ofbiz URI MAPPING about n depth - view

ofbiz uri mapping
1.my test source get from
1.1 source location : svn co http://svn.apache.org/repos/asf/ofbiz/trunk ofbiz /* source location in svn */
2. menu( examlple->ajaxexample )
2.1 #location : https://localhost:8443/example/control/authview/findExampleAjax /* location about uri */
3. sample url is follow
3.1 #uri https://localhost:8443/example/control/authview/findExampleAjax /* location about uri */
4. i want set uri
4.1 #https://localhost:8443/example/control/authview/findExampleAjax/* location about uri */
4.2 #https://localhost:8443/example/control/authview/t1/findExampleAjax
4.3 #https://localhost:8443/example/control/authview/t1/t2/findExampleAjax
how can i set controller.xml
I do not know request authview/findExampleAjax in controller.xml file
I can not find authview
how can i mapping nth depth directory( URI )
Thank you

You can map this screen by adding a <view-map> in controller.xml
<view-map name="findExampleAjax" type="screen"
page="component://example/control/authview/yourScreens.xml#findExampleAjax"/>
Here yourScreens.xml should contain multiple Screens and you can create a new screen like this
<screen name="findExampleAjax">
// Decoration for screen
</screen>
and updateExample is a service defined in a .xml file that contains services and the location of the file is given in ofbiz-component.xml

