I am deleting the files in all the directories and subdirectories using the command below:
find . -type f -name "*.txt" -exec rm -f {} \;
But I want to know which are the files deleted along with their paths. How can I do this?
Simply add a -print argument to your find.
$ find . -type f -name "*.txt" -print -exec rm -f {} \;
As noted by #JonathanRoss below, you can achieve an equivalent result with the -v option to rm.
It's not the scope of your question, but more generally it gets more interesting if you want to delete directories recursively. Then:
a simple -exec rm -r argument keeps it silent
a -print -exec rm -r argument reports the toplevel directories you're operating on
a -exec rm -rv argument reports all you're removing
Related
How can i search for example all .png files on an external disk and copy them to another directory?
Have tried to use the cp command. Have try it but don't work for me
?
Monterey 2.2.1
cp /Volumes/Data *.png /Volumes/Data/pictures_png
cp command won't work if you need to recursively copy from the sub directories. You need to use find.
Syntax:
find $SOURCE -type f -name '*.type' -exec cp '{}' $DESTINATION ';'
In your case,
find /Volumes/Data -type f -name '*.png' -exec cp '{}' /Volumes/Data/pictures_png ';'
Here is how it works:
-type f means copy only files not directories.
-name is to provide the filename to find. Here *.png for pattern matching
-exec executes the following line for each result the above find returns.
{} will be replaced with the results from find
; terminates -exec command
I am searching specific directory and subdirectories for new files, I will like to copy the files. I am using this:
find /home/foo/hint/ -type f -mtime -2 -exec cp '{}' ~/new/ \;
It is copying the files successfully, but some files have same name in different subdirectories of /home/foo/hint/.
I will like to copy the files with its base directory to the ~/new/ directory.
test#serv> find /home/foo/hint/ -type f -mtime -2 -exec ls '{}' \;
/home/foo/hint/do/pass/file.txt
/home/foo/hint/fit/file.txt
test#serv>
~/new/ should look like this after copy:
test#serv> ls -R ~/new/
/home/test/new/pass/:
file.txt
/home/test/new/fit/:
file.txt
test#serv>
platform: Solaris 10.
Since you can't use rsync or fancy GNU options, you need to roll your own using the shell.
The find command lets you run a full shell in your -exec, so you should be good to go with a one-liner to handle the names.
If I understand correctly, you only want the parent directory, not the full tree, copied to the target. The following might do:
#!/usr/bin/env bash
findopts=(
-type f
-mtime -2
-exec bash -c 'd="${0%/*}"; d="${d##*/}"; mkdir -p "$1/$d"; cp -v "$0" "$1/$d/"' {} ./new \;
)
find /home/foo/hint/ "${findopts[#]}"
Results:
$ find ./hint -type f -print
./hint/foo/slurm/file.txt
./hint/foo/file.txt
./hint/bar/file.txt
$ ./doit
./hint/foo/slurm/file.txt -> ./new/slurm/file.txt
./hint/foo/file.txt -> ./new/foo/file.txt
./hint/bar/file.txt -> ./new/bar/file.txt
I've put the options to find into a bash array for easier reading and management. The script for the -exec option is still a little unwieldy, so here's a breakdown of what it does for each file. Bearing in mind that in this format, options are numbered from zero, the {} becomes $0 and the target directory becomes $1...
d="${0%/*}" # Store the source directory in a variable, then
d="${d##*/}" # strip everything up to the last slash, leaving the parent.
mkdir -p "$1/$d" # create the target directory if it doesn't already exist,
cp "$0" "$1/$d/" # then copy the file to it.
I used cp -v for verbose output as shown in "Results" above, but IIRC it's also not supported by Solaris, and can be safely ignored.
The --parents flag should do the trick:
find /home/foo/hint/ -type f -mtime -2 -exec cp --parents '{}' ~/new/ \;
Try testing with rsync -R, for example:
find /your/path -type f -mtime -2 -exec rsync -R '{}' ~/new/ \;
From the rsync man:
-R, --relative
Use relative paths. This means that the full path names specified on the
command line are sent to the server rather than just the last parts of the
filenames.
