Please help i can't update the status by use the checked box.
When i selected the check box and select delete button, status will change to 'deleted' but now i can't update the data.
This is my view
<a href="javascript:;" id="delete" class="myButton" >Delete</a>
<div>
<input type="checkbox" class="cb_invoice" id="<?php echo $r->INVOICENUMBER;?>" value="<?php echo $r->INVOICENUMBER;?>">
</div>
This my script
<script>
$('#delete').click(function() {
var _url = "<?php echo site_url('commission/delete_invoices');?>";
var d_obj = $(".cb_invoice");
var d_val = [];
for (var i = 0; i < d_obj.length; i++){
if(d_obj[i].checked){
d_val.push(d_obj[i].value);
}
}
$.ajax({
url: _url,
data: {data: d_val},
type: 'post',
success: function(data) {
//console.log(data);
location.reload();
}
});
});
</script>
This my controller
function delete_invoices(){
$invoice = $this->input->post('data');
foreach ($invoice as $invoice) {
$this->m_commission->delete_invoice($invoice);
}
}
This is my model
function delete_invoice($invoice){
$this->db->update('salesinvoiceheader');
$this->db->set('STATUS','deleted');
$this->db->where('INVOICENUMBER', $invoice);
}
Change the order of update as follows in your modal:-
function delete_invoice($invoice){
$this->db->set('STATUS','deleted');
$this->db->where('INVOICENUMBER', $invoice);
$this->db->update('salesinvoiceheader');
}
Related
I want to update meta_key with ajax in wordpress i use this form
this is my code but not work for me
<?php
add_action( 'wp_head', 'ajax_the_clike' );
function ajax_the_clike() {
?>
<script>
var ajaxurl = 'http://'+window.location.host+'/wp-admin/admin-ajax.php';
var formd = "#like";
$(formd).submit(function(event) {
event.preventDefault();
$.ajax({
url: $(formd).attr('action'),
type: $(formd).attr('method'),
data: $(formd).serialize(),
success: function(data) {
console.log("SUCCESS!");
},
error: function(data) {
console.log("FAILURE");
}
});
});
</script>
<?php
}
add_action('wp_ajax_the_clike', 'the_clike'); // wp_ajax_{ACTION HERE}
add_action('wp_ajax_nopriv_the_clike', 'the_clike');
function the_clike() {
echo '<form action="'.site_url() .'/wp-admin/admin-ajax.php" method="post" id="like">';
echo '<input type="submit" value="VoteUp" id="submit" name="submits">';
if(isset($_POST['submits'])){
$postsid = get_the_ID();
$addone = get_field('like');
$addone++;
update_field('field_5f009fe6d7067' ,$addone, $postsid);
}
echo '</form><p> Like : '; if(get_field('like')) { the_field('like');}else{echo '0';} echo '</p>';
}
?>
I using a Advanced custom field plugin
Where is wrong? How do I solve this problem?
Thanks for any help
Here is my problem.
I'm trying to fetch the data from an auto-completing text-box.
There are two text-boxes:
Region and province.
I have successfully fetched the data on the text-box having region as name.
My problem is, it gives the same value to the next text-box having province as name.
In my Laravel blade I have this code:
<input id="region" type="text" class="form-control" name="region" value="" required autofocus>
<div id="regionList"> </div>
<input id="province" type="text" class="form-control" name="province" value="" required autofocus>
<div id="provinceList"> </div>
I have also a javascript file named auto-complete
$(document).ready(function() {
$('#region').keyup(function() {
var region = $(this).val();
if (region != '')
{
var _token = $('input[name="_token"]').val();
$.ajax({
url: "register/showRegion",
method: "POST",
data: { region: region, _token: _token },
success: function(data)
{
$('#regionList').fadeIn();
$('#regionList').html(data);
}
});
}
});
$(document).on('click', 'li', function() {
$('#region').val($(this).text());
$('#regionList').fadeOut();
});
$('#province').keyup(function() {
var province = $(this).val();
if (province != '')
{
var _prov_token = $('input[name="_token"]').val();
$.ajax({
url: "register/showProvince",
method: "POST",
data: { province: province, _token: _token },
success: function(data)
{
$('#provinceList').fadeIn();
$('#provinceList').html(data);
}
});
}
});
$(document).on('click', 'li', function() {
$('#province').val($(this).text());
$('#provinceList').fadeOut();
});
});
And on my routes I included this
Route::post('/register/showRegion', 'LocationController#showRegion');
Route::post('/register/showProvince', 'LocationController#showProvince');
And on my controller is this
public function index() {
return view('auth.register');
}
function showRegion(Request $request)
{
if ($request->get('region'))
{
$region = $request->get('region');
$regions = Refregion::where('regDesc', 'LIKE', "$region%")->get();
$output = '<ul class="dropdown-menu" style="display:block; position:absolute;">';
foreach($regions as $region)
{
$output .= '<li>'.$region->regDesc.'</li>';
}
$output .= '</ul>';
echo $output;
}
}
function showProvince(Request $request)
{
if ($request->get('province'))
{
$province = $request->get('province');
$province = Refprovince::where('provDesc', 'LIKE', "province%")->get();
$output = '<ul class="dropdown-menu" style="display:block; position:absolute;">';
foreach($provinces as $province)
{
$output .= '<li>'.$province->provDesc.'</li>';
}
$output .= '</ul>';
echo $output;
}
}
I'm trying to figure out why it gives the same value to the other text-box "province" when I have selected region.
