Generalized Suffix Tree Java Implementation For Large Datasets - data-structures

I have a collection of around 50 millions strings, each has around 100 characters. I am looking for very efficient (running time and memory usage) generalized suffix tree implementation.
I have tried https://github.com/npgall/concurrent-trees but it takes huge amount of memory eventhough the running time is efficient. With 2.5 million strings of length 100. It took like 50GB of memory already.

Not an ideal solution, but you could use enter link description here.
It has a CritBit1D version, were you can store arbitrary length keys.
Disadvantage #1:
You would have to convert your strings to long[] first, ie. 4-8 characters per long.
Disadvantage #2:
If you need a concurrent version, you would have to look at the Critbit64COW, which uses copy-on-write concurrency. However, this is not implemented for the Critbit1D yet, so you would need to do that yourself, using Critbit64COW as a template.
However, you could simply store only a 64bit hashcode as key, then you could use the CritBit64 (single-threaded) or CritBit64COW (multithreaded).
Btw, reading concurrently is not a problem, even with CritBit64.
Disclaimer: I'm the author of CritBit.

Related

What is the fastest way to intersect two large set of ids

The Problem
On a server, I host ids in a json file. From clients, I need to mandate the server to intersect and sometimes negate these ids (the ids never travel to the client even though the client instructs the server its operations to perform).
I typically have 1000's of ids, often have 100,000's of ids, and have a maximum of 56,000,000 of them, where each value is unique and between -100,000,000 and +100,000,000.
These ids files are stable and do not change (so it is possible to generate a different representation for it that is better adapted for the calculations if needed).
Sample ids
Largest file sizes
I need an algorithm that will intersect ids in the sub-second range for most cases. What would you suggest? I code in java, but do not limit myself to java for the resolution of this problem (I could use JNI to bridge to native language).
Potential solutions to consider
Although you could not limit yourselves to the following list of broad considerations for solutions, here is a list of what I internally debated to resolve the situation.
Neural-Network pre-qualifier: Train a neural-network for each ids list that accepts another list of ids to score its intersection potential (0 means definitely no intersection, 1 means definitely there is an intersection). Since neural networks are good and efficient at pattern recognition, I am thinking of pre-qualifying a more time-consuming algorithm behind it.
Assembly-language: On a Linux server, code an assembly module that does such algorithm. I know that assembly is a mess to maintain and code, but sometimes one need the speed of an highly optimized algorithm without the overhead of a higher-level compiler. Maybe this use-case is simple enough to benefit from an assembly language routine to be executed directly on the Linux server (and then I'd always pay attention to stick with the same processor to avoid having to re-write this too often)? Or, alternately, maybe C would be close enough to assembly to produce clean and optimized assembly code without the overhead to maintain assembly code.
Images and GPU: GPU and image processing could be used and instead of comparing ids, I could BITAND images. That is, I create a B&W image of each ids list. Since each id have unique values between -100,000,000 and +100,000,000 (where a maximum of 56,000,000 of them are used), the image would be mostly black, but the pixel would become white if the corresponding id is set. Then, instead of keeping the list of ids, I'd keep the images, and do a BITAND operation on both images to intersect them. This may be fast indeed, but then to translate the resulting image back to ids may be the bottleneck. Also, each image could be significantly large (maybe too large for this to be a viable solution). An estimate of a 200,000,000 bits sequence is 23MB each, just loading this in memory is quite demanding.
String-matching algorithms: String comparisons have many adapted algorithms that are typically extremely efficient at their task. Create a binary file for each ids set. Each id would be 4 bytes long. The corresponding binary file would have each and every id sequenced as their 4 bytes equivalent into it. The algorithm could then be to process the smallest file to match each 4 bytes sequence as a string into the other file.
Am I missing anything? Any other potential solution? Could any of these approaches be worth diving into them?
I did not yet try anything as I want to secure a strategy before I invest what I believe will be a significant amount of time into this.
EDIT #1:
