I want to fetch some environment variable which are set in .bash_aliases file. I want use them in my bash script
#!/bin/dash
echo $PATH
echo $DEPOT_TOOLS
Both are coming empty string once call it in myscript. In the terminal these variable are printing successfully.
All you have to do is source the .bash_aliases file -- however as dash does only supports POSIX shell syntax you'll likely find that there are definitions inside of .bash_aliases that don't work for dash. If this is the case simply put your aliases inside of a different file and source that. Also the environment variable PATH is generally always available not sure what's going on with your system.
#!/bin/dash
. .some_aliases
echo "$PATH"
echo "$something_else"
Related
How to set a global environment variable in a bash script?
If I do stuff like
#!/bin/bash
FOO=bar
...or
#!/bin/bash
export FOO=bar
...the vars seem to stay in the local context, whereas I'd like to keep using them after the script has finished executing.
Run your script with .
. myscript.sh
This will run the script in the current shell environment.
export governs which variables will be available to new processes, so if you say
FOO=1
export BAR=2
./runScript.sh
then $BAR will be available in the environment of runScript.sh, but $FOO will not.
When you run a shell script, it's done in a sub-shell so it cannot affect the parent shell's environment. You want to source the script by doing:
. ./setfoo.sh
This executes it in the context of the current shell, not as a sub shell.
From the bash man page:
. filename [arguments]
source filename [arguments]
Read and execute commands from filename in the current shell
environment and return the exit status of the last command executed
from filename.
If filename does not contain a slash, file names in PATH are used to
find the directory containing filename.
The file searched for in PATH need not be executable. When bash is not
in POSIX mode, the current directory is searched if no file is found
in PATH.
If the sourcepath option to the shopt builtin command is turned off,
the PATH is not searched.
If any arguments are supplied, they become the positional parameters
when filename is executed.
Otherwise the positional parameters are unchanged. The return status
is the status of the last command exited within the script (0 if no
commands are executed), and false if filename is not found or cannot
be read.
source myscript.sh is also feasible.
Description for linux command source:
source is a Unix command that evaluates the file following the command,
as a list of commands, executed in the current context
#!/bin/bash
export FOO=bar
or
#!/bin/bash
FOO=bar
export FOO
man export:
The shell shall give the export attribute to the variables corresponding to the specified names, which shall cause them to be in the environment of subsequently executed commands. If the name of a variable is followed by = word, then the value of that variable shall be set to word.
A common design is to have your script output a result, and require the cooperation of the caller. Then you can say, for example,
eval "$(yourscript)"
or perhaps less dangerously
cd "$(yourscript)"
This extends to tools in other languages besides shell script.
In your shell script, write the variables to another file like below and source these files in your ~/.bashrc or ~/.zshrc
echo "export FOO=bar" >> environment.sh
In your ~/.bashrc or ~/.zshrc, source it like below:
source Path-to-file/environment.sh
You can then access it globally.
FOO=bar
export FOO
How do I reference a variable from another file using ksh?
I know in bash you just use "source script" and then "echo $variable"
but in ksh, when I try that, it does not work.
example I am trying to do:
config.sh:
variable=apple
access_var.sh:
#!/bin/bash
source config.sh
echo $variable
in ksh I just get " config.sh: cannot open [No such file or directory]"
Provide a path for to the file. If the file is in the current directory use source ./config.sh. Otherwise an absolute or relative path is OK, the latter must not start with ./.
If you don't provide a path ksh searches the file in the directories in $PATH.
(And remember to change the shebang in the other script to whereever your ksh is (or make sure your scripts are POSIX shell compatible and just use #!/bin/sh to have scripts with a high chance to run everywhere).)
I am looking to execute a script but have it include another script before it executes. The problem is, the included script would be generated and the executed script would be unmodifiable. One solution I came up with, was to actually reverse the include, by having the include script as a wrapper, calling set to set the arguments for the executed script and then dotting/sourcing it. E.g.
#!/bin/bash
# Generated wrapper or include script.
: Performing some setup...
target_script=$1 ; shift
set -- "$#"
. "$target_script"
Where target_script is the script I actually want to run, importing settings from the wrapper.
However, the potential problem I face is that callers of the target script or even the target script itself may be expecting $0 to be set to the path of it's location on the file system. But because this wrapper approach overrides $0, the value of $0 may be unexpected and could produce undefined behaviour.
Is there another way to perform what is in effect, an LD_PRELOAD but in the scripted form, through bash without interfering with its runtime parameters?
I have looked at --init-file or --rcfile, but these only seem to be included for interactive shells.
Forcing interactive mode does seem to allow me to specify --rcfile:
$ bash --rcfile /tmp/x-include.sh -i /tmp/xx.sh
include_script: $0=bash, $BASH_SOURCE=/tmp/x-include.sh
target_script: $0=/tmp/xx.sh, $BASH_SOURCE=/tmp/xx.sh
Content of the x-include.sh script:
#!/bin/bash
echo "include_script: \$0=$0, \$BASH_SOURCE=$BASH_SOURCE"
Content of the xx.sh script:
#!/bin/bash
echo "target_script: \$0=$0, \$BASH_SOURCE=$BASH_SOURCE"
From the bash documentation:
When bash is started non-interactively, to run a shell script, for example, it looks for the variable BASH_ENV in
the environment, expands its value if it appears there, and uses the expanded value as the name of a file to read
and execute. Bash behaves as if the following command were executed:
if [ -n "$BASH_ENV" ]; then . "$BASH_ENV"; fi
but the value of the PATH variable is not used to search for the file name.