Can someone help me with this, or at least explain to me why this happen?
Thank you
change it
$(document).on('click', 'li', function() {
$('#region').val($(this).text());
$('#regionList').fadeOut();
});
on this
$('#regionList').on('click', 'li', function() {
$('#region').val($(this).text());
$('#regionList').fadeOut();
});
and change it
$(document).on('click', 'li', function() {
$('#province').val($(this).text());
$('#provinceList').fadeOut();
});
on this
$('#provinceList').on('click', 'li', function() {
$('#province').val($(this).text());
$('#provinceList').fadeOut();
});
Hi all i am trying to delete my record from datatable with out page refresh in codeigniter i have used ajax i don't know where i have done mistake its not deleting the record
Below is the my view:
<tbody>
<?php
if (!empty($employees)) {
foreach ($employees as $emp) {
?>
<tr>
<td><?php echo $emp->emp_name; ?></td>
<td><?php echo $emp->salary; ?></td>
<td class='text-center'>
<button type="submit" class="btn btn-info btn-xs confirmation" name="login"><i class='fas fa-edit'></i></button>
</td>
<td class='text-center'>
<button type="submit" onClick="return ConfirmDelete()" class="btn btn-danger btn-xs confirmation empdelete" id="<?php echo $emp->id;?>"><i class='fas fa-times'></i></button>
</td>
</tr>
<?php
}
}
?>
</tbody>
<script>
$(document).ready(function(){
$(".empdelete").click(function(e){
alert();
e.preventDefault();
$.ajax({
alert();
type: "POST",
url: "<?=site_url('Employee/delete');?>",
cache: false,
data: {id:$(this).attr("id")}, // since, you need to delete post of particular id
success: function(data) {
if (data){
alert("Success");
} else {
alert("ERROR");
}
return false;
}
});
});
});
</script>
Here is the my controller:
function delete()
{
$id = $this->input->post('id'); // get the post data
$empdelete=$this->Emp_model->delete($id);
if($empdelete){
echo true;
} else {
echo false;
}
}
Here is my model's method delete:
function delete($id)
{
$sql = "DELETE FROM employees WHERE id=?";
return $this->db->query($sql,array($id));
}
Can any one help me how can i do that with out page refresh i want to delete my record.
Thanks in advance.
Try this:
$(document).ready(function () {
function ConfirmDelete() {
var x = confirm("Are you sure you want to delete?");
if (x)
return true;
else
return false;
}
$(".empdelete").click(function (e) {
var obj = $(this);
e.preventDefault();
//alert(); what's this do?
if (ConfirmDelete() == false) {
return false;
}
$.ajax({
//alert(); this can't go here
type: "POST",
url: "<?php echo site_url('Employee/delete'); ?>",
cache: false,
data: {id: $(this).attr("id")},
success: function (data) {
console.log('ajax returned: ');
console.log(data);
if (data) {
obj.closest('tr').remove();
alert("Success");
} else {
alert("ERROR");
}
return false;
}
});
});
});
and remove HTML onClick:
<button type="submit" class="btn btn-danger btn-xs confirmation empdelete" id="<?php echo $emp->id;?>"><i class='fas fa-times'></i></button>
Hope this will help you :
Your button should be like this :
<button type="button" onClick="return ConfirmDelete(this)" class="btn btn-danger btn-xs confirmation empdelete" data-id="<?=$emp->id;?>"><i class='fas fa-times'></i></button>
Your ajax code should be like this :
function ConfirmDelete(obj)
{
var x = confirm("Are you sure you want to delete?");
if (x == true)
{
var id = $(obj).data('id');
alert(id);
if (id != '')
{
//do you ajax here
$.ajax({
type: "POST",
url: "<php echo site_url('Employee/delete'); ?>",
cache: false,
data: {'id': id},
success: function (data) {
console.log('ajax returned: ');
console.log(data);
if (data) {
alert("Success");
} else {
alert("ERROR");
}
return false;
}
});
}
}
else
{
return false;
}
}
Your controller should be like this :
function delete()
{
$id = $this->input->post('id'); // get the post data
$empdelete = $this->Emp_model->delete($id);
if($empdelete)
{
echo true;
} else
{
echo false;
}
exit;
}
Your delete method should be like this :
function delete($id)
{
$this->db->where('id',$id);
$this->db->delete('employees');
return $this->db->affected_rows();
}
I am newer to ajax. I want to add two fields using ajax and codeigniter.. When i click the submit button the two fields are added but the alert message is not showing also the page is not refreshing. Can any one solve my issue.. Thanks in advance..