Could the solution be a map of hashes for each sector in the list? If the information is structured in such a way that each id resides within its corresponding hash key, then, the smaller of the ids set could be sequentially ran and matching the id into the larger ids set first would require hashing the value to match, and then sequentially matching of the corresponding ids into that key match?
This should make the algorithm an O(n) time based one, and since I'd pick the smallest ids set to be the sequentially ran one, n is small. Does that make sense? Is that the solution?
Something like this (where the H entry is the hash):
{
"H780" : [ 45902780, 46062780, -42912780, -19812780, 25323780, 40572780, -30131780, 60266780, -26203780, 46152780, 67216780, 71666780, -67146780, 46162780, 67226780, 67781780, -47021780, 46122780, 19973780, 22113780, 67876780, 42692780, -18473780, 30993780, 67711780, 67791780, -44036780, -45904780, -42142780, 18703780, 60276780, 46182780, 63600780, 63680780, -70486780, -68290780, -18493780, -68210780, 67731780, 46092780, 63450780, 30074780, 24772780, -26483780, 68371780, -18483780, 18723780, -29834780, 46202780, 67821780, 29594780, 46082780, 44632780, -68406780, -68310780, -44056780, 67751780, 45912780, 40842780, 44642780, 18743780, -68220780, -44066780, 46142780, -26193780, 67681780, 46222780, 67761780 ],
"H782" : [ 27343782, 67456782, 18693782, 43322782, -37832782, 46152782, 19113782, -68411782, 18763782, 67466782, -68400782, -68320782, 34031782, 45056782, -26713782, -61776782, 67791782, 44176782, -44096782, 34041782, -39324782, -21873782, 67961782, 18703782, 44186782, -31143782, 67721782, -68340782, 36103782, 19143782, 19223782, 31711782, 66350782, 43362782, 18733782, -29233782, 67811782, -44076782, -19623782, -68290782, 31721782, 19233782, 65726782, 27313782, 43352782, -68280782, 67346782, -44086782, 67741782, -19203782, -19363782, 29583782, 67911782, 67751782, 26663782, -67910782, 19213782, 45992782, -17201782, 43372782, -19992782, -44066782, 46142782, 29993782 ],
"H540" : [...
You can convert each file (list of ids) into a bit-array of length 200_000_001, where bit at index j is set if the list contains value j-100_000_000. It is possible, because the range of id values is fixed and small.
Then you can simply use bitwise and and not operations to intersect and negate lists of ids. Depending on the language and libraries used, it would require operating element-wise: iterating over arrays and applying corresponding operations to each index.
Finally, you should measure your performance and decide whether you need to do some optimizations, such as parallelizing operations (you can work on different parts of arrays on different processors), preloading some of arrays (or all of them) into memory, using GPU, etc.
First, the bitmap approach will produce the required performance, at a huge overhead in memory. You'll need to benchmark it, but I'd expect times of maybe 0.2 seconds, with that almost entirely dominated by the cost of loading data from disk, and then reading the result.
However there is another approach that is worth considering. It will use less memory most of the time. For most of the files that you state, it will perform well.
First let's use Cap'n Proto for a file format. The type can be something like this:
struct Ids {
is_negated #0 :Bool;
ids #1 :List(Int32);
}
The key is that ids are always kept sorted. So list operations are a question of running through them in parallel. And now:
Applying not is just flipping is_negated.
If neither is negated, it is a question of finding IDs in both lists.
If the first is not negated and the second is, you just want to find IDs in the first that are not in the second.
If the first is negated and the second is not, you just want to find IDs in the second that are not in the first.
If both are negated, you just want to find all ids in either list.
If your list has 100k entries, then the file will be about 400k. A not requires copying 400k of data (very fast). And intersecting with another list of the same size involves 200k comparisons. Integer comparisons complete in a clock cycle, and branch mispredictions take something like 10-20 clock cycles. So you should be able to do this operation in the 0-2 millisecond range.
Your worst case 56,000,000 file will take over 200 MB and intersecting 2 of them can take around 200 million operations. This is in the 0-2 second range.
For the 56 million file and a 10k file, your time is almost all spent on numbers in the 56 million file and not in the 10k one. You can speed that up by adding a "galloping" mode where you do a binary search forward in the larger file looking for the next matching number and picking most of them. Do be warned that this code tends to be tricky and involves lots of mispredictions. You'll have to benchmark it to find out how big a size difference is needed.
In general this approach will lose for your very biggest files. But it will be a huge win for most of the sizes of file that you've talked about.