Related

relative path to folder won't work when jpackaged java

so my project is here: https://github.com/Potat-OS1/project_thingo and i started the project from a template.
under the champPortrait section is where i'm having my problem. when i run it in the IDE the path works, as i understand it its the relative path of the build folder. does it not use this path when its packaged? what path should i be using?
i can getResourceAsStream the contents of the folder but in this particular case i need the folder its self so i can put all the names of files inside of the folder into a list.
When the application is bundled with jpackage, all classes and resources are packaged in a jar file. So what you are trying to do is read all the entries in a particular package from a jar file. There is no nice way to do that.
Since the contents of the jar file can't be changed after deployment, the easiest solution is probably just to create a text resource listing the files. You just have to make sure the you update the text file at development time if you change the contents of that resource.
So, e.g., if in your source hierarchy you have
resources
|
|--- images
|
|--- img1.png
|--- img2.png
|--- img3.png
I would just create a text file resources/images/imageList.txt with the content
img1.png
img2.png
img3.png
Then in code you can do:
List<Image> images = new ArrayList<>();
String imageBase = "/images/"
try (BufferedReader br = new BufferedReader(new InputStreamReader(getClass().getResourceAsStream("/images/imageList.txt"))) {
br.lines().forEach(imageName -> {
URL imageUrl = getClass().getResource(imageBse + imageName);
Image image = new Image(imageURL.toExternalForm());
images.add(image);
}
} catch (Exception exc) {
exc.printStackTrace();
}
As mentioned, you will need to keep the text file in sync with the contents of the resource folder before building. If you're feeling ambitious, you could look into automating this as part of your build with your build tool (gradle/Maven etc.).
The Java resource API does not provide a supported way to list the resources in a given package. If you aren't using a framework that provides their own solution (e.g., Spring), then probably the easiest and sufficiently robust solution is to do what #James_D demonstrates: Create another resource that simply lists the names of the resources in the current package. Then you can read that resource to get the names of the other resources.
For a relatively small number of resources, where the number doesn't change often, creating the "name list" resource manually is probably sufficient. But you've tagged this question with gradle, so another option is to have the build tool create these "name list" resources for you. This can be done in plugin, or you could do it directly in your build script.
Example
Here's an example of creating the "plugin" in your build script.
Sources
Source structure:
\---src
\---main
+---java
| \---sample
| Main.java
|
\---resources
\---sample
bar.txt
baz.txt
foo.txt
qux.txt
Where each *.txt file in src/main/resources/sample contains a single line which says Hello from <filename>!.
build.gradle.kts (Kotlin DSL):
plugins {
application // implicitly applies the Java Plugin as well
}
application {
mainClass.set("sample.Main")
}
// gets the 'processResources' task and augments it to add the desired
// behavior. This task processes resources in the "main" source set.
tasks.processResources {
// 'doLast' means everything inside happens at the end, or at least
// near the end, of this task
doLast {
/*
* Get the "main" source set. By default, this essentially
* represents the files under 'src/main'. There is another
* source set added by the Java Plugin named "test", which
* represents the files under 'src/test'.
*/
val main: SourceSet by sourceSets
/*
* Gets *all* the source directories in the main source set
* used for resources. By default, this will only include
* 'src/main/resources'. If you add other resource directories
* to the main source set, then those will be included here as well.
*/
val source: Set<File> = main.resources.srcDirs
/*
* Gets the build output directory for the resources in the
* main source set. By default, this will be the
* 'build/resources/main` directory. The '!!' bit at the end
* of this line of code is a Kotlin language thing, which
* basically says "I know this won't be null, but fail if it is".
*/
val target: File = main.output.resourcesDir!!
/*
* This calls the 'createResourceListFiles' function for every
* resource directory in 'source'.
*/
for (root in source) {
// the last argument is 'root' because the first package is
// the so-called "unnamed/default package", which are resources
// under the "root"
createResourceListFiles(root, target, root)
}
}
}
/**
* Recursively traverses the package hierarchy of the given resource root and creates
* a `resource-list.txt` resource in each package containing the absolute names of every
* resource in that package, with each name on its own line. If a package does not have
* any resources, then no `resource-list.txt` resource is created for that package.
*
* The `resourceRoot` and `targetDir` arguments will never change. Only the `packageDir`
* argument changes for each recursive call.
*
* #param resourceRoot the root of the resources
* #param targetDir the output directory for resources; this is where the
* `resource-list.txt` resource will be created
* #param packageDir the current package directory
*/
fun createResourceListFiles(resourceRoot: File, targetDir: File, packageDir: File) {
// get all non-directories in the current package; these are the resources
val resourceFiles: List<File> = listFiles(packageDir, File::isFile)
// only create a resource-list.txt file if there are resources in this package
if (resourceFiles.isNotEmpty()) {
/*
* Determine the output file path for the 'resource-list.txt' file. This is
* computed by getting the path of the current package directory relative
* to the resource root. And then resolving that relative path against
* the output directory, and finally resolving the filename 'resource-list.txt'
* against that directory.
*
* So, if 'resourceRoot' was 'src/main/resources', 'targetDir' was 'build/resources/main',
* and 'packageDir' was 'src/main/resources/sample', then 'targetFile' will be resolved
* to 'build/resources/main/sample/resource-list.txt'.
*/
val targetFile: File = targetDir.resolve(packageDir.relativeTo(resourceRoot)).resolve("resource-list.txt")
// opens a BufferedWriter to 'targetFile' and will close it when
// done (that's what 'use' does; it's like try-with-resources in Java)
targetFile.bufferedWriter().use { writer ->
// prints the absolute name of each resource on their own lines
for (file in resourceFiles) {
/*
* Prepends a forward slash to make the name absolute. Gets the rest of the name
* by getting the relative path of the resource file from the resource root. Replaces
* any backslashes with forward slashes because Java's resource-lookup API uses forward
* slashes (needed on e.g., Windows, which uses backslashes for filename separators).
*
* So, a resource at 'src/main/resources/sample/foo.txt' would result in
* '/sample/foo.txt' being written to the 'resource-list.txt' file.
*/
writer.append("/${file.toRelativeString(resourceRoot).replace("\\", "/")}")
writer.newLine()
}
}
}
/*
* Gets all the child directories of the current package directory, as these
* are the "sub packages", and recursively calls this function for each
* sub package.
*/
for (packageSubDir in listFiles(packageDir, File::isDirectory)) {
createResourceListFiles(resourceRoot, targetDir, packageSubDir)
}
}
/**
* #param directory the directory to list the children of
* #param predicate the filter function; only children for which this function
* returns `true` are included in the list
* #return a possibly empty list of files which are the children of `dir`
*/
fun listFiles(directory: File, predicate: (File) -> Boolean): List<File>
= directory.listFiles()?.filter(predicate) ?: emptyList()
Main.java:
package sample;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.List;
public class Main {
public static void main(String[] args) throws IOException {
for (var resource : resources()) {
System.out.printf("Contents of '%s':%n", resource);
try (var reader = openResource(resource)) {
String line;
while ((line = reader.readLine()) != null) {
System.out.printf(" %s%n", line);
}
System.out.println();
}
}
}
public static List<String> resources() throws IOException {
try (var input = openResource("/sample/resource-list.txt")) {
return input.lines().toList();
}
}
public static BufferedReader openResource(String name) throws IOException {
var input = Main.class.getResourceAsStream(name);
return new BufferedReader(new InputStreamReader(input));
}
}
Output
After the processResources task runs, you'll have the following /sample/resource-list.txt file in your build output:
/sample/bar.txt
/sample/baz.txt
/sample/foo.txt
/sample/qux.txt
And running the application (./gradlew clean run) will give the following output:
> Task :run
Contents of '/sample/bar.txt':
Hello from bar.txt!
Contents of '/sample/baz.txt':
Hello from baz.txt!
Contents of '/sample/foo.txt':
Hello from foo.txt!
Contents of '/sample/qux.txt':
Hello from qux.txt!
BUILD SUCCESSFUL in 2s
4 actionable tasks: 4 executed
Notes
Note that the resource-list.txt resource(s) will only exist in your build output/deployment. It does not exist in your source directories. Also, the way I implemented this, it will only list resources in your source directories. Any resources generated by, for example, an annotation processor will not be included. You could, of course, modify the code to fix that if it becomes an issue for you.
The above will only run for production resources, not test resources (or any other source set). You can modify the code to change this as needed.
If a package does not have any resources, then the above will not create a resource-list.txt resource for that package.
Each name listed in resource-list.txt is the absolute name. It has a leading /. This will work with Class#getResource[AsStream](String), but I believe to call the same methods on ClassLoader (if you need to for some reason) you'll have to remove the leading / (in code).
Finally, I wrote the Kotlin code in the build script rather quickly. There may be more efficient, or at least less verbose, ways to do the same thing. And if you want to apply this to multiple projects, or even multiple subprojects of the same project, you can create a plugin. Though it may be that some plugin already exists for this, if you're willing to search for one.