This is my Form
<form action="" id="suggestionsform" method="post">
<div class="form-group">
<label for="suggname">Name</label>
<input type="text" class="form-control" name="suggname" id="suggname" placeholder="Enter Your Name" required="required">
</div>
<div class="form-group">
<label for="suggmessage">Suggestion</label>
<textarea class="form-control" rows="4" name="suggmessage" id="suggmessage"
placeholder="Enter Your Suggestions"></textarea>
</div>
<button type="submit" class="btn btn-default" id="suggestions">Submit</button>
</form>
This is my ajax codeing
<script>
// Ajax post
$(document).ready(function() {
$("#suggestions").click(function(event) {
event.preventDefault();
var name = $("#suggname").val();
var suggestion = $("#suggmessage").val();
$.ajax({
type: "POST",
url: "<?php echo site_url('Helen/addSuggestion')?>",
dataType: 'json',
data: {name: name, suggestion: suggestion},
success: function(data) {
if (data=='true')
{
alert("Thank you for your Suggestion");
}
}
});
});
});
</script>
Controller Coding
public function addSuggestion()
{
$data=array(
'name' => $this->input->post('name'),
'messages' => $this->input->post('suggestion'),
'date' => now()
);
$data=$this->Helen_model->setSuggestion($data);
echo json_encode($data);
}
Model Coding
public function setSuggestion($data){
$this->db->insert('messages', $data);
return $this->db->insert_id();
}
You can achieve like this..
Model
Return true status if insert successful.
public function setSuggestion($data){
$res = $this->db->insert('messages', $data);
if($res){
$result = array('status'=>true,'message'=>'successful');
}
else
{
$result = array('status'=>false,'message'=>'failed');
}
return $result;
}
JS
Check status in success function
<script>
// Ajax post
$(document).ready(function() {
$("#suggestions").click(function(event) {
event.preventDefault();
var name = $("#suggname").val();
var suggestion = $("#suggmessage").val();
$.ajax({
type: "POST",
url: "<?php echo site_url('Helen/addSuggestion')?>",
dataType: 'json',
data: {name: name, suggestion: suggestion},
success: function(response) {
data = eval(response);//or data = JSON.parse(response)
if (data.status ===true)
{
alert("Thank you for your Suggestion");
}
}
});
});
});
</script>
Try to use echo '{"status": "success"}; on your controller response.
That i see on your script you are shown database response.
I dont know what the problem is here, I try to append the content, but its not.
var InPro = false;
$(document).ready(function(){
var form = $('#form32');
var submit = $('#submit');
form.on('submit', function(e) {
if(InPro) return;
InPro = true;
// prevent default action
e.preventDefault();
// send ajax request
$.ajax({
url: 'post.php',
type: 'POST',
cache: false,
data: form.serialize(),
success: function(data){
InPro = false;
var item = $(data).hide().fadeIn(800);
$('#post-show').append(data);
$("#form32")[0].reset();
},
});
});
});
and here the post.php:
<?php
include_once("config.php");
include_once("verifica.php");
// No direct access to this file
define('IS_AJAX', isset($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest');
if(!IS_AJAX) {die('Restricted access');}
session_start();
$user = $_SESSION['user'];
$comment = $_POST['comment'];
if($comment==""){
die();
}
$ip = getenv("REMOTE_ADDR");
$data = date ("ymdHis");
$i=mysql_query("INSERT INTO posts (id, foto, user, titulo, youtube, button, data, ip) VALUES ('','0','$user','$comment','$youtube','$button','$data','$ip')");
$idpostfeed = mysql_insert_id();
echo"$comment";
?>
and my form:
<form id="form32" method="post"> <textarea name="comment" id="comment" class="comment" placeholder=""></textarea> <input type="submit" id="submit" class="button" value="Submit Comment"> </form> <div id=post-show></div>
so, I want to show result in #post-show div, but it is not working. what is wrong?
thank you!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!