Fastest algorithm to detect duplicate files

In the process of finding duplicates in my 2 terabytes of HDD stored images I was astonished about the long run times of the tools fslint and fslint-gui.
So I analyzed the internals of the core tool findup which is implemented as very well written and documented shell script using an ultra-long pipe. Essentially its based on find and hashing (md5 and SHA1).
The author states that it was faster than any other alternative which I couldn't believe. So I found Detecting duplicate files where the topic quite fast slided towards hashing and comparing hashes which is not the best and fastest way in my opinion.
So the usual algorithm seems to work like this:
generate a sorted list of all files (path, Size, id)
group files with the exact same size
calculate the hash of all the files with a same size and compare the hashes
same has means identical files - a duplicate is found
Sometimes the speed gets increased by first using a faster hash algorithm (like md5) with more collision probability and second if the hash is the same use a second slower but less collision-a-like algorithm to prove the duplicates. Another improvement is to first only hash a small chunk to sort out totally different files.
So I've got the opinion that this scheme is broken in two different dimensions:
duplicate candidates get read from the slow HDD again (first chunk) and again (full md5) and again (sha1)
by using a hash instead just comparing the files byte by byte we introduce a (low) probability of a false negative
a hash calculation is a lot slower than just byte-by-byte compare
I found one (Windows) app which states to be fast by not using this common hashing scheme.
Am I totally wrong with my ideas and opinion?
[Update]
There seems to be some opinion that hashing might be faster than comparing. But that seems to be a misconception out of the general use of "hash tables speed up things". But to generate a hash of a file the first time the files needs to be read fully byte by byte. So there a byte-by-byte-compare on the one hand, which only compares so many bytes of every duplicate-candidate function till the first differing position. And there is the hash function which generates an ID out of so and so many bytes - lets say the first 10k bytes of a terabyte or the full terabyte if the first 10k are the same. So under the assumption that I don't usually have a ready calculated and automatically updated table of all files hashes I need to calculate the hash and read every byte of duplicates candidates. A byte-by-byte compare doesn't need to do this.
[Update 2]
I've got a first answer which again goes into the direction: "Hashes are generally a good idea" and out of that (not so wrong) thinking trying to rationalize the use of hashes with (IMHO) wrong arguments. "Hashes are better or faster because you can reuse them later" was not the question.
"Assuming that many (say n) files have the same size, to find which are duplicates, you would need to make n * (n-1) / 2 comparisons to test them pair-wise all against each other. Using strong hashes, you would only need to hash each of them once, giving you n hashes in total." is skewed in favor of hashes and wrong (IMHO) too. Why can't I just read a block from each same-size file and compare it in memory? If I have to compare 100 files I open 100 file handles and read a block from each in parallel and then do the comparison in memory. This seams to be a lot faster then to update one or more complicated slow hash algorithms with these 100 files.
[Update 3]
Given the very big bias in favor of "one should always use hash functions because they are very good!" I read through some SO questions on hash quality e.g. this:
Which hashing algorithm is best for uniqueness and speed? It seams that common hash functions more often produce collisions then we think thanks to bad design and the birthday paradoxon. The test set contained: "A list of 216,553 English words (in lowercase),
the numbers "1" to "216553" (think ZIP codes, and how a poor hash took down msn.com) and 216,553 "random" (i.e. type 4 uuid) GUIDs". These tiny data sets produced from arround 100 to nearly 20k collisions. So testing millions of files on (in)equality only based on hashes might be not a good idea at all.
I guess I need to modify 1 and replace the md5/sha1 part of the pipe with "cmp" and just measure times. I keep you updated.
[Update 4]
Thanks for alle the feedback. Slowly we are converting. Background is what I observed when fslints findup had running on my machine md5suming hundreds of images. That took quite a while and HDD was spinning like hell. So I was wondering "what the heck is this crazy tool thinking in destroying my HDD and taking huge amounts of time when just comparing byte-by-byte" is 1) less expensive per byte then any hash or checksum algorithm and 2) with a byte-by-byte compare I can return early on the first difference so I save tons of time not wasting HDD bandwidth and time by reading full files and calculating hashs over full files. I still think thats true - but: I guess I didn't catch the point that a 1:1 comparison (if (file_a[i] != file_b[i]) return 1;) might be cheaper than is hashing per byte. But complexity wise hashing with O(n) may win when more and files need to be compared against each other. I have set this problem on my list and plan to either replace the md5 part of findup's fslint with cmp or enhance pythons filecmp.py compare lib which only compares 2 files at once with a multiple files option and maybe a md5hash version.
