How to extract only rows with hour and not half hour i libreoffice
2014/06/15 19:30:00
2014/06/15 20:00:00
2014/06/15 20:30:00
=>
2014/06/15 20:00:00
It turned out that i could:
extract the time part using a =right(D1;8)
Do a =IF(MINUTE(D1)<>0,"",1)
Sort by the 1's and remove the empty cells.
But, there must be a better and more neat way.
Nicolai
As moggi pointed out, it depends on the way the time data is presented:
If your values are valid date/time values for LO Calc, you can just apply the MINUTE() function to the complete value to extract the minutes, and compare it with 0. "Valid date/time" means that, e.g. the date/time value 2014/06/15 19:30:00 is internally represented as double value 40343.8125. Displaying this as date/time is a matter of formatting. You can check this by manually entering the double value into a unformatted cell and change the formatting to a date value.
If your values are text values, you may use a regex to match full-hour time values with something like .*[:digit:]{2}:00:00$. You can use this regex in Menu Data -> Filters -> Standard Filter or Advanced Filter; don't forget to enable Regular Expressions under the filter's Options.
Related
I am trying to program the system where you choose day of week and in a text field next to it you should be able to chose the time of the day in increment of 15 min + or -. Which of joins should I use for txt field and how to put default time in the field?
You would just need to use an initialised value for the default time and have it incremented +/- as needed. Text entry join numbers can be the same as text feedback joins but it's better to use different ones.
I use Google Sheets to keep a list of applications I am doing. In each row there is a date field. I want to sort by date now. The first row is frozen using View - Freeze - 1 row. When I select the whole table, press Data - Sort range... and then check Data has header row the sheet is sorted. But not by date but by string. The format of the cells is date. Is only string sorting possible? If yes, I would have to reformat the whole document to dates like 2017-01-11, correct?
The solution was to replace the . by /. Seems as if the common german format using . is not yet supported. Make sure the date is recognized as date. If the cell is right-aligned it worked, if not it did not work.
I learned that you can create a custom date format using the ..
Now the date is entered 10/01/2017 but displayed 10.01.2017. Just the way I wanted.
The fields look as described above. They are time fields from SQL imported as a varchar. I had to format as date in tableau. There can be NULL values, so I am having a tough time getting over that. Tableau statement I have is only ([time spent])+([time waited])+([time solved)].
Thank you!
If you only want to use the result for a graphical visualization of what took the longest, you can split and add all the values into seconds and using it into your view. E.g.
In this case the HH:MM:SS fields are Strings for Tableau.
The formula used to sum the three fields is:
//transforms everything into seconds for each variable
zn((INT(SPLIT([Time Spent],':',1))*3600))
+
zn((INT(SPLIT([Time Spent],":",2))*60))
+
zn((INT(SPLIT([Time Spent],":",3))))
+
zn((INT(SPLIT([Time Waited],':',1))*3600))
+
zn((INT(SPLIT([Time Waited],":",2))*60))
+
zn((INT(SPLIT([Time Waited],":",3))))
+
zn((INT(SPLIT([Time Solved],':',1))*3600))
+
zn((INT(SPLIT([Time Solved],":",2))*60))
+
zn((INT(SPLIT([Time Solved],":",3))))
Quick explanation of the formula:
I SPLIT every field three times, one for the hours, minutes and seconds, adding all the values.
There is an INT formula that will convert the strings into integers.
There is also a ZN for every field - this will make Null fields become Zeros.
You can also use the value as integer if you want, e.g. the Case A has a Total Time of 5310 seconds.
The best approach is usually to store dates in the database in a date field instead of in a string. That might mean a data prep/cleanup step before you get to Tableau, but it will help with efficiency, simplicity and robustness ever after.
You can present dates in many formats, including hh:mm, when the underlying representation is a date datatype. See the custom date options on the format pane in Tableau for example. But storing dates as formatted strings and converting them to something else for calculations is really doing things the hard way.
If you have no choice but to read in strings and convert them to dates, then you should look at the DateParse function.
Either way, decide what a null date means and make sure your calculations behave well in that case -- unless you can enforce that the date field not contain nulls in the database.
One example would be a field called Completed_Date in a table of Work_Orders. You could determine that a null Completed_Date meant the work order had not been fulfilled yet, and thus allow nulls for that field. But you could also have the database enforce that another field, say Submitted_Date, could never be null.
I'm stuck with sorting and showing the correct date in Xpages.
It is saved in format "dd.MM.yyyy" and it's a string.
Now why it's a string and formated that way, is because my boss has special wishes. And when I want to sort it from the newest date to older it does something like this:
26.05.2015
24.06.2014
22.04.2015
21.04.2015
20.03.2014
It starts sorting by day.
Is there a way to make it sort it like it should?
I see that i can write a Computed value to Sort column in view column header for date. But i don't know how to even start.
Change the underlying Notes view to get your date column into right order.
Convert the date strings to real date values in views column formula. Assuming your field is called DateText then your formula would be
#Date(#ToNumber(#Right(DateText; 4));
#ToNumber(#Middle(DateText; 3; 2));
#ToNumber(#Left(DateText; 2)))
It would be easier to use just #ToTime(DateText) but this can fail depending on server's local settings. Your date string format would work for a server with German locale settings but not for US. That's why is my suggested solution "safer".
If the date time value doesn't solve your problem and you do not transform your date via #Text (as mentioned in the comments) then create another (hidden) column BEFORE your column that should be displayed. Make this a true date (from your item), sort it and unsort the column to display.
Otherwise use this formula in the newly created sorted column:
#Text(#Year(yourDate))+"-"+#Right("00"+#Text(#Month(yourDate));2)+"-"+#Right("00"+#Text(#Day(yourDate));2)
For few columns from the source i.e .csv file, we are having values like 1:52:00, 14:45:00.
I am supposed to load to the Oracle table.
Which data type should I choose in Target as well as source?
Should i be doing any thing in the expression transformation?
Use SQLLDR to load the data into database with the format described as in the link
http://docs.oracle.com/cd/B19306_01/server.102/b14200/sql_elements004.htm
ie.'HH24:MI:SS'
Oracle does not support time-only values, it supports dates (with a time component).
You have a few options:
Store the value as a string, perhaps providing a leading zero for
the hour.
Store the value as the number of seconds (or minutes) past midnight.
Store the value as the time component of some arbitrarily defined date, for
example 0001-JAN-01 01:52:00 and 0001-Jan-01 14:45:00. Tell your report writers to ignore the date portion of the value.
Your source datatype will be string(8). Use LPAD to add leading zeroes.