I have a current bash script. echo will display all results when cmd has been finished. But I want in real time see output coming line by line when script is in execution process. How can I achieve that?
#!/bin/bash
echo $(docker build -t goapp -f deployments/dev/Dockerfile .)
docker already prints its output to standard output; that's why you can capture it with $(...) and pass it as arguments to echo. Just run docker:
#!/bin/bash
docker build -t goal -f deployments/dev/Dockerfile .
Related
The following script.sh is executed:
#!/bin/bash
set -eu
# code ...
su buser
mkdir /does/not/work
echo $?
echo This should not be printed
Output:
1
This should not be printed
How i execute the script:
docker exec -i fancy_container bash < script.sh
Question: Why does the script not terminate after the failing command even when set -e was defined and how can i get the script to exit on any failing command? I think the key point is the '<' operator, which i do not understand exactly how it executes the script.
Notes:
-e means: Abort script at first error, when a command exits with non-zero status (except in until or while loops, if-tests, list constructs)
Possible solution:
docker exec -i fancy_container bash -c "cat > tmp.sh; bash tmp.sh" < script.sh
How it works:
< script.sh - Pipe all rows of this file from the host, to the docker exec command.
cat > tmp.sh - Save the incoming piped content to a file inside the container.
bash tmp.sh - Execute the file as-whole inside the container, which means -e works again as expected!
But i still don't know why the initial approach isn't working.
I'm working on something at the moment and just now I even wonder if what I am working on is even possible.
I want to SSH from jenkins to a shell script and use variables form a rc file that are in a git Repository. (The Shell script and rc file are in the same repo)
Nothing that I tried works and now I'm starting to wondering if it's even possible.
Here's is my local script but i get the same output on jenkins.
docker exec -it test-container bash 'sed -f <(printf "s/${DOMAIN}\.%s/www.&.${DOMAIN_SUFFIX_STAGE}/g\n" ${LANG_KEYS}) /var/www/foo/sed/test.txt > /var/www/foo/sed/new-2.txt'
No matter what I do I get this error
bash: sed -f <(printf "s/${DOMAIN}\.%s/www.&.${DOMAIN_SUFFIX_STAGE}/g\n" ${LANG_KEYS}) /var/www/foo/sed/test.txt > /var/www/foo/sed/new-2.txt: No such file or directory
And yes I can confirm that the directory is there
Here's an easier way to reproduce your problem:
$ bash "echo Hello"
bash: echo Hello: No such file or directory
This happens because the expected syntax is bash yourfile. The string you are passing is not a useful filename, so it fails.
To run a string argument as a command, you can use bash -c commandstring:
$ bash -c "echo Hello"
Hello
This makes bash interpret the parameter as a shell command to execute, instead of a filename to open.
I want to write a shell script that enters into a running docker container, edits a specific file and then exits it.
My initial attempt was this -
Create run.sh file.
Paste the following commands into it
docker exec -it container1 bash
sed -i -e 's/false/true/g' /opt/data_dir/gs.xml
exit
Run the script -
bash ./run.sh
However, once the script enters into the container1 it lands to the bash terminal of it. Seems like the whole script breaks as soon as I enter into the container, leaving parent container behind which contains the script.
The issue is solved By using the below piece of code
myHostName="$(hostname)"
docker exec -i -e VAR=${myHostName} root_reverse-proxy_1 bash <<'EOF'
sed -i -e "s/ServerName .*/ServerName $VAR/" /etc/httpd/conf.d/vhosts.conf
echo -e "\n Updated /etc/httpd/conf.d/vhosts.conf $VAR \n"
exit
I think you are close. You can try something like:
docker exec container1 sed -i -e 's/false/true/g' /opt/data_dir/gs.xml
Explanations:
-it is for interactive session, so you don't need it here.
docker can execute any command (like sed). You don't have to run sed via bash
I want to execute a command like docker exec "$(docker-compose ps -q web)" start.sh from golang script using exec.command(). The problem is getting the command inside $() to execute.
The command inside of $() is executed and replaced with its output by your shell on the command line (typically bash but can be sh or others). exec.Command is running the program directly, so that replacement isn't happening. This means you need to pass that command into bash so it will interpret and execute the command:
bash -c "docker exec \"$(docker-compose ps -q web)\" start.sh"
Code Example:
exec.Command("/bin/sh", "-c", "docker exec \"$(docker-compose ps -q web)\" start.sh")
Alternatively, you can run docker-compose ps -q web yourself, get its output and do the substitution instead of having bash do it for you.
What would be the correct format for the following, where I want to execute two scripts? The following is only executing the first one for me:
if ps aux | grep -E "[a]ffiliate_download.py|[g]oogle_download.py" > /dev/null
then
echo "Script is already running. Skipping"
else
exec "$DIR/affiliate_download.py"
exec "$DIR/google_download.py"
fi
The exec command replaces the current shell process with the program it runs. Since the shell is no longer running, it can't run commands after that.
Just execute the commands normally:
else
"$DIR/affiliate_download.py"
"$DIR/google_download.py"
fi