So thank you all for the moment.
And generally the situation is like you guys say: the best way (TM) totally depends on the circumstances: HDD vs SSD, likelyhood of same length files, duplicate files, typical files size, performance of CPU vs. Memory vs. Disk, Single vs. Multicore and so on. And I learned that I should considder more often using hashes - but I'm an embedded developer with most of the time very very limited resources ;-)
Thanks for all your effort!
Marcel
The fastest de-duplication algorithm will depend on several factors:
how frequent is it to find near-duplicates? If it is extremely frequent to find hundreds of files with the exact same contents and a one-byte difference, this will make strong hashing much more attractive. If it is extremely rare to find more than a pair of files that are of the same size but have different contents, hashing may be unnecessary.
how fast is it to read from disk, and how large are the files? If reading from the disk is very slow or the files are very small, then one-pass hashes, however cryptographically strong, will be faster than making small passes with a weak hash and then a stronger pass only if the weak hash matches.
how many times are you going to run the tool? If you are going to run it many times (for example to keep things de-duplicated on an on-going basis), then building an index with the path, size & strong_hash of each and every file may be worth it, because you would not need to rebuild it on subsequent runs of the tool.
do you want to detect duplicate folders? If you want to do so, you can build a Merkle tree (essentially a recursive hash of the folder's contents + its metadata); and add those hashes to the index too.
what do you do with file permissions, modification date, ACLs and other file metadata that excludes the actual contents? This is not related directly to algorithm speed, but it adds extra complications when choosing how to deal with duplicates.
Therefore, there is no single way to answer the original question. Fastest when?
Assuming that two files have the same size, there is, in general, no fastest way to detect whether they are duplicates or not than comparing them byte-by-byte (even though technically you would compare them block-by-block, as the file-system is more efficient when reading blocks than individual bytes).
Assuming that many (say n) files have the same size, to find which are duplicates, you would need to make n * (n-1) / 2 comparisons to test them pair-wise all against each other. Using strong hashes, you would only need to hash each of them once, giving you n hashes in total. Even if it takes k times as much to hash than to compare byte-by-byte, hashing is better when k > (n-1)/2. Hashes may yield false-positives (although strong hashes will only do so with astronomically low probabilities), but testing those byte-by-byte will only increment k by at most 1. With k=3, you will be ahead as soon as n>=7; with a more conservative k=2, you reach break-even with n=3. In practice, I would expect k to be very near to 1: it will probably be more expensive to read from disk than to hash whatever you have read.
The probability that several files will have the same sizes increases with the square of the number of files (look up birthday paradox). Therefore, hashing can be expected to be a very good idea in the general case. It is also a dramatic speedup in case you ever run the tool again, because it can reuse an existing index instead of building it anew. So comparing 1 new file to 1M existing, different, indexed files of the same size can be expected to take 1 hash + 1 lookup in the index, vs. 1M comparisons in the no-hashing, no-index scenario: an estimated 1M times faster!
Note that you can repeat the same argument with a multilevel hash: if you use a very fast hash with, say, the 1st, central and last 1k bytes, it will be much faster to hash than to compare the files (k < 1 above) - but you will expect collisions, and make a second pass with a strong hash and/or a byte-by-byte comparison when found. This is a trade-off: you are betting that there will be differences that will save you the time of a full hash or full compare. I think it is worth it in general, but the "best" answer depends on the specifics of the machine and the workload.
[Update]
The OP seems to be under the impression that
Hashes are slow to calculate
Fast hashes produce collisions
Use of hashing always requires reading the full file contents, and therefore is overkill for files that differ in their 1st bytes.
I have added this segment to counter these arguments:
