I want to use PJax in Yii Grid View, not with the associative filter that comes inside the Grid View, but with the Search Filter that's outside it, so it can filter the results inside.
Here is the source of the index file:
<div class="cars-index">
<h1><?= Html::encode($this->title) ?></h1>
<?php echo $this->render('_search', ['model' => $searchModel]); ?>
<p>
<?= Html::a('Create Cars', ['create'], ['class' => 'btn btn-success']) ?>
</p>
<?= GridView::widget([
'dataProvider' => $dataProvider,
'columns' => [
'id',
'name',
['attribute' => 'code',
'label' => 'Colour',
'format' => 'raw',
'value' => 'colour',
'contentOptions' => function ($model, $key, $index, $column){
return ['style' => ' text-align: center; width: 100px;color:white;background-color:#'. $model -> code];
},
'headerOptions' => ['style' => 'text-align: center;'],
],
'price',
['class' => 'yii\grid\ActionColumn'],
],
]); ?>
Am I supposed to create an active form just for the part I want to filter? Or is there another way?
If You can't simply add the filter to you table like this
<?= GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
I suggest you use a proper action and a proper search function called by submit based on a specified active form
for action form eg:
<?php $form = ActiveForm::begin([
'id' => 'search-form',
'method' => 'post',
'action' => ['controller/yourAction']
]); ?>
in the controller
$model = new yourActiveForm();
if ($model->load(Yii::$app->request->post()) ) {
$dataProvider = $searchModel->search( [ 'yuorSearchModel'=> ['your_att1' => $model->yourValue1]]);
}
then your render
Conforming to yii2 doc
Pjax only deals with the content enclosed between its begin() and
end() calls, called the body content of the widget. By default, any
link click or form submission (for those forms with data-pjax
attribute) within the body content will trigger an AJAX request. In
responding to the AJAX request, Pjax will send the updated body
content (based on the AJAX request) to the client which will replace
the old content with the new one. The browser's URL will then be
updated using pushState. The whole process requires no reloading of
the layout or resources (js, css).
You may configure $linkSelector to specify which links should trigger
pjax, and configure $formSelector to specify which form submission may
trigger pjax.
You must add the
<?php Pjax::begin(); ?>
.... your active form
<?php Pjax::end(); ?>
and configure the proper $linkSelect and $formSelector
In your filter view:
<div id="myFilter">
<?php $form = ActiveForm::begin([
'id' => 'myFilterForm',
'method' => 'post',
'action' => [...],
]); ?>
...
</div>
And make sure you render filter between Pjax::begin and Pjax::end
Yet here comes the trick. If your server does not respond within default timeout, Pjax gets ignored and page reloaded, so make sure the timeout is big enough:
<?php Pjax::begin([
'id'=>'myGrid',
'timeout' => 10000, // <------------ THIS !!!!!!!
'formSelector' => '#myFilterForm'
]); ?>
<?= $this->render('myFilter', ['model' => $searchModel]); ?>
<?= GridView::widget([
...
]); ?>
<?php Pjax::end(); ?>
Also in your controller, you might want to "reset" the search model, so only data from the request used are attributes actually used by search:
public function actionSearch()
{
$searchModel = new MySearch();
if ($searchModel->load(Yii::$app->request->post())) {
$searchModel = new MySearch(); // "reset"
$dataProvider = $searchModel->search(Yii::$app->request->post());
} else {
$dataProvider = $searchModel->search(Yii::$app->request->queryParams);
}
return $this->render('search', [
'searchModel' => $searchModel,
'dataProvider' => $dataProvider,
]);
}
Hope this helps. Cheers!
Related
I want to apply validation rules only for the input fields that are not empty (not required) for the URL
For example,
If I submit a form and the input is empty, I got a validation error "Instagram Link must be valid URL.", However, I want it without requiring,
and if the input is not empty, I want to apply the rule "valid_url"
How can we fix it?
if (!$this->validate([
'instagram' => [
'rules' => 'valid_url',
'errors' => [
'valid_url' => 'Instagram Link must be valid url.',
],
],
])){
return redirect()->back()->withInput()->with('errors', $this->validator->getErrors());
}
I tried with a permit_link rule, but if I submit it (with an input value like 'mylink' (which is not a valid_url)), it will accept it, but it should not.
