Using bash how do I find a string and update the string next to it for example pass value
my.site.com|test2.spin:80
proxy_pass.map
my.site2.com test2.spin:80
my.site.com test.spin:8080;
Expected output is to update proxy_pass.map with
my.site2.com test2.spin:80
my.site.com test2.spin:80;
I tried using awk
awk '{gsub(/^my\.site\.com\s+[A-Za-z0-9]+\.spin:8080;$/,"my.site2.comtest2.spin:80"); print}' proxy_pass.map
but does not seem to work. Is there a better way to approch the problem. ?
One awk idea, assuming spacing needs to be maintained:
awk -v rep='my.site.com|test2.spin:80' '
BEGIN { split(rep,a,"|") # split "rep" variable and store in
site[a[1]]=a[2] # associative array
}
$1 in site { line=$0 # if 1st field is in site[] array then make copy of current line
match(line,$1) # find where 1st field starts (in case 1st field does not start in column #1)
newline=substr(line,1,RSTART+RLENGTH-1) # save current line up through matching 1st field
line=substr(line,RSTART+RLENGTH) # strip off 1st field
match(line,/[^[:space:];]+/) # look for string that does not contain spaces or ";" and perform replacement, making sure to save everything after the match (";" in this case)
newline=newline substr(line,1,RSTART-1) site[$1] substr(line,RSTART+RLENGTH)
$0=newline # replace current line with newline
}
1 # print current line
' proxy_pass.map
This generates:
my.site2.com test2.spin:80
my.site.com test2.spin:80;
If the input looks like:
$ cat proxy_pass.map
my.site2.com test2.spin:80
my.site.com test.spin:8080;
This awk script generates:
my.site2.com test2.spin:80
my.site.com test2.spin:80;
NOTES:
if multiple replacements need to be performed I'd suggest placing them in a file and having awk process said file first
the 2nd match() is hardcoded based on OP's example; depending on actual file contents it may be necessary to expand on the regex used in the 2nd match()
once satisified with the result the original input file can be updated in a couple ways ... a) if using GNU awk then awk -i inplace -v rep.... or b) save result to a temp file and then mv the temp file to proxy_pass.map
If the number of spaces between the columns is not significant, a simple
proxyf=proxy_pass.map
tmpf=$$.txt
awk '$1 == "my.site.com" { $2 = "test2.spin:80;" } {print}' <$proxyf >$tmpf && mv $tmpf $proxyf
should do. If you need the columns to be lined up nicely, you can replace the print by a suitable printf .... statement.
With your shown samples and attempts please try following awk code. Creating shell variable named var where it stores value my.site.com|test2.spin:80 in it. which further is being passed to awk program. In awk program creating variable named var1 which has shell variable var's value in it.
In BEGIN section of awk using split function to split value of var(shell variable's value container) into array named arr with separator as |. Where num is total number of values delimited by split function. Then using for loop to be running till value of num where it creates array named arr2 with index of current i value and making i+1 as its value(basically 1 is for key of array and next item is value of array).
In main block of awk program checking condition if $1 is in arr2 then print arr2's value else print $2 value as per requirement.
##Shell variable named var is being created here...
var="my.site.com|test2.spin:80"
awk -v var1="$var" '
BEGIN{
num=split(var1,arr,"|")
for(i=1;i<=num;i+=2){
arr2[arr[i]]=arr[i+1]
}
}
{
print $1,(($1 in arr2)?arr2[$1]:$2)
}
' Input_file
OR in case you want to maintain spaces between 1st and 2nd field(s) then try following code little tweak of Above code. Written and tested with your shown samples Only.
awk -v var1="$var" '
BEGIN{
num=split(var1,arr,"|")
for(i=1;i<=num;i+=2){
arr2[arr[i]]=arr[i+1]
}
}
{
match($0,/[[:space:]]+/)
print $1 substr($0,RSTART,RLENGTH) (($1 in arr2)?arr2[$1]:$2)
}
' Input_file
NOTE: This program can take multiple values separated by | in shell variable to be passed and checked on in awk program. But it considers that it will be in format of key|value|key|value... only.
#!/bin/sh -x
f1=$(echo "my.site.com|test2.spin:80" | cut -d'|' -f1)
f2=$(echo "my.site.com|test2.spin:80" | cut -d'|' -f2)
echo "${f1}%${f2};" >> proxy_pass.map
tr '%' '\t' < proxy_pass.map >> p1
cat > ed1 <<EOF
$
-1
d
wq
EOF
ed -s p1 < ed1
mv -v p1 proxy_pass.map
rm -v ed1
This might work for you (GNU sed):
<<<'my.site.com|test2.spin:80' sed -E 's#\.#\\.#g;s#^(\S+)\|(\S+)#/^\1\\b/s/\\S+/\2/2#' |
sed -Ef - file
Build a sed script from the input arguments and apply it to the input file.
