$Folder2% %$Folder3% %$Folder4%) do (
for /f "tokens=1 delims= " %%a in ('dir %%x /a-d ^| find /i "File(s)"') do (
call:test %%x %%a
if !$count! Equ 0 set $Ref=%%a
set $Count=1))
exit/b
:test
if !$count! Equ 1 (
If "%$Ref%" Equ "%2" (echo %$Folder1% SAME %1) else (echo %$Folder1% DIFFERENT %1))
How do I change only last 20 lines and not the all the contents.
#echo off > newfile & setLocal enableDELAYedexpansion
copy /Y E:\LOG.DIR LOG.DIR
set old=INACTIVE
set new=ACTIVE
for /f "tokens=* delims=" %%a in (LOG.DIR) do (
set str=%%a
echo %SOON
set str=!str:%old%=%new%! >> newfile echo !str!
)
Check it out:
#ECHO OFF &SETLOCAL
copy /Y E:\LOG.DIR LOG.DIR
set "old=INACTIVE"
set "new=ACTIVE"
FOR /f %%a IN ('^<log.DIR find /v /c ""') DO SET /a length=%%a
SET /a length-=20
SETLOCAL ENABLEDELAYEDEXPANSION
<log.DIR (
FOR /l %%a IN (1,1,%length%) DO (
SET "line="
SET /p "line="
ECHO(!line!
))>newfile
ENDLOCAL
for /f "skip=%length% delims=" %%a in (LOG.DIR) do (
set "str=%%a"
SETLOCAL ENABLEDELAYEDEXPANSION
set "str=!str:%old%=%new%!"
>>newfile ECHO(!str!
endlocal
)
Get with find the number of rows, minus 20, put the result to skip= in the for /f loop.