Please check the following images and the code:
A form HTML
Result after clicking on edit button
<?= form_open('/settings/edit/1', ['id' => 'setting-form']); ?>
<div class="row">
<div class="col-md-6">
<div class="form-group">
<?= form_label('Instagram'); ?>
<?= form_input(['name' => 'instagram', 'class' => 'form-control', 'id' => 'instagram', 'placeholder' => 'Enter instagram link', 'value' => old('instagram', $setting->instagram)]); ?>
</div>
</div>
</div>
<button type="submit" class="btn btn-dark">Edit</button>
<?= form_close(); ?>
public function edit($id)
{
if (!$this->validate([
'instagram' => [
'rules' => 'permit_empty|valid_url',
'errors' => [
'valid_url' => 'Instagram Link must be valid url.',
],
],
])) {
return redirect()->back()->withInput()->with('errors', $this->validator->getErrors());
}
die('submitted');
}
It should display "Instagram Link must be valid url" and not "submitted",
first
Use separate variable $rules like this :
$rules = ['data' => 'require']
Then
check if $this->request->getVar("instagram"); is empty / is true or etc.. then set it on the $rules
finally
Do Something like this :
$rules = ['extra_data' => 'require'];
if(!empty($this->request->getVar("instagram"))
$rules["instagram"] = "valid_url";
if ($this->validate(rules){
//do something ...
}else {
//do something ...
}
I just noticed that the following examples:
"mylink", "mylink.com", "https://www.mylink.com"
will consider correct for the rule valid_url in Codeigniter (No errors),
While: "https:://www.mylink.com", "mylink#" will apply the validation and the error is applied.
I have been developing a system to create a dynamic questioner, where an organizer can create questions for a user to respond, but I have been having trouble validating the answers of the users to the questioners. I have three types of inputs available for the organizer to create, a short answer, a long answer and an input field. I tried using the Each validation rule, but it doesn’t seem to be working. I search all around for an answer to this, but I didn't find anything that worked.
Here is my code.
View
<?php $form = ActiveForm::begin([ 'id' => 'respuesta-form', 'enableAjaxValidation' => true, 'options' => ['enctype' => 'multipart/form-data'], ]); ?>
<?php foreach ($preguntas as $i => $pregunta): ?>
<?php if($pregunta->tipo == 1): ?>
<?= $form->field($model, "respuesta[$i]")->textInput(['maxlength' => true])->label("<strong>" . $pregunta->descripcion . "</strong>") ?>
<?php endif; ?>
<?php if($pregunta->tipo == 2): ?>
<?= $form->field($model, "respuesta[$i]")->textarea(['maxlength' => true], ["style" => "resize: none;"])->label("<strong>" . $pregunta->descripcion . "</strong>") ?>
<?php endif; ?>
<?php if($pregunta->tipo == 3): ?>
<?= $form->field($model, "respuesta[$i]")->fileInput()->label("<strong>" . $pregunta->descripcion . "</strong>") ?>
<?php endif; ?>
<?php endforeach; ?>
<div class="form-group">
<?= Html::submitButton('Guardar', ['class' => 'btn btn-success']) ?>
</div>
<?php ActiveForm::end(); ?>
Model
public function rules()
{
return [
[['idpregunta', 'idinscripcion'], 'required'],
['respuesta', 'each', 'rule' => ['required']],
[['idpregunta', 'idinscripcion'], 'integer'],
[['respuesta'], 'string', 'max' => 500],
[['idpregunta'], 'exist', 'skipOnError' => true, 'targetClass' => Pregunta::className(), 'targetAttribute' => ['idpregunta' => 'id']],
[['idinscripcion'], 'exist', 'skipOnError' => true, 'targetClass' => Inscripcion::className(), 'targetAttribute' => ['idinscripcion' => 'idInscripcion']],
];
}
Controller
public function actionResponderFormulario($slug){
$evento = $this->findModel("", $slug);
$inscripcion = Inscripcion::find()->where(["idEvento" => $evento->idEvento, "idUsuario" => Yii::$app->user->identity->idUsuario])->one();
$preguntas = Pregunta::find()->where(["idevento" => $evento->idEvento])->all();
$model = new Pregunta();
if($inscripcion ==null){
$preguntas = Pregunta::find()->where(["idevento" => $evento->idEvento])->all();
return $this->render('responderFormulario',
["preguntas" => $preguntas,
"eventos" => $evento,
"model" => $model]);
}
}
The most important thing for me is for the questions to validate in general, I don’t care that much to validate each type separately, because I may remove this later.
