This is probably a very simple answer but I want to double check I'm not making some obvious assumption.
Let's say I have a picture of a person...and I know that person is 66 inches tall. If I want to determine how many pixels represents one inch RELATIVE TO THE IMAGE ITSELF...do I simply divide the number of pixels / the number of inches?
Example:
Person a = 66 inches tall
Bitmap of person a = person a is 500 pixels in the Bitmap
Pixels in "real world" inches of the photo -> 500 / 60??
Related
I currently display 115 (!) different sponsor icons at the bottom of many web pages on my website. They're lazy-loaded, but even so, that's quite a lot.
At present, these icons are loaded separately, and are sized 75x50 (or x2 or x3, depending on the screen of the device).
I'm toying with the idea of making them all into one sprite, rather than 115 separate files. That would mean, instead of lots of tiny little files, I'd have one large PNG or WEBP file instead. The way I'm considering doing it would mean the smallest file would be 8,625 pixels across; and the x3 version would be 25,875 pixels across, which seems like a really very large image (albeit only 225 px high).
Will an image of this pixel size cause a browser to choke?
Is a sprite the right way to achieve a faster-loading page here, or is there something else I should be considering?
115 icons with 75 pixel wide sure will calculate to very wide 8625 pixels image, which is only 50px heigh...
but you don't have to use a low height (50 pixel) very wide (8625 pixel) image.
you can make a suitable rectangular smart size image with grid of icons... say, 12 rows of 10 icons per line...
115 x 10 = 1150 + 50 pixel (5 pixel space between 10 icons) total 1200 pixel wide approx.
50 x 12 = 600 + 120 pixel (5 pixel space between 12 icons) total 720 pixel tall approx.
Suppose i have been given the reading distance of 12 inches and the dpi is say around 600. Is there anyway to calculate the dots per visual angle without the object size or any other information?
Yes, the size of the object is not important -- you can consider it to be an infinite plane of pixels extending in all directions at 600 DPI. This works because you want the dots per degree. It's like asking for density (mass per volume) of an object instead of the total mass - you need to know the size for the total mass, but not for the density.
So the answer to your problem would be the area (in square inches) of the base of a 12" tall cone with a 1-degree point, times the DPI.
My math must be very rusty. I have to come up with an algorithm that will take a known:
x
y
width
height
of elements in a document and translate them to the same area on a different hardware device. For example, The document is being created for print (let's assume 8.5"x11" letter size) and elements inside of this document will then be transferred to a proprietary e-reader.
Also, the known facts about the e-reader, the screen is 825x1200 pixels portrait. There are 150 pixels per inch.
I am given the source elements from the printed document in points (72 Postscript points per inch).
So far I have an algorithm that get's close, but it needs to be exact, and I have a feeling I need to incorporate aspect ratio into the picture. What I am doing now is:
x (in pixels) = ( x(in points)/width(of document in points) ) * width(of ereader in pixels)
etc.
Any clues?
Thanks!
You may want to revert the order of your operations to reduce the effect of integer truncation, as follows:
x (in pixels) = x(in points) * width(of ereader in pixels) / width(of document in points)
I don't think you have an aspect ratio problem, unless you forgot to mention that your e-reader device has non-square pixels. In that case you will have a different amount of pixels per inch horizontally and vertically on the device's screen, so you will use the horizontal ppi for x and the vertical ppi for y.
assuming your coordinates are integer numbers, the formula x/width is truncating (integer division). What you need is to perform the division/multiplication in floating point numbers, then truncate. Something like
(int)(((double)x)/width1*width2)
should do the trick (using C-like conversion to double and int)
May I know what are the ways to calculate the length of 1 pixel in centimeters? The images that I have are 640x480. I would like to compare 2 pixels at different places on the image and find the difference in distance. Thus I would need to find out what's the length of the pixel in centimeters.
Thank you.
A pixel is a relative unit of measure, it does not have an absolute size.
Edit. With regard to your edit: again, you can only calculate the distance between two pixels in an image in pixels, not in centimeters. As a simple example, think video projectors: if you project, say, a 3×3px image onto a wall, the distance between the leftmost and the rightmost pixels could be anything from a few millimeters to several meters. If you moved the projector closer to the wall or farther away from it, the pixel size would change, and whatever distance you had calculated earlier would become wrong.
Same goes for computer monitors and other devices (as Johannes Rössel has explained in his answer). There, the pixel size in centimeters depends on factors such as the physical resolution of the screen, the resolution of the graphical interface, and the zooming factor at which the image is displayed.
A pixel does not have a fixed physical size, by definition. It is simply the smallest addressable unit of picture, however large or small.
This is fully dependent on the screen resolution and screen size:
pixel width = width of monitor viewable area / number of horizontal pixels
pixel height = height of monitor viewable area / number of vertical pixels
Actually, the answer depends on where exactly your real-world units are.
It comes down to dpi (dots per inch) which is the number of image pixels along a length of 2.54 cm. That's the resolution of an image or a target device (printer, screen, &c.).
Image files usually have a resolution embedded within them which specifies their real-world size. It doesn't alter their pixel dimensions, it just says how large they are if printed or how large a “100 %” view on a display would be.
Then there is the resolution of your screen, as others have mentioned, as well as the specified resolution your graphical interface uses (usually 96 dpi, sometimes 120)—and then it's all a matter of whether programs actually honor that setting ...
The OS will assume some dpi (usually 96 dpi on windows) however the screens real dpi will depend on the physical size of the display and the resolution
e.g a 15" monitor should have a 12" width so depending on the horizontal resolution you will get a different horizontal dpi, assuming a 1152 pixel screen width you will genuinely get 96 dpi
or "How I learned to stop worrying and learned to love measurement systems"
I wanted a central spot that I can refer to later to give me a quick low-down on various units of measurement used in programming. SO seemed the best place to put it, and while I could go ahead and answer the question myself, y'all are a much smarter bunch than I, so I might as well let you do it.
