Distribution using the Poisson Point Process model - random

I need to use the Poisson Point Process (PPP) model to randomly distribute a set of 'objects'; over a given area:
Let's say that we have N objects to distribute over an area that has been split equally into S subsections. How might I use PPP to decide whether or not a subsection r (where r ∈ S) contains an object t (where t ∈ N)?
Ideally if anyone has a pseudo code solution then let me know, but I would be grateful for any form of help.
If you need me to be more specific let me know.

Not writing a complete solution, because a request that says you need to use a Poisson Point Process and aren’t sure what that is sounds a lot like homework.
First, if the sections have been divided equally, any given element is equally likely to be in any of them. You would use a PPP to determine how many elements each section is likely to contain. Keep in mind that, if the sections are divided equally, they all have equal measure, 1/S. The links you followed give the probability of finding exactly x elements in r given its measure and N, so the probability of finding at most x is the cumulative PDF of this, and the probability of finding more than x is the complement of the PDF.
One hint to actually calculate this: memoize a vector of the factorials up to N, and think of an easy way to find the lowest common denominator of a/n! + b/(n-1)! + c/(n-2)! + ….

Related

Markov chains and Random walks on top of biological data

I'm coming from biology's field and thus I have some difficulties in understanding (intuitively?) some of the ideas of that paper. I really tried my best to decipher it step by step by using a lot of google and youtube, but now I feel, it's the time to refer to the professionals in that field.
Before filling out the whole universe with (unordered) questions, let me put the whole thing down and try to introduce you to the subject while at the same time explain to you what I got so far from my research on that.
Microarrays
For those that do not have any idea of what this is, you can imagine, that it is literally an array (matrix) where each cell of it contains a probe for a specific gene. Making the long story short, by the end of the microarray experiment, you have a matrix (in computational terms) with each column representing a sample, each line a different gene while the contents of the matrix represent the expression values of the genes for each sample.
Pathways
In biology pathway / gene-set they call a set of genes that interact with each other forming a small network responsible for a specific function.These pathways are not isolated but they talk/interact with each other too. What that paper does on the first hand, is to expand the initial pathway (let us call it target pathway), by including some other genes from other pathways that might interact with that.
Procedure
1.
Let's assume now that we have a matrix G x S. Where G for genes and S for Samples. We construct a gene co-expression network (G x G) using as weights the Pearson's correlation coefficients between genes' pairs (a). This could also be represented as an undirected weighted graph. .
2.
For each gene (row OR column) we calculate the weighted degree (d) which is nothing more than the sum of all correlation coefficients of that gene.
3.
From the two previous matrices, they construct the transition matrix producing the probabilities (P) to transit from one gene to another by using the
formula
Q1. Why do they call this transition probability? Is there any intuitive way to see this as a probability in the biological context?
4.
Since we have the whole transition matrix, we can define a subnetwork of the initial one, that we want to expand it and it consisted out of let's say 15 genes. In that step, they used formula number 3 (on the paper) which transforms the values of the initial transition matrix as it says. They set the probability of 1 on the nodes that are part of the selected subnetwork because they define them as absorbing states.
Q2. In that same formula (3), I cannot understand what the second condition does. When should the probability be 0? Intuitively, in my opinion, all nodes that didn't exist in subnetwork, should have the P_ij value as a probability.
5.
After that, the newly constructed transition matrix is showed at formula (4) in the paper and I managed to understand it using this excellent article.
6.
Here is where everything is getting more blur for me and where I need the most of the help. What I imagine at that step, is that the algorithm starts randomly from one node and keep walking around the network. In order to construct a relevance function (What that exactly means?), they firstly calculate a probability called joint probability of visiting one node/edge E(i,j) and noted as :
From the other hand they seem to calculate another probability called probability of a walk of length L starting in x and denoted as :
7.
In the next step, they divide the previously calculated probabilities and calculate the number of times a random walk starts in x using the transition from i to j that I don't really understand what this means.
After that step, I lost their reasoning at all :-P.
I'm not expecting an expert to come open my mind and give me understand that procedure. What I'm expecting is some guidelines, hints, ideas, useful resources or more intuitive approaches to understanding the whole procedure. Then when I fully understand it I will try to implement it on R or python.
So any idea / critics is welcome.
Thanks.