Thank you in advance
I think this part of string validation with max length should change to this:
['respueusta', 'each', 'rule' => ['string', 'max' => 500]]
Sometime respuesta field receives the file in tipo=3 , you can not do this for clean and structured code. define another field for files.
I am trying to make an Ajax GridView using Pjax. Everything is working fine except the view, update and delete buttons are not AJAX. The code is:
<?php yii\widgets\Pjax::begin(['id' => 'demo']); ?>
<?= GridView::widget([
'dataProvider' => $dataProvider,
'columns' => [
['class' => 'yii\grid\SerialColumn'],
'id',
'name',
['class' => 'yii\grid\ActionColumn'],
],
]); ?>
<?php yii\widgets\Pjax::end(); ?>
The problem is that the links for delete, view and update have the attribute data-pjax=0 which disables AJAX functionality. I cant find out how to set it too data-pjax=1.
You must do like below:
For Delete Action
1- Change your delete action like below:
public function actionDelete($id) {
$this->findModel($id)->delete();
if (Yii::$app->getRequest()->isAjax) {
$dataProvider = new ActiveDataProvider([
'query' => ModelName::find(),
'sort' => false
]);
return $this->renderPartial('index', [
'dataProvider' => $dataProvider
]);
}
return $this->redirect(['index']);
}
2- In your grid view:
['class' => 'yii\grid\ActionColumn',
'buttons' => [
'delete' => function ($url, $model) {
return Html::a('<span class="glyphicon glyphicon-trash"></span>', $url, [
'title' => Yii::t('yii', 'Delete'),
'data-pjax'=>'w0',
]);
}
]
],
Now, it works with Pjax.
Notes
My code in deleteAction() may decrease performance. You can write your own.
w0 usually is the default id of PJax. You can add an id to PJax and write it there instead.
This is the same for Update and View, But you need to change the way you show your update and view views.
This is highly recommended to take a look at Yii2's official PJax document: http://www.yiiframework.com/doc-2.0/yii-widgets-pjax.html
In YII views folder i have test module and admin.php file to manage contents are below and i render form here where i put the code of form and dropdown in it , i want that grid refresh value of status change in dropdown
Suppose i select "Approved" than Grid show the data where status is approved
<?php
Yii::app()->clientScript->registerScript('dropdown', "
$('.dropdown-form form').submit(function(){
$('#testimonial-grid').yiiGridView('update', {
data: $(this).serialize()
});
return false;
});
");
?>
<h1>Manage Testimonials</h1>
<div class="dropdown-form">
<?php $this->renderPartial('_dropdownform',array(
'model'=>$model,
)); ?>
</div><!-- search-form -->
<?php $this->widget('zii.widgets.grid.CGridView', array(
'id'=>'testimonial-grid',
'dataProvider'=>$model->search(),
'filter'=>$model,
'columns'=>array(
'id',
'created_by',
'test_name',
'test_email',
'comments',
'created_at',
/*
'status',
'approved_on',
'approved_by',
*/
array(
'class'=>'CButtonColumn',
),
),
)); ?>
Form below is _dropdownform , it contain a form and dropdown from this dropdown i am choosing the value of status
<div class="wide form">
<?php
$form = $this->beginWidget('CActiveForm', array(
'action' => Yii::app()->createUrl($this->route),
'method' => 'get',
));
?>
<div class="row">
<?php
echo CHtml::dropDownList('status', '', array(0 => 'New', 1 => 'Approved', 2 => 'Declined'), array(
'prompt' => 'Select Status',
'ajax' => array(
'type' => 'POST',
'url' => Yii::app()->createUrl('testimonial/loadthedata'),
//or $this->createUrl('loadcities') if '$this' extends CController
'update' => '#testimonial-grid', //or 'success' => 'function(data){...handle the data in the way you want...}',
'data' => array('status' => 'js:this.value'),
)));
?>
</div>
<div class="row buttons">