A strong hash (sha1) takes about 5 cycles per byte to compute, or around 15ns per byte on a modern CPU. Disk latencies for a spinning hdd or an ssd are on the order of 75k ns and 5M ns, respectively. You can hash 1k of data in the time that it takes you to start reading it from an SSD. A faster, non-cryptographic hash, meowhash, can hash at 1 byte per cycle. Main memory latencies are at around 120 ns - there's easily 400 cycles to be had in the time it takes to fulfill a single access-noncached-memory request.
In 2018, the only known collision in SHA-1 comes from the shattered project, which took huge resources to compute. Other strong hashing algorithms are not much slower, and stronger (SHA-3).
You can always hash parts of a file instead of all of it; and store partial hashes until you run into collisions, which is when you would calculate increasingly larger hashes until, in the case of a true duplicate, you would have hashed the whole thing. This gives you much faster index-building.
My points are not that hashing is the end-all, be-all. It is that, for this application, it is very useful, and not a real bottleneck: the true bottleneck is in actually traversing and reading parts of the file-system, which is much, much slower than any hashing or comparing going on with its contents.
The most important thing you're missing is that comparing two or more large files byte-for-byte while reading them from a real spinning disk can cause a lot of seeking, making it vastly slower than hashing each individually and comparing the hashes.
This is, of course, only true if the files actually are equal or close to it, because otherwise a comparison could terminate early. What you call the "usual algorithm" assumes that files of equal size are likely to match. That is often true for large files generally.
But...
When all the files of the same size are small enough to fit in memory, then it can indeed be a lot faster to read them all and compare them without a cryptographic hash. (an efficient comparison will involve a much simpler hash, though).
Similarly when the number of files of a particular length is small enough, and you have enough memory to compare them in chunks that are big enough, then again it can be faster to compare them directly, because the seek penalty will be small compared to the cost of hashing.
When your disk does not actually contain a lot of duplicates (because you regularly clean them up, say), but it does have a lot of files of the same size (which is a lot more likely for certain media types), then again it can indeed be a lot faster to read them in big chunks and compare the chunks without hashing, because the comparisons will mostly terminate early.
Also when you are using an SSD instead of spinning platters, then again it is generally faster to read + compare all the files of the same size together (as long as you read appropriately-sized blocks), because there is no penalty for seeking.
So there are actually a fair number of situations in which you are correct that the "usual" algorithm is not as fast as it could be. A modern de-duping tool should probably detect these situations and switch strategies.
Byte-by-byte comparison may be faster if all file groups of the same size fit in physical memory OR if you have a very fast SSD. It also may still be slower depending on the number and nature of the files, hashing functions used, cache locality and implementation details.
The hashing approach is a single, very simple algorithm that works on all cases (modulo the extremely rare collision case). It scales down gracefully to systems with small amounts of available physical memory. It may be slightly less than optimal in some specific cases, but should always be in the ballpark of optimal.
A few specifics to consider:
1) Did you measure and discover that the comparison within file groups was the expensive part of the operation? For a 2TB HDD walking the entire file system can take a long time on its own. How many hashing operations were actually performed? How big were the file groups, etc?
2) As noted elsewhere, fast hashing doesn't necessarily have to look at the whole file. Hashing some small portions of the file is going to work very well in the case where you have sets of larger files of the same size that aren't expected to be duplicates. It will actually slow things down in the case of a high percentage of duplicates, so it's a heuristic that should be toggled based on knowledge of the files.
3) Using a 128 bit hash is probably sufficient for determining identity. You could hash a million random objects a second for the rest of your life and have better odds of winning the lottery than seeing a collision. It's not perfect, but pragmatically you're far more likely to lose data in your lifetime to a disk failure than a hash collision in the tool.
4) For a HDD in particular (a magnetic disk), sequential access is much faster than random access. This means a sequential operation like hashing n files is going to be much faster than comparing those files block by block (which happens when they don't fit entirely into physical memory).