Constrained random solution of an underspecified system of linear equations

Premise
I've a system of linear equations
dot(A,x) = y
whose solutions have many degrees of freedom: indeed the Number of linearly independent Equations (E) is less than the dimension of x, A.K.A. the Number of Variables (N).
The number of degrees of freedom left constrains the solutions to be a hyperplane N-E of the overall space R^N. Given the (unimportant) characteristics of A, I am always able to write the solutions x (a vector N x 1) as
x=dot(B,t)+q
where B is a N x (N-E) matrix, t a (N-E) x 1 vector and q a N x 1 vector. This define the hyperplane of the solutions of my original problem, A x = y in parametric form.
I need to extract a random solution, with uniform probability over any possible point of the hyperplane, such that all x are positive (we will refer to it as a positive solution). Note that, for the specific problem I am dealing with, the space of positive solutions of x exists and it is bounded (that's how the notion of uniform probability is reasonable for the specific case, to clarify as suggested by #Petr comment). In the beginning, once I was able to write x=Bt+q, I thought it extremely simple. Now I am starting to doubt it.
Proposed Solution
By now I do something like this:
For each dimension i in range(N-E) I compute the maximum and minimum value of t[i]: t_min[i] and t_max[i]. Intervals big enough to not exclude any possible positive solution. Those are algebraically computed, always existing and defining a limited space.
I extract N-E uniform random values t[i], each comprised between t_min [i] and t_max[i].
I compute x = dot(B,t)+q
If all x[j] are positives, accept the solution. If some x[j] is negative, go back to point 2.
An example is visible for a two dimensional space N-E in the next figure.
Caption: A problem in N dimension reduced to a N-E=2 space. The yellow diamond is the space of positive solutions of the N-dimensional problem. I randomly sample points in the orange box between (t1(min),t2(min)) and (t1(max),t2(max)) until I find a point in the yellow box.
I think it is a good enough solution, but...
Problem
When N-E is big, the space of the hyperparallelogram bounded inside the hypercube can be small. In general it will be small^(N-E), that can be very small. How small?
While for sure an infinite number of positive solutions to the original problem exist, the space of the solutions can have measure zero in the N-E dimensional space. This can happen if all the positive solutions of the original problem have one dimension of x = 0. The borders of a diamond will make contact, transforming the diamond of solutions to a line. Of course you will never randomly pick EXACTLY a line in 2D, let alone in 5D.
A obvious idea would be to further reduce the dimensionality from N-E to a smaller number, i.e. to extract directly points from the aforementioned line instead of the square. Algebra is not easy, but I'm working on it. I'm not positive I will be able to solve it.
Note that choosing first one dimension (for example t1), computing the new limits of t2 conditional to the value of t1 extracted and then extract a possible value of t2 in this boundary, while much faster, does not give a uniform probability among all the possible solutions.
I know that the problem is very specific, but even some general ideas or thoughts would be gladly received. I am doubtful if there is some computing technique to extract directly the solution in the diamond...

Testing if a vector is in a population of vectors

Suppose that I have an object that has N different scalar qualities, each of which I've measured (for example, the (x,y) coordinates at the tips of the major arms of a leaf). Together, I have N such measurements for each object, which I'll save as a 1D list of N reals.
Now I'm given a large number R of such objects, each with its corresponding N-element list. Let's call this the population. We can represent this as a matrix M with R rows, each of N elements.
I'm now given a new object B, with its 1D N-element list. I'd like to hand Mathematica my matrix M and my new object B, and get back a single number that tells me how confident I can be that B belongs to the population represented by M.
I'd also be happy with a probability, or any other number with a simple interpretation. I'm willing to assume that everything is uncorrelated, that the values in columns of M are normally distributed, and other such typical assumptions.
When N=1, Student's t-test seems the right tool. There seem to be tools built into Mathematica that can solve precisely this problem when N>1, but the documentation (and web references) presume more statistical depth than I have, so I don't have confidence that I know what to do. I feel like the solution is tantalizingly just out of reach. If anyone can provide a code example that solves this problem, I would be very grateful.