<?php //echo CHtml::submitButton('Search'); ?>
</div>
<?php $this->endWidget(); ?>
</div><!-- search-form -->
AND THE CODE IN MY CONTROLLER OR URL GIVEN IN DROPDOWN TO FETCH DATA IS FOLLOWING ACTION BUT I DONT KNOW HOW TO FETCH DATA FROM THIS FUNCTION AND PASS TO GRID VIEW
public function actionloadthedata() {
if (isset($_POST['status'])) {
$status = $_POST['status'];
if($status==0){
$status='New';
}
if($status==1){
$status='Approved';
}
if($status==2){
$status='Declined';
}
Testimonial::model()->findByAttributes(array('status'=>$status));
}
}
You can use CGridView property filterCssClass to link the grid filter, for example
$this->widget('CGridView', array(
'id' => 'my-list',
'filterCssClass' => '#filterFormId .filter',
And there is filter form
<?php $form = $this->beginWidget('CActiveForm', array(
'id' => 'filter-fomr-id',
)); ?>
<div class="filter clearfix">
<?php echo $form->dropDownList($model, 'name', [0=>'all', '1'=>'some else']); ?>
</div>
Replace #filterFormId .filter on jquery selector specific to you form. In other words, set id attribute for filter form, then use "#THISID .row".
In your gridview file, make sure you have this code:
Yii::app()->clientScript->registerScript('search', "
$('.search-button').click(function(){
$('.search-form').toggle();
return false;
});
$('.search-form form').submit(function(){
$('#ad-grid').yiiGridView('update', {
data: $(this).serialize()
});
return false;
});
");
then in the CGridView definition:
$this->widget('zii.widgets.grid.CGridView', array(
'id'=>'testimonial-grid',
'dataProvider'=>$model->search(),
'filter'=>$model,
'columns'=>array(
...
array(
'name'=>'Status',
'filter'=>CHtml::dropDownList('YourModel[status]', $model->status, array(0 => 'New', 1 => 'Approved', 2 => 'Declined'), array('empty' => '--all--') ),
'value'=>'( $data->status == 0) ? "New": ( $data->status == 1) ? "Approved" : "Declined"',
'htmlOptions' => array(
'style' => 'width: 40px; text-align: center;',
),
),
...
array(
'class'=>'CButtonColumn',
),
),
));
// CGridView
In order to save if/else in the 'value' section, you can implement a method in your model that returns the string associated to the integer.
It works great, just with the default Yii admin.php view, which you can edit as much as you need.
Update
Added support for empty status, does not filter query results
Thanks #Alex for your help but i am successful to make filterdropdown for grid , code is following but will you please tell me that i want that grid show only values where status=New , how i can do when page load grid show values where status is New
but first i paste the working code of dropdown filter for grid
Here is my admin.php file
<?php
$this->breadcrumbs = array(
'Testimonials' => array('index'),
'Manage',
);
$this->menu = array(
array('label' => 'List Testimonial', 'url' => array('index')),
array('label' => 'Create Testimonial', 'url' => array('create')),
);
?>
<h1>Manage Testimonials</h1>
<!-----------drop down form------------->
<?php
Yii::app()->clientScript->registerScript('dropdownfilter', "
$('.dropdown-form form #staticid').change(function(){
$.fn.yiiGridView.update('testimonial-grid', {
data: $(this).serialize()
});
return false;
});
");
?>
<div class="dropdown-form">
<?php
$this->renderPartial('_dropdownfilter', array(
'model' => $model,
));
?>
</div><!-- search-form -->
<?php
$this->widget('zii.widgets.grid.CGridView', array(
'id' => 'testimonial-grid',
'dataProvider' => $model->search(),
// 'filter' => $model,
'columns' => array(
'id',
'created_by',
'test_name',
'test_email',
'comments',
'created_at',
'status',
array(
'class' => 'CButtonColumn',
),
),
));
?>
Here is my render partial form where i place the static drop dow
<div class="wide form">
<?php
$form = $this->beginWidget('CActiveForm', array(