The input arguments are first prepared so that their metacharacters ( in this case the .'s are escaped.
Then the first argument is used to prepare a match command and the second is used as the value to be replaced in a substitution command.
The result is piped into a second sed invocation that takes the sed script and applies it the input file.
I would like to replace a range of number in a file with another range. Let say I have:
/dev/raw/raw16
/dev/raw/raw17
/dev/raw/raw18
And I want modify them as:
/dev/raw/raw1
/dev/raw/raw2
/dev/raw/raw3
I know I can do it using sed or awk but just cannot write it correctly. What is the easiest way to do it?
awk to the rescue!
$ awk -F'/dev/raw/raw' '{print FS (++c)}' ile
/dev/raw/raw1
/dev/raw/raw2
/dev/raw/raw3
I would not recomment changing device names.
Anyway, just to replace letters or numbers you could use the option 's' with sed.
cat file.txt | sed s/raw16/raw1/g; > newfile.txt
In this example you replace all the raw16 with raw1.
Here some other examples ...
sed 's/foo/bar/' # replaces in each row the first foo only
sed 's/foo/bar/4' # replaces in each row every 4.
sed 's/foo/bar/g' # replaces all foo with bar
sed 's/\(.*\)foo/\1bar/' # replace the last only per line
.
# using /raw as field separator, so $2 is the end number in this case
awk -v From=16 -v To=18 -v NewStart=1 -F '/raw' '
# for lines where last number is in the scope
$2 >= From && $2 <=To {
# change last number to corresponding in new scope
sub( /[0-9]+$/, $2 - From + NewStart)
}
# print (default action of a non 0 value "filter") the line (modified or not)
7
' file.txt \
> newfile.txt
Note:
adapt the field separator for your real need
suite for your sample of data, not if other element are in the line but you could easily adapt this code foir your purpose
I have a text file and I'm trying to replace a specific character (.) in the first column to another character (-). Every field is delimited by comma. Some of the lines have the last 3 columns empty, so they have 3 commas at the end.
Example of text file:
abc.def.ghi,123.4561.789,ABC,DEF,GHI
abc.def.ghq,124.4562.789,ABC,DEF,GHI
abc.def.ghw,125.4563.789,ABC,DEF,GHI
abc.def.ghe,126.4564.789,,,
abc.def.ghr,127.4565.789,,,
What I tried was using awk to replace '.' in the first column with '-', then print out the contents.
ETA: Tried out sarnold's suggestion and got the output I want.
ETA2: I could have a longer first column. Is there a way to change ONLY the first 3 '.' in the first column to '-', so I get the output
abc-def-ghi-qqq.www,123.4561.789,ABC,DEF,GHI
abc-def-ghq-qqq.www,124.4562.789,ABC,DEF,GHI
abc-def-ghw-qqq.www,125.4563.789,ABC,DEF,GHI
abc-def-ghe-qqq.www,126.4564.789,,,
abc-def-ghr-qqq.www,127.4565.789,,,
. is regexp notation for "any character". Escape it with \ and it means .:
$ awk -F, '{gsub(/\./,"-",$1); print}' textfile.csv
abc-def-ghi 123.4561.789 ABC DEF GHI
abc-def-ghq 124.4562.789 ABC DEF GHI
abc-def-ghw 125.4563.789 ABC DEF GHI
abc-def-ghe 126.4564.789
abc-def-ghr 127.4565.789
$
The output field separator is a space, by default. Set OFS = "," to set that:
$ awk -F, 'BEGIN {OFS=","} {gsub(/\./,"-",$1); print}' textfile.csv
abc-def-ghi,123.4561.789,ABC,DEF,GHI
abc-def-ghq,124.4562.789,ABC,DEF,GHI
abc-def-ghw,125.4563.789,ABC,DEF,GHI
abc-def-ghe,126.4564.789,,,
abc-def-ghr,127.4565.789,,,
This still allows changing multiple fields:
$ awk -F, 'BEGIN {OFS=","} {gsub(/\./,"-",$1); gsub("1", "#",$2); print}' textfile.csv
abc-def-ghi,#23.456#.789,ABC,DEF,GHI
abc-def-ghq,#24.4562.789,ABC,DEF,GHI
abc-def-ghw,#25.4563.789,ABC,DEF,GHI
abc-def-ghe,#26.4564.789,,,
abc-def-ghr,#27.4565.789,,,
I don't know what -OFS, does, but it isn't a supported command line option; using it to set the output field separator was a mistake on my part. Setting OFS within the awk program works well.