Single Pass Seed Selection Algorithm for k-Means

I've recently read the Single Pass Seed Selection Algorithm for k-Means article, but not really understand the algorithm, which is:
Calculate distance matrix Dist in which Dist (i,j) represents distance from i to j
Find Sumv in which Sumv (i) is the sum of the distances from ith point to all other points.
Find the point i which is min (Sumv) and set Index = i
Add First to C as the first centroid
For each point xi, set D (xi) to be the distance between xi and the nearest point in C
Find y as the sum of distances of first n/k nearest points from the Index
Find the unique integer i so that D(x1)^2+D(x2)^2+...+D(xi)^2 >= y > D(x1)^2+D(x2)^2+...+D(x(i-1))^2
Add xi to C
Repeat steps 5-8 until k centers
Especially step 6, do we still use the same Index (same point) over and over or we use the newly added point from C? And about step 8, does i have to be larger than 1?
Honestly, I wouldn't worry about understanding that paper - its not very good.
The algorithm is poorly described.
Its not actually a single pass, it needs do to n^2/2 pairwise computations + one additional pass through the data.
They don't report the runtime of their seed selection scheme, probably because it is very bad doing O(n^2) work.
They are evaluating on very simple data sets that don't have a lot of bad solutions for k-Means to fall into.
One of their metrics of "better"ness is how many iterations it takes k-means to run given the seed selection. While it is an interesting metric, the small differences they report are meaningless (k-means++ seeding could be more iterations, but less work done per iteration), and they don't report the run time or which k-means algorithm they use.
You will get a lot more benefit from learning and understanding the k-means++ algorithm they are comparing against, and reading some of the history from that.
If you really want to understand what they are doing, I would brush up on your matlab and read their provided matlab code. But its not really worth it. If you look up the quantile seed selection algorithm, they are essentially doing something very similar. Instead of using the distance to the first seed to sort the points, they appear to be using the sum of pairwise distances (which means they don't need an initial seed, hence the unique solution).
Single Pass Seed Selection algorithm is a novel algorithm. Single Pass mean that without any iterations first seed can be selected. k-means++ performance is depends on first seed. It is overcome in SPSS. Please gothrough the paper "Robust Seed Selestion Algorithm for k-means" from the same authors
John J. Louis

What's a good weighting function?

I'm trying to perform some calculations on a non-directed, cyclic, weighted graph, and I'm looking for a good function to calculate an aggregate weight.
Each edge has a distance value in the range [1,∞). The algorithm should give greater importance to lower distances (it should be monotonically decreasing), and it should assign the value 0 for the distance ∞.
My first instinct was simply 1/d, which meets both of those requirements. (Well, technically 1/∞ is undefined, but programmers tend to let that one slide more easily than do mathematicians.) The problem with 1/d is that the function cares a lot more about the difference between 1/1 and 1/2 than the difference between 1/34 and 1/35. I'd like to even that out a bit more. I could use √(1/d) or ∛(1/d) or even ∜(1/d), but I feel like I'm missing out on a whole class of possibilities. Any suggestions?
(I thought of ln(1/d), but that goes to -∞ as d goes to ∞, and I can't think of a good way to push that up to 0.)
Later:
I forgot a requirement: w(1) must be 1. (This doesn't invalidate the existing answers; a multiplicative constant is fine.)
perhaps:
exp(-d)
edit: something along the lines of
exp(k(1-d)), k real
will fit your extra requirement (I'm sure you knew that but what the hey).
How about 1/ln (d + k)?
Some of the above answers are versions of a Gaussian distribution which I agree is a good choice. The Gaussian or normal distribution can be found often in nature. It is a B-Spline basis function of order-infinity.
One drawback to using it as a blending function is its infinite support requires more calculations than a finite blending function. A blend is found as a summation of product series. In practice the summation may stop when the next term is less than a tolerance.
If possible form a static table to hold discrete Gaussian function values since calculating the values is computationally expensive. Interpolate table values if needed.
How about this?
w(d) = (1 + k)/(d + k) for some large k
d = 2 + k would be the place where w(d) = 1/2
It seems you are in effect looking for a linear decrease, something along the lines of infinity - d. Obviously this solution is garbage, but since you are probably not using a arbitrary precision data type for the distance, you could use yourDatatype.MaxValue - d to get a linear decreasing function for this.
In fact you might consider using (yourDatatype.MaxValue - d) + 1 you are using doubles, because you could then assign the weight of 0 if your distance is "infinity" (since doubles actually have a value for that.)
Of course you still have to consider implementation details like w(d) = double.infinity or w(d) = integer.MaxValue, but these should be easy to spot if you know the actual data types you are using ;)

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