'action' => Yii::app()->createUrl($this->route),
'method' => 'get',
));
?>
<div class="row">
<?php
echo CHtml::dropDownList('staticid', '', array('0' => 'New', '1' => 'Approved', '2' => 'Declined'), array(
// 'onChange' => 'this.form.submit()',
'ajax' => array(
'type' => 'POST', //request type
)));
?>
</div>
<?php $this->endWidget(); ?>
And Here is code of my adminaction in controller
public function actionAdmin() {
$model = new Testimonial('search');
$model->unsetAttributes(); // clear any default values
if (isset($_GET['staticid'])) {
$getStatus = $_GET['staticid'];
if ($getStatus == 0)
$status = 'New';
if ($getStatus == 1)
$status = 'Approved';
if ($getStatus == 2)
$status = 'Declined';
$model->status = $status;
}
if (isset($_GET['Testimonial']))
$model->attributes = $_GET['Testimonial'];
$this->render('admin', array(
'model' => $model,
));
}
Now i want that when i actionadmin triggered first time it show status=New values
I'm just learning Yii a few days ago to developer a website for company. Now i have some issue with Yii pagination and i really need your help.
Currently i can make Yii pagination. However, i need to create a button besides pagination area. Everytime, i click that button, it will call ajax to load next page or previous pages (if current page is last page).
Here is my model:
public function getListDesc()
{
$arrPlace = array(0 => '--- --- --- ---');
$criteria=new CDbCriteria;
$criteria->select='t.*,pi.path path';
$criteria->join='JOIN places_images pi ON t.id=pi.places_id';
$criteria->group = 't.id';
$criteria->compare('t.deleted', '<>1', false);
$criteria->compare('t.status',1);
$criteria->compare('outlet','Outlet 1');
$criteria->order = 't.id DESC';
return new CActiveDataProvider('Places', array(
'criteria'=>$criteria,
'pagination' => array(
'pageSize' => 2
)
));
}
Here is a part of my index page which is call that model:
<?php
$this->widget('zii.widgets.CListView', array(
'id' => 'places-list-right',
'dataProvider'=> Places::model()->getListAsc(),
'summaryText'=>'',
'pager' => array(
'header' => '',
'prevPageLabel' => '<<',
'nextPageLabel' => '>>',
),
'itemView'=>'_fea_oulet',)
);
?>
Here is _fea_oulet.php file:
<div class="place_img" id="<?=$data->id?>">
<div class="plusimage">
<a href="javascript:void(0);" onclick="randnew();">
<img alt="<?=$data->id?>" src="<?php echo Yii::app()->request->baseUrl; ?>/images/9life-show-more-images.png" style="border:none;border-radius:0;-webkit-border-radius: 0; -moz-border-radius:0">
</a>
</div>
<?php echo CHtml::image("timthumb.php?src=".$data->path."&w=294&h=294&zc=1&q=100",$data->title);?>
<div class="featitle">
<h3><span><?php
if(strlen($data->title) > 30) {
echo CHtml::encode(mb_substr($data->title,0,30,'UTF-8')) . '...';
}
else{
echo CHtml::encode($data->title);
}
?></span>
<img src="<?php echo Yii::app()->request->baseUrl; ?>/images/9life-show-more-green.png" style="border:none;border-radius:0;-webkit-border-radius: 0; -moz-border-radius:0">
</h3>
</div>
</div>
Any help are appreciates.
Thanks,
You can override CLinkPager class and use your own implementation MyLinkPager in your CListView widget's call specifying its pager property like this:
$this->widget('zii.widgets.CListView', array(
'id' => 'places-list-right',
'dataProvider' => Places::model()->getListAsc(),
'summaryText' => '',
'pager' => array(
'class' => 'MyLinkPager',
'header' => '',
'prevPageLabel' => '<<',
'nextPageLabel' => '>>',
),
'itemView' => '_fea_oulet'
));
run() method of CLinkPager is the place where pager buttons' rendering happens so you can override this method directly. Or you can override createPageButtons() method by adding your custom button to $buttons array if you want to see it along with other page buttons.