Swift 2 get minutes and seconds from double - time

Question

I am currently storing time in seconds (for example 70.149 seconds). How would I easily get the minutes and seconds? What I mean is 70.149 seconds is 1min and 10sec. How would I be able to do this easily in swift?
Here is an example of what I want to do.
let time:Double = 70.149 //This can be any value
let mins:Int = time.minutes //In this case it would be 1
let secs:Int = time.seconds //And this would be 10
How would I do this using Swift 2 OS X (not iOS)

Answer 1

Something like this:
let temp:Int = Int(time + 0.5) // Rounding
let mins:Int = temp / 60
let secs:Int = temp % 60

Answer 2

This would be a relatively simple solution. It's worth noting this would truncate partial seconds. You'd have to use floating point math on the third line and call trunc()/ceil()/floor() on the result before conversion to an Int if you wanted control over that.
let time:Double = 70.149 //This can be any value
let mins:Int = Int(time) / 60 //In this case it would be 1
let secs:Int = Int(time - Double(mins * 60)) //And this would be 10

Answer 3

Swift 5
The date components formatter has lots of advantages when displaying human readable text to a user. This function will take a double.
func humanReadable(time:Double) -> String {
let formatter = DateComponentsFormatter()
formatter.allowedUnits = [.hour, .minute, .second]
formatter.unitsStyle = .full
if let str = formatter.string(from: time) {
return str
}
return "" // empty string if number fails
}
// will output '1 minute, 10 seconds' for 70.149