Laravel Eloquent for display row from subject table? - laravel

Question

i have three database tables
category (id,name)
subcategory (id,name,category_id) foreign_key category_id on table category(id).
subject(id,name,subcategory_id) foreign_key subcategory_id on table subcategory (id).
i want a row containing the following -
subject_id subject_name category_name subcategory_id
how to do this using eloquent .and if approach is wrong .please suggest a good method to achieve the same .

Answer 1

Assuming you have the following models:
// Category Model
class Category extends \Eloquent {
protected $table = "category";
public function subcategory(){
$this->hasMany('Subcategory','category_id');
}
}
// Subcategory Model
class Subcategory extends \Eloquent {
protected $table = "subcategory";
public function category(){
$this->belongsTo('Category', 'category_id');
}
pubic function subject(){
$this->hasMany('Subject', 'subcategory_id');
}
}
// Subject model
class Subject extends \Eloquent {
protected $table = "subject";
public function subcategory(){
$this->belongsTo('Subcategory','subcategory_id');
}
}
You can get the data in your controller as follows:
// for subject with id 1
public function getOneRow(){
$subject = Subject::with('subcategory.category')->findOrFail(1);
//subject_id = $subject->id
//subject_name = $subject->name
//subcategory_id = $subject->subcategory->id
//category_name = $subject->subcategory->category->name
return array("subject_name"=>$subject->name, "category_name"=>$subject->subcategory->id, "subcategory_name"=>$subject->subcategory->category->name);
}
// for all subjects
public function getOneRow(){
$subjects = Subject::with('subcategory.category')->all();
$out = array();
foreach($subjects as $subject){
// each row
//subject_id = $subject->id
//subject_name = $subject->name
//subcategory_id = $subject->subcategory->id
//category_name = $subject->subcategory->category->name
$out[] = array("subject_name"=>$subject->name, "category_name"=>$subject->subcategory->id, "subcategory_name"=>$subject->subcategory->category->name);
}
return $out;
}
Edit for Laravel 5.1
Your models will be defined differently. Here's an example. Or follow the docs:
// Category Model Laravel 5.1
use Illuminate\Database\Eloquent\Model;
class Category extends Model {
protected $table = "category";
public function subcategory(){
$this->hasMany('Subcategory','category_id');
}
}
Edit: Completed the functions with return statements as requested in comment