How to serve index.html on non root path using golang

I want to serve my angular app index.html under localhost:3000/mypath/ is there a way to accomplish that?
package main
import (
"net/http"
)
func main() {
// This works
http.Handle("/", http.FileServer(http.Dir("./my-project/dist/")))
// This doesn't work, you get 404 page not found
http.Handle("/mypath/", http.FileServer(http.Dir("./my-project/dist/")))
http.ListenAndServe(":3000", nil)
}
Remove the / handler, and change the /mypath/ handler into code below:
http.Handle("/mypath/", http.StripPrefix("/mypath/", http.FileServer(http.Dir("./my-project/dist/"))))
The http.StripPrefix() function is used to remove the prefix of requested path. On your current /mypath handler, every request will be prefixed with /mypath/. Take a look at example below.
/mypath/index.html
/mypath/some/folder/style.css
...
If the requested url path is not stripped, then (as per above example) it'll point into below respective locations, which is INVALID path and will result file not found error.
./my-project/dist/mypath/index.html
./my-project/dist/mypath/some/folder/style.css
...
By stripping the /mypath, it'll point into below locations, the correct one.
./my-project/dist/index.html
./my-project/dist/some/folder/style.css
...

How to delete a file in laravel 4

I'm using laravel 4 and I need to change an uploaded image, I have it in:
Public
--uploads
---news
----id_news.jpg
When editing the new's I want to make a change image form, but how could I delete and upload another file. I am using:
Input::file('img')->move('uploads/news', $id.'_news.jpg');
The problem it's that it doesn't work, it's not replacing the file, so how could I delete The image so I could upload again.
In laravel 3 I only used:
File::delete('path/to/file');
But I don't see anything about removing files in laravel docs.
I think you should append public_path() to file names , to get real file path, like this
File::delete(public_path().$id.'_news.jpg');
There is still the delete method in Laravel 4:
src/Illuminate/Filesystem/Filesystem.php
otherwise just use good old unlink()!?
You can easily do something like:
$filename = public_path().'/uploads/foo.bar';
if (File::exists($filename)) {
File::delete($filename);
}
Reference: Laravel-recipes Delete a File
Other delete usage:
// Delete a single file
File::delete($filename);
// Delete multiple files
File::delete($file1, $file2, $file3);
// Delete an array of files
$files = array($file1, $file2);
File::delete($files);
Source: http://laravel-recipes.com/recipes/133/deleting-a-file
$destinationPath = 'uploads/my-image.jpeg'; // from public/
if ( File::exists($destinationPath) ) {
File::delete($destinationPath);
}
This works on laravel 4.2.
File::delete(storage_path()."/ProductSalesReport-20150316.csv");
// Here are some other paths to directories laravel offers, Hope this
helps
/* Path to the 'app' folder */
echo app_path();
/* Path to the project's root folder */
echo base_path();
/* Path to the 'public' folder */
echo public_path();
/* Path to the 'app/storage' folder */
echo storage_path();

web services calling error in flex

When i call web services, i got below mentioned error
[FaultEvent fault=[RPC Fault faultString="Error #1098: Illegal prefix ns0 for no namespace." faultCode="EncodingError" faultDetail="null"] messageId=null type="fault" bubbles=false cancelable=true eventPhase=2]
<mx:WebService id="myWebService1" wsdl="URL">
<mx:operation name="loginservice" result="getMonths_result(event);" fault="getMonths_fault(event);">
</mx:operation>
</mx:WebService>
I know nothing about flex4 but it seems that there is a XML document somewere wich has prefixed elements (<ns0:Element>) but it has not a defined namespace (xmlns:ns0 = "URI").
OR
There is not an URI in the namespace definition (xmlns:ns0 = "")

how do we compare a localfile and hdfs file for consistency

public String getDirs() throws IOException{
fs=FileSystem.get(conf);
fs.copyFromLocalFile(new Path("/private/tmp/as"), new Path("/test"));
LocalFileSystem lfs=LocalFileSystem.getLocal(conf);
// System.out.println(new LocalFileSystem().ge (conf.getLocalPath("/private/tmp/as")));
System.out.println("Local Path : "+lfs.getFileChecksum(new Path("/private/tmp/as")));
System.out.println("HDFS PATH : "+ fs.getFileChecksum(new Path("/test/as")));
return "done";
}
Output is
Local Path : null
HDFS PATH : MD5-of-0MD5-of-512CRC32:a575c5e99b2e08605dc7c6723889519c
Not sure why the checksum is null for local file
Hadoop relies on the FileSystem to have a checksum ready to match against. It does not generate one on-the-fly.
By default, the LocalFileSystem (or the specific implementation used for file:// paths) does not create/store checksums for all files created through it. You can toggle this behavior via the FileSystem#setWriteChecksum API call, and subsequently retrieving the checksum post-write will then work.

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