This might work for you:
awk -F, -vOFS=, '{for(n=1;n<=3;n++)sub(/\./,"-",$1)}1' file
abc-def-ghi-qqq.www,123.4561.789,ABC,DEF,GHI
abc-def-ghq-qqq.www,124.4562.789,ABC,DEF,GHI
abc-def-ghw-qqq.www,125.4563.789,ABC,DEF,GHI
abc-def-ghe-qqq.www,126.4564.789,,,
abc-def-ghr-qqq.www,127.4565.789,,,
I have the requirement to convert row string data to column format and pre/postfix specific strings. The data string in file has 4 major fixed columns (separated by ";") and each column is further divided in two sections (separated by ":").
E.g.
Source data file:
A100:T100;B100:T200;A200:T300;B200:T400
Output from file should be:
TABa:BatchID=A100:TagId=T100:ProcId=1
TABb:BatchID=B100:TagId=T200:ProcId=2
TABc:BatchID=A200:TagId=T300:ProcId=3
TABd:BatchID=B200:TagId=T400:ProcId=4
Meanwhile I am trying with following code:
String="A100:T100;B100:T200;A200:T300;B200:T400"
> File.txt
for deploy in $(echo $String | tr ";" "\n")
do
echo $deploy >> File.txt
done
cat File.txt | awk 'BEGIN { FS=":"; OFS=":" } NR==1{ print "TABa:BatchID="$1,$2 } NR==2{ print "TABb:BatchID="$1,$2 }'
printf handles this:
$ awk -F: '{sub(/\n/,""); printf "TAB%c:BatchID=%s:TagId=%s:ProcId=%i\n",(NR+96),$1,$2,NR }' RS=';' File.txt
TABa:BatchID=A100:TagId=T100:ProcId=1
TABb:BatchID=B100:TagId=T200:ProcId=2
TABc:BatchID=A200:TagId=T300:ProcId=3
TABd:BatchID=B200:TagId=T400:ProcId=4
How it works
-F:
This sets the field separator to a colon: :.
sub(/\n/,"")
This removes newline characters.
printf "TAB%c:BatchID=%s:TagId=%s:ProcId=%i\n",(NR+96),$1,$2,NR
This does all the work. It makes use of the record number, NR, and the first and second fields and prints the output that you want.
RS=';'
This tells awk to use a semicolon, ;, as the record separator.
I have to process a file with data organized like this
AAAAA:BB:CCC:EEEE:DDDD
FF:III:JJJ:KK:LLL
MMMM:NN:OOO:PP
etc
Columns can have different length but lines always have the same number of columns.
I want to be able to cut a specific column of a given line and change it to the value I want.
For example I'd apply my command and change the file to
AAAAA:BB:XXXX:EEEE:DDDD
FF:III:JJJ:KK:LLL
MMMM:NN:OOO:PP
I know how to select a specific line with sed and then cut the field but I have no idea on how to replace the field with the value I have.
Thanks
Here's a way to do it with awk:
Going with your example, if you wanted to replace the 3rd field of the 1st line:
awk 'BEGIN{FS=OFS=":"} {if (NR==1) {$3 = "XXXX"}; print}' input_file
Input:
AAAAA:BB:CCC:EEEE:DDDD
FF:III:JJJ:KK:LLL
MMMM:NN:OOO:PP
Output:
AAAAA:BB:XXXX:EEEE:DDDD
FF:III:JJJ:KK:LLL
MMMM:NN:OOO:PP
Explanation:
awk: invoke the awk command
'...': everything enclosed by single-quotes are instructions to awk
BEGIN{FS=OFS=":"}: Use : as delimiters for both input and output. FS stands for Field Separator. OFS stands for Output Field Separator.
if (NR==1) {$3 = "XXXX"};: If Number of Records (NR) read so far is 1, then set the 3rd field ($3) to "XXXX".
print: print the current line
input_file: name of your input file.
If instead what you are trying to accomplish is simply replace all occurrences of CCC with XXXX in your file, simply do:
sed -i 's/CCC/XXXX/g` input_file
Note that this will also replace partial matches, such as ABCCCDD -> ABXXXXDD
This might work for you (GNU sed):
sed -r 's/^(([^:]*:?){2})CCC/\1XXXX/' file
or
awk -F: -vOFS=: '$3=="CCC"{$3="XXXX"};1' file