I made an alias for this function in order to kill processes in bash:
On my .bashrc file
kill_process(){
# $1 being a parameter for the process name
kill $(ps ax | grep "$1" | awk '{print $1}')
}
alias kill_process=kill_process
So, suppose I want to kill the meteor process:
Let's see all meteor processes:
ps aux | grep 'meteor' | awk '{print $2}'
21565
21602
21575
21546
Calling the kill_process function with the alias
kill_process meteor
bash: kill: (21612) - No such process
So, the kill_process function effectively terminates the meteor processes, but it's kill command looks for an inexistent pid. Notice the pid 21612 wasn't listed by ps aux | grep. Any ideas to improve the kill_process function to avoid this?
I think in your case the killall command would do what you want:
killall NAME
The standard way of killing processes by name is using killall, as Swoogan suggests in his answer.
As to your kill_process function, the grep expression that filters ps will match the very own grep process (you can see this running the pipeline without awk), but by the time kill is invoked, that process is no longer running. That's the message you see.
Each time you run the command, grep runs again with a new PID: that's the reason you can't find it on the list when you test it.
You could:
Run ps first, pipe it into a file or variable, then grep
Filter grep's PID out of the list
(Simpler) supress kill output:
kill $(...) 2>/dev/null
Related
I am trying to kill a process using a shell script.Looks shell itself is getting killed in this process. Also I am seeing non zero return value of the script in terminal.
I am running it on Amazon Linux 2 with sudo.
#!/bin/bash
kill -9 $(ps -ef | grep myapp | grep -v grep | awk '{print $2}')
I am executing like:
sudo ./myscript.sh
"echo $?" after executing is returning 137 instead of zero. Can someone please help to understand what is going wrong.
Another observation:
if i directly run kill command in my terminal, i.e below command,
kill -9 $(ps -ef | grep myapp | grep -v grep | awk '{print $2}')
I see echo $? is returning zero.
Update:
Problem is solved. Name of process I am trying to kill is overlapping with name of my script. Hence grep is returning both the pid's. Both the process are getting killed. Also learnt that better way of doing this by using pkill or using pidof() to get pid.
If you want the exit code of your last-run command to be the exit code for the script, your script must end with exit $? as the last line. Any function before that must also end with the $? so the chain flows to that final line. Otherwise some other exit is taking place.
If the script is being killed along side the application or script you are trying to kill, then your ps and grep work is likely including both in the results. Look at the output of the ps and grep while the script is running. You could add a line prior to your kill line which just shows the output of the ps and greps so you can see what is actually getting killed.
Finally (and I don't think this is the case) if you are trying to end the script after the kill, manually run an exit (again likely using exit $? for the reason stated above) where appropriate within the script.
Hope that helps you get where you are going.
If I do a:
npm run script
Can I stop it with a stop?
npm stop script
Why I tried it and it does not work.
I know that with the combination of "Ctrl + c" I kill it, but I want to do it by command.
Try something like that:
ps -ef | grep script | awk '{print $2}' | head -n1 | xargs kill -9
This command should find first process named script on the list of all unix processes created by all users and kill it by with using its PID.
I was running an ubuntu console, when I type the following command, all the processes would be perfectly killed.
kill -9 $(ps -ef | grep 'job1/' | grep -v grep| awk '{print $2}')
But when I was trying to use crontab to call a script routinely, things went wrong.
#!/bin/bash
pid=$(ps -ef | grep 'job1/' | grep -v grep | awk '{print $2}')
echo $pid
kill -9 $pid
# the following commands were never executed
sleep 5
/data/job1/tomcat8/bin/startup.sh
The result was just like this:
15432 15438
Killed
It seems to just killed the job, but won't execute the following commands. Any idea?
If you are going to make a script that kills things by PID then you need to be very careful that you kill the right things.
You already have grep -v grep to avoid killing the grep itself, but it seems that you have not put in anything to protect against the script killing itself. Since you know your own PID you could grep -v that, but what if you are 123 and one of the things you want to kill is 1234? Probably safer to go by script name.
I'd like to kill a process/script with a simple command using. At the moment I do the following
ps -ef | grep myscriptname
kill 123456
But is there a way to maybe combine the 2 command together so I don't need to look and manually write the pid, something like this kill grep myscriptname?
You want pkill:
pkill myscriptname
On some systems there is a similar tool called killall, but be careful because on Solaris it really does kill everything!
Note that there is also pgrep which you can use to replace your ps | grep pipeline:
pgrep myscriptname
It prints the PID for you, and nothing else.
Another alternative is using the pidof command:
kill $(pidof processname)
you can try this simple trick
pkill -f "my_sript_filename"
I use kill $(pgrep <program name>), it works.
Another alternative, pgrep with xargs
ps aux | pgrep gitlab | xargs kill
An alternative is piping to the xargs command:
ps -ef | grep myscriptname | xargs kill
http://man7.org/linux/man-pages/man1/xargs.1.html
This command ps -ef | grep php returns a list of processes
I want to kill in one command or with a shell script all those processes
Thanks
The easiest way to kill all commands with a given name is to use killall:
killall php
Note, this only sends an interrupt signal. This should be enough if the processes are behaving. If they're not dying from that, you can forcibly kill them using
killall -9 php
The normal way to do this is to use xargs as in ps -ef | grep php | xargs kill, but there are several ways to do this.
ps -ef lists all processes and then you use grep to pick a few lines that mention "php". This means that also commands that have "php" as part of their command line will match, and be killed. If you really want to match the command (and not the arguments as well), it is probably better to use pgrep php.
You can use a shell backtick to provide the output of a command as arguments to another command, as in
kill `pgrep php`
If you want to kill processes only, there is a command pkill that matches a pattern to the command. This can not be used if you want to do something else with the processes though. This means that if you want to kill all processes where the command contain "php", you can do this using pkill php.
Hope this helps.
You can find its pid (it's on the first column ps prints) and use the kill command to forcibly kill it:
kill -9 <pid you found>
Use xargs:
ps -ef | grep php | grep -v grep | awk '{print $2}' | xargs kill -9
grep -v grep is exclude the command itself and awk gives the list of PIDs which are then passed kill command.
Use pkill php. More on this topic in this similar question: How can I kill a process by name instead of PID?