Using hashing for efficient Deep Packet Inspection

In order to enhance the performance of Deep Packet Inspection we are preprocessing the set of rules by performing a hashing algorithm on them which in turn divides the rules into smaller chunks of sub-rules, making the inspection much faster.
The hashing is done on the first 17 bits of the originally 104. After the preprocessing is done, whenever a packet arrives, we hash its first 17 bits and check it against the much smaller set of rules based on the result.
(The algorithm is used twice, after hashing the first 17 it hashes the next 16 bits and stores the results as well, but for this specific problem we can assume that we're only performing a simple hash on a fixed number of bits)
The algorithm is indeed efficient, however, we can't seem to find a way to apply it on entries with don't care bits - which we get a lot.
We searched for a solution in numerous places, and tried for instance a suggestion of duplicating rules with don't care bits. It didn't work however, for the vast amount of memory it would take (for each don't care bit of the 17 of the numerous rules there is an option of it being either 1 or zero - this would demand an exponential amount of space).
We would very much appreciate any suggestion or insight, even a partial solution would be great.
Note: There is no limit on preprocessing time or additional space as long as it is not exponential or anything impractical.
If you use the hash table as a cache and revert to something slower if an entry for the current value isn't found then you don't need to populate it completely. You could either build it ahead of time based on an analysis of previous traffic, creating as many entries as you can afford, or you could populate it dynamically, creating new entries after you process a packet when an entry was not found, and removing old entries that had not been used for some time to reclaim store.
217 is 131,072: large, but not inordinately so. If you use a bit of indirection (for example, storing your rules in an array without duplication, and then building a size-217 table of indices into that array), then you should be able to do this in well under 1 MB.

Choosing a Data structure for very large data

I have x (millions) positive integers, where their values can be as big as allowed (+2,147,483,647). Assuming they are unique, what is the best way to store them for a lookup intensive program.
So far i thought of using a binary AVL tree or a hash table, where the integer is the key to the mapped data (a name). However am not to sure whether i can implement such large keys and in such large quantity with a hash table (wouldn't that create a >0.8 load factor in addition to be prone for collisions?)
Could i get some advise on which data structure might be suitable for my situation
The choice of structure depends heavily on how much memory you have available. I'm assuming based on the description that you need lookup but not to loop over them, find nearest, or other similar operations.
Best is probably a bucketed hash table. By placing hash collisions into buckets and keeping separate arrays in the bucket for keys and values, you can both reduce the size of the table proper and take advantage of CPU cache speedup when searching a bucket. Linear search within a bucket may even end up faster than binary search!
AVL trees are nice for data sets that are read-intensive but not read-only AND require ordered enumeration, find nearest and similar operations, but they're an annoyingly amount of work to implement correctly. You may get better performance with a B-tree because of CPU cache behavior, though, especially a cache-oblivious B-tree algorithm.
Have you looked into B-trees? The efficiency runs between log_m(n) and log_(m/2)(n) so if you choose m to be around 8-10 or so you should be able to keep your search depth to below 10.
Bit Vector , with the index set if the number is present. You can tweak it to have the number of occurrences of each number. There is a nice column about bit vectors in Bentley's Programming Pearls.
If memory isn't an issue a map is probably your best bet. Maps are O(1) meaning that as you scale up the number of items to be looked up the time is takes to find a value is the same.
A map where the key is the int, and the value is the name.
Do try hash tables first. There are some variants that can tolerate being very dense without significant slowdown (like Brent's variation).
If you only need to store the 32-bit integers and not any associated record, use a set and not a map, like hash_set in most C++ libraries. It would use only 4-bytes records plus some constant overhead and a little slack to avoid being 100%. In the worst case, to handle 'millions' of numbers you'd need a few tens of megabytes. Big, but nothing unmanageable.
If you need it to be much tighter, just store them sorted in a plain array and use binary search to fetch them. It will be O(log n) instead of O(1), but for 'millions' of records it's still just twentysomething steps to get any one of them. In C you have bsearch(), which is as fast as it can get.
edit: just saw in your question you talk about some 'mapped data (a name)'. are those names unique? do they also have to be in memory? if yes, they would definitely dominate the memory requirements. Even so, if the names are the typical english words, most would be 10 bytes or less, keeping the total size in the 'tens of megabytes'; maybe up to a hundred megs, still very manageable.