Please pick one unit that you're familiar with, use "#name" in the first line to give it as the heading (making it easy to find) and define it within your answer. Please do not duplicate - add comments or edit existing answers rather than adding a new answer. Similar units are still seperate - so please don't define em and en in the same answer. If a unit is exactly the same as another unit, add a line for "aliases" below the heading.
If it's a particularly obscure measurement type, please link to a second reference so people don't downvote you because they've never heard of it.
Point
Pica
Twips
Pixel
Em
En
CPI
DPI
I'm seeing a lot of downvoting - I suppose people believe this doesn't add value to StackOverflow's community. Please consider commenting below if you feel this doesn't add to the community, or if you think this is a bad question. I'm interested in improving it if you have any suggestions.
The great thing about standards is there are so many to choose from!
-Adam
I recommend to ammend the above answers using the following descriptions
PICA
Pica Typographic unit of measurement in the anglo-american point system. One pica is 1/72 Inch (0,351 mm) and equals 12 pica points. The didot equivalent of a pica is a cicero. A standard unit of measure in newspapers. There are 6 picas in one inch, 12 points in one pica.
PICA POINT
Pica Point 1/12 of a pica
POINT
996 points are equivalent to 35 centimeters, or one point is equal to .01383 inches. This means about 72.3 points to the inch. We in electronic printing use 72 points per inch
1 point (Truchet) = 0.188 mm (obsolete today)
1 point (Didot) = 0.376 mm = 1/72 of a French royal inch (27.07 mm)
1 point (ATA) = 0.3514598 mm = 0.013837 inch
1 point (TeX) = 0.3514598035 mm = 1/72.27 inch
1 point (Postscript) = 0.3527777778 mm = 1/72 inch
1 point (l’Imprimerie nationale, IN) = 0.4 mm
EM
An old printing term for a square-shaped blank space that’s as wide as the type is high; in other words, a 10-point em space will be 10 points wide.
EN
Half an em space; a 10-point en space will be 5 points wide.
DPI
The number of dots per inch a printer prints. The higher the dpi, the finer the resolution of the output.
PIXEL
The smallest dot you can draw on a computer screen
CPI
Counts per inch for Mouse properties and The number of horizontal characters that will fit in one inch for Printer properties
PITCH Alias CPI
Pitch describes the width of a character. Pitch equals the number of characters that can fit side-by-side in 1 inch; for example, 10 pitch equals 10 characters-per-inch or 10 CPI. Pitch is a term generally used with non-proportional (fixed-width) fonts.
TWIPS
A twip (derived from TWentieth of an Imperial Point) is a typographical measurement, defined as 1/20 of a typographical point. One twip is 1/1440 inch or 17.639 µm when derived from the PostScript point at 72 to the inch, and 1/1445.4 inch or 17.573 µm based on the printer's point at 72.27 to the inch
Additional Units:
LPI
The number of vertical lines of text that will fit in one inch
PPI
Thickness of paper, expressed in thousandths of an inch or pages per inch.
or sometimes no of horizontal pixels closely printed or displayed per inch.
FONT SIZE
Font size or Type size is the baseline distance for which the font was designed. A font should normally be identified and selected by this size, because the intended baseline distance is much more relevant for practical layout work than the actual dimensions of certain characters.
FONT HEIGHT
Font height is the height in mm of letters such as k or H. Typically, the font height is around 72% of the font size, but this is of course at the discretion of the font designer.
X-HEIGHT
x-height indicate typesize of lower-case letters excluding ascenders and descenders (from the height of the lower-case x)
H-HEIGHT
h-height or cap height refers to the height of a capital letter above the baseline for a particular typeface. It specifically refers to the height of capital letters that are flat—such as H or I—as opposed to round letters such as O.
Pixel
One of the little colored squares on your screen.
Pica
A typographical measure of 12 points, sometimes (incorrectly) called an Em. (in fact, an em is actually a horizontal distance the same as the point size of the type).
Twips
'Twentieth of an Imperial Point'. A measure used for marking up positions of widgets in Visual BASIC user interfaces. It was used this way so that positions could be specified precisely using integers. One Twip = 1/20 point = 1/1440 inch.
EM
An old printing term for a square-shaped blank space that’s as wide as the type is high; in other words, a 10-point em space will be 10 points wide.
DPI
Dots per inch. A dimensionless number used to measure the resolution of something in space, i.e. with respect to real occupied physical size.
dds complexity and headache since the standard/default DPI of a computer screen varies with the operating system. Macintosh screens generally have 72 DPI, while Windows favors 96. If you don't compensate for this when displaying images (and text), you will get unexpected variations.
Always amusing when people start talking of "the DPI of this image", for digital images such as PNG or JPEG. To me, they only have absolute pixels in them, unconnected to any physical size. If you want to print the image on a (for instance) 300 DPI printer, then you need to adapt and scale to get it correct, but the image itself only has pixels.
EN
Half an em space; a 10-point en space will be 5 points wide.
CPI
Counts per inch for Mouse properties and
The number of horizontal characters that will fit in one inch for Printer properties
PITCH Alias CPI
Pitch describes the width of a character. Pitch equals the number of characters that can fit side-by-side in 1 inch; for example, 10 pitch equals 10 characters-per-inch or 10 CPI. Pitch is a term generally used with non-proportional (fixed-width) fonts.
PostScript Point
1/72th of an inch.