So that settles it then:
BASH_ENV=/tmp/x-include.sh /bin/bash /tmp/xx.sh
I have a number of Bash and Perl scripts which are unrelated in functionality, but are related in that they work within the same project.
The fact that they work in the same project means that I commonly specify the same directories, the same project specific commands, the same keywords at the top of every script.
Currently, this has not bitten me, but I understand that it would be easier to have all of these values in one place, then if something changes I can change a value once and have the various scripts pick up on those changes.
The question is - how is best to declare these values? A single Perl script that is 'required' in each script would require less changes to the Perl scripts, though doesn't provide a solution to the Bash script. A configuration file using a "key=value" format would perhaps be more universal, but requires each script to parse the configuration and has the potential to introduce issues. Is there a better alternative? Using environmental variables? Or a Bash specific way that Perl can easily execute and interpret?
When you run a shell script, it's done in a sub-shell so it cannot affect the parent shell's environment. So when you declare a variable as key=value its scope is limited to the sub-shell context. You want to source the script by doing:
. ./myscript.sh
This executes it in the context of the current shell, not as a sub shell.
From the bash man page:
. filename [arguments]
source filename [arguments]
Read and execute commands from filename in the current shell environment and return the exit status of the last command executed from filename.
If filename does not contain a slash, file names in PATH are used to find the directory containing filename.
Also you can use the export command to create a global environment variable. export governs which variables will be available to new processes, so if you say
FOO=1
export BAR=2
./myscript2.sh
then $BAR will be available in the environment of myscript2.sh, but $FOO will not.
Define environments variables :
user level : in your ~/.profile or ~/.bash_profile or ~/.bash_login or ~/.bashrc
system level : in /etc/profile or /etc/bash.bashrc or /etc/environment
For example add tow lines foreach variable :
FOO=myvalue
export FOO
To read this variable in bash script :
#! /bin/bash
echo $FOO
in perl script :
#! /bin/perl
print $ENV{'FOO'};
You could also source another file, so you do not create extra env variables, that may lead to unexpected behaviours.
source_of_truth.sh:
FOO="bar"
scritp1.sh
#!/usr/bin/env bash
source source_of_truth.sh
echo ${FOO}
# ... doing something
scritp2.sh
#!/usr/bin/env bash
source source_of_truth.sh
echo ${FOO}
# ... doing something else
How to set a global environment variable in a bash script?
If I do stuff like
#!/bin/bash
FOO=bar
...or
#!/bin/bash
export FOO=bar
...the vars seem to stay in the local context, whereas I'd like to keep using them after the script has finished executing.
Run your script with .
. myscript.sh
This will run the script in the current shell environment.
export governs which variables will be available to new processes, so if you say
FOO=1
export BAR=2
./runScript.sh
then $BAR will be available in the environment of runScript.sh, but $FOO will not.
When you run a shell script, it's done in a sub-shell so it cannot affect the parent shell's environment. You want to source the script by doing:
. ./setfoo.sh
This executes it in the context of the current shell, not as a sub shell.
From the bash man page:
. filename [arguments]
source filename [arguments]
Read and execute commands from filename in the current shell
environment and return the exit status of the last command executed
from filename.
If filename does not contain a slash, file names in PATH are used to
find the directory containing filename.
The file searched for in PATH need not be executable. When bash is not
in POSIX mode, the current directory is searched if no file is found
in PATH.
If the sourcepath option to the shopt builtin command is turned off,
the PATH is not searched.
If any arguments are supplied, they become the positional parameters
when filename is executed.
Otherwise the positional parameters are unchanged. The return status
is the status of the last command exited within the script (0 if no
commands are executed), and false if filename is not found or cannot
be read.
source myscript.sh is also feasible.
Description for linux command source:
source is a Unix command that evaluates the file following the command,
as a list of commands, executed in the current context
#!/bin/bash
export FOO=bar
or
#!/bin/bash
FOO=bar
export FOO
man export:
The shell shall give the export attribute to the variables corresponding to the specified names, which shall cause them to be in the environment of subsequently executed commands. If the name of a variable is followed by = word, then the value of that variable shall be set to word.
A common design is to have your script output a result, and require the cooperation of the caller. Then you can say, for example,
eval "$(yourscript)"
or perhaps less dangerously
cd "$(yourscript)"
This extends to tools in other languages besides shell script.
In your shell script, write the variables to another file like below and source these files in your ~/.bashrc or ~/.zshrc
echo "export FOO=bar" >> environment.sh
In your ~/.bashrc or ~/.zshrc, source it like below:
source Path-to-file/environment.sh
You can then access it globally.
FOO=bar
export FOO