Best way to store and retrieve a DAWG data structure for fast loading

I have a 500k+ wordlist that I loaded it into a DAWG data structure. My app is for mobile phones. I of course don't want to repeat all the conversion steps to load this wordlist into a DAWG every time, since it would take to much storage space to have the wordlist on the phone and to much time to load it into a DAWG every time. So, I am looking for a way to store the data in my DAWG to a file or DB in a format that will both conserve space and allow for me to quickly load it back into my DAWG data structure.
I received one suggestion that I could store each node in a SQLite DB, but I am not sure how that would exactly work and if I did that how would I retrieve it quickly. I certainly wouldn't want to run lots of queries. Would some other type of storage method be better? I also received suggestions of creating a serialised file or to store it as a bitmap.
You can basically do a memory dump, just use offsets instead of pointers (in Java terms, put all nodes in an array, and use array index to refer to a node).
500k doesn't seem like amount that would be problematic for modern phones, especially that DAWG is quite efficient already. If you mmap the file, you would be able to work with the data structure even if it doesn't fit in memory.
Did you tried to reduce the wordlist? Are you saving only the word stam if possible for your application?
Other hand: You never should rebuild the data structure because the wordlist is constant. Try do use a memory dump like suggusted. Use mmap for the file, java serialization or pickle pickle technics to load a ready-made data structure into your memory.
I guess, you are using DAWG for fast searching some word in a dictionary. DAWG has O(LEN) search complexity.
Many years ago, I developed J2ME app and faced with the same problem. But in that times phones definetely couldn't provide such RAM amount of RAM memory, to store 500K+ strings) The solution I used is the following:
Read all words, sort them, put in some file line by line and for
each word precompute skipBytes. - number of bytes before this
word. Computing skipBytes is trivial. pseudocode is
skipBytes[0]=words[0].bytesLen;
for i=1 to n skipBytes[i]=skipBytes[i-1]+words[i].getBytesLength
When app starts read 500k skipBytes to some int array. It
is much smaller that 500K strings)
Searching word in a dict - binary search. Imagine that you are perfoming it on sorted array but, instead of making array[i] you make something like RandomAccessFile.read(skipBytes[i]). Google Java Random Access Files my pseucode of course wrong it's just direction.
Complexity - O(LEN*LOG(N)) = LOG of Binary search and comparing strings is linear complexity. LOG(500000)~19, LEN ~ average word leng in worst case is 50 (fantastic upper bound), so search operation is still very fast, only ~1000 operation it will be done in microseconds. Advantage - small memory usage.
I should mention, that in case of web app when many users perform searhing, LOG(N) becomes important, but if your app provides service for only one person LOG(500000) doesn't change much if it performed not inside a loop)

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