The problem with the answers by #Mureinik and #nbari might be that the absolute path of new files will spawn in the target directory. In this case you might want to switch to the base directory before the command and go back to your current directory afterwards:
path_current=$PWD; cd /home/foo/hint/; find . -type f -mtime -2 -exec cp --parents '{}' ~/new/ \; ; cd $path_current
or
path_current=$PWD; cd /home/foo/hint/; find . -type f -mtime -2 -exec rsync -R '{}' ~/new/ \; ; cd $path_current
Both ways work for me at a Linux platform. Let’s hope that Solaris 10 knows about rsync’s -R ! ;)
I found a way around it:
cd ~/new/
find /home/foo/hint/ -type f -mtime -2 -exec nawk -v f={} '{n=split(FILENAME, a, "/");j= a[n-1];system("mkdir -p "j"");system("cp "f" "j""); exit}' {} \;
I have many files without file extention. Now I want to add .txt to all files. I tried the following but it gives an error, mv: rename . to ..txt: Invalid argument.
How can I achieve this?
find . -iname "*.*" -exec bash -c 'mv "$0" "$0.txt"' {} \;
You're nearly there!
Just add -type f to only deal with files:
find . -type f -exec bash -c 'mv "$0" "$0.txt"' {} \;
If your mv handles the -n option, you might want to use it (that's the option to not overwrite existing files).
The error your having is because . is one of the first found by found, and your system complains (rightly) when you want to rename .! with the -type f you're sure this won't happen. Now if you wanted to act on everything inside your directory, you would, e.g., add -mindepth 1 at the beginning of the find command (as . is considered depth 0).
It is not very clear in your question, but what if you want to add the extension .txt to all files that don't have an extension? (we'll agree that to have an extension means to have a period in the name). In this case, you'll use the negation of -name '*.*' as follows:
find . -type f \! -name '*.*' -exec bash -c 'mv "$0" "$0.txt"' {} \;
find . -name "*.pyc" -print0| xargs -0 rm
i use this command delete python compiled file but if current directory didn't have any *.pyc
file this cmd will not work
print out the error with rm command need operator args
how to handle this work if current directory didn't have *.pyc file this situation?
Using find -exec:
find -name '*.pyc' -exec rm {} \;
or the discard output technique:
find . -name "*.pyc" -print0| xargs -0 -I{} rm {} &> /dev/null
If you can assume GNU find, then you can use find . -name '*.pyc' -delete.
Alternatively, find . -name '*.pyc' -exec rm -rf {} '+'.
I'm trying to do something which is probably very simple, I have a directory structure such as:
dir/
subdir1/
subdir2/
file1
file2
subsubdir1/
file3
I would like to run a command in a bash script that will delete all files recursively from dir on down, but leave all directories. Ie:
dir/
subdir1/
subdir2/
subsubdir1
What would be a suitable command for this?
find dir -type f -print0 | xargs -0 rm
find lists all files that match certain expression in a given directory, recursively. -type f matches regular files. -print0 is for printing out names using \0 as delimiter (as any other character, including \n, might be in a path name). xargs is for gathering the file names from standard input and putting them as a parameters. -0 is to make sure xargs will understand the \0 delimiter.
xargs is wise enough to call rm multiple times if the parameter list would get too big. So it is much better than trying to call sth. like rm $((find ...). Also it much faster than calling rm for each file by itself, like find ... -exec rm \{\}.
With GNU's find you can use the -delete action:
find dir -type f -delete
With standard find you can use -exec rm:
find dir -type f -exec rm {} +
find dir -type f -exec rm '{}' +
find dir -type f -exec rm {} \;
where dir is the top level of where you want to delete files from
Note that this will only delete regular files, not symlinks, not devices, etc. If you want to delete everything except directories, use
find dir -not -type d -exec rm {} \;